the user exists in the database into the Get_Id - php

Question

This is how I'm going to make a small sign system, it is such that it must find out if username is in the Get_id that you have visited,
GET_Id it is the page ID as it is for example 1 or 10
tilmeldt_navn the user's name on the page.
tilmeldt_email the person's own email.
I think like here in this still:
if ($stmt = $mysqli->prepare('SELECT tilmeldt_navn, tilmeldt_email FROM `tilmeldtOpgave` WHERE `get_id` = ?')) {
$stmt->bind_param('i', $id);
$id = $_GET['id'];
$stmt->execute();
$stmt->bind_result($tilmeldt_navn, $tilmeldt_email);
while ($stmt->fetch()) {
if($tilmeldt_navn == "")
{
echo "finds in the database";
}
else
{
echo "The finds in the database so can not sign me again!";
}
}
$stmt->close();
}
the problem is: it does not appear in the with some of them at all.
The need to find out whether the user has signed up for the get_id and if it has it must take the last of if and when it does not have to be the roof the first in the if

Answer 1

Honestly, it's really hard to understand what you really want to happen. But, since you try to
echo "finds in the database" it seems that you want to check if the record exist from your database.
Just try this:
if(isset($_GET['id'])){
$stmt = $mysqli->prepare("SELECT tilmeldt_navn, tilmeldt_email FROM `tilmeldtOpgave` WHERE `get_id` = ?");
$id= $_GET['id'];
$stmt->bind_param('s', $id);
$stmt->execute();
$stmt->bind_result($id);
$stmt->store_result();
if($stmt->num_rows == 1) //Check if value is returned
{
while($stmt->fetch()) //To fetch the contents of the row
{
echo 'Result Found';
}
}
else {
echo 'No result found';
}
$stmt->close();
$stmt->free_result();
}
$mysqli->close();
?>
Hope this helps.