Ajax Doesn't give me anything in the console? - php

Updated Question to better reflect the communities support
Based on community support I have changed the Ajax function to be as such:
(function($){
$(document).ready(function(){
$('a').click(function(e){
var el = $(this).prev('input[type="checkbox"]');
if(el.is(':checked')){
el.prop('checked',false);
}
$.ajax({
url : "http://localhost/wordpress/wp-content/themes/Aisis-Framework/CoreTheme/AdminPanel/Template/Helper/UncheckPackageThemeHelper.php",
type : 'GET',
data : { 'element_name' : el.prop('name') },
success: function(data, textStatus, jqXHR){
console.log(data);
},
error: function(jqXHR, textStatus, errorThrown ){
console.log(jqXHR, textStatus, errorThrown);
}
});
e.preventDefault();
});
});
})(jQuery);
The resulting PHP Class is as such:
class CoreTheme_AdminPanel_Template_Helper_UncheckPackageThemeHelper{
private $_element_name = null;
public function __construct(){
if(isset($_GET['element_name'])){
$this->_element_name = $_GET['element_name'];
echo $this->_element_name;
}
}
}
The network tab shows that I have some out put from activating the Jquery which I have shown below:
The Console is spitting out no errors, yet not echoing the element name. I have read up on the Jquery Ajax API and everything I have been doing, thus far, seems to be correct. Yet I am not getting the desired out put.
Note: The response tab is empty.... In other words I am not getting a response back.

You're not passing in the event to your click handler.
Use.
$('a').click(function(e){
// Your code
});
$.ajax({
url : "<?php echo CORETHEME_ADMIN_TEMPLATE_HELPER_URL . 'UncheckPackageThemeHelper.php'; ?>",
type : 'GET',
data : { 'element_name' : el.prop('name') },
success: function(result) {
console.log(result)
},
error: function(jqXHR, textStatus, errorThrown ){
console.log(jqXHR, textStatus, errorThrown);
}
});

Simplify the situation. Just for a moment, change your AJAX processor file (UncheckPackageThemeHelper.php) to read like this:
UncheckPackageThemeHelper.php
<?php
$test = $_POST['element_name'];
$r = 'PHP received: [' .$test. ']';
echo $r;
die();
Also, change your AJAX success function to read like this:
success: function(result) {
alert(result);
},
At least, this will show you that your AJAX is getting through.
Then, start adding things back into your AJAX processor file (one or two at a time) and keep echoing something out so that you can discover where the error is happening.

So I was doing a lot of things wrong. But this is the only way it works, for me - please post your comments if you have better solution.
In the class, I have to do this:
class CoreTheme_AdminPanel_Template_Helper_UncheckPackageThemeHelper{
private $_element_name = null;
public function __construct(){
if(isset($_GET["element_name"])){
$this->_element_name = $_GET["element_name"];
echo json_encode($this->_element_name);
}
}
}
new CoreTheme_AdminPanel_Template_Helper_UncheckPackageThemeHelper();
The class cannot be instantiated in the .phtml file with the resulting Ajax or the request is never sent back. Also notice the json_encode You cannot pass regular variables back to Ajax - when in a class (I think) - How ever when not in a class it seems to work - clarification is needed.
The Ajax then looks like this:
(function($){
$(document).ready(function(){
$('a').click(function(e){
var el = $(this).prev('input[type="checkbox"]');
if(el.is(':checked')){
el.prop('checked',false);
}
$.ajax({
url : "http://localhost/wordpress/wp-content/themes/Aisis-Framework/CoreTheme/AdminPanel/Template/Helper/UncheckPackageThemeHelper.php",
type : 'GET',
data : { 'element_name' : el.prop('name') },
success: function(data, textStatus, jqXHR){
console.log(data);
},
error: function(jqXHR, textStatus, errorThrown ){
console.log(jqXHR, textStatus, errorThrown);
}
});
e.preventDefault();
});
});
})(jQuery);
The Data that comes back is what I expect: "aisis_options[package_RelatedPosts]"
There ar a couple of issues with this answer - One I dont understand why I have to instantiate the class inside the file its written in, and two not sure why I have to encode the response in a class, but not when its just a "script kiddy" file.

