I am working on trying to post to ajax file with jquery and showing result on page posted from. Post gets posted but I get no reply from ajax. Am i missing something here?
form file
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test Ajax</title>
<script src="js/jquery-1.10.2.js"></script>
</head>
<body>
<form id="myform" />
<input type="text" id="youTyped" value=""/>
<input type="submit" value="Submit">
</form>
<div id="answer"></div>
<script type="text/javascript">
$('#myform').submit(function(){
var youTyped = $("#youTyped").val();
var data = {youTyped:youTyped};
$.ajax({
type: "POST",
url: "scripts/ajaxTest.php",
data: data,
success: function(response){
$("#answer").html(response);
}
});
});
</script>
</body>
</html>
ajax file
<?php
if(isset($_POST['youTyped'])){
$youTyped = $_POST['youTyped'];
}
echo $youTyped;
?>
Well, first of all, you didn't write your form correctly, the elements you want to send are not inside the form.
Second, your js function is not avoiding the form for being sent, so you're reloading the page when submitting the form.
So, to correct it, and get the answer, just change the code to:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test Ajax</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8/jquery.min.js"></script>
</head>
<body>
<form id="myform">
<input type="text" id="youTyped" value=""/>
<input type="submit" value="Submit">
<div id="answer"></div>
</form>
<script type="text/javascript">
$('#myform').submit(function(e){
// Avoid send the form as a normal request
e.preventDefault();
var youTyped = $("#youTyped").val();
var data = {youTyped:youTyped};
$.ajax({
type: "POST",
url: "scripts/ajaxTest.php",
data: data,
success: function(response){
$("#answer").html(response);
}
});
});
</script>
</body>
</html>
One last thing. To test it, when you're sending and receiving AJAX, if you're using Chrome you can use the development tools to know if you're sending correctly the requests. Just press F12, and then go to Network tab. If you're using correctly AJAX, you'll see how new lines are added when you press the submit button:
You need to return false on form submit. The form is being submited before ajax request. Also add a closing tag for form.
<script type="text/javascript">
$('#myform').submit(function () {
var youTyped = $("#youTyped").val();
var data = {
youTyped: youTyped
};
$.ajax({
type: "POST",
url: "scripts/ajaxTest.php",
data: data,
success: function (response) {
$("#answer").html(response);
}
});
return false;
});
</script>
Try if this code is working:
<body>
<input type="text" id="youTyped" value=""/>
<input type="submit" id="submit" value="Submit">
<div id="answer"></div>
<script type="text/javascript">
$(document).ready(function(){
$('#submit').click(function(){
var youTyped = $("#youTyped").val();
$.post('scripts/ajaxTest.php',{"youTyped" : youTyped},function(response)
{
$("#answer").html(response);
});
});
});
</script>
</body>
</html>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test Ajax</title>
<script src="js/jquery.min.js"></script>
<script type="text/javascript">
$('#myform').submit(function(event){
event.preventDefault();
var youTyped = $("#youTyped").val();
var data = {youTyped:youTyped};
$.ajax({
type: "POST",
url: "ajaxTest.php",
data: data,
success: successMsg,
error: errorMsg
});
});
function successMsg(response){
alert(response);
$("#answer").html(response);
}
function errorMsg(){
alert("Invalid Ajax Call");
}
</script>
</head>
<body>
<form id="myform" />
<input type="text" id="youTyped" value=""/>
<input type="submit" value="Submit">
<div id="answer"></div>
</body>
</html>
As I toyed with the idea, thought that this would make a good addition/contribution to the question.
I added and modified a few things.
One of which being:
If nothing was typed into the form input field, it would return "You typed: Nothing".
