For the last 4 hours I've been struggling to get something to work. I checked SO and other sources but couldn't find anything related to the subject. Here is the code:
<?php
$email=$_SESSION['email'];
$query1="SELECT * FROM oferte WHERE email='$email'";
$rez2=mysql_query($query1) or die (mysql_error());
if (mysql_num_rows($rez2)>0)
{
while ($oferta = mysql_fetch_assoc($rez2))
{
$id=$oferta['id_oferta'];
echo "<input type='radio' name='selectie' value='$id' id='$id'> <a href='oferta.php?id={$oferta['id_oferta']}'>{$oferta['denumire_locatie']}</a>";
echo "</br>";
}
echo "</br>";
//echo "<input type=\"button\" id=\"cauta\" value=\"Vizualizeaza\" onclick=\"window.location.href='oferta.php?id={$oferta['id_oferta']}'\" />";
//echo " <input type=\"button\" id=\"cauta\"value=\"Modifica\" onclick=\"window.location.href='modifica.php?id={$oferta['id_oferta']}'\" />";
echo " <input type=\"button\" id=\"sterge\" value=\"Sterge\" onclick=\"window.location.href='delete.php?id=$id'\" />";
echo "</form>";
echo "</div>";
}
else
{
}
?>
The while drags all of the user's entries from the database and creates a radio button for each one of them with the value and id (because I don't really know which one is needed) equal to the entry's id from the db. I echoed that out and the id is displayed as it should so no problems there.
The delete script works ok as well so I won't attach it unless you tell me to. All good, no errors, until I try to delete an entry. Whatever I choose from the list of entries, it will always delete the last one. Note that I have two other inputs echoed out, those will be the "view" and "modify" buttons for the entry.
I really hope this is not JavaScript related because I have no clue of JS. I think this will be of major help to others having this problem. Please let me know if I need to edit my question before downrating. Thanks!
After edit:
This is the delete script, which as I said earlier works fine.
<?php
if (isset($_GET['id']))
{
$id = $_GET['id'];
echo $id;
require_once('mysql_connect.php');
$query = "DELETE FROM oferte Where id_oferta = '$id'";
mysql_query($query) or die(mysql_error());
//header('Location: oferte.php');
}
else
{
//header('Location: oferte.php');
}
?>
The session is started as well, like this:
<?php
session_start();
?>
The reason the last $id is deleted is because this line is outside/after the while loop:
echo " <input type=\"button\" id=\"sterge\" value=\"Sterge\" onclick=\"window.location.href='delete.php?id=$id'\" />";
You want to move this line inside the loop so that you have a button that executes delete for each radio button.
Update:
To have links to delete and
echo "<input type='radio' name='selectie' value='$id' id='$id'> ";
echo "<a href='oferta.php?id={$oferta['id_oferta']}'>{$oferta['denumire_locatie']}</a> ";
echo "<a href='delete.php?id=$id'>delete</a>";
Also I do not think the radio button is needed here at all since you are not really doing anything with it. You could simply echo out the value of your choice and have these links as follows:
echo $oferta['denumire_locatie'] . ' '; // replace $oferta['denumire_locatie'] with something of your choice
echo "<a href='oferta.php?id={$oferta['id_oferta']}'>{$oferta['denumire_locatie']}</a> ";
echo "<a href='delete.php?id=$id'>delete</a>";
echo "<br />";
The problem, in this case, is JavaScript related, yes. What I recommend you to do is to simply add a Remove link for each item.
echo "<a href='oferta.php?id={$oferta['id_oferta']}'>{$oferta['denumire_locatie']}</a>";
echo " - <a href='delete.php?id={$oferta['id_oferta']}'>Remove</a>";
echo "</br>";
Your $id is outside your while() loop.
The last one is getting deleted because the $id has the last one's value when the loops is exited.
