Get return values of code with tokenizer - php

Question

I'm trying to parse PHP source code with the token_get_all(). So far everything worked out with that function, but now i need a way to get the return values of methods.
Identifying where a return is done isn't the problem. I just see no way of getting the piece of code that comes after the return value.
For example for this piece of code:
<?php
class Bla {
public function Test1()
{
$t = true;
if($t) {
return 1;
}
return 0;
}
public function Test2()
{
echo "bbb";
return; // nothing is returned
}
public function Test3()
{
echo "ccc";
$someval1 = 1;
$someval2 = 2;
return ($someval + $otherval)*2;
}
}
?>
I'm using get_token_all() to identify where a return is done:
$newStr = '';
$returnToken = T_RETURN;
$tokens = token_get_all($source);
foreach ($tokens as $key => $token)
{
if (is_array($token))
{
if (($token[0] == $returnToken))
{
// found return, now get what is returned?
}
else
{
$token = $token[1];
}
}
$newStr .= $token;
}
I have no clue how to get the piece of code that is actually returned. That is what i want to get.
Anyone any idea how i could do this?

Answer 1

Perhaps this might help. Though I curious to know what you are ultimately trying to do.
$tokens = token_get_all($str);
$returnCode = '';
$returnCodes = array();
foreach ($tokens as $token) {
// If return statement start collecting code.
if (is_array($tokens) && $token['0'] == T_RETURN) {
$returnCode .= $token[1];
continue;
}
// if we started collecting code keep collecting.
if (!empty($returnCode)) {
// if we get to a semi-colon stop collecting code
if ($token === ';') {
$returnCodes[] = substr($returnCode, 6);
$returnCode = '';
} else {
$returnCode .= isset($token[1]) ? $token[1] : $token;
}
}
}