PHP:
<?php
if(!empty($_POST['youTyped'])){
$youTyped = $_POST['youTyped'];
echo "You typed: " .$youTyped;
}
else if (empty($_POST['youTyped'])){
echo "You typed: Nothing";
}
?>
Related
I am trying to create a form that user is choosing an option let's say that he will choose his name i used ajax to call another page , in this page i create the connection and inserting the answer the problem it's inserting null
Code
index.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>MyDataBase </title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js"> </script>
$(document).ready(function(){
$("#mysubmit").click( function (){
$.ajax({
url:"Final.php",
type:"POST",
success: function(success_array)
{
alert(" Well Done ");
},
error: function(xhr, ajaxOptions, thrownError)
{
alert( " Didn't work ! ");
}
});
});
});
</script>
</head>
<form method="post" id = "myform">
<input type="radio" name="kname" value="X1" />X1<br />
<input type="radio" name="kname" value="Y1" />Y1<br />
<input type="radio" name="kname" value="A1" />A1<br />
<input type="radio" name="kname" value="G1" />G1<br />
<input type="submit" onclick="save()" id="mysubmit"/>
</form>
<body>
</body>
</html>
Final.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Thanks</title>
</head>
<body>
<?php
$con = mysqli_connect("localhost","root","xyz","test");
mysqli_query($con,"INSERT INTO name values ('$_POST[kname]')");
?>
</body>
</html>
You have to reference the kname via $_POST['kname'].
But please! always escape your values!
When submitting/posting via ajax you need to add your data. simplest is with serialize().
var form = $('#myform');
$.ajax({
url:"Final.php",
type:"POST",
data: form.serialize(),
...
or you could get a single field -
data: {kname: $('#id_of_your_radio').val()},
just make sure to sanitize the userdata before inserting into your db.
I have here a page in which I am trying to update a users email now the div refreshes on submit like it is ment to but it is not updating the database and I ain't for the life of me know why.
My layout is one page click a menu link and it loads the page into the content div (below does) now I am wanting to post a form and it reload in that div and update the mysql database but for some reason it don't want to update the database.
Anyone got any suggestions into why it's not updating the database? have i made a small error somewhere in the php or is it due to my page set up on loading this way?
Thanks in advance. :)
<?php
session_start();
include_once("./src/connect.php");
include_once("./src/functions.php");
//Update email
if (isset($_POST['update'])){
$email = makesafe($_POST['email']);
$result = mysql_query("UPDATE Accounts SET email='$email' WHERE `id`= '{$fetchAccount['id']}'")
or die(mysql_error());
echo "<font color='lime'>Updated.</font>";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Home</title>
<link rel="stylesheet" href="./static/css/LoggedIn/Index.css" type="text/css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
jQuery(document).ready(function($) {
$("#Submit").click(function() {
var url = "Profile.php"; // the script where you handle the form input.
$.ajax({
type: "POST",
url: url,
data: $("#myForm").serialize(), // serializes the form's elements.
success: function(html){ $("#right").html(html); }
});
return false; // avoid to execute the actual submit of the form.
});
});
</script>
</head>
<body>
<div id="right">
<form method="post" action="Profile.php" id="myForm">
E-mail: <input type="text" value="<?=$fetchAccount['email']?>" name="email"><br>
<input type="submit" value="Edit" name="update" id="Submit">
</form>
</div>
</body>
</html>
Heres some changes, read code comments, though the main thing wrong with your code is ajax will get the whole page not just echo "<font color='lime'>Updated.</font>"; part.
<?php
session_start();
include_once("./src/connect.php");
include_once("./src/functions.php");
//Update email only if request is from ajax request
if(isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) === 'xmlhttprequest'){
//check its POST, and email is real, then do update or exit a error message back
if($_SERVER['REQUEST_METHOD']=='POST' && !empty($_POST['email']) && filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)){
header('Content-Type: text/html');
//check its an email
if(!filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)){
exit('<span style="color:red;">Invalid email.</span>');
}
//Do update
mysql_query("UPDATE Accounts
SET email='".mysql_real_escape_string($_POST['email'])."'