Related

php ajax display data from database in multiple textboxes

Every one am new to php and ajax.
Am writing a code to fetch data from mysql database
and display them in textboxes but is not working.
Here is my code.
I need your help please.
Thanks in advance
$('#btn_get').on('click', function(){
$.ajax({
type : "get",
url : '/path/to/php/file',
success : function(data)
{
$('#input-box1').val(data);
$('#input-box2').val(data);
}
});
});
<input type="text" id="input-box1">
<input type="text" id="input-box2">
<button type="button" id="btn_get">Click</button>
//get data from db here
$textbox1 = 'foo';
$textbox2 = 'deen';
echo $textbox1;
echo $textbox2;
Here are some approaches, maybe them can help you:
The first approach would be to check your console to make sure that the jQuery version allows you to use the $.ajax() resource. Some jQuery versions like the "slim" doesn't provide ajax calls.
Once you have checked that put the property error within your ajax call:
$('#btn_get').on('click', function(){
$.ajax({
type : "get",
url : '/path/to/php/file',
success : function(data)
{
$('#input-box1').val(data);
$('#input-box2').val(data);
},
error: function(xhr, ajaxOptions, thrownError) {
console.log(xhr);
}
});
});
If you have a error response you will be able to identify it checking your browser's console tool (F12).
Check your /path/to/php/file to make sure that your file really exists.
Remember that the success callback gets your echo command as a string. So probably your return will be something like this:
foodeen
A good approach would be to return a json response:
$textbox1 = 'foo';
$textbox2 = 'deen';
echo json_encode(array($textbox1 ,"textBox1"));
Finally when your response is executed in the success callback you'll be able to convert it from plain string to a json format:
$('#btn_get').on('click', function(){
$.ajax({
type : "get",
url : '/path/to/php/file',
success : function(data)
{
var response = JSON.stringify(data);
$('#input-box1').val(response[0]);
$('#input-box2').val(response[1]);
},
error: function(xhr, ajaxOptions, thrownError) {
console.log(xhr);
}
});
});

Uncaught TypeError: a.split is not a function pagecontainer

Spend a couple of days now on trying to get swipe on a php website with dynamic content. I've been looking at jQuery mobile but there is no example out the how to get swipe to work with dynamic content. Anybody that can point in a direction how to accomplish this? Does not have to be jQuery mobile it could be anything as long as they have an example to work after. This is what I've accomplished with jQuery mobile and it of course doesn't swipe nice with animation but do load the content on swipe.
$(document).on('swipeleft', '.ui-page', function(event){
if(event.handled !== true) // This will prevent event triggering more then once
{
getartikel('1');
}
});
getartikel() is a function that runs an ajax request getting the data from mysql and put it in a div.
function getartikel(id) {
$.ajax({
url: "ajax/getartikel.php",
type: "post",
data: {id:id} ,
success: function (data) {
$("#artikel").html(data);
},
error: function(jqXHR, textStatus, errorThrown) {
console.log(textStatus, errorThrown);
}
});
}
It is a bunch of articles that I want to be able to swipe between. data from the database I just HTML.
Pagecontainer is what I understand I must use but I can't figure out how to get that to work with a ajax call.
done some change to my code but still no slide, now I get Uncaught TypeError: a.split is not a function. It comes up when I add
$.mobile.pageContainer.pagecontainer('change', "#"+sida, {transition: 'slide'});
here is my complete code
<script>
$(document).on("pageshow", function (event) {
getartikellist();
//this get the menue and put into a ul listview with the class artikel
});
$(document).ready(function(){
$(document).on("click", \'[class^=artikel]\', function(event, ui) {
$("#menyn").panel("close");
getartikel($(this).data(\'secid\'));
});
});
</script>
function getartikel(id) {
var sida;
if($.mobile.activePage.attr("id")=="1"){
sida="2";
}else{
sida="1";
}
$.ajax({
url: "ajax/getartikel.php",
type: "post",
data: {id:id} ,
beforeSend: function() {
$.mobile.loading("show");
},
success: function (data) {
$("#innehall"+sida).html(data);
},
complete: function() {
$.mobile.loading("hide");
$.mobile.pageContainer.pagecontainer('change', "#"+sida, {transition: 'slide'});
},
error: function(jqXHR, textStatus, errorThrown) {
console.log(textStatus, errorThrown);
}
});
}
Everything works fine until I add the pagecontainer row, It adds the content to the right page and all.