Include all your code :
echo "</br>";
//echo "<input type=\"button\" id=\"cauta\" value=\"Vizualizeaza\" onclick=\"window.location.href='oferta.php?id={$oferta['id_oferta']}'\" />";
//echo " <input type=\"button\" id=\"cauta\"value=\"Modifica\" onclick=\"window.location.href='modifica.php?id={$oferta['id_oferta']}'\" />";
echo " <input type=\"button\" id=\"sterge\" value=\"Sterge\" onclick=\"window.location.href='delete.php?id=$id'\" />";
Inside your while loop.
When the rendered html reaches the browser, it will be something like this:
<input type='radio' name='selectie' value='1' id='1'> <a href='oferta.php?id=1'>TEXT</a>
<input type='radio' name='selectie' value='2' id='2'> <a href='oferta.php?id=2'>TEXT</a>
<input type='radio' name='selectie' value='3' id='3'> <a href='oferta.php?id=3'>TEXT</a>
<input type='radio' name='selectie' value='4' id='4'> <a href='oferta.php?id=4'>TEXT</a>
<br/>
<input type="button" id="sterge" value="Sterge" onclick="window.location.href='delete.php?id=5'" />
With this markup you won't be able to accomplish what you want without using javascript to update the onclick attribute whenever you select a radio button.
On the other hand, instead of using the client-side onclick event you can use the button's default behaviour, which is to submit the form.
You'll just have to set the action attribute:
<form method="post" action="http://myurl.php">
and write the myurl.php page which will just read the posted variable $_POST['selectie'] and call the delete method with the posted id.
Related
Am puzzled about how to make a system that can automatically mark.
Am using a variable $count in PHP and is the one storing data from the checked radio button.
I have not tried to check on how to do it and am just afraid of how to do it.
I have the following codes which out puts the data in radio buttons
<?php
$get=mysql_query("select * from courses where courseid='".$cid."'");
while ($picked=mysql_fetch_array($get)) {
echo "<b>The questions for ".$picked['coursename']." are:</b><br><br>";
}
$query=mysql_query("select * from papers where cid='".$cid."'");
if (mysql_num_rows($query)>0) {
$count=1;
while ($row=mysql_fetch_array($query)) {
echo "Qn ".$count.". ".$row['question']."<br><input type='radio' name='".$count."' value='A'>".$row['A']."<br><input type='radio' name='".$count."' value='B'>".$row['B']."<br><input type='radio' name='".$count."' value='C'>".$row['C']."<br><input type='radio' name='".$count."' value='D'>".$row['D']."<br><br>";
$count++;
}
}else{
echo "No papar has been set yet for this paper.";
}
?>
<input type="submit" name="but" value="Submit Assessment">
and it outputs the following:
And the database is like:
I have trouble when creating code for adding an item to shopping cart. What I did is echo each individual item customers could buy, and I wanted to add an input type for how many of that specific item they want, then "add to cart" button and repeat (echo another item, another input and button etc.)
while ($zaznam = mysqli_fetch_assoc($vysledek)) {
$soubor=$zaznam["img_nazev"];
echo "<div id='zbozi_info'>";
echo "<img src='img/$soubor'>";
echo "<p class='popis'>".$zaznam["dlouhy_popis"]."</p>";
echo "<p class='cena'> Cena bez DPH: ";
echo "<span style=color:#FF0000>".$zaznam["cena"]." Kč </span> </p>";
echo "<p class='cena'> Cena s DPH: ";
echo "<span style=color:#FF0000>".$zaznam["CenaDPH"]." Kč </span> </p>";
echo "</div>";
echo "<form method='post'>
<label for='pocetk'>Počet kusů</label>
<br>
<input type='text' name='pocetk' id='pocetk' value='1'>
<br>
<input type='submit' name='pridkos' id='pridkos' value='Přidat do košíku'>
</form>";
}
This works and all, the trouble starts when I add this if to the mix, to enable that adding function
if (isset($_POST["pridkos"]) && isset($_SESSION['user'])) {
$ksk="INSERT INTO kosik
(ID_uzivatele,ID_zbozi, pocet_kusu)
VALUES ('".$_SESSION['user']."',
'".$zaznam["ID_zbozi"]."',
'".$_POST["pocetk"]."');";
$vysledek = mysqli_query($con,$ksk)
or die("Zboží nebylo přidáno do košíku");
This just dies on the mysqli_query. I am not exactly sure if to put it inside the while or outside, my suspicion is inside, but it isn't working either way
Session[user] has the user ID (ID_uzivatele), not sure what else can I clarify.
