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How do I use the json_encode() function with MySQL query results? Do I need to iterate through the rows or can I just apply it to the entire results object?
$sth = mysqli_query($conn, "SELECT ...");
$rows = array();
while($r = mysqli_fetch_assoc($sth)) {
$rows[] = $r;
}
print json_encode($rows);
The function json_encode needs PHP >= 5.2 and the php-json package - as mentioned here
NOTE: mysql is deprecated as of PHP 5.5.0, use mysqli extension instead http://php.net/manual/en/migration55.deprecated.php.
Try this, this will create your object properly
$result = mysql_query("SELECT ...");
$rows = array();
while($r = mysql_fetch_assoc($result)) {
$rows['object_name'][] = $r;
}
print json_encode($rows);
http://www.php.net/mysql_query says "mysql_query() returns a resource".
http://www.php.net/json_encode says it can encode any value "except a resource".
You need to iterate through and collect the database results in an array, then json_encode the array.
When using PDO
Use fetchAll() to fetch all rows as an associative array.
$stmt = $pdo->query('SELECT * FROM article');
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($rows);
When your SQL has parameters:
$stmt = $pdo->prepare('SELECT * FROM article WHERE id=?');
$stmt->execute([1]);
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($rows);
When you need to rekey the table you can use foreach loop and build the array manually.
$stmt = $pdo->prepare('SELECT * FROM article WHERE id=?');
$stmt->execute([1]);
$rows = [];
foreach ($stmt as $row) {
$rows[] = [
'newID' => $row['id'],
'Description' => $row['text'],
];
}
echo json_encode($rows);
When using mysqli
Use fetch_all() to fetch all rows as an associative array.
$res = $mysqli->query('SELECT * FROM article');
$rows = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($rows);
When your SQL has parameters you need to perform prepare/bind/execute/get_result.
$id = 1;
$stmt = $mysqli->prepare('SELECT * FROM article WHERE id=?');
$stmt->bind_param('s', $id); // binding by reference. Only use variables, not literals
$stmt->execute();
$res = $stmt->get_result(); // returns mysqli_result same as mysqli::query()
$rows = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($rows);
When you need to rekey the table you can use foreach loop and build the array manually.
$stmt = $mysqli->prepare('SELECT * FROM article WHERE id=?');
$stmt->bind_param('s', $id);
$stmt->execute();
$res = $stmt->get_result();
$rows = [];
foreach ($res as $row) {
$rows[] = [
'newID' => $row['id'],
'Description' => $row['text'],
];
}
echo json_encode($rows);
When using mysql_* API
Please, upgrade as soon as possible to a supported PHP version! Please take it seriously. If you need a solution using the old API, this is how it could be done:
$res = mysql_query("SELECT * FROM article");
$rows = [];
while ($row = mysql_fetch_assoc($res)) {
$rows[] = $row;
}
echo json_encode($rows);
if ($result->num_rows > 0) {
# code...
$arr = [];
$inc = 0;
while ($row = $result->fetch_assoc()) {
# code...
$jsonArrayObject = (array('lat' => $row["lat"], 'lon' => $row["lon"], 'addr' => $row["address"]));
$arr[$inc] = $jsonArrayObject;
$inc++;
}
$json_array = json_encode($arr);
echo $json_array;
} else {
echo "0 results";
}
The code below works fine here!
<?php
$con=mysqli_connect("localhost",$username,$password,databaseName);
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query = "the query here";
$result = mysqli_query($con,$query);
$rows = array();
while($r = mysqli_fetch_array($result)) {
$rows[] = $r;
}
echo json_encode($rows);
mysqli_close($con);
?>
The above will not work, in my experience, before you name the root-element
in the array to something, I have not been able to access anything in the
final json before that.
$sth = mysql_query("SELECT ...");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
$rows['root_name'] = $r;
}
print json_encode($rows);
That should do the trick!
<?php
define('HOST', 'localhost');
define('USER', 'root');
define('PASS', '');
define('DB', 'dishant');
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$con = mysqli_connect(HOST, USER, PASS, DB);
$sql = "select * from demo ";
$sth = mysqli_query($con, $sql);
$rows = array();
while ($r = mysqli_fetch_array($sth, MYSQLI_ASSOC)) {
$row_array['id'] = $r;
array_push($rows, $row_array);
}
echo json_encode($rows);
array_push($rows,$row_array); helps to build an array otherwise it gives the last value in the while loop.
This works like append method of StringBuilder in Java.