WHERE id= ".mysql_real_escape_string($fetchAccount['id'])) or die('<span style="color:red;">Error updating email. '.mysql_error().'</span>');
exit('<span style="color:lime;">Updated.</span>');
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Home</title>
<link rel="stylesheet" href="./static/css/LoggedIn/Index.css" type="text/css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"/></script>
<script type="text/javascript">
$(function(){
$("#Submit").click(function(e) {
$.ajax({
type: "POST",
url: "Profile.php",
data: $("#myForm").serialize(), // serializes the form's elements.
success: function(html){ $("#right").html(html); }
});
e.preventDefault();
});
});
</script>
</head>
<body>
<div id="right">
<form method="post" action="Profile.php" id="myForm">
E-mail: <input type="text" value="<?=htmlspecialchars($fetchAccount['email'])?>" name="email"/><br/>
<input type="submit" value="Edit" name="update" id="Submit"/>
</form>
</div>
</body>
</html>
Hope it helps
I have an HTML file that has a form with two fields. These fields' value should be posted to a PHP and this PHP should be fetched from the HTML using JQuery. This is what I implemented.
My HTML file:
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script src="//ajax.aspnetcdn.com/ajax/jQuery/jquery-1.9.1.min.js"></script>
<script>
$(document).ready(function(){
$("button").click(function(){
$("#first").load("result_jquery.php");
});
});
</script>
</head>
<body>
<div id="first"></div>
<div>
<form method="POST" id="myForm">
Name: <input type="text" name="name"/><br/>
Number: <input type="text" name="number"/><br/>
<button>submit</button>
</form>
</div>
</body>
This is my result_jquery.php
<?php
$n = $_POST["name"];
echo "hello ".$n;
?>
When I click the submit button, the hello is getting printed. But the name is not getting printed. Can you please help me with this. I don't know where I am going wrong.
I think that the use of the button element is the worry and the code that i will put now it is working properly as you need so try this and tell me the result :)
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script src="//ajax.aspnetcdn.com/ajax/jQuery/jquery-1.9.1.min.js"></script>
<script>
$(document).ready(function(){
$("#button").click(function(){
var n = $('[name="namee"]').val();
var nb = $('[name="number"]').val();
$("#first").load("result_jquery.php",{'namee':n,'number':nb},function(data){});
});
});
</script>
</head>
<body>
<div id="first"></div>
<div>
<form method="POST" id="myForm">
Name: <input type="text" name="namee"/><br/>
Number: <input type="text" name="number"/><br/>
<input type="button" value="Submit" id="button" />
</form>
</div>
</body>
</html>
copy this code:
<script type="text/javascript">
$(document).ready(function() {
$("#send").click(function() {
$.ajax({
type: "POST",
data : "name="+$( '#name' ).val(),
url: "result_jquery.php",
success: function(msg) {
$('#first').html(msg);
}
});
});
});
</script>
change this in form
<form method="POST" id="myForm">
Name: <input type="text" id="name" name="name"/><br/>
Number: <input type="text" id="number" name="number"/><br/>
<input type="button" id="send" value="Submit">
</form>
just try that and tell me the result :)
var n = $('[name="name"]').val();
var nb = $('[name="number"]').val();
$('#error').load("result_jquery.php", {'name':n,'number':nb},function(data){});
Note try to change the element name for the name field from "name" to "namee" and apply changes as needed look like this :
var n = $('[name="namee"]').val();
var nb = $('[name="number"]').val();
$('#error').load("result_jquery.php", {'namee':n,'number':nb},function(data){});
and the result_jquery.php file :
<?php
$n = $_POST["name"];
echo "hello ".$n;
?>
From the jQuery documentation on load:
This method is the simplest way to fetch data from the server. It is
roughly equivalent to $.get(url, data, success) except that it is a
method rather than global function and it has an implicit callback
function. When a successful response is detected (i.e. when textStatus
is "success" or "notmodified"), .load() sets the HTML contents of the
matched element to the returned data. This means that most uses of the
method can be quite simple:
You are performing a HTTP GET with that method, and not a POST.