Any help is appreciated.
I think this query syntax is wrong.
Check with below one:-
$ksk="INSERT INTO kosik(ID_uzivatele,ID_zbozi, pocet_kusu)
VALUES ('$_SESSION[user]',
'$zaznam[ID_zbozi]',
'.$_POST["pocetk"]')";
I have made a php page. On which I am displaying table 'prod' from my data base.
each row is displayed nicely. Today i tried to add a button named 'rate' at the end of each row of my table. which I did successfully. Now I want to send the the value of the first column of that row to another php page when that button is clicked. I am stuck that how to do so? can you help please ??
I know i have to use the method post in my form and i have to use $_post[that value] on the other php page to inculcate the value for further function.
I just need to ask that where to add the value of my first column in the button line. so that onclick it can send that value. I hope I am clear over this. Thank You very much for help :)
<?php
include("connection.php");
$query = "select * from prod";
$res = oci_parse($conn,$query);
usleep(100);
if (oci_execute($res)){
usleep(100);
print "<TABLE border \"1\">";
$first = 0;
while ($row = #oci_fetch_assoc($res)){
if (!$first){
$first = 1;
print "<TR><TH>";
print implode("</TH><TH>",array_keys($row));
print "</TH></TR>\n";
}
print "<TR><TD>";
print #implode("</TD><TD>",array_values($row));
print "</TD></TR>\n";
echo "<td><form action='detailform.php' method='POST'><input type='submit' name='submit-btn' value='Rate'/></form></td></tr>";
}
print "</TABLE>";
}
?>
you have to add inputs in your form whatever kind u prefer
echo "<td>
<form action='detailform.php' method='POST'>
<input type='hidden' name='your_val_key' value='".$row[your_val_key_in_query]."'> <!-- input hidden, change to text 4 debug -->
<input type='submit' name='submit-btn' value='Rate'/>
</form>
</td></tr>";
and than, in your detailform.php u can get the val with
echo $_POST["your_val_key"];
if u are not sure how much data u send or somthing, try this and u get the full data:
echo "<pre>".print_r($_POST,true)."</pre>";
BTW: why are u mixing print and echo?
Use hidden input
echo "<td><form action='detailform.php' method='POST'><input type='hidden' name='col-name' value='you-col-value'><input type='submit' name='submit-btn' value='Rate'/></form></td></tr>";
I have PHP radio buttons being generated by the following code:
while($a_row = mysql_fetch_array($answers_result))
{
// print each answer choice
?>
<input type='radio' name='question_<?php echo $current_question['id'] ?>'
value='<?php echo $a_row['prompt']?>'><?php echo $a_row['prompt']?>
<br />
<?php
}
I am then defining the user's choice with this code:
$user_answer = $_POST["question_{$_SESSION['current_question']['id']}"];
However, this isn't always returning the value, which should be whatever $a_row['prompt'] is.. If it is the first radio button in the list, it returns "answer 1", etc.. It is not getting the correct values from my sql table. Am I doing something wrong in my code that is causing it to not actually get the "value" of each radio button when the user selects it and submits the form?
You need to escape the ' ' as you start with them
<input type='radio' name='question_<?php echo $current_question[\'id\']; ?>'
value='<?php echo $a_row[\'prompt\'];?>'><?php echo $a_row['prompt'];?>
Also note that your need to finish your PHP command with ; that not the case.
To avoid ' ' trouble I recompend using " " when you know that you will have to add some ' ' in your code, that way they do not interfere.