My simple fix to stop it putting speech marks around numeric values...
while($r = mysql_fetch_assoc($rs)){
while($elm=each($r))
{
if(is_numeric($r[$elm["key"]])){
$r[$elm["key"]]=intval($r[$elm["key"]]);
}
}
$rows[] = $r;
}
Sorry, this is extremely long after the question, but:
$sql = 'SELECT CONCAT("[", GROUP_CONCAT(CONCAT("{username:'",username,"'"), CONCAT(",email:'",email),"'}")), "]")
AS json
FROM users;'
$msl = mysql_query($sql)
print($msl["json"]);
Just basically:
"SELECT" Select the rows
"CONCAT" Returns the string that results from concatenating (joining) all the arguments
"GROUP_CONCAT" Returns a string with concatenated non-NULL value from a group
One more option using FOR loop:
$sth = mysql_query("SELECT ...");
for($rows = array(); $row = mysql_fetch_assoc($sth); $rows[] = $row);
print json_encode($rows);
The only disadvantage is that loop for is slower then e.g. while or especially foreach
For example
$result = mysql_query("SELECT * FROM userprofiles where NAME='TESTUSER' ");
1.) if $result is only one row.
$response = mysql_fetch_array($result);
echo json_encode($response);
2.) if $result is more than one row. You need to iterate the rows and save it to an array and return a json with array in it.
$rows = array();
if (mysql_num_rows($result) > 0) {
while($r = mysql_fetch_assoc($result)) {
$id = $r["USERID"]; //a column name (ex.ID) used to get a value of the single row at at time
$rows[$id] = $r; //save the fetched row and add it to the array.
}
}
echo json_encode($rows);
I solved like this
$stmt->bind_result($cde,$v_off,$em_nm,$q_id,$v_m);
$list=array();
$i=0;
while ($cresult=$stmt->fetch()){
$list[$i][0]=$cde;
$list[$i][1]=$v_off;
$list[$i][2]=$em_nm;
$list[$i][3]=$q_id;
$list[$i][4]=$v_m;
$i=$i+1;
}
echo json_encode($list);
This will be returned to ajax as result set
and by using json parse in javascript part like this :
obj = JSON.parse(dataX);
we could simplify Paolo Bergantino answer like this
$sth = mysql_query("SELECT ...");
print json_encode(mysql_fetch_assoc($sth));
We shouldn't see any use of mysql_ functions in modern applications, so either use mysqli_ or pdo functions.
Explicitly calling header("Content-type:application/json"); before outputting your data payload is considered to be best practice by some devs. This is usually not a requirement, but clarifies the format of the payload to whatever might be receiving it.
Assuming this is the only data being printed, it is safe to print the json string using exit() which will terminate the execution of the script as well. This, again, is not essential because echo will work just as well, but some devs consider it a good practice to explicitly terminate the script.
MySQLi single-row result set from query result set object:
exit(json_encode($result->fetch_assoc())); // 1-dimensional / flat
MySQLi multi-row result set from query result set object:
Prior to PHP 8.1.0, available only with mysqlnd.
exit(json_encode($result->fetch_all(MYSQLI_ASSOC))); // 2-dimensional / array of rows
MySQLi single-row result set from prepared statement:
$result = $stmt->get_result();
exit(json_encode($result->fetch_assoc())); // 1-dimensional / flat
MySQLi multi-row result set from prepared statement:
$result = $stmt->get_result();
exit(json_encode($result->fetch_all(MYSQLI_ASSOC))); // 2-dimensional / array of rows
PDO single-row result set from query result set object:
exit(json_encode($result->fetch(PDO::FETCH_ASSOC))); // 1-dimensional / flat
PDO multi-row result set from query result set object:
exit(json_encode($result->fetchAll(PDO::FETCH_ASSOC))); // 2-dimensional / array of rows
PDO single-row result set from prepared statement:
exit(json_encode($stmt->fetch(PDO::FETCH_ASSOC))); // 1-dimensional / flat
PDO multi-row result set from prepared statement:
exit(json_encode($stmt->fetchAll(PDO::FETCH_ASSOC))); // 2-dimensional / array of rows
Obey these rules to prevent the possibility of generating invalid json.:
you should only call json_encode() after you are completely finished manipulating your result array and
you should always use json_encode() to encode the payload (avoid the urge to manually craft a json string using other string functions or concatenation).
