Getting user data - php

There are two parts to this application I've been building. There's the website which is powered by the CMS and there's the CMS (wrestling manager) that goes with it. With the two controllers I created called frontend and backend I use those accordingly. The frontend controller is responsible for the code that needs to be ran across all controllers on the website. The backend controller is responsible for the code that needs to be ran across all controllers on the CMS.
I'm looking for the ideal way to work with the user data after the user successfully logs in again gets directed to the dashboard which is extended by the backend controller. I've heard different solutions for example a hook. That's just one I've heard.

Inheritance is your friend here
You would simply create a master controller(front-controller) that extends CI_Controller
You might consider doing a SPA application, if so there are many great frameworks to help you achieve this, quite a popular one is angular.js
some more useful reading on the subject...
class MY_Controller extends CI_Controller
{
protected $currentUser;
protected $template;
public function __construct()
{
//You talked about hooks
//this constructor is the same as saying
//post_controller_constructor
$this->template = 'master/default';
}
//Ok so what functions need to be run
//throughout the application
//run them once here, keeping our app DRY
protected function isAjax()
{
return ($this->input->is_ajax_request())
? true
: show_error('Invalid Request!');
}
protected function isLoggedIN()
{
//load your auth library maybe here
$this->load->library('auth');
//check you have a "current logged In user"
//expect object or null/false
$this->currentUser = $this->auth->getLoggedInUser();
return ($this->currentUser) ?: false;
}
}
class Frontend_Controller extends MY_Controller
{
public function __construct()
{
parent::__construct();
}
public function testFirst()
{
//maybe you just need to test for ajax request here
//inheritance from parent
$this->isAjax();
}
public function testSecond()
{
//maybe you DO need a user logged in here
//inheritance from parent
$this->isAjax();
//or yet again, abstract this to the parent level
if(!$this->currentUser || is_null($this->currentUser))
{
//handle errors on frontend
return $this->output->set_status_header(401); //un-authorized
}
}
}

Related

Make things available in any view file Laravel

I have a question about making some elements available in any view file
Lets say im building a webshop and on every page i will be having my sidebar, shoppingcart, user greeting in the top.
How can i make these things available in all my view files?
I could make a class, lets say class Frontend
I could do something like this:
class Frontend {
static $me;
public function get(){
if(!self::$me){
self::$me = new self();
}
return self::$me;
}
private function getShoppingCart(){
// do things
}
public function getData(){
return array(
'Username' => User::find(1)->UserName,
'Cart' => $this->getShoppingCart()
);
}
}
Now in my controller i could pass this Frontend object into the view
View::make('file.view')->with(array('data' => Frontend::get()->getData()));
But this way i will end up with a god class containing way too much stuff and in every controller method i would have to pass these data, which is not relevant to the controller method
Is there a way in Laravel that makes specific data available across all view files?
Thanks!
Use share:
View::share('name', 'Steve');
as per http://laravel.com/docs/responses#views
To keep everything clean, every part of the page should be its own *.blade.php file which would be put together using a master template of sorts.
master.blade.php
#yield('includes.sidebar')
#yield('users.greeting')
#yield('store.shoppingcart')
Then you can use view composers so that each time these views are loaded, the data you want is injected into them. I would probably either create a new file which would get autoloaded, or if you have service providers for the separate portions of your app that these views would use, it would also go great in there.
View::composer('users.greeting', function($view)
{
$view->with('user', Auth::user());
});
In this case, it would make the user model available inside your view. This makes it very easy to manage which data gets injected into your views.
You are close with your 'god class' idea.
Setting a $data variable in a basecontroller has helped me with similar issues
class BaseController extends Controller {
protected $data;
public function __construct() {
$this->data['Username'] = User::find(1)->UserName
$this->data['Cart'] = $this->getShoppingCart()
}
}
class Frontend extends BaseController {
function someMethod(){
View::make('file.view', $this->data)
}
}

