Get value in PHP from JSON - php

Question

I need to get the objects information for "label", "name" where value=true in a PHP variable and not were value=false.
How is this done with this JSON array?
If I make a var_dump of the JSON I get this:
array(8) {
[0]=>
object(stdClass)#8 (3) {
["label"]=>
string(4) "Name"
["name"]=>
string(7) "txtName"
["value"]=>
bool(true)
}
[1]=>
object(stdClass)#9 (3) {
["label"]=>
string(6) "E-mail"
["name"]=>
string(8) "txtEmail"
["value"]=>
bool(true)
}
[2]=>
object(stdClass)#10 (3) {
["label"]=>
string(12) "Phone Number"
["name"]=>
string(8) "txtPhone"
["value"]=>
bool(false)
}
[3]=>
object(stdClass)#11 (3) {
["label"]=>
string(19) "Mobile Phone Number"
["name"]=>
string(14) "txtMobilePhone"
["value"]=>
bool(false)
}
}

Answer 1

$arr = array();
$i = 0;
foreach($json as $key => $items) {
if($items->value == true) {
$arr[$i]['label'] = $items->label;
$arr[$i]['name'] = $items->name;
$i++;
}
}

Answer 2

You can decode it as an object or an array, in this example I use an array.
First you want to take the JSON encoded information and decode it into a PHP array, you can use json_decode() for this:
$data = json_decode($thejson,true);
//the Boolean argument is to have the function return an array rather than an object
Then you can loop through it as you would a normal array, and build a new array containing only elements where 'value' matches your needs:
foreach($data as $item) {
if($item['value'] == true) {
$result[] = $item;
}
}
You then have the array
$result
at your disposal.

Answer 3

Simplification of the suggestions proposed by users JohnnyFaldo and som:
$data = json_decode($thejson, true);
$result = array_filter($data, function($row) {
return $row['value'] == true;
});