My suggestion would be if you want to send an AJAX request to your server with information in it, get used to using the long form jQuery AJAX:
$.ajax({
data: 'url=encoded&query=string&of=data&or=object',
url: 'path/to/server/script.php',
success: function( output ) {
// Handle response here
}
});
For more info, see jQuery documentation: http://api.jquery.com/jQuery.ajax/
i have a simple form where one one field is there which is random javascript file whose name ranges from 1 to 500000 so i have used rand function to populate its field without any issue
i want form to be automatically submitted after loading but i dont want pages to be refreshed and even i dont want field value to be changed after form is submitted. my code is very clear but dont know why it is not working
index.html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script>
<title>testing</title>
</head>
<body>
<script type="text/javascript" >
$(function() {
$("form1#form1").submit(function() {
var searchBox = $("#searchBox").val();
var dataString = 'searchBox='+ searchBox ;
if(searchBox=='')
{
$('.success').fadeOut(200).hide();
$('.error').fadeOut(200).show();
}
else
{
$.ajax({
type: "POST",
url: "test34.php",
data: dataString,
success: function(){
$('.success').fadeIn(200).show();
$('.error').fadeOut(200).hide();
}
});
}
return false;
});
});
</script>
<form method="post" name="form1" id="form1" enctype="multipart/form-data">
<input type="text" class="status" name="searchBox" id="searchBox" value="<?= "".rand(1,2889889).".js"; ?>">
<input class="button" type="submit" value="Submit" /></form>
</body>
</html>
test34.php
<?php
include('connect.php');
$title23 = $_POST['searchBox'];
mysql_query("insert into test (title) values('$title23')");
echo $title23;
?>
but it is not submitting the form automatically please advise
Your selector should probably look like this $("form#form1") instead of $("form1#form1")
After you've bound your submit method to the form, try triggering the submit method by doing this.
return false;
});
$("form1#form1").trigger('submit'); // Here
});
jquery-ajax: pass values from a textfield to php file and show the value
i made a variation of the link above this time using only one file and no div tag.
test.php
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#submit").click(function(){
var dataString = $("#inputtext").val();
$.ajax({
type: "POST",
url: "test.php",
data: "dataString=" + dataString,
success: function(result){
window.location.reload(true);
}
});
window.location.reload(true);
});
});
</script>
</head>
<body>
<input type="text" id="inputtext">
<input type="button" id="submit" value="send">
<?PHP
if(isset($_POST['dataString'])){
$searchquery = trim($_POST['dataString']);
print "Hello " . $searchquery;
}
?>
</body>
</html>
value from dataString won't show. why?
Sorry for the question, but what's the point of using ajax to reload the same page?? Use it to call another page and then load the result, not the way you're doing it.
Try this
In test.php:
$("#submit").click(function(){
var dataString = $("#inputtext").val();
$.ajax({
type: "POST",
url: "anothepage.php",
data: dataString,
success: function(result){
$('#result').html(result).
}
});
return false; //so the browser doesn't actually reload the page
});
And you should actually use a form, not just inputs. And use the name attribute for them, or php won't pick the value! ID is for javascript and css.
<form method="POST" action="">
<input type="text" id="inputtext" value="" name="inputtext">
<input type="submit" id="submit" value="send" name="submit">
</form>
<div id="result"> <!-- result from ajax call will be written here --> </div>
In anotherpage.php:
if(isset($_POST['inputtext'])){
$searchquery = trim($_POST['inputtext']);
echo htmlentities($searchquery); // We don't want people to write malicious scripts here and have them printed and run on the page, wouldn't we?
}
When you refresh the page using JavaScript, you lose any POST parameters you sent to the page. That is one reason why you never saw any valid results.
You are also missing the benefits from using AJAX - A motivating reason to deploy AJAX is to remove the requirement to refresh the page while still accepting and processing user input.
If you prefer to process the data from AJAX on the same page that is serving the HTML, here is a working example based on your supplied code.
<?php
if( isset($_POST['dataString']))
{
echo 'Hello ' . trim( $_POST['dataString']);
exit;
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-type" content="text/html;charset=UTF-8" />
<title>Testing jQuery AJAX</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#submit").click(function(){
var dataString = $("#inputtext").val();
$.ajax({
type: "POST",
url: "test.php",
data: "dataString=" + dataString,
success: function( data){
alert( data);
}
});
});
});
</script>
</head>
<body>
<form action="test.php" method="post">
<input type="text" id="inputtext" />
<input type="button" id="submit" value="send" />
</form>
</body>
</html>