How to make a REST API first web application in Laravel

I want to make an API first application in Laravel. I don't know what is the best approach to do this, I will explain what I am trying to do, but please feel free to give answers how to do this in a different way.
I don't want all my frontend to be written in javascript and parse the JSON output of the API with angular.js or something similar. I want my Laravel application to produce the HTML views. I am trying to go down the road of having two controllers one on for the API and one for the web. For the show User action my routes.php looks like this:
# the web controller
Route::controller('user', 'WebUserController');
# the api controller
Route::group(array('prefix' => 'api'), function() {
Route::resource('user', 'UserController');
});
So /user will take me to WebUserController and /api/user will take me to the UserController. Now I want to put all my logic in the API UserController, and call its actions from the WebUserController. Here is the code for both of them:
class UserController extends BaseController
{
public function show($id)
{
$user = User::find($id);
return Response::json(array('success'=>true,'user'=>$user->toArray()));
}
}
class WebUserController extends UserController
{
public function getView($id)
{
# call the show method of the API's User Controller
$response = $this->show($id);
return View::make('user.view')->with('data', $response->getData());
}
}
In the WebUserController I am able to get the json content of the response with getData(), but I am not able to get the headers and status code (they are protected properties of Illuminate\Http\JsonResponse).
I think that my approach might not be the best, so I am open to suggestions how to make this app.
EDIT: The question how to get the headers and status of the response has been answered by Drew Lewis, but I still think that there might be a better way how to design this
You should utilize the Repository / Gateway design pattern: please see the answers here.
For example, when dealing with the User model, first create a User Repository. The only responsibility of the user repository is to communicate with the database (performing CRUD operations). This User Repository extends a common base repository and implements an interface containing all methods you require:
class EloquentUserRepository extends BaseRepository implements UserRepository
{
public function __construct(User $user) {
$this->user = $user;
}
public function all() {
return $this->user->all();
}
public function get($id){}
public function create(array $data){}
public function update(array $data){}
public function delete($id){}
// Any other methods you need go here (getRecent, deleteWhere, etc)
}
Then, create a service provider, which binds your user repository interface to your eloquent user repository. Whenever you require the user repository (by resolving it through the IoC container or injecting the dependency in the constructor), Laravel automatically gives you an instance of the Eloquent user repository you just created. This is so that, if you change ORMs to something other than eloquent, you can simply change this service provider and no other changes to your codebase are required:
use Illuminate\Support\ServiceProvider;
class RepositoryServiceProvider extends ServiceProvider {
public function register() {
$this->app->bind(
'lib\Repositories\UserRepository', // Assuming you used these
'lib\Repositories\EloquentUserRepository' // namespaces
);
}
}
Next, create a User Gateway, who's purpose is to talk to any number of repositories and perform any business logic of your application:
use lib\Repositories\UserRepository;
class UserGateway {
protected $userRepository;
public function __construct(UserRepository $userRepository) {
$this->userRepository = $userRepository;
}
public function createUser(array $input)
{
// perform any sort of validation first
return $this->userRepository->create($input);
}
}
Finally, create your User web controller. This controller talks to your User Gateway:
class UserController extends BaseController
{
public function __construct(UserGatway $userGateway)
{
$this->userGateway = $userGateway;
}
public function create()
{
$user = $this->userGateway->createUser(Input::all());
}
}
By structuring the design of your application in this way, you get several benefits: you achieve a very clear separation of concerns, since your application will be adhering to the Single Responsibility Principle (by separating your business logic from your database logic) . This enables you to perform unit and integration testing in a much easier manner, makes your controllers as slim as possible, as well as allowing you to easily swap out Eloquent for any other database if you desire in the future.
For example, if changing from Eloquent to Mongo, the only things you need to change are the service provider binding as well as creating a MongoUserRepository which implements the UserRepository interface. This is because the repository is the only thing talking to your database - it has no knowledge of anything else. Therefore, the new MongoUserRepository might look something like:
class MongoUserRepository extends BaseRepository implements UserRepository
{
public function __construct(MongoUser $user) {
$this->user = $user;
}
public function all() {
// Retrieve all users from the mongo db
}
...
}
And the service provider will now bind the UserRepository interface to the new MongoUserRepository:
$this->app->bind(
'lib\Repositories\UserRepository',
'lib\Repositories\MongoUserRepository'
);
Throughout all your gateways you have been referencing the UserRepository, so by making this change you're essentially telling Laravel to use the new MongoUserRepository instead of the older Eloquent one. No other changes are required.
You should be use Repository for this design.
Example -
//UserRepository Class
class UserRepository {
public function getById($id)
{
return User::find($id);
}
}
// WebUser Controller
class WebUserController extends BaseController {
protected $user;
public function __construct(UserRepository $user)
{
$this->user = $user;
}
public function show($id)
{
return View::make('user.view')->with('data', $this->user->getById($id));
}
}
// APIUser Controller
class UserController extends BaseController {
protected $user;
public function __construct(UserRepository $user)
{
$this->user = $user;
}
public function show($id)
{
$data =>$this->user->getById($id);
return Response::json(array('success'=>true,'user'= $data->toArray()));
}
}
Checkout Laravel's RESTful controllers:
http://laravel.com/docs/controllers#restful-controllers
Their docs do a pretty good job.
But even better is this tutorial:
http://code.tutsplus.com/tutorials/laravel-4-a-start-at-a-restful-api-updated--net-29785
This is a video by Jeffrey Way he is one of the better Laravel developers. In this tutorial he is connecting a BackboneJS application to a RESTful service that he sets up in Laravel. It doesn't get any better then this. I can write you a lot of boilerplate, but just learn it by watching a nice video and having a coffee. ;)
https://www.youtube.com/watch?v=uykzCfu1RiQ
I have a response to the problem you are having with the Response.
You can get the headers, status code and data from the Response.
// your data
$response->getData();
// the status code of the Response
$response->getStatusCode();
// array of headers
$response->headers->all();
// array of headers with preserved case
$response->headers->allPreserveCase();
$response->headers is a Symfony\Component\HttpFoundation\ResponseHeaderBag which inherits from Symfony\Component\HttpFoundation\HeaderBag
I would also recommend using a repository.
Attempting to call one controller from another would be falling into a pattern called HMVC (Hierarchical model–view–controller).
This means that your entire application relies on lower modules.
In this case, your API would serve as a repository for your data (which isn't the worst thing in the world at first).
However, when you then modify the structure of how data is returned in your API, everything else relying on it would have to know how to respond.
Say you wanted to have authorization checks to see if a logged in user should be able to see the details of a returned user and there was an error.
In the API, you would return a Response object with a 403 forbidden code and some meta data.
Your HTML controller would have to know how to handle this.
Contrast this to a repository which could throw an exception.
public function findById ($id)
{
$user = User::findOrFail($id);
if (Auth::user->hasAccessTo($user)) {
return $user;
} else {
throw new UnauthorizedAccessException('you do not have sufficient access to this resource');
}
}
And your API controller would look more like this:
public function show($id)
{
try {
return $this->user->findById($id);
} catch (UnauthorizedAccessException $e) {
$message = $e->getMessage();
return Response::json('403', ['meta' => ['message' => $message]]));
}
}
Your HTML controller would then look like this:
public function show($id)
{
try {
$user = $this->user->findById($id);
} catch (UnauthorizedAccessException $e) {
Session::flash('error', $e->getMessage());
// Redirect wherever you would like
return Response::redirect('/');
}
}
This gives you very reusable code and let's you change your controller implementations independently without worry of changing the other's behavior.
I wrote more on how to implement the repository pattern in this post: you can ignore the interface and skip right to the implementations if you would like.

