validating a drop down list using javascript - php

<?PHP
session_start();
if (isset($_SESSION['login']) && $_SESSION['login'] = '1') {
//=========================================================
//The following page is used to create a dynamic survey.
//=========================================================
$qNum = 'q1';
$question = 'Question not set';
$answerA = 'unchecked';
$answerB = 'unchecked';
$answerC = 'unchecked';
$qID = array();
$question = array();
$A = array();
$B = array();
$C = array();
$D = array();
$E = array();
$quesType = array();
$survey_Answers1 = '';
$nominatefriend = '';
//============================================
// OPEN A CONNECTION TO THE DATABASE
//============================================
$user_name = "root";
$password = "";
$database = "surveyTest";
$server = "127.0.0.1";
$mysqli = new mysqli($server, $user_name, $password, $database);
$SID = $_SESSION['user'];
if (!mysqli_connect_errno()) {
$result = $mysqli->query("SELECT * FROM tblquestions ORDER BY SUBSTRING(QID,2)+0");
$numRows = mysqli_num_rows($result); //return number of rows in the table
//var_dump($numRows);
echo '<FORM NAME ="form1" METHOD ="POST" ACTION ="survey.php">';
for ($i = 1; $i <= $numRows; $i++)
{
//var_dump ($mysqli->error);
//var_dump($i);
$db_field = mysqli_fetch_assoc($result);
//var_dump($db_field);
$qID[$i] = $db_field['QID'];
$question[$i] = $db_field['Question'];
$quesType = $db_field['qType'];
//var_dump($quesType);
$A[$i] = $db_field['qA'];
$B[$i] = $db_field['qB'];
$C[$i] = $db_field['qC'];
$D[$i] = $db_field['qD'];
$E[$i] = $db_field['qE'];
if ($quesType == 'rating')
{
echo '<P>';
print $qNum.': '.$question[$i];
echo '<P>';
if ($A[$i] != ""){
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= '".$A[$i]."' id = '".$qNum."'>";
print $A[$i];
}
echo '<P>';
if ($B[$i] != ""){
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= '".$B[$i]."' id = '".$qNum."'>";
print $B[$i];
}
echo '<P>';
if ($C[$i] != ""){
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= '".$C[$i]."' id = '".$qNum."'>";
print $C[$i];
}
echo '<P>';
if ($D[$i] != ""){
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= '".$D[$i]."' id = '".$qNum."'>";
print $D[$i];
}
echo '<P>';
if ($E[$i] != ""){
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= '".$E[$i]."' id = '".$qNum."'>";
print $E[$i];
}
echo "<span style='color:red' id='radio_error'></span>";
if (isset($_POST[$qNum])){
$survey_Answers1 = $survey_Answers1.', '.$_POST["$qNum"];
var_dump($survey_Answers1);
}
$question_Number = ltrim($qNum,'q');
$question_Number++;
$qNum ='q'.$question_Number;
}
else if ($quesType == 'nominate')
{
//echo "<INPUT TYPE = 'hidden' Name = '".$qNum."' id = '".$qNum."'>";
$number_of_Combos = $A[$i];
//var_dump($number_of_Combos);
echo '<p>';
print $qNum.': '.$question[$i];
echo '</BR>';
for ($j = 1; $j <= $number_of_Combos; $j++)
{
$nominatefriend = $qNum.$j;
//var_dump($nominatefriend);
$result_Combo = $mysqli->query("SELECT SID, fName, lName FROM students WHERE SID!='$SID'");
echo "<select name = '".$nominatefriend."' id = '".$qNum."'>";
echo "<option value = '0'>".'Select a Name'."</option>";
while ($select_query_array = mysqli_fetch_array($result_Combo))
{
echo "<option value='".$select_query_array['SID']."'>".$select_query_array['fName'].' '.$select_query_array['lName']."</option>";
}
echo "</select>";
}
$question_Number = ltrim($qNum,'q');
$question_Number++;
$qNum ='q'.$question_Number;
//var_dump ($qNum);
}
}
echo '<p>';
echo "<INPUT TYPE = 'hidden' Name = 'h2' VALUE = '".$survey_Answers1."'>";
echo '<p>';
echo '<INPUT TYPE = "Submit" Name = "Submit1" VALUE = "Click here to vote">';
echo '</form>';
//$value1 = $_POST['nominateFriend1'];
//var_dump($value1);
//$value2 = $_POST['nominateFriend2'];
//var_dump($value2);
//$value3 = $_POST['nominateFriend3'];
//var_dump($value3);
mysqli_close($mysqli);
}
else {
print "Error getting Survey";
mysqli_close($mysqli);
}
}
else
{
header("location:login.php");
}
$_SESSION['user'] = $SID; // refers to student ID from the login page
?>
<html>
<head>
<title>Radio Buttons</title>
</head>
<body>
<!--
<P>
<FORM NAME ="form2" METHOD ="GET" ACTION ="viewResults.php">
<INPUT TYPE = "Submit" Name = "Submit2" VALUE = "View results">
<INPUT TYPE = "Hidden" Name = "h1" VALUE = <?PHP print $qID; ?>>
</FORM>
-->
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js"></script>
<script>
$(function(){
if ($('form').length > 0) {
$('form').submit(function(e){
var answers = '';
var len = <?php echo $numRows; ?>;
$('input[type=Radio]:checked').each(function() {
if (answers !== '') {
answers += ',';
}
answers += $(this).val();
//alert(answers);
})
$('input[name=h2]').val(answers);
for (var i = 1; i <= len; i++ ) {
var qNum = 'q'+i;
//document.write(qNum);
if ($('#'+qNum+'').is(':radio')) {
if (($('input[name='+qNum+']:checked').length == 0) ){
alert("No Selection is made for "+ qNum);
return false;
}
}
else if ($('#'+qNum+'').is('select')) {
var j = 1;
var nominatefriend = qNum+j;
alert (nominatefriend);
var check = '';
var chosen = new Array();
while (check = document.getElementsByName("nominatefriend")) {
alert(check);
var len = document.form1[nominatefriend].length;
alert (len);
for (var i = 0; i < len; i++) {
if (document.form1[nominatefriend[i]].selected) {
chosen[j] = document.form1[nominatefriend[i]].value;
alert (chosen[j]);
}
}
j++;
nominatefriend = qNum+j;
alert (nominatefriend);
}
}
} // for loop
}); // form submit function
}// form.length
})//function
</script>
</body>
</html>
I'm trying to validate the drop down list which is created dynamically based on a value in mysql database. However, I'm getting the following error: TypeError: document.form1.nominatefriend is undefined in the following if condition:
if (document.form1[nominatefriend[i]].selected) {
chosen[j] = document.form1.nominatefriend[i].value;
alert (chosen[j]);
}


