Joomla custom PHP, jQuery module - php

I have a cascade menu using PHP, jQuery and mysql. It works like a charm, but if I try to import it in Joomla as an article (with a Joomla extension wich activates PHP code in articles) it won't work correctly. The problem is, I don't even know where to find the source of the problem... I can select the category, but whenever I do, the second level of the cascade dropdown menu (category -> type -> model is the order) won't load, actually it says 'Please wait...', and after a few seconds the select option will be blank. I tested it on localhost, only the cascade menu not in Joomla framework and it worked...
I've got some files:
script.php -> handles the jQuery effects, also the dropdowns:
<script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.10.2.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("select#type").attr("disabled","disabled");
$("select#model").attr("disabled","disabled");
$("select#category").change(function(){
$("select#type").attr("disabled","disabled");
$("select#type").html("<option>Please wait...</option>");
var id = $("select#category option:selected").attr('value');
$.post("select_type.php", {id:id}, function(data){
$("select#type").removeAttr("disabled");
$("select#type").html(data);
});
});
$("select#type").change(function(){
$("select#model").attr("disabled","disabled");
$("select#model").html("<option>Please wait...</option>");
var id2 = $("select#type option:selected").attr('value');
$.post("select_model.php", {id2:id2}, function(data){
$("select#model").removeAttr("disabled");
$("select#model").html(data);
});
});
$("select#model").change(function(){
var cat = $("select#category option:selected").attr('value');
var type = $("select#type option:selected").attr('value');
var model = $("select#model option:selected").attr('value');
if(cat>0 && type>0 && model >0)
{
var model = $("select#model option:selected").html();
var type = $("select#type option:selected").html();
$("#result").html('<br>Your choice: ' + type + ' ' + model + '.');
}
else
{
$("#result").html("<br>One of the inputs is empty!");
}
return false;
});
});
</script>
<form id="select_form">
Choose category: <select id="category">
<?php echo $opt->ShowCategory(); ?>
</select><br />
Choose type: <select id="type">
<option value="0">Please select...</option>
</select>
<br />
Choose model: <select id="model">
<option value="0">Please select...</option>
</select></form>
<div id="result"></div>
<br><br>
select_type.php -> after user selects category, this should show the types in that category in the second menu.
<?php
include "class.php";
echo $opt->ShowType();
?>
select_model.php -> same as select type, but it's under the type selection, so this is the last level of the cascade menu.
<?php
include "class.php";
echo $opt->ShowModel();
?>
And finally, the class.php, which connects to the database where I fetch the datas from to load them in the select menus.
<?php
class SelectList
{
protected $conn;
public function __construct()
{
$this->DbConnect();
}
protected function DbConnect()
{
$host = "localhost";
$user = "root";
$password = "usbw";
$db = "test";
$this->conn = mysql_connect($host,$user,$password) OR die("error!");
mysql_select_db($db,$this->conn) OR die("error!");
return TRUE;
}
public function ShowCategory()
{
$sql = "SELECT * FROM categories";
$res = mysql_query($sql,$this->conn);
$category = '<option value="0">Please select a category...</option>';
while($row = mysql_fetch_array($res))
{
$category .= '<option value="' . $row['id_cat'] . '">' . $row['name'] . '</option>';
}
return $category;
}
public function ShowType()
{
$sql = mysql_query( "SELECT * FROM type WHERE id_cat=$_POST[id]");
$res = mysql_query($sql,$this->conn);
$type = '<option value="0">Please select a type...</option>';
while($row = mysql_fetch_array($sql))
{
$type .= '<option value="' . $row['id_type'] . '">' . $row['name'] . '</option>';
}
return $type;
}
public function ShowModel()
{
$sql = "SELECT * FROM model WHERE id_model=$_POST[id2]";
$res = mysql_query($sql,$this->conn);
$model = '<option value="0">Please select a model...</option>';
while($row = mysql_fetch_array($res))
{
$model .= '<option value="' . $row['id_model'] . '">' . $row['name'] . '</option>';
}
return $model;
}
}
$opt = new SelectList();
?>

