show row data from a specific ID - php

Question

I'm building a simple bug tracking tool.
You can create new projects, when you create a project you have to fill in a form, that form posts to project.class.php (which is this code)
$name = $_POST['name'];
$descr = $_POST['description'];
$leader = $_POST['leader'];
$email = $_POST['email'];
$sql="INSERT INTO projects (name, description, leader, email, registration_date)
VALUES ('$name', '$descr', '$leader', '$email', NOW())";
$result = mysql_real_escape_string($sql);
$result = mysql_query($sql);
if($result){
header('Location: ../projectpage.php?id='.mysql_insert_id());
}
else {
echo "There is something wrong. Try again later.";
}
mysql_close();
(It's not yet sql injection prove, far from complete...)
Eventually you get redirected to the unique project page, which is linked to the id that is stored in the MySQL db. I want to show the name of that project on the page, but it always shows the name of the first project in the database.
(here I select the data from the MySQL db.)
$query = 'SELECT CONCAT(name)
AS name FROM projects';
$result = mysql_real_escape_string($query);
$result = mysql_query ($query);
(here I show the name of the project on my page, but it's always the name of the first project in the MySQL db)
<?php
if ($row = mysql_fetch_array ($result))
echo '<h5>' . $row['name'] . '</h5>';
?>
How can I show the name of the right project? The one that is linked with the id?
Do I have the use WHERE .... ?

Answer 1

Yes, You have to use the WHERE to specify which project You want to get. I'm also not sure why are You using CONCAT function when You want to get only one project.
Other important thing is that You have to use mysql_real_escape_string() function on parameters before You put them in the query string. And use apropriate functions for specific type of data You receive.
So Your statement for getting the project should look like this:
SELECT name FROM projects WHERE id = ' . intval($_GET['id'])
Also when before You use the mysql_fetch_assoc() function, check if there are any records in the result with
if(mysql_num_rows($result) > 0)
{
$project = mysql_fetch_assoc($result);
/* $project['name'] */
}

Answer 2

try this
// first get the id, if from the url use $_GET['id']
$id = "2";
$query = "SELECT `name` FROM `projects` WHERE `id`='".intval($id). "'";
$result = mysql_query(mysql_real_escape_string($query));
use mysql_fetch_row, here you'll not have to loop through each record, just returns single row
// if you want to fetch single record from db
// then use mysql_fetch_row()
$row = mysql_fetch_row($result);
if($row) {
echo '<h5>'.$row[0].'</h5>';
}
$row[0] indicates the first field mentioned in your select query, here its name

Answer 3

The might be of assistance:
Your are currently assing a query string parameter projectpage.php?id=
When you access the page the sql must pick up and filter on the query string parameter like this:
$query = 'SELECT CONCAT(name) AS name FROM projects WHERE projectid ='. $_GET["id"];
$result = mysql_real_escape_string($query);
$result = mysql_query ($query);
Also maybe move mysql_insert_id() to right after assigning the result just to be safe.
$result = mysql_query($sql);
$insertId = mysql_insert_id();
Then when you assign it to the querystring just use the parameter and also the
header('Location: ../projectpage.php?id='.$insertId);