Map Reduce in Mongo, Convert mongo query to php mongo - php

Question

I had a query in mongo which looks like
db.Table_Name.group({
"key": { "Camp": true },
"initial": { "Clicks": 0 },
"reduce": function(obj, prev) {
prev.Clicks = prev.Clicks + obj.Clicks-0;
},
"cond": { "Date": { $gte: "2012-10-26", $lte: "2012-10-28" } }
});
I want to use this code in php. I tried all the possible ways. Can any one help me out from this problem. Even I followed this http://php.net/manual/en/mongodb.command.php Please any one help me out.
I tried this
$reduce = new MongoCode(
"function(obj, prev) {prev.Clicks = prev.Clicks + obj.Clicks-0;}"
);
$result = $db_1->command(array(
'mapreduce' => 'Collection_Name',
'key' => array("Camp" => true),
'initial' => array('Clicks' => 0),
'reduce' => $reduce,
'cond' => array(
'Date' => array('$gte' => '2010-07-12' , '$lte' => '2013-07-12')
),
));

Answer 1

Have you tried using MongoCollection::group? For your example, it might look something like this (not tested).
$keys = array("Camp" => 1);
$initial = array("Clicks" => 0);
$reduce = "function(obj, prev) {prev.Clicks = prev.Clicks + obj.Clicks-0;}";
$condition = array(
'Date' => array('$gte' => '2010-07-12', '$lte' => '2013-07-12')
);
$result = $collection->group($keys, $initial, $reduce, $condition);
Also, you should try to embrace the MongoDB terminology, i know it's just an example, but Table_Name should be Collection_Name as MongoDb does not have tables.

Answer 2

You could use the group command here but it is:
Slow
Basically a Map Reduce
JavaScript
Normally does not work with sharding (some people have made it)
Is deprecated in favour of the aggregation framework
Instead a better option would be to use the aggregation framework:
$mongo->db->collection->aggregate(array(
array('$match'=>array('date'=>array('$gte' => '2010-07-12','$lte' => '2013-07-12'))),
array('$group'=>array('_id'=>'$Camp', 'sum_clicks'=>array('$sum'=>'$Clicks')))
));