A few points to go through:
don't use mysql_connect is this method of connecting to a database is deprecated, nor is it secure.
There is no need to manually connect to a database. You can use the JFactory::getDBO(); method. More information on that can be found here
I'm not sure how you're adding this custom code to your article, but I hope you realise that you should be usign a plugin such as Sourcerer
Rather than adding all this code into your article, I think it might be better off making a creating a custom module. By that I actually mean developing one and using you're code. It won't take too long. then you can embed the module into you article.
Rather than importing jQuery using the tags, please refer to my answer on the best method of importing it using Joomla coding standards here
If you haven't already looked at the Joomla Extensions Directory, I suggest you do so, as there are lots of menu modules that your could install and edit to your own liking.
Hope this helps

Related

Combine the results of several select boxes by using PHP and MySQL in WordPress

I have 4 dynamic dependent select boxes, now I want to combine the result of the 4 selects into a query. I have all the relative code below.
font-end part of the select boxes
<form class="select-boxes" action="<?php echo site_url("/part-search-result/"); ?>" method="POST" target="_blank">
<?php include(__DIR__.'/inc/part-search.php'); ?>
</form>
part-search.php
<?php
include( __DIR__.'/db-config.php' );
$query = $db->query("SELECT * FROM ps_manufact WHERE status = 1 ORDER BY manufact_name ASC");
$rowCount = $query->num_rows;
?>
<select name="manufacturer" id="manufact" onchange="manufactText(this)">
<option value="">Select Manufacturer</option>
<?php
if($rowCount > 0){
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['manufact_id'].'">'.$row['manufact_name'].'</option>';
}
}else{
echo '<option value="">Manufacturer Not Available</option>';
}
?>
</select>
<input id="manufacturer_text" type="hidden" name="manufacturer_text" value=""/>
<script type="text/javascript">
function manufactText(ddl) {
document.getElementById('manufacturer_text').value = ddl.options[ddl.selectedIndex].text;
}
</script>
<select name="type" id="type" onchange="typeText(this)">
<option value="">Select Manufacturer First</option>
</select>
<input id="type_text" type="hidden" name="type_text" value=""/>
<script type="text/javascript">
function typeText(ddl) {
document.getElementById('type_text').value = ddl.options[ddl.selectedIndex].text;
}
</script>
<select name="year" id="year" onchange="yearText(this)">
<option value="">Select Type First</option>
</select>
<input id="year_text" type="hidden" name="year_text" value=""/>
<script type="text/javascript">
function yearText(ddl) {
document.getElementById('year_text').value = ddl.options[ddl.selectedIndex].text;
}
</script>
<select name="model" id="model" onchange="modelText(this)">
<option value="">Select Year First</option>
</select>
<input id="model_text" type="hidden" name="model_text" value=""/>
<script type="text/javascript">
function modelText(ddl) {
document.getElementById('model_text').value = ddl.options[ddl.selectedIndex].text;
}
</script>
<input type="submit" name="search" id="search" value="Search">
<script type="text/javascript">
jQuery(function($) {
$('#manufact').on('change',function(){
var manufactID = $(this).val();
if(manufactID){
$.ajax({
type:'POST',
url:'<?php echo home_url('wp-content/themes/myTheme/inc/ajax-data.php') ?>',
data:'manufact_id='+manufactID,
success:function(html){
$('#type').html(html);
$('#year').html('<option value="">Select Type First</option>');
}
});
}else{
$('#type').html('<option value="">Select Manufact First</option>');
$('#year').html('<option value="">Select Type First</option>');
}
});
$('#type').on('change',function(){
var typeID = $(this).val();
if(typeID){
$.ajax({
type:'POST',
url:'<?php echo home_url('wp-content/themes/myTheme/inc/ajax-data.php') ?>',
data:'type_id='+typeID,
success:function(html){
$('#year').html(html);
$('#model').html('<option value="">Select Year First</option>');
}
});
}else{
$('#year').html('<option value="">Select Type First</option>');
$('#model').html('<option value="">Select Year First</option>');
