php - check whether string end with image extension [duplicate] - php

Question

This question already has answers here:
How to get a file's extension in PHP?
(31 answers)
Closed 9 years ago.
I need to verify string whether the string is image file name.
$aaa = 'abskwlfd.png';
if ($aaa is image file) {
echo 'it's image';
else {
echo 'not image';
}
How do i do that? It will chck 100 images, so it should be fast. I know there is a filetype verification method, but I think that's slow.. What about preg_match? Is it faster?
I'm not good at preg_match.
Thank you in advance.

Answer 1

Try this:
<?php
$supported_image = array(
'gif',
'jpg',
'jpeg',
'png'
);
$src_file_name = 'abskwlfd.PNG';
$ext = strtolower(pathinfo($src_file_name, PATHINFO_EXTENSION)); // Using strtolower to overcome case sensitive
if (in_array($ext, $supported_image)) {
echo "it's image";
} else {
echo 'not image';
}
?>

Answer 2

try this code,
if (preg_match('/(\.jpg|\.png|\.bmp)$/i', $aaa)) {
echo "image";
} else{
echo "not image";
}

Answer 3

Maybe you are looking for this:
function isImageFile($file) {
$info = pathinfo($file);
return in_array(strtolower($info['extension']),
array("jpg", "jpeg", "gif", "png", "bmp"));
}
I am using pathinfo to retrieve detail information about file including extension.
I am using strtolower to ensure that the extension will match our list of supported image even it is in different case
Using in_array to check whether file extension is in our list of image extenion.

Answer 4

try this
$allowed = array(
'.jpg',
'.jpeg',
'.gif',
'.png',
'.flv'
);
if (!in_array(strtolower(strrchr($inage_name, '.')), $allowed)) {
print_r('error message');
}else {
echo "correct image";
}
or strrchr it takes last occurence of character string..
else some other concept.
$allowed = array(
'image/jpeg',
'image/pjpeg',
'image/png',
'image/x-png',
'image/gif',
'application/x-shockwave-flash'
);
if (!in_array($image_name, $allowed)) {
print_r('error message');
}else {
echo "correct image";
}
Here you can used STRTOLOWER function and also used in_array function

Answer 5

try this:
$a=pathinfo("example.exe");
var_dump($a['extension']);//returns exe

Answer 6

Yes, regex is the way to go. Alternatively, you could split around the "." and check the last element in the returned array against an array of image extensions. I'm not a PHP guy so I can't write the code for you, but I can write the regex:
^[a-zA-Z\.0-9_-]+\.([iI][mM][gG]|[pP][nN][gG]|etc....)$
This one is fairly simple. I know you don't have much experience with regex, but here's what this one does:
^: start of string
[a-zA-Z\.0-9_-]: describes range of characters including all letters, numbers, and ._-
\.: "." character
([iI][mM][gG]|[pP][nN][gG]|etc....): | means or. So just put all image extensions you know here. Again, the brackets for case-insensitivity
if you want to match any sequence then instead of the stuff in the brackets and the +, just use:
.*
"." matches any character and "*" means any amount of it. So this just basically says "no restrictions" (except newlines)
There are probably a lot of other things I'm missing, as you can see in the comments. Just read those, look at a regex reference, and you'll be fine.

Answer 7

Try this
use pathinfo():
$ext = pathinfo($file_name, PATHINFO_EXTENSION); case sensitive
if (in_array($ext, $supported_image)) {
echo "it's image";
} else {
echo 'not image';
}