$nominatefriend = $qNum.$j;
echo "<select name = '".$nominatefriend."' id = '".$qNum."'>";
so it's just undefined yet


The error says that nominatefriend is undefined.
If I look into your PHP file code I find that in line number 99 and 102 you have as
$nominatefriend = $qNum.$j;
echo "<select name = '".$nominatefriend."' id = '".$qNum."'>";
If I look into more I find $qNum as
$qNum = 'q1';
Thus it will be probably document.form1.q1[i] rather than document.form1.nominatefriend[i].
Error is in the naming, so if you can view source the page, you will probably find the right value that should be used in your js.

Related

Value of post does not update

I have created a reservation form. The user has the option when selecting a residence option from the drop down menu to not choose one, so the value would be 'Select One...'. If they do not select a residence area, once they submit the form it brings them to another page which gives them a drop down list of the options they have for residence areas based on their class and preferences. The results from the form print out on the third page with their name, gender, residence area, etc. The problem is that I retrieve the residence area by using $_POST["dorm"]. This works when the user does select a residence area, but if they do not, then the $_POST doesn't seem to update and reads as 'Select One...'.
Here is my code for the page that gives the user their residence area options:
<html>
<?php
require 'sql_helper.php';
echo " <form action = \"results2.php\" method = \"post\">\n<br> ";
//Read the information entered on the index page
$specialNeeds = isset($_POST["specialNeeds"]);
$laundry = isset($_POST["laundry"]);
$fullyEquippedKitchen = isset($_POST["fullyEquippedKitchen"]);
$class = $_POST["class"];
$dorm = $_POST["dorm"];
//If user did not choose a dorm
if ($dorm == "Select One...") {
$sql = "SELECT name, roomsAvailable FROM $dormTable WHERE class = $class || class = 'Select One...'";
if($result = mysqli_query($conn, $sql)) {
$numRows = mysqli_num_rows($result);
echo " <strong>Residence Areas</strong>\n ";
echo " <select name = dorm> \n";
for ($i = 0; $i < $numRows; $i++){
$aDorm = mysqli_fetch_assoc($result);
$dormName = $aDorm['name'];
$dormAvailable = $aDorm['roomsAvailable'];
if($dormName != 'Select One...'){
echo "<option value = \"$dormName\" > $dormName ($dormAvailable)</option>\n";
}
elseif ($dormAvailable == 0 && $dormName != 'Select One...'){
echo "<option value = \"$dormName\" disabled=\"disabled\"> $dormName </option> \n";
}
elseif ($dormName == 'Select One...'){
echo "<option value = \"$dormName\" disabled=\"disabled\" selected = \"true\"> $dormName </option> \n";
}
}
echo "</select>\n<br><br>";
}
foreach ($_POST as $k => $v){
echo"<input type = hidden name = $k value = \"$v\" ><?php echo print_r($_POST) ?>";
}
echo " <input type = \"submit\" value = \"Submit\"> \n <br> ";
}
//If user did choose a dorm
else {
$sql = "SELECT * FROM $dormTable WHERE name = '$dorm'";
if ($result = mysqli_query($conn, $sql)) {
$dormRecord = mysqli_fetch_assoc($result);
if ($class == $dormRecord['class']) {
unset($errorString);
// check preferences
if ($fullyEquippedKitchen) {
if (!$dormRecord['fullyEquippedKitchen']) {
$errorString = "$dormRecord[name] does not have a kitchen.\n";
echo $errorString;
echo 'Go back to the previous page to re-enter your preferences.<br><br>';
echo 'Go back<br><br>';
}
else{
foreach ($_POST as $k => $v){
echo"<input type = hidden name = $k value = \"$v\"> <?php echo print_r($_POST) ?>";
}
echo "Your preferences are a match!<br>";
echo " <input type = \"submit\" value = \"Submit\"> \n <br> ";
}
}
else{
foreach ($_POST as $k => $v){
echo"<input type = hidden name = $k value = \"$v\"> <?php echo print_r($_POST) ?>";
}
echo "Your preferences are a match!<br>";
echo " <input type = \"submit\" value = \"Submit\"> \n <br> ";
}
}
else {
$errorString = "You cannot live in $dormRecord[name] because of your class status.\n";
echo $errorString;
echo 'Go back to the previous page to re-enter your preferences.<br><br>';
echo 'Go back<br><br>';
}
}
else {
echo "something is wrong: ".mysqli_error($conn);
die;
}
?>
</form>
<?php
}
?>