}
});
$('#year').on('change',function(){
var yearID = $(this).val();
if(yearID){
$.ajax({
type:'POST',
url:'<?php echo home_url('wp-content/themes/myTheme/inc/ajax-data.php') ?>',
data:'year_id='+yearID,
success:function(html){
$('#model').html(html);
}
});
}else{
$('#model').html('<option value="">Select Year First</option>');
}
});
});
</script>
ajax-data.php
<?php
include( __DIR__.'/db-config.php' );
if(isset($_POST["manufact_id"]) && !empty($_POST["manufact_id"])){
$query = $db->query("SELECT * FROM ps_type WHERE manufact_id = ".$_POST['manufact_id']." AND status = 1 ORDER BY type_name ASC");
$rowCount = $query->num_rows;
if($rowCount > 0){
echo '<option value="">Select Type</option>';
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['type_id'].'">'.$row['type_name'].'</option>';
}
}else{
echo '<option value="">Type Not Available</option>';
}
}
if(isset($_POST["type_id"]) && !empty($_POST["type_id"])){
$query = $db->query("SELECT * FROM ps_year WHERE type_id = ".$_POST['type_id']." AND status = 1 ORDER BY year_name ASC");
$rowCount = $query->num_rows;
if($rowCount > 0){
echo '<option value="">Select Year</option>';
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['year_id'].'">'.$row['year_name'].'</option>';
}
}else{
echo '<option value="">Year Not Available</option>';
}
}
if(isset($_POST["year_id"]) && !empty($_POST["year_id"])){
$query = $db->query("SELECT * FROM ps_model WHERE year_id = ".$_POST['year_id']." AND status = 1 ORDER BY model_name ASC");
$rowCount = $query->num_rows;
if($rowCount > 0){
echo '<option value="">Select Model</option>';
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['model_id'].'">'.$row['model_name'].'</option>';
}
}else{
echo '<option value="">Model Not Available</option>';
}
}
?>
part-search-result.php
<?php
if (isset($_POST['search'])) {
$clauses = array();
if (isset($_POST['manufacturer_text']) && !empty($_POST['manufacturer_text'])) {
$clauses[] = "`manufacturer` = '{$_POST['manufacturer_text']}'";
}
if (isset($_POST['type_text']) && !empty($_POST['type_text'])) {
$clauses[] = "`type` = '{$_POST['type_text']}'";
}
if (isset($_POST['year_text']) && !empty($_POST['year_text'])) {
$clauses[] = "`year` = '{$_POST['year_text']}'";
}
if (isset($_POST['model_text']) && !empty($_POST['model_text'])) {
$clauses[] = "`model` = '{$_POST['model_text']}'";
}
$where = !empty( $clauses ) ? ' where '.implode(' and ',$clauses ) : '';
$sql = "SELECT * FROM `wp_products` ". $where;
$result = filterTable($sql);
} else {
$sql = "SELECT * FROM `wp_products` WHERE `manufacturer`=''";
$result = filterTable($sql);
}
function filterTable($sql) {
$con = mysqli_connect("localhost", "root", "root", "i2235990_wp2");
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
$filter_Result = mysqli_query($con, $sql);
return $filter_Result;
}
?>
<?php get_header(); ?>
<div class="container">
<div id="products" class="row list-group">
<?php while ( $rows = mysqli_fetch_array($result) ): ?>
<div class="item col-xs-12 col-sm-4 col-md-4 col-lg-4">
<div class="thumbnail">
<?php
echo '<img name="product-image" class="group list-group-image hvr-bob" src=' . $rows['image_url'] . ' width="400px" height="250px" alt="" />';
?>
<div class="caption">
<h4 class="group inner list-group-item-heading">
<?php
echo "Manufacturer:\t".$rows['manufacturer'].'<br>';
echo "Type:\t".$rows['type'].'<br>';
echo "Year:\t".$rows['year'].'<br>';
echo "Model:\t".$rows['model'].'<br>';
echo '<br>';
echo "Description:\t".$rows['description'].'<br>';
?>
</h4>
</div>
</div>
</div>
<?php endwhile; ?>
</div>
</div>
<?php get_footer(); ?>
Now my problem is:
If only select the first one box, or select the first two boxes, and click the Search button, it successfully jumps to the result page. However, if continuously select the third box, the result page is gone and Chrome Console returns the error:
Failed to load resource: the server responded with a status of 404 (Not Found)
Let me ask you a question. You've tagged this as a WordPress website. Correct? Then why aren't you using the built-in database handler, $wpdb to both prepare and communicate with the database? It's the safest and fastest way for you to work with the database.
Revised Code
Here I've revised your code to do the following:
