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This is the error I get when I load any of my sites but one:
Fatal error: Call to undefined method Settings::printLinks() in /home/admin/server/index.php on line 87
Call Stack: 0.0001 644544 1. {main}() /home/admin/server/index.php:0
The error showed about 2 hours ago caused by no obvious reasons... nothing has been moderated to cause it.
It happened yesterday to thousand (or more?) of wordpress users.
The mainly reasons are plugins, so disable them all.
If it still shows, then its probably caused by your theme
you can change it or upload it on another blog just to be sure
Problem for me was a popup plugin.
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when i use imagejpeg() it works fine in local while giving error on live
here is the warning message
Warning: imagejpeg() [function.imagejpeg]: Unable to open 'http://test.ourserv.com/Optfolder/cmp_dd5ac79bcf/20131027_185925.jpg' for writing: No such file or directory in /home3/test/public_html/server/Optfolder/image_re.php on line 36
i had same error with opendir() but when i write path like this it resolved but when i use even this kind of path instead of http it does not work with imagejpeg()
what is the path should i use,why path work locally fine and not on live server in php??
opendir('/home3/test/public_html/server/Optfolder/upload/upload');
use path like this
this will help you
$abs_dir=dirname(__FILE__);
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I'm running PHP on a Windows 8.1 server with IIS. I have a PHP script, and have managed to turn displaying errors on. I found an error on this line.
$hr06status = mysqli_fetch_array(mysqli_query($connection, "SELECT status FROM hours WHERE hour = 6"))['status'];
The exact error is on line 14 Parse error: syntax error, unexpected '['
You trying to do array dereferencing which is only available in PHP 5.4 or later. You are probably running a version older than that so that line of code won't work.
The code in the comment above is the correct way to write it for your version of PHP.
Indexing on the return value of a function is something PHP added only recently. As Dave Chen says in the comment, you need an interim variable that you can then later index.
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Well am creating a php based application therefore I wish to accompany it with a configuration file. However the configuration will have a few variables which will be updated once in a while.
Therefore how can I read a file and update a specific variable in it?
It's common to define your own configuration in .ini files and parse them with parse_ini_file()
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When I try to insert data into MySQL database I got this error:
Error Msg
#1030 - Got error -1 from storage engine
What could be the problem?
The first thing you do is check whether you are out of disk space.This error probably means you don't have enough memory for allocating to your table or database, or the specified memory settings for MySQL are too high for the configuration of your machine.
the following link may be useful to you http://wiki.jumpbox.com/doc/runtime/faq/mysql_maintenance
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How to Download 4 files at a time which are stored in database? It is combination of pdf,png,jpg,jpeg files. I want to download all the four files on a click on download button.
Create a .zip file using php, then once you have the 1 file, link to it so that the user can right click-download as or something similar.
This way, it be faster than downloading 4 separate files.
(link found on Google, i'm sure there are better tutorials out there, but google really is your friend).