I have a script below that detects for words in my word filter (an array), and determines whether a string is clean or not.
What I have below works well when the words are used with spacing. But ifiwritesomething without spaces, it doesn't detect.
How can I make it such that it searches the whole string instead of words? I tried removing the explode function but I got some errors...
$string = 'goodmorningnoobs';
$array = array("idiot","noob");
if(0 == count(array_intersect(array_map('strtolower', explode(' ', $string)), $array))){
echo"clean";
} else {
echo "unclean";
}
Can anyone help?
$clean = true;
foreach ( $array as $word ) {
if ( stripos($string, $word) !== false ) {
$clean = false;
break;
}
}
echo $clean ? 'clean' : 'unclean';
How about?
$hasWords = preg_match('/'. implode('|', $words) .'/', $string);
echo $hasWords ? 'unclean' : 'clean';
Related
I have a string example
this-is-the-example/exa
I want to trim /exa from the above line
$string1 = "this-is-the-example/exa";
$string2 = "/exa";
I am using rtrim($string1, $sting2)
But the output is this-is-the-exampl
I want to this-is-the-example as output.
Both string are dynamic and may have multiple occurrences within the string. But I only want to remove the last part. Also its not compulsory that the string2 has / in it. this may be normal string too. like a, abc too..
There are various approaches you can use for this:
With substr(DEMO):
function removeFromEnd($haystack, $needle)
{
$length = strlen($needle);
if(substr($haystack, -$length) === $needle)
{
$haystack = substr($haystack, 0, -$length);
}
return $haystack;
}
$trim = '/exa';
$str = 'this-is-the-example/exa';
var_dump(removeFromEnd($str, $trim));
With regex(DEMO):
$trim = '/exa';
$str = 'this-is-the-example/exa';
function removeFromEnd($haystack, $needle)
{
$needle = preg_quote($needle, '/');
$haystack = preg_replace("/$needle$/", '', $haystack);
return $haystack;
}
var_dump(removeFromEnd($str, $trim));
First explode the string, remove last element from exploded array using array_pop, then implode it back again with /.
$str = "this-is-the-example/exa";
if(strpos($str, '/') !== false)
{
$arr = explode('/', $str);
array_pop($arr);
$str = implode('/', $arr);
// output this-is-the-example
}
This will work event if you have multiple / in the URL and will remove last element only.
$str = "this-is-the-example/somevalue/exa";
if(strpos($str, '/') !== false)
{
$arr = explode('/', $str);
array_pop($arr);
$str = implode('/', $arr);
// output this-is-the-example
}
Say hi to strstr()
$str = 'this-is-the-example/exa';
$trim = '/exa';
$result = strstr($str, $trim, true);
echo $result;
You can use explode
<?php
$x = "this-is-the-example/exa";
$y = explode('/', $x);
echo $y[0];
the second parameter of rtrim is a character mask and not a string, your last "e" is trimed and that's normal.
COnsider using something else, regexp for example (preg_replace) to fit your needs
This keeps everything before "/" char :
$str = preg_replace('/^([^\/]*).*/','$1', 'this-is-the-example/exa');
This removes the last part.
$str = preg_replace('/^(.*)\/.*$/','$1', 'this-is-the-example/exa/mple');
Hope this helps. :)
Simply try this code:
<?php
$this_example = substr("this-is-the-example/exa", 0, -4);
echo "<br/>".$this_example; // returns "this-is-the-example"
?>
To allow for error handling, if the substring is not found in the search string ...
<?php
$myString = 'this-is-the-example/exa';
//[Edit: see comment below] use strrpos, not strpos, to find the LAST occurrence
$endPosition = strrpos($myString, '/exa');
// TodO; if endPosition === False then handle error, substring not found
$leftPart = substr($myString, 0, $endPosition);
echo($leftPart);
?>
outputs
this-is-the-example
In the event of a string that says:
Once upon a time a small young LKTgoblingLKT had an unfortunate accident and LKTfellLKT.
How could I extract each occurrence of content contained within LKT into an array and replace them in the string.