PHP: Undefined shown on blank page

I'm trying to print/echo values from previous file however instead of showing error, all that is shown is 'Undefined' on a blank page. I've researched and tried several method but nothing works. Please help.
<?PHP
$user_name = "root";
$password = "";
$database = "leadership_program";
$server = "localhost";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
if (isset($_POST['survey_id'])) {
$survey_id = $_POST['survey_id'];
echo $survey_id;
}
if (isset($_POST['marks'])) {
foreach ($_POST['marks'] as $value) {
echo"$value";
}
}
if (isset($_POST['id'])) {
$id = $_POST['id'];
echo $id;
}
// $SQL2 = "UPDATE answer_table SET marks='$value' WHERE survey_id= '$survey_id' AND student_id= '$id'";
//$result2 = mysql_query($SQL2);
//mysql_close($db_handle);
} else {
print "Database NOT Found ";
mysql_close($db_handle);
// header("Location: surveyView.php");
}
?>
Here is displayresult.php
<form action="student_mark_save.php" method="POST"> //<?php...more codes here
if ($strucrow["qns$i"] === 'radio' || $strucrow["qns$i"] === 'checkbox') {
foreach ($arr as $b) {
echo "<br/>";
if (strpos($b, '%#%') !== false) {
$c = substr($b, 3, -2);
//echo $c;
$d = str_replace("$arr[0] :-", ':', $c);
echo $d, "<br/>";
echo "<br/>";
echo "<tr> Marks : <input type=\"text\" name=\"marks[]\"></tr><br />";
//echo $b;
} else {
echo $b;
// echo "is not with comment qns";
}
}
} else if ($strucrow["qns$i"] === 'comment') {
foreach ($arr as $b) {
echo $b;
echo "<tr> Marks : <input type=\"text\" name=\"marks[]\"></tr><br />";
// echo "is not with comment qns";
}
} else {
}
echo "<p/>";
}
$marksquery = sprintf(
"SELECT marks FROM answer_table WHERE survey_id = '%d' AND student_id = '$studentid' ", mysql_real_escape_string($survey_id)
);
$marksQuer = mysql_query($marksquery) or die(mysql_error());
$marksrow = mysql_fetch_assoc($marksQuer);
echo "<td><input type=\"hidden\" value= \"$survey_id\" name=\"survey_id\"></td><br />" ;
echo "<td><input type=\"hidden\" value= \"$studentid\" name=\"id\"></td><br />" ;
echo "<p><input type=\"submit\" value=\"Update\"></p>";
?>
</form>

for undefined mean, there is something which is not existing in global $_POST[]
check try to print $_POST in your first if statement as:
if ($db_found) {
print_r($_POST);
exit();
if (isset($_POST['survey_id'])) {
$survey_id = $_POST['survey_id'];
echo $survey_id;
}
now just see what do you have in $_POST, It might help you...Thanks

Most likely some Post data is not set. Try vardump($_POST); die('happy');.
It would also be better to handle missing Post data instead of just ignoring it so maybe if ($db_found) { should be
<?php
if ( $db_found
&& isset($_POST['survey_id'])
&& isset($_POST['marks'])
&& isset($_POST['id'])
)
{
$survey_id = $_POST['survey_id']; //maybe ensure int
$id = $_POST['id']; //maybe ensure int
$values = array(); //this is important $value will not be available outside the for loop or contain only the last value
foreach ((array)$_POST['marks'] as $value) { //ensure $_POST['marks'] is an array
$values[] = $value; //maybe mysql escape each $value here
}
$SQL2 = sprintf(
"UPDATE answer_table SET marks='%s' WHERE survey_id=%d AND student_id=%d",
impolde(',' $values), //assuming comma separated list here
$survey_id,
$id
);
$result2 = mysql_query($SQL2);
mysql_close($db_handle);
} else { ...
Please also consider to escape the values you read from POST. Doing it this way makes it very easy to SQL inject into your script!

MySQL Error: Duplicate 'Candidate Name'