Use $wpdb->prepare to sanitize the $_POST values to protect the database from nefarious folks
Remove redundancies by looping through a list of column names and using the field naming pattern you specified by suffixing _text to the column name
Using $wpdb->get_results() to go fetch the results.
Here is the revised code:
/**
* Build the search's WHERE SQL from the form's $_POST fields.
*
* #since 1.0.0
*
* #return string
*/
function build_search_where_sql() {
global $wpdb;
$column_names = array(
'manufacturer',
'type',
'year',
'model',
);
$where_clauses = [];
foreach( $column_names as $column_name ) {
$post_key = $column_name . '_text';
if ( isset( $_POST[ $post_key ] ) && $_POST[ $post_key ] ) {
$where_clauses[] = $wpdb->prepare( "{$column_name} = %s", $_POST[ $post_key ] );
}
}
if ( empty( $where_clauses ) ) {
return '';
}
$where_sql = " WHERE " . join( ' AND ', $where_clauses );
return $where_sql;
}
/**
* Get the search results from the database. If the records
* do not exist or an error occurs, false is returned. Else,
* an array with stdClass objects for each record is returned.
*
* #since 1.0.0
*
* #return bool|array
*/
function get_search_database_results() {
$where_sql = isset( $_POST['search'] )
? build_search_where_sql()
: "WHERE manufacturer = ''";
if ( ! $where_sql ) {
return false;
}
global $wpdb;
$sql_query = "SELECT * FROM wp_products {$where_sql};";
$records = $wpdb->get_results( $sql_query );
if ( ! $records ) {
return false;
}
return $records;
}
UPDATE: Strategy for You
Now that I've seen the HTML code you are proposing as well as knowing you are learning about building websites, let's talk about a different architectural strategy for your project.
Don't use a custom database table.
Use a custom post type called products instead.
Use post metadata to set the attributes for each product, i.e. the manufacturer, model, year, type, etc.
Use a form plugin, such as Ninja Forms.
You can build the meta boxes yourself for the metadata, if you have the technical chops to do it. Else, you can use a third-party plugin such as CMB2 or ACF.
Custom Post Type
WordPress provides you the ability to add custom content. They provide built-in post types. We developers can add custom ones that are specific content context. Products is a good candidate for a custom post type.
You can generate the code on GenerateWP. It's literally a few lines of code to create it.
Where can you learn about Custom Post Types?
Well, there are plenty of tutorials. Codex gives you the documentation and examples. I teach it at Know the Code. Tuts+ has lots of tutorials. And many others....
Why Custom Post Type Instead of Custom Db Table?
Yes, you can build a custom database table. But it requires you to add the schema, seed the table, write the interface for admins to interact with the content, and then write and secure the interaction. To populate the options in the select, you'd have to query the database using $wpdb and then write a model to translate it into a view. Then you'd have to write the form processing to interact and save.
In other words, it's going to cost you time and money. Why? Because it's more code and not native to WordPress. You have to write, secure, test, and maintain it yourself.
If You Want to Stick With Your Current Strategy
If you prefer to stick with the custom database table strategy, then here are some suggestions to help you out:
You don't need the hidden input for each of the select elements. Why? When the form is posted, the option set for each select will post back to the server.
I'd change the select names to be an array, like this: name="part-select[manufacturer]" and then repeat for type, model, year, etc. Then you can grab the $_POST['part-select'] to get all of the values.
You are going to want to add nonce to protect the content. Make sure to pass it with the data packet when doing AJAX too.
Using AJAX, you can request the records from the database. You'll need to modify the code I gave to you in order to build the SQL query. Then loop through the results to build the HTML you want to send back to the front-end.
I like building the HTML markup on the server side and then sending that back to the front-end when doing AJAX.
Cheers.