If you need to iterate your result set data to run php functions or provide functionality that your database language doesn't offer, then you can immediately iterate the result set object with foreach() and access values using array syntax -- e.g.
$response = [];
foreach ($result as $row) {
$row['col1'] = someFunction($row['id']);
$response[] = $row;
}
exit(json_encode($response));
If you are calling json_encode() on your data payload, then it won't make any difference to whether the payload is an array of arrays or an array of objects. The json string that is created will have identical syntax.
You do not need to explicitly close the database connection after you are finished with the connection. When your script terminates, the connection will be closed for you automatically.
Considering there's not really any NESTED json objects in mysql in general etc., it's fairly easy to make your own encoding function
First, the function to retrieve the mysqli results in an array:
function noom($rz) {
$ar = array();
if(mysqli_num_rows($rz) > 0) {
while($k = mysqli_fetch_assoc($rz)) {
foreach($k as $ki=>$v) {
$ar[$ki] = $v;
}
}
}
return $ar;
}
Now, function to encode array as json:
function json($ar) {
$str = "";
$str .= "{";
$id = 0;
foreach($ar as $a=>$b) {
$id++;
$str .= "\"".$a."\":";
if(!is_numeric($b)) {
$str .= "\"".$b."\"";
} else {
$str .= $b;
}
if($id < count($ar)) {
$str .= ",";
}
}
$str .= "}";
return $str;
}
Then to use it:
<?php
$o = new mysqli(
"localhost",
"root",""
);
if($o->connect_error) {
echo "DUDE what are you/!";
} else {
$rz = mysqli_query($o,
"SELECT * FROM mydatabase.mytable"
);
$ar = noom($rz);
echo json($ar);
}
?>
How do I use the json_encode() function with MySQL query results? Do I need to iterate through the rows or can I just apply it to the entire results object?
$sth = mysqli_query($conn, "SELECT ...");
$rows = array();
while($r = mysqli_fetch_assoc($sth)) {
$rows[] = $r;
}
print json_encode($rows);
The function json_encode needs PHP >= 5.2 and the php-json package - as mentioned here
NOTE: mysql is deprecated as of PHP 5.5.0, use mysqli extension instead http://php.net/manual/en/migration55.deprecated.php.
Try this, this will create your object properly
$result = mysql_query("SELECT ...");
$rows = array();
while($r = mysql_fetch_assoc($result)) {
$rows['object_name'][] = $r;
}
print json_encode($rows);
http://www.php.net/mysql_query says "mysql_query() returns a resource".
http://www.php.net/json_encode says it can encode any value "except a resource".
You need to iterate through and collect the database results in an array, then json_encode the array.
When using PDO
Use fetchAll() to fetch all rows as an associative array.
$stmt = $pdo->query('SELECT * FROM article');
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($rows);
When your SQL has parameters:
$stmt = $pdo->prepare('SELECT * FROM article WHERE id=?');
$stmt->execute([1]);
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($rows);
When you need to rekey the table you can use foreach loop and build the array manually.
$stmt = $pdo->prepare('SELECT * FROM article WHERE id=?');
$stmt->execute([1]);
$rows = [];
foreach ($stmt as $row) {
$rows[] = [
'newID' => $row['id'],
'Description' => $row['text'],
];
}
echo json_encode($rows);
When using mysqli
Use fetch_all() to fetch all rows as an associative array.
$res = $mysqli->query('SELECT * FROM article');
$rows = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($rows);
When your SQL has parameters you need to perform prepare/bind/execute/get_result.
$id = 1;
$stmt = $mysqli->prepare('SELECT * FROM article WHERE id=?');
$stmt->bind_param('s', $id); // binding by reference. Only use variables, not literals
$stmt->execute();
$res = $stmt->get_result(); // returns mysqli_result same as mysqli::query()
$rows = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($rows);
When you need to rekey the table you can use foreach loop and build the array manually.
$stmt = $mysqli->prepare('SELECT * FROM article WHERE id=?');
$stmt->bind_param('s', $id);
$stmt->execute();
$res = $stmt->get_result();
$rows = [];
foreach ($res as $row) {
$rows[] = [
'newID' => $row['id'],
'Description' => $row['text'],
];
}
echo json_encode($rows);
When using mysql_* API
Please, upgrade as soon as possible to a supported PHP version! Please take it seriously. If you need a solution using the old API, this is how it could be done:
$res = mysql_query("SELECT * FROM article");
$rows = [];
while ($row = mysql_fetch_assoc($res)) {
$rows[] = $row;
}
echo json_encode($rows);
if ($result->num_rows > 0) {
# code...
$arr = [];
$inc = 0;
while ($row = $result->fetch_assoc()) {
# code...
$jsonArrayObject = (array('lat' => $row["lat"], 'lon' => $row["lon"], 'addr' => $row["address"]));
$arr[$inc] = $jsonArrayObject;
$inc++;
}
$json_array = json_encode($arr);
echo $json_array;
} else {
echo "0 results";
}
The code below works fine here!