I have created a MySQL database along with a front-end to manipulate it using PHP. However, while I can add content to the database manually, I cannot utilize my front-end. When I try to submit the data in my front-end's form fields, I receive the prompt "Duplicate Candidate Name."
The following PHP file is my general script for displaying the front-end:
<?php
if(isset($_POST['sbmtbtn']) && ($_POST['sbmtbtn'] != ""))
{
$desc = strip_tags($_POST['txtdesc']);
$date = glb_func_chkvl($_POST['txtdate']);
$first = glb_func_chkvl($_POST['txtfirst']);
$last = glb_func_chkvl($_POST['txtlast']);
$skill = glb_func_chkvl($_POST['txtskill']);
$sub1 = glb_func_chkvl($_POST['txtsub1']);
$sub2 = glb_func_chkvl($_POST['txtsub2']);
$person = glb_func_chkvl($_POST['txtperson']);
$company = glb_func_chkvl($_POST['txtcompany']);
$location = glb_func_chkvl($_POST['txtlocation']);
$complex = glb_func_chkvl($_POST['complex']);
$sts = glb_func_chkvl($_POST['lststs']);
$dt = date('Y-m-d');
$emp = $_SESSION['sesadmin'];
$sqryquestion_info
= "SELECT candi_first
FROM question_info
WHERE candi_first='$first'";
if(isset($_POST['frmtyp']) && ($_POST['frmtyp'] == "add"))
{
$srsquestion_info =mysql_query($sqryquestion_info);
$rows = mysql_num_rows($srsquestion_info);
if($rows > 0)
{
$gmsg = "<font color=red size=2>Duplicate Candidate Name . Record not saved</font>";
}
else
{
$iqryquestion_info="insert into question_info(
candi_first,candi_last,date,
skill,subtype_1,
subtype_2,person_int,
comp_name,loc_int,complex_lvl,
type_int,question_candi,q_crton,
q_crtby)
values('$first','$last','$date','$skill','$sub1','$sub2','$person','$company',
'$location','$complex','$sts','$desc','$dt','$emp')";
$irsquestion_info = mysql_query($iqryquestion_info);
if($irsquestion_info==true)
{
$gmsg = "<font color=green size=2>Record saved successfully</font>";
}
else
{
$gmsg = "<font color=red size=2>Record not saved</font>";
}
}
}
if(isset($_POST['frmtyp']) && ($_POST['frmtyp'] == "edit"))
{
$id = $_REQUEST['hdnedit'];
$pg = $_REQUEST['hdnpg'];
$countstart = $_REQUEST['hdncntstrt'];
$sqryquestion_info .=" and ques_id !=$id";
$srsquestion_info = mysql_query($sqryquestion_info);
$rows = mysql_num_rows($srsquestion_info);
if($rows > 0)
{
?>
<script>location.href="view_all_questions.php?sts=d&pg=<?php echo $pg;?>&countstart=<?php echo $countstart;?><?php echo $srchval;?>";</script>
<?php
}
else
{
$uqryquestion_info="update question_info set
date ='$date',
candi_first ='$first',
candi_last ='$last',
skill ='$skill',
subtype_1 ='$sub1',
subtype_2 ='$sub2',
person_int ='$person',
comp_name ='$company',
loc_int ='$location',
complex_lel ='$complex',
type_int ='$company',
question_candi ='$desc',
q_mdfdon ='$dt',
q_mdfdby ='$emp' ";
$uqryquestion_info .= " where ques_id=$id";
$ursquestion_info = mysql_query($uqryquestion_info);
if($ursquestion_info==true)
{
?>
<script>location.href="view_all_questions.php?sts=y&pg=<?php echo $pg;?>&countstart=<?php echo $countstart;?><?php echo $srchval;?>";
</script>
<?php
}
else
{
?>
<script>location.href="view_all_questions.php?sts=n&pg=<?php echo $pg;?>&countstart=<?php echo $countstart;?><?php echo $srchval;?>";
