First I'm sorry if this question is duplicated but I tried to find here the solution and spent some time reading some tutorials but I haven't found the solution.
I'm starting to learn PHP. I use Easy PHP 13.1 VC9.
In my testing project I have to files:
index.php:
<?php
global $str_texto;
echo 'before ';
require ('vars.php');
echo "$str_texto";
echo ' after';
?>
vars.php:
<? php
global $str_texto = 'String text';
$data_hoje = date('j / F / Y');
?>
When I start index.php my browser shows the page without errors (so I assume that EasyPHP found the file). It shows the words "before" and "after" but doesn't show the $str_texto string.
I compared my code to some code available on web like this available on PHP: Include - Manual :
vars.php
<?php
$color = 'green';
$fruit = 'apple';
?>
test.php
<?php
echo "A $color $fruit"; // A
include 'vars.php';
echo "A $color $fruit"; // A green apple
?>
The same problem happens with that sample so, on my code, I changed the Include command to Require so I can get an error message. Same behavior and no error. There's a blank space between "before" and "after" were should be "String text". Declaring $str_texto as global and change quotation marks to single quotes didn't solve the problem.
I wasn't able to find any problem on web like this. Can you help?
There is a space in your php declaration in vars.php
<? php
Should be
<?php
Try this without quotes because is a variable:
echo $str_texto;
AND
change open-tag:
<? php
to
<?php
Try this:
var.php:
<?php
global $str_texto;
$str_texto = 'String text';
$data_hoje = date('j / F / Y');
?>
index.php:
<?php
global $str_texto;
echo 'before ';
require ('vars.php');
echo $str_texto;
echo ' after';
?>
Related
<?php echo $row["html"]; ?>
Inside of the $row["html"] there's:
<?php $Site->Nav($owner); ?>
but when I echo it, it only echoes:
Nav($owner); ?>
How may I print the full and make it usable, which means that it will print the function Nav?
I've tried to replace <?php with [[// i the database, and just before echoing it, I change back with replace. But without success
I think you need to use eval function of php. See the example below.
$string = 'cup';
$name = 'coffee';
$str = 'This is a $string with my $name in it.';
echo $str. "\n";
eval("\$str = \"$str\";");
echo $str. "\n";
Might be it can help.
Use eval function. It might solve your problem like this:
<?php echo eval($row["html"]); ?>
Keep the code as is in DB as if you are writing it in PHP file but without PHP opening and closing tags i.e. <?php and ?>. I haven't checked this (as i am not sure what $Site->Nav($owner); will do) but hope it would work in this case.
If I understand correctly you are wanting to output the results of $Site->Nav($owner);
I have no idea what this is expected to output, but assuming it is a string of some kind that you wish to display (hence echo) - an example of achieving this would be calling your code and have that method return the value, so you can echo it out. Ie:
function Nav($owner){
// Do your stuff
return 'Your Desired Output';
}
Then on your page you would have
<?php echo $Site->Nav($owner); ?>
Which would echo "Your Desired Output".
How can I use the HTML <code> element to output a block of PHP code, without the page running that PHP code? Eg;
<pre><code>
<?php
// Some super duper PHP code
?>
</code></pre>
I'm creating an API docs page, which features snippets of PHP that anyone wishing to use the API can use as examples, but anything wrapped in <?php> tags runs as an actual PHP function
Use <?php and ?>.
The HTML entities will show up as PHP opening and closing tags when the page is rendered, but PHP will obviously not see them. But you have to html-escape your code anyways, otherwise contained HTML-tags will be rendered. So there should be
<?php echo 'Hello, World.<br>'; ?>
Another way would be to have a string specified by a nowdoc and then output html-escaped (demo):
<?php
$code = <<<'EOC'
<?php
echo 'Hello, World.<br>';
// ...your code here...
?>
EOC;
echo htmlentities($code);
?>
Have look for different approaches at How do I display PHP code in HTML?.
Do this via PHP like so:
<?php
$code = '<?php
echo "Hello, World!";
?>';
echo '<code>' . htmlspecialchars($code) . '</code>';
?>
try something like this:
<?php echo '<?php'; ?>
This may help you.........
