Passing JavaScript variables to PHP as a hidden input - php

Question

I'm using CodeIgniter and in a single PHP file with JavaScript inside, I want to pass a JavaScript variable to the body (PHP) and make it a hidden input. But whenever I use the controller to post the value (where the JavaScript variable is), it returns none. Here are some parts of the code:
JS:
function pass() {
//some code
document.getElementById('yes').innerHTML = yes; //where yes is a var
}
HTML (PHP):
<form action="search">
<input type="hidden" name="yes" value="<?php $yes= "<p id='yes'> </p>"; echo $yes;?>" />
<input type="submit" name="yes" value="Done" />
</form>
So whenever I post the yes in the controller $yes = $this->input->post('yes'); it returns nothing.
How can I pass the JavaScript variable so I can use it again in the next file? Thank you!

Answer 1

You did'nt set the form method so it defaults to GET
You should set
<form action="search" method="POST">
try
JS :
var yes = "<?php echo $_POST['yes']; ?>";
document.getElementById('yes').innerHTML = yes;

Answer 2

You have to set the value property of the <input>, not the innerHTML. You also need to give the <input> a different name than other fields or the "submit" button. Finally, you have to give your <input> an "id" property so that you can actually get it with getElementById().

Answer 3

You should be setting the value of the hidden input, not the innerHTML. This code should work:
function pass() {
//some code
document.getElementById('yes').value = yes; //where yes is a var
}
Another problem, as noted by Pointy, is that the hidden input doesn't actually have an id, so you should give it an id (in this case the id should be yes).
Something you should also do is escape the html you are inserting into the hidden input with PHP, so it doesn't accidentally get parsed. You can do this with htmlspecialchars():
<form action="search">
<input type="hidden" id="yes" name="yes" value="<?php $yes= htmlspecialchars("<p id='yes'> </p>"); echo $yes;?>" />
<input type="submit" value="Done" />
</form>

Answer 4

Your submit button and your hidden field have the same name
yes .
You try to access your hidden input by id yes , and your input
does not have this id , use getElementByName('yes') instead or give
your hidden field id='yes'.
You use innerHtml which only sets or returns the inner HTML of an element,it should be value.
HTML CODE:
<form action="search">
<input id='yes' type="hidden" name="yes" value="<?php $yes= "<p id='yes'> </p>"; echo $yes;?>" />
<input type="submit" name="yess" value="Done" />
</form>
JS :
document.getElementById('yes').value = yes;//yes is a variable