</script>
<?php
}
}
}
/*********************************** End Editing ******************************************************/
}
?>
Here begins my "main file" for editing:
<?php
if(isset($_POST['sbmtbtn']) && ($_POST['sbmtbtn'] != ""))
{
$desc = strip_tags($_POST['txtdesc']);
$date = glb_func_chkvl($_POST['txtdate']);
$first = glb_func_chkvl($_POST['txtfirst']);
$last = glb_func_chkvl($_POST['txtlast']);
$skill = glb_func_chkvl($_POST['txtskill']);
$sub1 = glb_func_chkvl($_POST['txtsub1']);
$sub2 = glb_func_chkvl($_POST['txtsub2']);
$person = glb_func_chkvl($_POST['txtperson']);
$company = glb_func_chkvl($_POST['txtcompany']);
$location = glb_func_chkvl($_POST['txtlocation']);
$complex = glb_func_chkvl($_POST['complex']);
$sts = glb_func_chkvl($_POST['lststs']);
$dt = date('Y-m-d');
$emp = $_SESSION['sesadmin'];
$sqryquestion_info="select candi_first
from question_info
where candi_first='$first'";
if(isset($_POST['frmtyp']) && ($_POST['frmtyp'] == "add"))
{
$srsquestion_info =mysql_query($sqryquestion_info);
$rows = mysql_num_rows($srsquestion_info);
if($rows > 0)
{
$gmsg = "<font color=red size=2>Duplicate Candidate Name . Record not saved</font>";
}
else
{
$iqryquestion_info="insert into question_info(
candi_first,candi_last,date,
skill,subtype_1,
subtype_2,person_int,
comp_name,loc_int,complex_lvl,
type_int,question_candi,q_crton,
q_crtby)
values('$first','$last','$date','$skill','$sub1','$sub2','$person','$company',
'$location','$complex','$sts','$desc','$dt','$emp')";
$irsquestion_info = mysql_query($iqryquestion_info);
if($irsquestion_info==true)
{
$gmsg = "<font color=green size=2>Record saved successfully</font>";
}
else
{
$gmsg = "<font color=red size=2>Record not saved</font>";
}
}
}
if(isset($_POST['frmtyp']) && ($_POST['frmtyp'] == "edit"))
{
$id = $_REQUEST['hdnedit'];
$pg = $_REQUEST['hdnpg'];
$countstart = $_REQUEST['hdncntstrt'];
$sqryquestion_info .=" and ques_id !=$id";
$srsquestion_info = mysql_query($sqryquestion_info);
$rows = mysql_num_rows($srsquestion_info);
if($rows > 0)
{
?>
<script>location.href="view_all_questions.php?sts=d&pg=<?php echo $pg;?>&countstart=<?php echo $countstart;?><?php echo $srchval;?>";</script>
<?php
}
else
{
$uqryquestion_info="update question_info set
date ='$date',
candi_first ='$first',
candi_last ='$last',
skill ='$skill',
subtype_1 ='$sub1',
subtype_2 ='$sub2',
person_int ='$person',
comp_name ='$company',
loc_int ='$location',
complex_lel ='$complex',
type_int ='$company',
question_candi ='$desc',
q_mdfdon ='$dt',
q_mdfdby ='$emp' ";
$uqryquestion_info .= " where ques_id=$id";
$ursquestion_info = mysql_query($uqryquestion_info);
if($ursquestion_info==true)
{
?>
<script>location.href="view_all_questions.php?sts=y&pg=<?php echo $pg;?>&countstart=<?php echo $countstart;?><?php echo $srchval;?>";
</script>
<?php
}
else
{
?>
<script>location.href="view_all_questions.php?sts=n&pg=<?php echo $pg;?>&countstart=<?php echo $countstart;?><?php echo $srchval;?>";
</script>
<?php
}
}
}
/*********************************** End Editing ******************************************************/
}
?>

