how to make with print_r only display text in array - php

Question

I created a members table on my database and entered the username row as user and the password row as password. Then I wrote a script that has to display the password and the username in a database. This is it:
<?PHP
$user_name = "root";
$password = "Hunter123";
$database = "adventure_of_dragons";
$server = "127.0.0.1";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$SQL = "SELECT * FROM members";
$result = mysql_query($SQL);
while ( $db_field = mysql_fetch_assoc($result) ) {
$id = array($db_field['member_id']); "<BR>";
$username = array($db_field['username']); "<BR>";
$password = array($db_field['password']); "<BR>";
$rank = array($db_field['rank']); "<BR>";
print_r($username);
print_r($password);
}
mysql_close($db_handle);
}
else {
print "Database NOT Found " . $db_handle;
}
?>
but when i run the code it displays this:
Array ( [0] => user ) Array ( [0] => password )
how do I make it display the text like this:
-User -Password
Please help.

Answer 1

That's simple. Just don't make arrays of them in the first place, and use regular echo.
Other bugs in the code
print_r is a debug function (just like var_dump), it is not used for printing out data to user.
Also, this statement: "<BR>"; simply means nothing.
You must echo it for it to have any effect at all.
Another thing is that you've overwritten the DB connection variables in your fetching loop. It's better to use constants for this, like shown below.
Here's your code, fixed
<?php
define("DB_USERNAME", "root");
define("DB_PASSWORD", "Hunter123");
define("DB_DATABASE", "adventure_of_dragons");
define("DB_SERVER", "127.0.0.1");
$db_handle = mysql_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);
$db_found = mysql_select_db(DB_DATABASE, $db_handle);
if ($db_found || true) {
$SQL = "SELECT * FROM members";
$result = mysql_query($SQL) or die(mysql_error());
while ( $row = mysql_fetch_assoc($result) ) {
$id = $row['member_id'];
$username = $row['username'];
$password = $row['password'];
$rank = $row['rank'];
echo 'ID = ' . $id . '<br>';
echo 'RANK = ' . $rank . '<br>';
echo 'USERNAME = ' . $username . '<br>';
echo 'PASSWORD = ' . $password . '<br><br>';
// two <br>'s, so we get an empty line between users
}
mysql_close($db_handle);
} else {
echo "Database NOT Found " . $db_handle;
}