I want to insert selected data from one of my table under the same database. I have a code but it doesn't work.
moduleindex.php
<?php
include "connectdatabase.php";//include the connection file
$db = mysql_select_db("section_masterfile",$connectDatabase);
$queries = "Select student_Firstname, student_Lastname, student_Section FROM masterfile_table";
if(isset($_POST['TeacherName'])&& isset($_POST['SectionName']))
{
$searchTeacher = $_POST['TeacherName'];
$searchSection = $_POST['SectionName'];
$queries = "Select student_Firstname, student_Lastname, student_Section FROM masterfile_table WHERE section_Teacher = '{$searchTeacher}' AND student_Section='{$searchSection}'";
}
$queried = mysql_query($queries,$connectDatabase);
?>
insertdata.php
<?php
include 'moduleindex.php';
include 'connectdatabase.php';
$db_pdf = mysql_select_db("section_masterfile",$connectDatabase);
while($row = mysql_fetch_array($queried))
{
$field1 = $row['student_Lastname'];
$field2 = $row['student_Firstname'];
$field3 = $row['student_Section'];
$insert_query = mysql_query("INSERT INTO pdf_table (student_Lastname,student_Firstname,student_Section) VALUES ('{$field1}', '{$field2}', '{$field3}')",$connectDatabase);
}
?>
You can use single query for both purpose, Try something like this
INSERT INTO pdf_table (student_Lastname, student_Firstname, student_Section )
SELECT student_Lastname, student_Firstname, student_Section FROM masterfile_table
You can also add the conditions with your select query as per your requirement.
There is a mechanism in sql/mysql called select into, search it on Google.
I am not sure what you are trying to do this is the approach.
INSERT INTO tbl_temp2 (fld_id)
SELECT tbl_temp1.fld_order_id
FROM tbl_temp1 WHERE tbl_temp1.fld_order_id > 100;
As per an example taken from:
http://dev.mysql.com/doc/refman/5.0/en/ansi-diff-select-into-table.html
I'm looking to loop the following script, as to save lines of code, and manual hardcoding. The script pulls specific values from my database and assigns them to variables that are used across my website.
$w1001a = $conn->query("SELECT columnB FROM table WHERE columnA='w1001a' limit 1")->fetch_object()->content;
$w1001b = $conn->query("SELECT columnB FROM table WHERE columnA='w1001b' limit 1")->fetch_object()->content;
....
$w1025b = $conn->query("SELECT columnB FROM table WHERE columnA='w1001b' limit 1")->fetch_object()->content;
Thanks in advance!
Don't loop the query, use one query to get all the info.
The below is just dummy code:
$stmt = $conn->query("SELECT columnA, columnB FROM table WHERE columnA IN ('w1001a', 'w1001b', ...)");
$result = array();
while ($obj = $stmt->fetch_object()) {
$result[$obj->columnA] = $obj->columnB;
}
I'm trying to display a field from my MySQL database. It's in the table tblproducts in the row with the id is set to 1. And under the column qty.
This is the code I'm using:
<?php
mysql_connect("localhost","username","password");
mysql_select_db("database_name");
$available = "SELECT qty FROM tblproducts WHERE id = 1";
$result = mysql_query($available);
echo $result;
?>
However, I keep getting this message: Resource id #2
I've done a bit of research and seen where other people are having similar problems but most of them are trying to display their data in an HTML table whereas I just need the data from 'qty' to display. And of course I'm definitely not a MySQL guru.
Can anyone help me out with this please?
Try changing this:
$result = mysql_query($available);
To this:
$result = mysql_result(mysql_query($available), 0);
Let's start from the start. (I'll assume you have the connection set)
Form the query
$query = "SELECT `qty`
FROM `tblproducts`
WHERE `id` = 1";
Execute the query
$run = mysql_query($query);
Now, put the result in an assoc array
$r = mysql_fetch_array($run);
See the contents of the array
echo $r['qty'];
It's also advised that you move up from mysql to either mysqli, or PDO. PDO is preferred as you're not bound to the MySQL database model.
Try this:
Here you need to generate associative array and then get the resulting row.
$query = "SELECT `qty` FROM `tblproducts` WHERE `id` = 1";
$run = mysql_query($query);
$r = mysql_fetch_array($run);
echo $r['qty'];
-
Thanks
I have a mysql database called A.
I would like to to get informations where country=usa (There are about 40 000 with usa) and i want to insert to B database.
How i can do that with php?
Thanks in advance
Yes, you can do this slowly with PHP:
<?php
$data = mysql_query("SELECT x,y,z FROM db1.table WHERE where country='usa'");
$values = Array();
while ($row = mysql_fetch_assoc($data)) {
// do some work...
$row['x'] = mysql_real_escape_string($row['x']);
$row['y'] = mysql_real_escape_string($row['y']);
$row['z'] = mysql_real_escape_string($row['z']);
$values[] = "('$row[x]','$row[y]','$row[z]')";
}
mysql_query("insert into db2.table (x,y,z) VALUES ".implode(',',$values)."");
?>
But i prefer quicker and simplier MySQL INSERT ... SELECT statement, directly in MySQL console:
INSERT INTO db2.table (x,y,z) SELECT x,y,z FROM db1.table WHERE country='usa';
You should be able to do a dump of the database schema and data, as a big SQL file, and just run that SQL on the different database... no need for PHP scripting at all if you have phpMyAdmin. Just use the operations tab on the main database screen. Export database on the source, import it in to the destination.
<?php
$query = "SELECT * FROM database1.table_name WHERE country = 'USA'";
$result2 = mysql_query($query);
while($row = mysql_fetch_assoc($result)){
//assigning of value to variable
$val1 = $row['field_name1'];
$val2 = $row['filed_name2'];
//and so on
$query2 = "INSERT INTO database2.table_name (field1,field2,.....) VALUES ('$val1', 'val2',....)"