Submit button needs to be clicked twice to get my results from radio buttons in a php script

The problem with this code is that I can't read the results in $survey_Answers1 except after clicking on the submit button twice.
file:survey.php
<?PHP
session_start();
//=========================================================
//The following page is used to create a dynamic survey.
//=========================================================
$qNum = 'q1';
$question = 'Question not set';
$answerA = 'unchecked';
$answerB = 'unchecked';
$answerC = 'unchecked';
$qID = array();
$question = array();
$A = array();
$B = array();
$C = array();
$survey_Answers = array();
$survey_Answers1 = '';
//============================================
// OPEN A CONNECTION TO THE DATABASE
//============================================
$user_name = "root";
$password = "";
$database = "surveyTest";
$server = "127.0.0.1";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
$SQL = "SELECT * FROM tblquestions";
if ($db_found) {
$result = mysql_query($SQL);
$numRows = mysql_num_rows($result); //return number of rows in the table
echo '<FORM NAME ="form1" METHOD ="POST" ACTION ="survey.php">';
for ($i = 1; $i <= 2; $i++)
{
$db_field = mysql_fetch_assoc($result);
$qID[$i] = $db_field['QID'];
$question[$i] = $db_field['Question'];
$A[$i] = $db_field['qA'];
$B[$i] = $db_field['qB'];
$C[$i] = $db_field['qC'];
echo '<P>';
print $question[$i];
echo '<P>';
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= 'A'>";
print $A[$i];
echo '<P>';
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= 'B'>";
print $B[$i];
echo '<P>';
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= 'C'>";
print $C[$i];
if (isset($_POST[$qNum])){
$survey_Answers1 = $survey_Answers1.', '.$_POST["$qNum"];
}
//var_dump($survey_Answers1);
$question_Number = ltrim($qNum,'q');
$question_Number++;
$qNum ='q'.$question_Number;
}
echo '<p>';
//$_SESSION['answers'] = $survey_Answers1;
//var_dump($_SESSION['answers']);
echo "<INPUT TYPE = 'hidden' Name = 'h2' VALUE = '".$survey_Answers1."'>";
echo '<INPUT TYPE = "Submit" Name = "Submit1" VALUE = "Click here to vote">';
var_dump($_POST['h2']);
echo '</form>';
mysql_close($db_handle);
}
else {
print "Error getting Survey";
mysql_close($db_handle);
}
?>
The value stored in var_dump($_POST['h2']); after hitting clicking the submit button once is: string '' (length=0)
P.S., using session variables doesn't resolve the problem, so please don't suggest this answer!!!!