<?php
$con=mysqli_connect("localhost",$username,$password,databaseName);
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query = "the query here";
$result = mysqli_query($con,$query);
$rows = array();
while($r = mysqli_fetch_array($result)) {
$rows[] = $r;
}
echo json_encode($rows);
mysqli_close($con);
?>
The above will not work, in my experience, before you name the root-element
in the array to something, I have not been able to access anything in the
final json before that.
$sth = mysql_query("SELECT ...");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
$rows['root_name'] = $r;
}
print json_encode($rows);
That should do the trick!
<?php
define('HOST', 'localhost');
define('USER', 'root');
define('PASS', '');
define('DB', 'dishant');
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$con = mysqli_connect(HOST, USER, PASS, DB);
$sql = "select * from demo ";
$sth = mysqli_query($con, $sql);
$rows = array();
while ($r = mysqli_fetch_array($sth, MYSQLI_ASSOC)) {
$row_array['id'] = $r;
array_push($rows, $row_array);
}
echo json_encode($rows);
array_push($rows,$row_array); helps to build an array otherwise it gives the last value in the while loop.
This works like append method of StringBuilder in Java.
My simple fix to stop it putting speech marks around numeric values...
while($r = mysql_fetch_assoc($rs)){
while($elm=each($r))
{
if(is_numeric($r[$elm["key"]])){
$r[$elm["key"]]=intval($r[$elm["key"]]);
}
}
$rows[] = $r;
}
Sorry, this is extremely long after the question, but:
$sql = 'SELECT CONCAT("[", GROUP_CONCAT(CONCAT("{username:'",username,"'"), CONCAT(",email:'",email),"'}")), "]")
AS json
FROM users;'
$msl = mysql_query($sql)
print($msl["json"]);
Just basically:
"SELECT" Select the rows
"CONCAT" Returns the string that results from concatenating (joining) all the arguments
"GROUP_CONCAT" Returns a string with concatenated non-NULL value from a group
One more option using FOR loop:
$sth = mysql_query("SELECT ...");
for($rows = array(); $row = mysql_fetch_assoc($sth); $rows[] = $row);
print json_encode($rows);
The only disadvantage is that loop for is slower then e.g. while or especially foreach
For example
$result = mysql_query("SELECT * FROM userprofiles where NAME='TESTUSER' ");
1.) if $result is only one row.
$response = mysql_fetch_array($result);
echo json_encode($response);
2.) if $result is more than one row. You need to iterate the rows and save it to an array and return a json with array in it.
$rows = array();
if (mysql_num_rows($result) > 0) {
while($r = mysql_fetch_assoc($result)) {
$id = $r["USERID"]; //a column name (ex.ID) used to get a value of the single row at at time
$rows[$id] = $r; //save the fetched row and add it to the array.
}
}
echo json_encode($rows);
I solved like this
$stmt->bind_result($cde,$v_off,$em_nm,$q_id,$v_m);
$list=array();
$i=0;
while ($cresult=$stmt->fetch()){
$list[$i][0]=$cde;
$list[$i][1]=$v_off;
$list[$i][2]=$em_nm;
$list[$i][3]=$q_id;
$list[$i][4]=$v_m;
$i=$i+1;
}
echo json_encode($list);
This will be returned to ajax as result set
and by using json parse in javascript part like this :
obj = JSON.parse(dataX);
we could simplify Paolo Bergantino answer like this
$sth = mysql_query("SELECT ...");
print json_encode(mysql_fetch_assoc($sth));
We shouldn't see any use of mysql_ functions in modern applications, so either use mysqli_ or pdo functions.
Explicitly calling header("Content-type:application/json"); before outputting your data payload is considered to be best practice by some devs. This is usually not a requirement, but clarifies the format of the payload to whatever might be receiving it.
Assuming this is the only data being printed, it is safe to print the json string using exit() which will terminate the execution of the script as well. This, again, is not essential because echo will work just as well, but some devs consider it a good practice to explicitly terminate the script.