$result2 = mysql_query($query2);
}
?>
What's the best way with PHP to read a single record from a MySQL database? E.g.:
SELECT id FROM games
I was trying to find an answer in the old questions, but had no luck.
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$id = mysql_result(mysql_query("SELECT id FROM games LIMIT 1"),0);
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database_name', $link);
$sql = 'SELECT id FROM games LIMIT 1';
$result = mysql_query($sql, $link) or die(mysql_error());
$row = mysql_fetch_assoc($result);
print_r($row);
There were few things missing in ChrisAD answer. After connecting to mysql it's crucial to select database and also die() statement allows you to see errors if they occur.
Be carefull it works only if you have 1 record in the database, because otherwise you need to add WHERE id=xx or something similar to get only one row and not more. Also you can access your id like $row['id']
Using PDO you could do something like this:
$db = new PDO('mysql:host=hostname;dbname=dbname', 'username', 'password');
$stmt = $db->query('select id from games where ...');
$id = $stmt->fetchColumn(0);
if ($id !== false) {
echo $id;
}
You obviously should also check whether PDO::query() executes the query OK (either by checking the result or telling PDO to throw exceptions instead)
Assuming you are using an auto-incrementing primary key, which is the normal way to do things, then you can access the key value of the last row you put into the database with:
$userID = mysqli_insert_id($link);
otherwise, you'll have to know more specifics about the row you are trying to find, such as email address. Without knowing your table structure, we can't be more specific.
Either way, to limit your SELECT query, use a WHERE statement like this:
(Generic Example)
$getID = mysqli_fetch_assoc(mysqli_query($link, "SELECT userID FROM users WHERE something = 'unique'"));
$userID = $getID['userID'];
(Specific example)
Or a more specific example:
$getID = mysqli_fetch_assoc(mysqli_query($link, "SELECT userID FROM users WHERE userID = 1"));
$userID = $getID['userID'];
Warning! Your SQL isn't a good idea, because it will select all rows (no WHERE clause assumes "WHERE 1"!) and clog your application if you have a large number of rows. (What's the point of selecting 1,000 rows when 1 will do?) So instead, when selecting only one row, make sure you specify the LIMIT clause:
$sql = "SELECT id FROM games LIMIT 1"; // Select ONLY one, instead of all
$result = $db->query($sql);
$row = $result->fetch_assoc();
echo 'Game ID: '.$row['id'];
This difference requires MySQL to select only the first matching record, so ordering the table is important or you ought to use a WHERE clause. However, it's a whole lot less memory and time to find that one record, than to get every record and output row number one.
One more answer for object oriented style. Found this solution for me:
$id = $dbh->query("SELECT id FROM mytable WHERE mycolumn = 'foo'")->fetch_object()->id;
gives back just one id. Verify that your design ensures you got the right one.
First you connect to your database. Then you build the query string. Then you launch the query and store the result, and finally you fetch what rows you want from the result by using one of the fetch methods.
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database',$link);
$sql = 'SELECT id FROM games'
$result = mysql_query($sql,$link);
$singleRow = mysql_fetch_array($result)
echo $singleRow;
Edit: So sorry, forgot the database connection. Added it now
'Best way' aside some usual ways of retrieving a single record from the database with PHP go like that:
with mysqli
$sql = "SELECT id, name, producer FROM games WHERE user_id = 1";
$result = $db->query($sql);
$row = $result->fetch_row();
with Zend Framework
//Inside the table class
$select = $this->select()->where('user_id = ?', 1);
$row = $this->fetchRow($select);
The easiest way is to use mysql_result.
I copied some of the code below from other answers to save time.
$link = mysql_connect('localhost','root','yourPassword')
mysql_select_db('database',$link);
$sql = 'SELECT id FROM games'
$result = mysql_query($sql,$link);
$num_rows = mysql_num_rows($result);
// i is the row number and will be 0 through $num_rows-1
for ($i = 0; $i < $num_rows; $i++) {
$value = mysql_result($result, i, 'id');
echo 'Row ', i, ': ', $value, "\n";
}
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$db = new mysqli('localhost', 'tmp', 'tmp', 'your_db');
$db->set_charset('utf8mb4');
if($row = $db->query("SELECT id FROM games LIMIT 1")->fetch_row()) { //NULL or array
$id = $row[0];
}
I agree that mysql_result is the easy way to retrieve contents of one cell from a MySQL result set. Tiny code:
$r = mysql_query('SELECT id FROM table') or die(mysql_error());
if (mysql_num_rows($r) > 0) {
echo mysql_result($r); // will output first ID
echo mysql_result($r, 1); // will ouput second ID
}
Easy way to Fetch Single Record from MySQL Database by using PHP List
The SQL Query is SELECT user_name from user_table WHERE user_id = 6
The PHP Code for the above Query is
$sql_select = "";
$sql_select .= "SELECT ";
$sql_select .= " user_name ";
$sql_select .= "FROM user_table ";
$sql_select .= "WHERE user_id = 6" ;
$rs_id = mysql_query($sql_select, $link) or die(mysql_error());
list($userName) = mysql_fetch_row($rs_id);
Note: The List Concept should be applicable for Single Row Fetching not for Multiple Rows
Better if SQL will be optimized with addion of LIMIT 1 in the end:
$query = "select id from games LIMIT 1";
SO ANSWER IS (works on php 5.6.3):
If you want to get first item of first row(even if it is not ID column):
queryExec($query) -> fetch_array()[0];
If you want to get first row(single item from DB)
queryExec($query) -> fetch_assoc();
If you want to some exact column from first row
queryExec($query) -> fetch_assoc()['columnName'];
or need to fix query and use first written way :)