Try to insert after for-loop
for ($i = 1; $i <= 2; $i++)
{
// your code here
}
if (empty($_POST['h2'])) $_POST['h2'] = $survey_Answers1; // insert this line
Or use JavaScript, insert to the end of file:
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js"></script>
<script>
$(function(){
if ($('form').length > 0) {
$('form').submit(function(e){
var answers = '';
$('input[type=Radio]:checked').each(function() {
if (answers !== '') {
answers += ',';
}
answers += $(this).val();
})
$('input[name=h2]').val(answers);
});
}
})
</script>

From what I see your problem is with your for loop try to see whats returning survey_Answers1 in each loop. you can try this to see whats returning each time it loops and part from there
if (isset($_POST[$qNum])){
$survey_Answers1 = $survey_Answers1.', '.$_POST["$qNum"];
?>
<script type="text/javascript"><?php echo $survey_Answers1; ?></script>
<?php
}

Passing an array in PHP to another PHP script through html hidden form element

My question is that when I copy my array elements between different php scripts using session variables, nothing gets printed out. The following are my two php files.
file1.php
$SQL = "SELECT * FROM tblquestions";
if ($db_found) {
$result = mysql_query($SQL);
$numRows = mysql_num_rows($result); //return number of rows in the table
echo '<FORM NAME ="form1" METHOD ="POST" ACTION ="file2.php">';
for ($i = 1; $i <= 2; $i++)
{
$db_field = mysql_fetch_assoc($result);
$qID[$i] = $db_field['QID'];
$question[$i] = $db_field['Question'];
$A[$i] = $db_field['qA'];
$B[$i] = $db_field['qB'];
$C[$i] = $db_field['qC'];
echo '<P>';
print $question[$i];
echo '<P>';
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= 'A'>";
print $A[$i];
echo '<P>';
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= 'B'>";
print $B[$i];
echo '<P>';
echo "<INPUT TYPE = 'Radio' Name = '".$qNum."' value= 'C'>";
print $C[$i];
//if (isset($_POST[$name_Value]))
$survey_Answers[$i-1] = $_POST[$qNum];
print '</BR>'.$survey_Answers[$i-1]."</BR>";
$question_Number = ltrim($qNum,'q');
$question_Number++;
$qNum ='q'.$question_Number;
}
echo '<p>';
session_start();
$_SESSION['answers'] = $survey_Answers;
echo '<INPUT TYPE = "Submit" Name = "Submit1" VALUE = "Click here to vote">';
echo '</form>';
On my Second file (file2.php), I have the following:
<?PHP
session_start();
if (isset($_POST['Submit1'])) {
$results = $_SESSION['answers'];
print $results[0];
?>
Nothing gets printed out when executing the above code.
Thanks in advance

I am pretty sure that the session values stored need to be strings.
In file1.php change:
$_SESSION['answers'] = $survey_Answers;
to this:
$_SESSION['answers'] = json_encode($survey_Answers);
Then in file2.php change:
$results = $_SESSION['answers'];
to this:
$results = json_decode($_SESSION['answers']);

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