How to call PHP function in dropdown menu?

I want to call php function in dropdown menu by onchange event. I want with choose one of the options, the appropriate valuse are read from database and are list in another dropdown menu.
code:
<?php
function read() {
mysql_connect("localhost", "username", "password");
mysql_select_db("database_name");
$sql = mysql_query("SELECT name FROM table");
if (mysql_num_rows($sql)) {
$select = '<select name="select">';
while ($rs = mysql_fetch_array($sql)) {
$select.='<option value="' . '">' . $rs['name'] . '</option>';
}
}
$select.='</select>';
echo $select;
}
?>
<!--html code -->
<select onchange="document.write('<?php read(); ?>');">
<option value="0">a</option>
<option value="1">b</option>
<option value="2">c</option>
</select>
This code output:
My desired output:
How can I get My desired output ? Thanks
Just to explain:
PHP code is executed before the page is rendered in your user's browser (Server side).
In the other hand, Javascript is executed in the Client-side. It means that php finnished execution already.
If you wanna call a php function, you will have to make another request to the Server.
To do that "on the fly", you will have to use AJAX, as meantioned by #Jon in the comments.
Here is an example using jQuery (Just a javascript library, to simplify our task):
<script src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<script type="text/javasript">
//Listen to select 'onchange' event
$('select#your_select_id').change(function(){
//Read selected value
var inputValue = $(this).val();
//Make an ajax call
$.post('ajaxscript.php', { value: inputValue }, function(data){
//The return of 'read' function will be accessible trough 'data'
//You may create DOM elements here
alert('Finnished');
});
});
</script>
and here is our ajaxscript.php content:
<?php
//Declare (or include) our function here
//function read(){ ... }
$value = $_POST['value']; //Selected option
//...
echo read();
Hi You can also use javascript form submit in this and call a php function
<?php
function read() {
mysql_connect("localhost", "username", "password");
mysql_select_db("database_name");
$sql = mysql_query("SELECT name FROM table");
if (mysql_num_rows($sql)) {
$select = '<select name="select">';
while ($rs = mysql_fetch_array($sql)) {
$select.='<option value="' . '">' . $rs['name'] . '</option>';
}
}
$select.='</select>';
echo $select;
}
if (isset($_POST['value'])) {
read($_POST['value']);
}
?>
<form method="POST">
<select name="value" onchange="this.form.submit()">
<option value="0">a</option>
<option value="1">b</option>
<option value="2">c</option>
</select>
</form>

How do I get a VAR from jquery passed to a php query request

<script src="http://code.jquery.com/jquery-1.5.min.js"></script>
<script>
$(document).ready(function() {
var $article = null;
$('#category').change(function() {
var $categoryName = $('#category').val();
if ($article == null) {
$article = $('<h4>Select a business you wish to view.</h4><select id="business" name="business" class="business"><option value="0">Select A Business To View Listing</option></select>').appendTo('.query');
}
$("#business").load("php.php");
});
});
</script>
This is what I am currently doing, I am loading the php.php script, instead I want to pass the value of $categoryName to the WHERE clause in my query so it's like this:
<?php
$con = mysqli_connect(,,,,);
// Check connection
if (mysqli_connect_errno())
{
echo "<option>Failed to connect to MySQLi</option>" ;
}
$result = mysqli_query($con,"SELECT Bname, Category FROM Business WHERE Category='$categoryName'");
while($row = mysqli_fetch_array($result)) {
echo "<option value='".$row['Bname']."'>".$row['Bname']."</option>";
}
// Free result set
mysqli_free_result($result);
mysqli_close($con);
?>
The way this should work is, the first select box is populated by php on my server showing a list of categories. A user selects a category from that box and onchange, a second select box is created, added to the form, and will query, to populate all of the business name's listed in my database that share a category(i.e the selectedindex from the first box) Can you help me change this to work how I need it to?
UPDATE: This is the updated code, now the second select box never loads.
<script src="http://code.jquery.com/jquery-1.5.min.js"></script>
<script>
$(document).ready(function () {
var $article = null;
$('#category').change(function () {
var categoryName = $('#category').val();
if ($article == null) {
$article = $('<h4>Select a business you wish to view.</h4><select id="business" name="business" class="business"><option value="0">Select A Business To View Listing</option></select>').appendTo ('.query');
$("#business").load( "php.php",
data:{myVar:$categoryName}
);
}
});
});
</script>
Heres the php.php
<?php
$con = mysqli_connect(,,,,);
// Check connection
if (mysqli_connect_errno())
{
echo "<option>Failed to connect to MySQLi</option>" ;
}
$myVar = $_GET["myVar"];
$result = mysqli_query($con,"SELECT Bname, Category FROM Business WHERE Category='$myVar'");
while($row = mysqli_fetch_array($result)) {
echo "<option value='".$row['Bname']."'>".$row['Bname']."</option>";
}
// Free result set
mysqli_free_result($result);
mysqli_close($con);
?>
As seen below you can make a data object with one parameter myVar
JS:
$('#category').change(function() {
var $categoryName = $('#category').val();
if ($article == null) {
$article = $('<h4>Select a business you wish to view.</h4><select id="business" name="business" class="business"><option value="0">Select A Business To View Listing</option></select>').appendTo('.query');
}
$("#business").load("php.php",
data:{myVar:$categoryName}
);
});
Then get the variable in PHP like this
PHP:
$con = mysqli_connect(,,,,);
$myVar = $_GET["myVar"];
// Check connection
if (mysqli_connect_errno())
{
echo "<option>Failed to connect to MySQLi</option>" ;
}