You can try the following solution:
Store the sentence in a variable
explode() the sentence with space as the delimiter
Loop through the array
Check if the word contains your string using strpos()
If it does, push the word into the result array
Something like this:
$string = '...';
$words = explode(' ', $string);
foreach ($words as $word) {
if (strpos($word, 'LKT') !== FALSE) {
$result[] = $word;
}
}
print_r($result);
Output:
Array
(
[0] => LKTgoblingLKT
[1] => LKTfellLKT.
)
Demo!
If you want the string to be replaced with another word, you can use str_replace() and implode(), like so:
$string = '...';
$words = explode(' ', $string);
$result = array();
foreach ($words as $word) {
if (strpos($word, 'LKT') !== FALSE) {
$word = str_replace($word, 'FOO', $word);
}
$result[] = $word;
}
$resultString = implode(' ', $result);
echo $resultString;
Output:
Once upon a time a small young FOO had an unfortunate accident and FOO
Demo!
Example input string: "[A][B][C]test1[/B][/C][/A] [A][B]test2[/B][/A] test3"
I need to find out what parts of text are NOT between the A, B and C tags. So, for example, in the above string it's 'test2' and 'test3'. 'test2' doesn't have the C tag and 'test3' doesn't have any tag at all.
If can also be nested like this:
Example input string2: "[A][B][C]test1[/B][/C][/A] [A][B]test2[C]test4[/C][/B][/A] test3"
In this example "test4" was added but "test4" has the A,B and C tag so the output wouldn't change.
Anyone got an idea how I could parse this?
This solution is not clean but it does the trick
$string = "[A][B][C]test1[/B][/C][/A] [A][B]test2[/B][/A] test3" ;
$string = preg_replace('/<A[^>]*>([\s\S]*?)<\/A[^>]*>/', '', strtr($string, array("["=>"<","]"=>">")));
$string = trim($string);
var_dump($string);
Output
string 'test3' (length=5)
Considering the fact that everyone of you tags is in [A][/A] What you can do is: Explode the [/A] and verify if each array contains the [A] tag like so:
$string = "[A][B][C]test1[/B][/C][/A] [A][B]test2[/B][/A] test3";
$found = ''; // this will be equal to test3
$boom = explode('[/A]', $string);
foreach ($boom as $val) {
if (strpos($val, '[A] ') !== false) { $found = $val; break; }
}
echo $found; // test3
try the below code
$str = 'test0[A]test1[B][C]test2[/B][/C][/A] [A][B]test3[/B][/A] test4';
$matches = array();
// Find and remove the unneeded strings
$pattern = '/(\[A\]|\[B\]|\[C\])[^\[]*(\[A\]|\[B\]|\[C\])[^\[]*(\[A\]|\[B\]|\[C\])([^\[]*)(\[\/A\]|\[\/B\]|\[\/C\])[^\[]*(\[\/A\]|\[\/B\]|\[\/C\])[^\[]*(\[\/A\]|\[\/B\]|\[\/C\])/';
preg_match_all( $pattern, $str, $matches );
$stripped_str = $str;
foreach ($matches[0] as $key=>$matched_pattern) {
$matched_pattern_str = str_replace($matches[4][$key], '', $matched_pattern); // matched pattern with text between A,B,C tags removed
$stripped_str = str_replace($matched_pattern, $matched_pattern_str, $stripped_str); // replace pattern string in text with stripped pattern string
}
// Get required strings
$pattern = '/(\[A\]|\[B\]|\[C\]|\[\/A\]|\[\/B\]|\[\/C\])([^\[]+)(\[A\]|\[B\]|\[C\]|\[\/A\]|\[\/B\]|\[\/C\])/';
preg_match_all( $pattern, $stripped_str, $matches );
$required_strings = array();
foreach ($matches[2] as $match) {
if (trim($match) != '') {
$required_strings[] = $match;
}
}
// Special case, possible string on start and end
$pattern = '/^([^\[]*)(\[A\]|\[B\]|\[C\]).*(\[\/A\]|\[\/B\]|\[\/C\])([^\[]*)$/';
preg_match( $pattern, $stripped_str, $matches );
if (trim($matches[1]) != '') {
$required_strings[] = $matches[1];
}
if (trim($matches[4]) != '') {
$required_strings[] = $matches[4];
}
print_r($required_strings);
I want to normalize (so canonicalize) a string into the normal form for names:
First letter of the name is uppercase
The difficulty by this is now to follow this rule with second and third name.