MySQLi single-row result set from query result set object:
exit(json_encode($result->fetch_assoc())); // 1-dimensional / flat
MySQLi multi-row result set from query result set object:
Prior to PHP 8.1.0, available only with mysqlnd.
exit(json_encode($result->fetch_all(MYSQLI_ASSOC))); // 2-dimensional / array of rows
MySQLi single-row result set from prepared statement:
$result = $stmt->get_result();
exit(json_encode($result->fetch_assoc())); // 1-dimensional / flat
MySQLi multi-row result set from prepared statement:
$result = $stmt->get_result();
exit(json_encode($result->fetch_all(MYSQLI_ASSOC))); // 2-dimensional / array of rows
PDO single-row result set from query result set object:
exit(json_encode($result->fetch(PDO::FETCH_ASSOC))); // 1-dimensional / flat
PDO multi-row result set from query result set object:
exit(json_encode($result->fetchAll(PDO::FETCH_ASSOC))); // 2-dimensional / array of rows
PDO single-row result set from prepared statement:
exit(json_encode($stmt->fetch(PDO::FETCH_ASSOC))); // 1-dimensional / flat
PDO multi-row result set from prepared statement:
exit(json_encode($stmt->fetchAll(PDO::FETCH_ASSOC))); // 2-dimensional / array of rows
Obey these rules to prevent the possibility of generating invalid json.:
you should only call json_encode() after you are completely finished manipulating your result array and
you should always use json_encode() to encode the payload (avoid the urge to manually craft a json string using other string functions or concatenation).
If you need to iterate your result set data to run php functions or provide functionality that your database language doesn't offer, then you can immediately iterate the result set object with foreach() and access values using array syntax -- e.g.
$response = [];
foreach ($result as $row) {
$row['col1'] = someFunction($row['id']);
$response[] = $row;
}
exit(json_encode($response));
If you are calling json_encode() on your data payload, then it won't make any difference to whether the payload is an array of arrays or an array of objects. The json string that is created will have identical syntax.
You do not need to explicitly close the database connection after you are finished with the connection. When your script terminates, the connection will be closed for you automatically.
Considering there's not really any NESTED json objects in mysql in general etc., it's fairly easy to make your own encoding function
First, the function to retrieve the mysqli results in an array:
function noom($rz) {
$ar = array();
if(mysqli_num_rows($rz) > 0) {
while($k = mysqli_fetch_assoc($rz)) {
foreach($k as $ki=>$v) {
$ar[$ki] = $v;
}
}
}
return $ar;
}
Now, function to encode array as json:
function json($ar) {
$str = "";
$str .= "{";
$id = 0;
foreach($ar as $a=>$b) {
$id++;
$str .= "\"".$a."\":";
if(!is_numeric($b)) {
$str .= "\"".$b."\"";
} else {
$str .= $b;
}
if($id < count($ar)) {
$str .= ",";
}
}
$str .= "}";
return $str;
}
Then to use it:
<?php
$o = new mysqli(
"localhost",
"root",""
);
if($o->connect_error) {
echo "DUDE what are you/!";
} else {
$rz = mysqli_query($o,
"SELECT * FROM mydatabase.mytable"
);
$ar = noom($rz);
echo json($ar);
}
?>
Data retrieve from the ms access database 2007 in php using odbc driver. ALL data retrieve using query but its get only one record retrieve other data is not retrieve.
below query three records but its retrieved only one data. which problem below code in php?how get all data using query from this code what's changes it?
<?PHP
include 'Connection2.php';
$sql = "select FYearID,Description,FromDate,ToDate from mstFinancialyear";
$stmt = odbc_exec($conn, $sql);
//print_r($stmt);
$rs = odbc_exec($conn, "SELECT Count(*) AS counter from mstFinancialyear");
//print_r($stmt);
$arr = odbc_fetch_array($rs);
$arr1 = $arr['counter'];
$result = array();
//print_r($arr);
if (!empty($stmt)) {
// check for empty result
if ($arr1 > 0) {
// print_r($stmt);
$stmt1 = odbc_fetch_array($stmt);
$year = array();
$year['FYearID'] = $stmt1['FYearID'];
$year['Description'] = $stmt1['Description'];
$year['FromDate'] = $stmt1['FromDate'];
$year['ToDate'] = $stmt1['ToDate'];
// success
$result["success"] = 1;
// user node
$result["year"] = array();
array_push($result["year"], $year);
echo json_encode($result);
//return true;
} else {
// no product found
$result["success"] = 0;
$result["message"] = "No product found";
echo json_encode($result);
}
odbc_close($conn); //Close the connnection first
}
?>
You return only a single record in the JSON data because you do not iterate through the recordset. Initially I misread that you had called odbc_fetch_array twice on the same recordset but upon closer inspection see that one query is imply used, as far as I can tell, to see if there are any records likely to be returned from the main query. The re-written code below has not been tested - I have no means to do so - and has a single query only but does attempt to iterate through the loop.