zend validate user for a specific controller?

HI i would like to know how to validate a users for a specific controller, so that we can check that a specific users is authenticate before accessing resources of a controller?
you should take a look at Zend_Auth and Zend_Acl Component.
Zend_Auth is responsible for assigning and managing authentication of the user.
Zend_Acl is responsible for managing different permissions and roles for different resources.
here is the tutorial explaining how you can implement Zend_Auth.
http://akrabat.com/zend-auth-tutorial/
and the below tutorial explains about Zend_Auth/Zend_Acl
http://devzone.zend.com/844/zend_acl-zend_auth-example-scenario/
Lets says for a specific controller in controller folder we have CashoutController. Before a user accessing this controller we will authenticate the users as below with make use of custom library.
<?php
class CashoutController extends Zc_Controller_Action_User
{
public function init()
{
/* Initialize action controller here */
parent::init();
}
// rest code goes here
}
now we defined new library name Zc
<?php
class Zc_Controller_Action_User extends Zc_Controller_Action
{
public function init()
{
parent::init();
$this->validateAccess();
}
private function validateAccess()
{
$auth = Zend_Auth::getInstance();
if (is_null($auth->getIdentity())) {
$this->_helper->redirector('index', 'index');
}
}
}
where we define controller action library as
<?php
class Birdtoldme_Controller_Action extends Zend_Controller_Action
{
}
hope this is has been an informative for you.