Pass AJAX Variable to PHP and displaying MySQL results after selection from Dynamic Dropdown

I'm having a problem passing a variable selected from a dynamic drop dropdown to a PHP file. I want the PHP to select all rows in a db table that match the variable. Here's the code so far:
select.php
<html>
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("select#type").attr("disabled","disabled");
$("select#category").change(function(){
$("select#type").attr("disabled","disabled");
$("select#type").html("<option>wait...</option>"); var id = $("select#category option:selected").attr('value');
$.post("select_type.php", {id:id}, function(data){
$("select#type").removeAttr("disabled");
$("select#type").html(data);
});
});
$("form#select_form").submit(function(){
var cat = $("select#category option:selected").attr('value');
var type = $("select#type option:selected").attr('value');
if(cat>0 && type>0)
{
var result = $("select#type option:selected").html();
$("#result").html('your choice: '+result);
$.ajax({
type: 'POST',
url: 'display.php',
data: {'result': myval},
});
}
else
{
$("#result").html("you must choose two options!");
}
return false;
});
});
</script>
</head>
<body>
<?php include "select.class.php"; ?>
<form id="select_form">
Choose a category:<br />
<select id="category">
<?php echo $opt->ShowCategory(); ?>
</select>
<br /><br />
Choose a type:<br />
<select id="type">
<option value="0">choose...</option>
</select>
<br /><br />
<input type="submit" value="confirm" />
</form>
<div id="result"></div>
<?php include "display.php"; ?>
<div id="result2"></div>
</body>
</html>
select.class.php
<?php
class SelectList
{
protected $conn;
public function __construct()
{
$this->DbConnect();
}
protected function DbConnect()
{
include "db_config.php";
$this->conn = mysql_connect($host,$user,$password) OR die("Unable to connect to the database");
mysql_select_db($db,$this->conn) OR die("can not select the database $db");
return TRUE;
}
public function ShowCategory()
{
$sql = "SELECT * FROM profession";
$res = mysql_query($sql,$this->conn);
$category = '<option value="0">choose...</option>';
while($row = mysql_fetch_array($res))
{
$category .= '<option value="' . $row['id_cat'] . '">' . $row['prof_name'] . '</option>';
}
return $category;
}
public function ShowType()
{
$sql = "SELECT * FROM specialties WHERE id_cat=$_POST[id]";
$res = mysql_query($sql,$this->conn);
$type = '<option value="0">choose...</option>';
while($row = mysql_fetch_array($res))
{
$type .= '<option value="' . $row['id_type'] . '">' . $row['sp_name'] . '</option>';
}
return $type;
}
}
$opt = new SelectList();
?>
And here's the display.php that I want the variable passed to. This file will select the criteria from the db and then print the results in select.php.
<?php
class DisplayResults
{
protected $conn;
public function __construct()
{
$this->DbConnect();
}
protected function DbConnect()
{
include "db_config.php";
$this->conn = mysql_connect($host,$user,$password) OR die("Unable to connect to the database");
mysql_select_db($db,$this->conn) OR die("can not select the database $db");
return TRUE;
}
public function ShowResults()
{
$myval = $_POST['result'];
$sql = "SELECT * FROM specialities WHERE 'myval'=sp_name";
$res = mysql_query($sql,$this->conn);
echo "<table border='1'>";
echo "<tr><th>id</th><th>Code</th></tr>";
while($row = mysql_fetch_array($res))
{
while($row = mysql_fetch_array($result)){
echo "<tr><td>";
echo $row['sp_name'];
echo "</td><td>";
echo $row['sp_code'];
echo "</td></tr>";
}
echo "</table>";
//}
}
return $category;
}
}
$res = new DisplayResults();
?>
I'd really appreciate any help. Please let me know if I can provide more details.
Link to db diagram: http://imgur.com/YZ0SuVw
The first dropdown draws from the profession table, the second from the specialties table. What I'd like to do is to display all of the rows in the jobs table that match the specialty selected in the dropdown box. This will require the result from the variable (result) from the dropdown to be converted into the spec_code that is in the job table. Not sure exactly how to do this. Thanks!
I just want to outline some points about following block of code:
where did you defined myval
data: {'result': myval}: result not require any quota change it to data: {result: myval}
why you need to get HTML from selected options? it's better to send option values the change
$("select#type option:selected").html();
to
$("select#type option:selected").val();
if(cat>0 && type>0)
{
var result = $("select#type option:selected").html();
$("#result").html('your choice: '+result);
$.ajax({
type: 'POST',
url: 'display.php',
data: {'result': myval},
});
}