My method:
public function namilize($string)
{
$strings = explode(' ', $string);
foreach ($strings as $string) {
$string = ucfirst(strtolower($string));
}
$string = implode(' ', $strings);
return $string;
}
Somehow the
$string = ucfirst(strtolower($string));
fails.
What do I have to correct?
Is there a better way?
Regards
EDIT:
Hi,
thank you all for all the comments and answers.
I found another "modern" method:
public function namilize($string)
{
$string = mb_convert_case($string, MB_CASE_TITLE, mb_detect_encoding($string));
}
When I now would additionally add some regex for Mc and O's than it would be complete :)
public function namilize($name) {
$name = strtolower($name);
$normalized = array();
foreach (preg_split('/([^a-z])/', $name, NULL, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY) as $word) {
if (preg_match('/^(mc)(.*)$/', $word, $matches)) {
$word = $matches[1] . ucfirst($matches[2]);
}
$normalized[] = ucfirst($word);
}
return implode('', $normalized);
}
Note that this will work for names like John O'Brian, James McManus, etc. For other names with prefixes like McManus, simply add the prefix to the preg_match(). Obviously, this runs the possibility of false positives, but no method is going to be 100% foolproof.
You have to pass the $string by reference, note the &:
public function namilize($string)
{
$strings = explode(' ', $string);
foreach ($strings as &$string) {
$string = ucfirst(strtolower($string));
}
$string = implode(' ', $strings);
return $string;
}
Or use the function suggested by #thetaiko ucwords($string)
The $string inside the foreach will only store the last iteration (or the last name). This doesn't really matter though because the variable in the foreach is never used for output. The implode just undoes what you did with the explode so you will end up with the exact same output as the input. I changed the variable names to be more descriptive in this example:
function namilize($name_in)
{
$a_names = explode(' ', $name_in); //explode string into array
foreach ($a_names as $name) {
$a_fullname[] = ucfirst(strtolower($name)); //build array of proper case names
}
$string = implode(' ', $a_fullname); //convert array into string
return $string;
}
I am trying to test if a string made up of multiple words and has any values from an array at the end of it. The following is what I have so far. I am stuck on how to check if the string is longer than the array value being tested and that it is present at the end of the string.
$words = trim(preg_replace('/\s+/',' ', $string));
$words = explode(' ', $words);
$words = count($words);
if ($words > 2) {
// Check if $string ends with any of the following
$test_array = array();
$test_array[0] = 'Wizard';
$test_array[1] = 'Wizard?';
$test_array[2] = '/Wizard';
$test_array[4] = '/Wizard?';
// Stuck here
if ($string is longer than $test_array and $test_array is found at the end of the string) {
Do stuff;
}
}
By end of string do you mean the very last word? You could use preg_match
preg_match('~/?Wizard\??$~', $string, $matches);
echo "<pre>".print_r($matches, true)."</pre>";
I think you want something like this:
if (preg_match('/\/?Wizard\??$/', $string)) { // ...
If it has to be an arbitrary array (and not the one containing the 'wizard' strings you provided in your question), you could construct the regex dynamically:
$words = array('wizard', 'test');
foreach ($words as &$word) {
$word = preg_quote($word, '/');
}
$regex = '/(' . implode('|', $words) . ')$/';
if (preg_match($regex, $string)) { // ends with 'wizard' or 'test'
Is this what you want (no guarantee for correctness, couldn't test)?
foreach( $test_array as $testString ) {
$searchLength = strlen( $testString );
$sourceLength = strlen( $string );
if( $sourceLength <= $searchLength && substr( $string, $sourceLength - $searchLength ) == $testString ) {
// ...
}
}
I wonder if some regular expression wouldn't make more sense here.