All admin/user functions checking if he/she is logged in - How to avoid this?

I am very, very new with MVC (just started yesterday) so this question is probably stupid, but I need to know how to check automatically if user is logged in on my functions that are in admin/user models.
I can put the checking in construct, this would help, but I have several models and maybe there is some even better way. I hope you will understand better what I want after you see my folder structure and code. Oh, and by the way - I use Code Igniter 2.0
Folders:
controllers/
../admin/
../../item.php
../../cat.php
Let's see my item.php file...
<?php
class Item extends CI_Controller
{
function Index()
{
//Checking if admin is logged in on every function is bad
/*
* Is it possible to somehow make all admin functions go through
* some kind of Admin class that will check automatically?
*/
$isLogged = $this->session->userdata('is_logged_in');
if ($isLogged == true)
{
$this->load->view('admin/item/main');
}
else
{
$this->load->view('admin/login');
}
}
function Add()
{
$this->load->view('admin/item/add');
}
function Edit()
{
$this->load->view('admin/item/edit');
}
function Delete()
{
$this->load->view('admin/item/delete');
}
}
I hope that this is easy question, thanks in advance :)
I would implement the login-function in CI_Controller.
Then I would set an protected variable in Item protected $loginRequired = true;.
In function __construct() or Item() I would call parent::isLoginRequired($this->loginRequired) which checks if a login is required.
I would also redirect to a specific login page with a parameter which redirects the user back to the page he needs to be logged in.
Make a new class, for example, My_Controller extends Ci_Controller and write some auth checker code in it... in controller file just extend My_Controller
what i usually do is -like Teeed recommends- Create my own controller Class which is between the CI_Controller and each controller you might create.
In that class (MY_Controller) you can instantiate a model which handles all user related data and logics (loading session data, executing specific checks, etc..) and finally set as class variables those results, so you will end up having:
$this->isLogged ;
$this->isPaying ;
$this->isPlatinumMember ;
etc..
in any of your classes extending from MY_Controller
that makes very easy to check any condition within any of your Controllers.

How to make user object available across pages in CodeIgniter?

I'm fairly new to CodeIgniter and I'm using Ion Auth for user authorization. With the Ion Auth library, you get a user object like:
$user = $this->ion_auth->get_user();
echo $user->email;
If a user is logged in, I want the $user object to be available on any of the pages (in any of the controllers). How can I do this? (I'm using CodeIgniter 2)
This blog post of mine goes into a lot of detail in specifically using Ion_Auth to allow your entire application (including views) to access your current user's information.
The short version... (specifically for the topic at hand)
Adding this to your MY_Controller.php file
class User_Controller extends CI_Controller {
protected $the_user;
public function __construct() {
parent::__construct();
if($this->ion_auth->logged_in()) {
$data->the_user = $this->ion_auth->get_user();
$this->the_user = $data->the_user;
$this->load->vars($data);
}
else {
redirect('/');
}
}
}
Then in your application just create your controller like this
class App_Controller extends User_Controller {
public function __construct() {
parent::__construct();
}
function index() {
//do stuff
}
}
Then not only in your controller will you have access to $this->the_user but you will also have $the_user loaded into every view with $this->load->vars()
Normally you'd cache something like this in the session, however I've moved away from that in most of my CI apps.
An example: you log the user in (caching the user data) and then they go to update their email on their profile page. You now have to reload you cache. Many other things could drive this reload. Usually the most I cache any more is the ID, then I do what you're doing and get the user's data on any page I need it.
One thing I found that helps is to have base controllers. For example I have a RegisteredUserController. Any controller whose actions all require the user to be logged in extend this. That way I can keep the logged in check and things like get the user data in one spot (in the constructor). For example:
class RegisteredUserController extends CI_Controller {
var $user;
function __construct() {
parent::__construct();
$this->user = $this->ion_auth->get_user();
}
}
Then any controller that extends RegisteredUserController instead of just controller can get to the user with $this->user. Following this pattern would get it on every page (that extends the controller) without resorting to caching.

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