I included the count as a sub-query in the main query if for some reason the number of records was required somehow - I don't think that it is however.
<?php
include 'Connection2.php';
$result=array();
$sql = "select
( select count(*) from `mstFinancialyear` ) as `counter`,
`FYearID`,
`Description`,
`FromDate`,
`ToDate`
from
`mstFinancialyear`";
$stmt = odbc_exec( $conn, $sql );
$rows = odbc_num_rows( $conn );
/* odbc_num_rows() after a SELECT will return -1 with many drivers!! */
/* assume success as `odbc_num_rows` cannot be relied upon */
if( !empty( $stmt ) ) {
$result["success"] = $rows > 0 ? 1 : 0;
$result["year"] = array();
/* loop through the recordset, add new record to `$result` for each row/year */
while( $row=odbc_fetch_array( $stmt ) ){
$year = array();
$year['FYearID'] = $row['FYearID'];
$year['Description'] = $row['Description'];
$year['FromDate'] = $row['FromDate'];
$year['ToDate'] = $row['ToDate'];
$result["year"][] = $year;
}
odbc_close( $conn );
}
$json=json_encode( $result );
echo $json;
?>
I've searched and can't find an answer to my question.
I have the following code which is to loop through an array and then fetch back results for the different $id's.
The output when using echo json_encode($row); returns all results but the zend layout displays.
However when using $this->_helper->json($row,true); the layout doesn't display but only one result returns.
How can I return more than one result?
Any help would be much appreciated.
public function testAction()
{
//Get latest revision from database and loop through $id's
$id = array('308', '307', '306');
//Connect to database
foreach($id as $lId) {
$db = Zend_Db_Table::getDefaultAdapter();
$select = $db->select('')
->from('LinktagRevisions')
->where('linktagId = ?', $lId)
->order('updated DESC')
->limit(1);
$stmt = $select->query();
while ($row = $stmt->fetch()) {
$this->_helper->json($row,true);
//Encode as json and echo result
// echo json_encode($row);
}
}
}
I think you can try this:
$result = array();
foreach($id as $lId) {
....
$stmt = $select->query();
$result[$lId] = $stmt->fetchAll();
}
$this->_helper->json($result,true);
How do I use the json_encode() function with MySQL query results? Do I need to iterate through the rows or can I just apply it to the entire results object?
$sth = mysqli_query($conn, "SELECT ...");
$rows = array();
while($r = mysqli_fetch_assoc($sth)) {
$rows[] = $r;
}
print json_encode($rows);
The function json_encode needs PHP >= 5.2 and the php-json package - as mentioned here
NOTE: mysql is deprecated as of PHP 5.5.0, use mysqli extension instead http://php.net/manual/en/migration55.deprecated.php.
Try this, this will create your object properly
$result = mysql_query("SELECT ...");
$rows = array();
while($r = mysql_fetch_assoc($result)) {
$rows['object_name'][] = $r;
}
print json_encode($rows);
http://www.php.net/mysql_query says "mysql_query() returns a resource".
http://www.php.net/json_encode says it can encode any value "except a resource".
You need to iterate through and collect the database results in an array, then json_encode the array.
When using PDO
Use fetchAll() to fetch all rows as an associative array.
$stmt = $pdo->query('SELECT * FROM article');
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($rows);
When your SQL has parameters:
$stmt = $pdo->prepare('SELECT * FROM article WHERE id=?');
$stmt->execute([1]);
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($rows);
When you need to rekey the table you can use foreach loop and build the array manually.
$stmt = $pdo->prepare('SELECT * FROM article WHERE id=?');
$stmt->execute([1]);
$rows = [];
foreach ($stmt as $row) {
$rows[] = [
'newID' => $row['id'],
'Description' => $row['text'],
];
}
echo json_encode($rows);
When using mysqli
Use fetch_all() to fetch all rows as an associative array.