<input type='radio' name="question_<?php echo $current_question['id']; ?>"
value="<?php echo $a_row['prompt'];?>"><?php echo $a_row['prompt'];?>
I have a PHP code which generates a dynamic list inside a form like the following, note that the list is built dynamically from database:
echo '<form name="List" action="checkList.php" method="post">';
while($rows=mysqli_fetch_array($sql))
{
echo "<input type='password' name='code' id='code'>";
echo "<input type='hidden' name='SessionID' id='SessionID' value='$rows[0]' />";
echo "<input type='submit' value='Take Survey'>";
}
What I need is to POST the data corresponding to the user choice when he clicks on the button for that row to another page.
If we use hyperlinks with query strings there will be no problem as I'll receive the data from the other page using a GET request and the hyperlinks would be static when showed to the user.
Also I need to obtain the user input from a textbox which is only possible with POST request.
Simply from the other page (checkList.php) I need these data for further processing:
$SessionID=$_POST['SessionID'];
$Code=$_POST['code'];
As I have a while loop that generates the fields, I always receive the last entry form the database and not the one corresponding to the line (row) that the user chosed from the LIST.
I'm going to recommend that you clean up the names of variables so that your code can
at least tell us what it's supposed to do. It should be rare that someone looks at your code
and has a lot of trouble trying to see what you're trying to accomplish :P, ESPECIALLY when you need help with something ;]. I'm going to try some things and hope that it makes doing what you want easier to comprehend and perhaps get you your answer.
It's good to try your best to not echo large amounts of HTML unnecessarily within a script , so firstly I'm going to remove the
echos from where they are not necessary.
Secondly, I'm going to use a mysql function that returns an easier to process result.
$user = mysqli_fetch_assoc($sql)
Third, I don't know if form having a name actually does anything for the backend or frontend of php, so I'm
just going to remove some of the extra crust that you have floating around that is either invalid HTML
or just doesn't add any value to what you're trying to do as you've presented it to us.
And yes, we "note" that you're building something from the database because the code looks like it does =P.
I'm also sooo sad seeing no recommendations from the other answers in regard to coding style or anything in regard to echoing html like this :(.
<?php while($user = mysqli_fetch_assoc($sql)): ?>
<form action="checkList.php" method="post">
<input type='password' name='code' value='<?php echo $user['code'] ?>' />
<input type='hidden' name='SessionID' value='<?php echo $user['id'] //Whatever you named the field that goes here ?>' />
<input type='submit' value='Take Survey' />
</form>
<?php endwhile; ?>
i not sure this is correct
echo '<form name="List" method="post">';
while($rows=mysqli_fetch_array($result))
{
echo "<input type='password' name='code' id='code'>";
echo "<input type='button' value='Take Survey' onclick=show($rows[0])>";
echo "<br>";
}
and javascript
<script>
function show(id)
{
alert(id);
window.location="checkList.php?id="+id;
}
</script>
On checkList.php
$id=$_GET['id'];
echo $id;
You can just check in checkList.php whether $_POST['code'] exists and if exists retrieve $_POST['SessionID'] which will be generated from database. But one thing, if You have all hidden fields in one form, they all will be sent, so You need to think how to correct that - maybe seperate forms for each hidden field, submit button and maybe other POST fields.
And afterwards, You will be able to get data in the way You need - $SessionID=$_POST['SessionID'];
I suppose it is the easiest way to solve that.
You can try something like this:
while($rows=mysqli_fetch_array($sql))
{
$index = 1;
echo "<input type='password' name='code' id='code'>";
//Attach $index with SessionID
echo "<input type='hidden' name='SessionID_$index' id='SessionID' value='$rows[0]' />";
echo "<input type='submit' value='Take Survey'>";
}
On checkList.php
<?php
$num = explode('_', $_POST['SessionID']);
$num = $num[1];
//in $num you will get the number of row where you can perform action
?>
$form = 1;
while($rows=mysqli_fetch_array($sql))
{
echo '<form name="List_$form" action="checkList.php" method="post">';
echo "<input type='password' name='code' id='code_$form'>";
echo "<input type='hidden' name='SessionID' id='SessionID_$form' value='$rows[0]' />";
echo "<input type='submit' value='Take Survey'>";
echo '</form>';
$form++;
}