split output value via ajax,

Inside my page I have an input ("Model") with a datalist attribute and a select menu ("Brand"). When a user select one of the options of the datalist from the Model, it will dynamically change the options value from the Brand select menu. Both options value from Model and Brand are called from the database. This is what I code so far;
<input type="text" name="type" id="type" list="datalist1" onchange="fw();"/>
<datalist id="datalist1">
<?php
$query9 = "SELECT DISTINCT model FROM server ORDER BY model ASC";
$result9 = mysql_query($query9);
while($row9 = mysql_fetch_assoc($result9))
{
echo '<option value="'.$row9['model'].'">';
} ?>
</datalist>
<select name="brand" id="test2"><option value="">-- Select Brand--</option></select>
Script;
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
function fw()
{
var selname = $("#type").val();
$.ajax({ url: "getBrand.php",
data: {"brand":brand},
type: 'post',
success: function(output) {
document.getElementById('test2').options.length = 0;
document.getElementById('test2').options[0]=new Option(output,output);
// document.getElementById('test2').options[1]=new Option(output,output);
}
});
}
</script>
getBrand.php
<?php
define('DB_HOST1', 'localhost');
define('DB_NAME1', 'standby');
define('DB_USER1', 'root');
define('DB_PASS1', '');
$link = mysql_connect(DB_HOST1, DB_USER1, DB_PASS1);
if(!$link)
{
exit('Cannot connect to server "' . DB_HOST1 . '"');
}
mysql_select_db(DB_NAME1, $link) or die('Cannot use database "' . DB_NAME1 . '"');
if (isset($_POST['brand'])) {
$selname = $_POST['brand'];
$query = "SELECT * FROM server WHERE model='$brand'";
$res = mysql_query($query);
$aBrand= array();
while($rows = mysql_fetch_assoc($res)) {
$brand= $rows['brand'];
$aBrand[] = $brand;
echo $aBrand[0];
echo $aBrand[1];
}
} ?>
From what I have coded, I have succesfully change the select menu dynamically but there is one problem. When there is more one data is called from getBrand.php, the 'output' in the select menu will combine all of the data into one line. For example, if the data is "M3000" and "M4000", it will display as "M3000M4000". Now, how do I split it and make it as a normal select options?
I'm still learning Javascript and I hope anyone here can guide me.
NOTE : The code only works in Firefox because of the datalist attribute
Send your data from getBrand.php as
echo implode(";", $aBrand);
this will generate a string like M3000;M4000;M5000;M6000
and in your java script code break the string into array using this code.
StrArr = Str.split (";");
here 'Str' is your output given by getBrand.php, and 'StrArr' is the array which contains your brands.
add a special character in the string returned form php
PHP
elementcount=0;
while($row9 = mysql_fetch_assoc($result9))
{
if(elementcount>0)
echo '$<option value="'.$row9['model'].'">';//place a $ sign in start or you can for any special character
else
echo '<option value="'.$row9['model'].'">';
}
now in javascript
success: function(output) {
output = output.split("$");
document.getElementById('test2').options.length = 0;
//here now loop through the elements and add
for(var i=0,i<output.length-1)
document.getElementById('test2').options[0]=new Option(output[i],output[i]);
// document.getElementById('test2').options[1]=new Option(output,output);
}

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