How recuperate data from GET method with ajax/jquery - php

Question

Here is my function to get the data requested from a remote server. All is fine but one thing.
function get_users_request()
{
var result = [];
var idx=0;
$.get("getUsers_actions.php",
function(data) {
for (var key in data)
{
result[idx++]=data[key];
console.log(data[key].login);
}
},
"json");
return result;
}
The output is:
hissou
hbadri
user_1
But when i try to get get_users_request() result an empty array is given [].

Answer 1

Since it's an asynchronous call, you need to make use of a callback when you call the function:
function get_users_request(callback)
{
$.get("getUsers_actions.php", callback,"json");
}
get_user_request(function(data){
//var result = [];
//var idx=0;
//for (var key in data)
//{
// result[idx++]=data[key];
// console.log(data[key].login);
//}
$.each(data, function(k, v){
console.log(v.login);
});
});
To understand the code above, you could simulate an ajax call using a timeout:
var myAjaxResult;
setTimeout(function(){
myAjaxResult = 1; // try to update the value
}, 1000 /* simulates a 1 second ajax call */);
console.log(myAjaxResult); //undefined
Since console.log(myAjaxResult); isn't wrapped in a callback, it will be called immediately, and thus still be undefined.
If we would have waited for at least one second, the value would be set. But instead of presuming a time when the call is completed, we can make a callback function and know exactly when its done:
function myFunc(callback){
setTimeout(function(){
callback(1 /* returns the value 1 to the callback */);
}, 1000 /* simulates a 1 second ajax call */);
}
myFunc(function(callbackData){ //call the function using
//the callback we just specified
console.log(callbackData);
});
Hope this helps! Just let me know if anything is unclear.

Answer 2

This is what can give the result.
function get_users_request(s)
{
var s =new Array(), idx=0;
$.ajax({
url: "getUsers_actions.php",
success: function(data){
$.each(data, function(k, v){
s[idx++] = v.login;
console.log(v.login);
})
},
dataType: "json"
});
console.log(s);
}

Answer 3

You should put return result; after the for loop. The return should be done AFTER the $.get call is finished. Where is it now, the return is accessed right after the $.get call STARTS