$res = $mysqli->query('SELECT * FROM article');
$rows = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($rows);
When your SQL has parameters you need to perform prepare/bind/execute/get_result.
$id = 1;
$stmt = $mysqli->prepare('SELECT * FROM article WHERE id=?');
$stmt->bind_param('s', $id); // binding by reference. Only use variables, not literals
$stmt->execute();
$res = $stmt->get_result(); // returns mysqli_result same as mysqli::query()
$rows = $res->fetch_all(MYSQLI_ASSOC);
echo json_encode($rows);
When you need to rekey the table you can use foreach loop and build the array manually.
$stmt = $mysqli->prepare('SELECT * FROM article WHERE id=?');
$stmt->bind_param('s', $id);
$stmt->execute();
$res = $stmt->get_result();
$rows = [];
foreach ($res as $row) {
$rows[] = [
'newID' => $row['id'],
'Description' => $row['text'],
];
}
echo json_encode($rows);
When using mysql_* API
Please, upgrade as soon as possible to a supported PHP version! Please take it seriously. If you need a solution using the old API, this is how it could be done:
$res = mysql_query("SELECT * FROM article");
$rows = [];
while ($row = mysql_fetch_assoc($res)) {
$rows[] = $row;
}
echo json_encode($rows);
if ($result->num_rows > 0) {
# code...
$arr = [];
$inc = 0;
while ($row = $result->fetch_assoc()) {
# code...
$jsonArrayObject = (array('lat' => $row["lat"], 'lon' => $row["lon"], 'addr' => $row["address"]));
$arr[$inc] = $jsonArrayObject;
$inc++;
}
$json_array = json_encode($arr);
echo $json_array;
} else {
echo "0 results";
}
The code below works fine here!
<?php
$con=mysqli_connect("localhost",$username,$password,databaseName);
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query = "the query here";
$result = mysqli_query($con,$query);
$rows = array();
while($r = mysqli_fetch_array($result)) {
$rows[] = $r;
}
echo json_encode($rows);
mysqli_close($con);
?>
The above will not work, in my experience, before you name the root-element
in the array to something, I have not been able to access anything in the
final json before that.
$sth = mysql_query("SELECT ...");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
$rows['root_name'] = $r;
}
print json_encode($rows);
That should do the trick!
<?php
define('HOST', 'localhost');
define('USER', 'root');
define('PASS', '');
define('DB', 'dishant');
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$con = mysqli_connect(HOST, USER, PASS, DB);
$sql = "select * from demo ";
$sth = mysqli_query($con, $sql);
$rows = array();
while ($r = mysqli_fetch_array($sth, MYSQLI_ASSOC)) {
$row_array['id'] = $r;
array_push($rows, $row_array);
}
echo json_encode($rows);
array_push($rows,$row_array); helps to build an array otherwise it gives the last value in the while loop.
This works like append method of StringBuilder in Java.
My simple fix to stop it putting speech marks around numeric values...
while($r = mysql_fetch_assoc($rs)){
while($elm=each($r))
{
if(is_numeric($r[$elm["key"]])){
$r[$elm["key"]]=intval($r[$elm["key"]]);
}
}
$rows[] = $r;
}
Sorry, this is extremely long after the question, but:
$sql = 'SELECT CONCAT("[", GROUP_CONCAT(CONCAT("{username:'",username,"'"), CONCAT(",email:'",email),"'}")), "]")
AS json
FROM users;'
$msl = mysql_query($sql)
print($msl["json"]);
Just basically:
"SELECT" Select the rows
"CONCAT" Returns the string that results from concatenating (joining) all the arguments
"GROUP_CONCAT" Returns a string with concatenated non-NULL value from a group
One more option using FOR loop:
$sth = mysql_query("SELECT ...");
for($rows = array(); $row = mysql_fetch_assoc($sth); $rows[] = $row);
print json_encode($rows);
The only disadvantage is that loop for is slower then e.g. while or especially foreach
For example
$result = mysql_query("SELECT * FROM userprofiles where NAME='TESTUSER' ");
1.) if $result is only one row.
$response = mysql_fetch_array($result);
echo json_encode($response);
2.) if $result is more than one row. You need to iterate the rows and save it to an array and return a json with array in it.
$rows = array();
if (mysql_num_rows($result) > 0) {
while($r = mysql_fetch_assoc($result)) {
$id = $r["USERID"]; //a column name (ex.ID) used to get a value of the single row at at time
$rows[$id] = $r; //save the fetched row and add it to the array.