Receive data from php using AJAX

I am working on a function, where if a user selects a value from a drop down list, then this calls an AJAX function, which then should get me a list of Names and their email addresses
$.ajax({
type:'POST',
url:'get_distusers.php',
data:'dist_id='+dist_id+'&study_id='+study_id,
success: function(data){
$('#dist_list2').html(data);
$('#dist_list').val(data);
},
error : function(XMLHttpRequest, textStatus, errorThrown) {
alert("There was an error."+textStatus+" - " + XMLHttpRequest.status);
}
});
Then the other page has this to send back the list of names and emails
unset($contact);
if ($count_du>0) {
while($row_du = mysqli_fetch_array($result_du)) {
if(!empty($contacts))
$contacts.="<br>, ";
$contact['name']=$row_du[0];
$contact['email']=$row_du[1];
}
}
$contacts[]=$contact;
//$contacts=array($contact_email,$contact_name);
//echo $sql_patrand;
echo json_encode($contacts);
However, when I try to retrieve the contact list, I either get the word object or nothing.
Can someone tell me what I am doing wrong?
You have return echo json_encode($contacts); json format from the your php code, but your ajax not understand json format because you have not set dataType: 'json' param, Please check the below mention code, it will defiantly helpful, any query comment inside answer....
$.ajax({
type:'POST',
url:'get_distusers.php',
data:'dist_id='+dist_id+'&study_id='+study_id,
dataType: 'json', //NOTE:Your missing point - update first
success: function(data){
console.log(data); //Print your data, so it will help you to how manage
$('#dist_list2').html(data);
$('#dist_list').val(data);
},
error : function(XMLHttpRequest, textStatus, errorThrown) {
alert("There was an error."+textStatus+" - " + XMLHttpRequest.status);
}
});

Issues with Jquery/PHP ajax form submission

I am using the following code to post form data to a php file..
jQuery("#form-submit").click(function(data){
var url = "save-data.php";
jQuery.ajax({
type: "POST",
data: jQuery('#my-form').serialize(),
url: url,
cache : "false",
success: function(data){
jQuery("#dl-message").html(data);
jQuery("#dl-message").css('background-color', '#0C3');
jQuery('#dl-message').slideToggle('slow', function() {
jQuery('#dl-message').delay(2000).slideToggle('slow', function() {
//Animation Complete
});
});
},
error: function ( jqXHR, textStatus, errorThrown){
jQuery("#dl-message").html('There was an error saving your form: ' + errorThrown);
jQuery("#dl-message").css('background-color', '#F33');
jQuery('#dl-message').slideToggle('slow', function() {
jQuery('#dl-message').delay(2000).slideToggle('slow', function() {
//Animation Complete
});
});
}
});
return false;
});
and then in my php file I am simply looking for $_POST['field-name'] to see if the contents of the form were posted. The ajax call returns successful, however no data from the form seems to be posted to the PHP file. When I call...
$name = $_POST['name'];
echo "Your name is: " . $name;
I get nothing.... Does anyone see anything wrong with my ajax call at all?
Thanks so much for your time...
So it seems the post was empty at the first place (btw you can include your last three posts inside the question by editing it). Are you sure your form's id is 'my-form'?

Jquery or Ajax if load fails

When you use Jquery or Ajax to call a page or script, which loads into a div,
or example
$.post('pagename.php', $(#cpay'.$id.'").serialize(), function(data) { $('#conSupp".$id."').html(data);
is there a way to display an error message in the div if the page fails to load
Many thanks
If you are using jquery 1.5 or above, the post will return a jqXhr object. If so, you could do something like this:
$.post('pagename.php', data, function(data) {
//success, do stuff with the data object
}).fail(function(jqXhr, ajaxOptions, thrownError){
//something went wrong
alert('Error: ' + thrownError);
});
Yes, bind an error handler, by calling the .fail() function on the jqXhr object returned by the call to $.post():
$.post(url, data, function(data) {
...
}).fail(function(jqXhr, textStatus, errorThrown) {
// an error occurred - do something here
});
I prefer just doing:
$.ajax({
type: 'POST',
url : 'pagename.php',
data: $(#cpay'.$id.').serialize()
}).done(function(data {
$('#conSupp".$id."').html(data);
}).fail(function() {
$('#conSupp".$id."').html('An error occured');
});
It's a little longer, but I find it much easier to read an change to whatever I need, and it's exactly what $.post does internally anyway, so saves me a function call?

Categories