######################################################################
echo "<h2><br>Source Code of ".basename((string)__FILE__) . "</h2><hr>";
show_source(__FILE__);
echo "<hr>";
echo "<h2>Output of ".basename((string)__FILE__) . "<hr></h2>";
#######################################################################
I had to convert the less-than and greater-than to their HTML name.
<pre><code><?php echo
"<!--
This is the church title to be used in the heading of the web-pages.
Author: John Fischer III of Written For Christ in 2018
Updated:
-->
<?php echo 'Our Little Church:'; ?>" ?>
</code></pre>
I'm looking for something much like the Using PHP variables inside HTML tags? question, but a little different.
In my case, I'd like to use code ore like this:
$somevar = 'a test';
include("file.html");
and file.html would contain
<b>hello, this is {$somevar}</b>
The problem is that it just prints hello, this is {$somevar}.
How can I make the HTML read the vars in the included file?
echo "<b>hello, this is {$somevar}</b>";
or
<b>hello, this is <?=$somevar?></b>
or
<b>hello, this is <?php echo $somevar; ?></b>
or
<b>hello, this is <?php print $somevar; ?></b>
You need to include the variable defining program, in the other program wanting to access it.
Example:
Say test.html has $somevar.
in file.html you do,
<?php
include('test.html');
echo "<b>hello, this is $somevar</b>";
?>
<?php
include "stuff.php";
$somevar = "test";
?>
<html>
<body><p><?php echo($somevar); ?></p></body>
</html>
I wanted to try out an example you can find here: http://php.net/manual/en/function.include.php,
but I can't seem to be able to make it work.
In a first file, index1.php, I put this:
<?php
$color = 'green';
$fruit = 'apple';
?>
In the second file,index2.php, I put this:
<?php
include("http://www.domain.com/mypathtothefile/index2.php");
echo "A $color $fruit";
?>
It should echo 'A green apple', but it echos nothing.
The path is correct though, since when I put the echo part in the first file (index1.php), then it does echo 'A geen apple', both in index1.php as index2.php.
Hope someone can help.
Thanks in advance!
Shouldn't it just be:
include('index1.php');
Edit: corrected to reflect file names.
I want to be able to put PHP into the database and run it. I have to do this because I store page layouts in the database and each our different for each other, however in some cases I want to use dynamic content for some of the pages.
Assume $query_from_db is the string returned from the database. PHP should only eval() the code in between <?php and ?>
$query_from_db = '<div>
<?php
//php to run
function dosomething() {
//bleh
}
?>
</div>
';
php echo eval($query_from_db);
How can I do this? I'm aware this is not recommended.
I'm not arguing about the sense or nonsense of this approach. To some extend, this is a valid question.
See the documentation:
To mix HTML output and PHP code you can use a closing PHP tag to leave PHP mode.
So you have to do:
eval('?> ' . $query_from_db . ' <?php ');
DEMO
Also note that eval is outputting directly to the browser. It does not return a value. Have a look at Output Control Functions for buffering.
You are aware that this is not recommended and I strongly urge everyone to review the comments to this question.
But to provide an answer:
<?php
$string = 'hello <?php echo "world"; ?>';
eval('?>'.$string.'<?'); // will output "hello world";
be aware that this however will not work:
<?php
$string = 'hello <?php echo "world"; ?>';
eval('?>'.$string.'<?php'); // error will be thown
This works again:
<?php
$string = 'hello <?php echo "world"; ?>';
eval('?> '.$string.' <?php '); // will output "hello world";
i am not really sure why.
following up on your comment to grab the output you can do:
<?php
$string = 'hello <?php echo "world"; ?>';
ob_start();
eval('?> '.$string.' <?php '); // will output "hello world";
$output = ob_get_clean(); // $output will now contain "hello world". No text will have ben printed.
If you want to avoid the eval stigmata, you can alternatively use:
include("data:,$query_from_db");
It's just another name for eval which doesn't upset people as much. It depends on the php.ini setting allow_url_include however.
What you are doing is functionally equivalent to include("$template/$by_name.php"); and just differs in that you didn't put the database content into a file before. (But that's the other workaround: file_put_contents && include).