pagination outputting to disable a link after clicking a page - php

Question

hello i have a code the next previous and last page are working but i can't get the link for the pages to work where the page will be disabled when you go there . i tried changing some parts but when i tried it there's no error simply all of the page number is disabled
here's my php code the last part only can't fix it tried but i'm still really a beginner
echo "<center>" . $numrows . " search results found</center>";
echo "<center>";
if ($pages >=1 && $page <= $pages) {
if($page == $first_page){
echo "Previous ";
} else{
if(!isset($page)){
echo "Previous ";
}else{
// But if page is set and it's not 1.
$previous = $page-1; echo "<a
href='?page=".$previous."&q=".$searchtext."'>Previous</a> ";
}
}
for ($x=1; $x<=$pages; $x++) {
echo ($x == $page) ? '<strong>'.$x.' </strong>' : ''.$x.' ' ;
}
if($page == $last_page){
echo "Next ";
}else{
// If page is not set or it is set and it's not the last page.
if(!isset($page)){
$next = $first_page+1; echo "<a href='?page=".$next."'>Next</a> ";
}else{
$next = $page+1; echo "<a href='?page=".$next."'>Next</a> ";
}
} echo "<a href='?page=".$last_page."&q=".$searchtext."'>Last
page</a>";
}
echo "</center>";
the
for ($x=1; $x<=$pages; $x++) {
echo ($x == $page) ? '<strong>'.$x.' </strong>' : ''.$x.' ' ;
}
part is the one i use to output the pages don't know the configuration for the isset of that part.

Answer 1

If I understand your question correctly you want the current page number to have no link? If so you could try something like the following.
for ($x=1; $x<=$pages; $x++) {
if ($page <> $x){
echo ($x == $page) ? '<strong>'.$x.'</strong>' : ''.$x.' ';
} else { echo $x.' '; }
}