}
}
echo json_encode($rows);
I solved like this
$stmt->bind_result($cde,$v_off,$em_nm,$q_id,$v_m);
$list=array();
$i=0;
while ($cresult=$stmt->fetch()){
$list[$i][0]=$cde;
$list[$i][1]=$v_off;
$list[$i][2]=$em_nm;
$list[$i][3]=$q_id;
$list[$i][4]=$v_m;
$i=$i+1;
}
echo json_encode($list);
This will be returned to ajax as result set
and by using json parse in javascript part like this :
obj = JSON.parse(dataX);
we could simplify Paolo Bergantino answer like this
$sth = mysql_query("SELECT ...");
print json_encode(mysql_fetch_assoc($sth));
We shouldn't see any use of mysql_ functions in modern applications, so either use mysqli_ or pdo functions.
Explicitly calling header("Content-type:application/json"); before outputting your data payload is considered to be best practice by some devs. This is usually not a requirement, but clarifies the format of the payload to whatever might be receiving it.
Assuming this is the only data being printed, it is safe to print the json string using exit() which will terminate the execution of the script as well. This, again, is not essential because echo will work just as well, but some devs consider it a good practice to explicitly terminate the script.
MySQLi single-row result set from query result set object:
exit(json_encode($result->fetch_assoc())); // 1-dimensional / flat
MySQLi multi-row result set from query result set object:
Prior to PHP 8.1.0, available only with mysqlnd.
exit(json_encode($result->fetch_all(MYSQLI_ASSOC))); // 2-dimensional / array of rows
MySQLi single-row result set from prepared statement:
$result = $stmt->get_result();
exit(json_encode($result->fetch_assoc())); // 1-dimensional / flat
MySQLi multi-row result set from prepared statement:
$result = $stmt->get_result();
exit(json_encode($result->fetch_all(MYSQLI_ASSOC))); // 2-dimensional / array of rows
PDO single-row result set from query result set object:
exit(json_encode($result->fetch(PDO::FETCH_ASSOC))); // 1-dimensional / flat
PDO multi-row result set from query result set object:
exit(json_encode($result->fetchAll(PDO::FETCH_ASSOC))); // 2-dimensional / array of rows
PDO single-row result set from prepared statement:
exit(json_encode($stmt->fetch(PDO::FETCH_ASSOC))); // 1-dimensional / flat
PDO multi-row result set from prepared statement:
exit(json_encode($stmt->fetchAll(PDO::FETCH_ASSOC))); // 2-dimensional / array of rows
Obey these rules to prevent the possibility of generating invalid json.:
you should only call json_encode() after you are completely finished manipulating your result array and
you should always use json_encode() to encode the payload (avoid the urge to manually craft a json string using other string functions or concatenation).
If you need to iterate your result set data to run php functions or provide functionality that your database language doesn't offer, then you can immediately iterate the result set object with foreach() and access values using array syntax -- e.g.
$response = [];
foreach ($result as $row) {
$row['col1'] = someFunction($row['id']);
$response[] = $row;
}
exit(json_encode($response));
If you are calling json_encode() on your data payload, then it won't make any difference to whether the payload is an array of arrays or an array of objects. The json string that is created will have identical syntax.
You do not need to explicitly close the database connection after you are finished with the connection. When your script terminates, the connection will be closed for you automatically.
Considering there's not really any NESTED json objects in mysql in general etc., it's fairly easy to make your own encoding function
First, the function to retrieve the mysqli results in an array:
function noom($rz) {
$ar = array();
if(mysqli_num_rows($rz) > 0) {
while($k = mysqli_fetch_assoc($rz)) {
foreach($k as $ki=>$v) {
$ar[$ki] = $v;
}
}
}
return $ar;
}
Now, function to encode array as json:
function json($ar) {
$str = "";
$str .= "{";
$id = 0;
foreach($ar as $a=>$b) {
$id++;
$str .= "\"".$a."\":";
if(!is_numeric($b)) {
$str .= "\"".$b."\"";
} else {
$str .= $b;
}
if($id < count($ar)) {
$str .= ",";
}
}
$str .= "}";
return $str;
}
Then to use it:
<?php
$o = new mysqli(
"localhost",
"root",""
);
if($o->connect_error) {
echo "DUDE what are you/!";
} else {
$rz = mysqli_query($o,
"SELECT * FROM mydatabase.mytable"
);
$ar = noom($rz);
echo json($ar);
}
?>