How can I merge the dates on this ledger? - php

Question

I have tow tables for reciepts and expenture, am using union to merge them AND generate reports
SELECT MIN(date) AS trx, MAX(date), COUNT(*), SUM(amount), CONCAT(' - ','-'),
$f as _
FROM expenditure WHERE date >= '$start_date' AND date <= '$end_date'
AND client_id like '{$_SESSION['client']['id']}'
GROUP BY _
UNION
SELECT MIN(date) AS trx, MAX(date), COUNT(*),CONCAT(' - ','-'), SUM(amount),
$f as _
FROM receipts
WHERE date >= '$start_date' AND date <= '$end_date'
AND client_id like '{$_SESSION['client']['id']}'
GROUP BY _
ORDER BY trx
I get the following results
Array (
[0] => Array ( [trx] => 2012-03-06 [MAX(date)] => 2012-03-06 [COUNT(*)] => 1 [SUM(amount)] => 120000 [CONCAT(' - ','-')] => - - [_] => 2012-03-06 )
[1] => Array ( [trx] => 2012-03-08 [MAX(date)] => 2012-03-08 [COUNT(*)] => 1 [SUM(amount)] => 120000 [CONCAT(' - ','-')] => - - [_] => 2012-03-08 )
[2] => Array ( [trx] => 2012-06-06 [MAX(date)] => 2012-06-06 [COUNT(*)] => 2 [SUM(amount)] => 60000 [CONCAT(' - ','-')] => - - [_] => 2012-06-06 )
[3] => Array ( [trx] => 2012-06-06 [MAX(date)] => 2012-06-06 [COUNT(*)] => 1 [SUM(amount)] => - - [CONCAT(' - ','-')] => 487200 [_] => 2012-06-06 )
[4] => Array ( [trx] => 2012-06-08 [MAX(date)] => 2012-06-08 [COUNT(*)] => 1 [SUM(amount)] => 120000 [CONCAT(' - ','-')] => - - [_] => 2012-06-08 )
[5] => Array ( [trx] => 2012-06-29 [MAX(date)] => 2012-06-29 [COUNT(*)] => 2 [SUM(amount)] => 320000 [CONCAT(' - ','-')] => - - [_] => 2012-06-29 ) )
problem
If you notice on 3 and four there are two records for one day.
[trx] => 2012-06-06
Because on that day the client carried out both a credit and debit. is there way to just only combine rows like 3 and 4 into one row. SELECT DISTINCT dindnt work either or is it posible for mysql to sum records from both tables that occur on the same date.

Answer 1

You can use the subselect for your custom aliases to group
$query = "
SELECT q.*
FROM (
SELECT
MIN(date) AS trx,
MAX(date) as max_date,
COUNT(*),
SUM(amount),
CONCAT(' - ','-'),
$f as _
FROM
expenditure
WHERE
date >= '$start_date'
AND date <= '$end_date'
AND client_id like '{$_SESSION['client']['id']}'
GROUP BY _
UNION
SELECT
MIN(date) AS trx,
MAX(date),
COUNT(*),
CONCAT(' - ','-'),
SUM(amount),
$f as _
FROM
receipts
WHERE
date >= '$start_date'
AND date <= '$end_date'
AND client_id like '{$_SESSION['client']['id']}'
GROUP BY _ ORDER BY trx
) q GROUP BY q.max_date
";
Above query will group the results by MAX(date) as max_date
And for the sum of amount on same date you can modify as
$query = "
SELECT
q.*,
SUM(q.amount) AS grand_sum
FROM (
SELECT
MIN(date) AS trx,
MAX(date) as max_date,
COUNT(*),
SUM(amount) AS amount,
CONCAT(' - ','-'),
$f as _
FROM
expenditure
WHERE
date >= '$start_date'
AND date <= '$end_date'
AND client_id like '{$_SESSION['client']['id']}'
GROUP BY _
UNION
SELECT
MIN(date) AS trx,
MAX(date),
COUNT(*),
CONCAT(' - ','-'),
SUM(amount),
$f as _
FROM
receipts
WHERE
date >= '$start_date'
AND date <= '$end_date'
AND client_id like '{$_SESSION['client']['id']}'
GROUP BY _ ORDER BY trx
) q GROUP BY q.max_date
";
This grand_sum column has the sum of amount on the same date

Answer 2

You can UNION the expenditures and receipts tables first, then select from the unioned result. Note that the unioned result has separate columns for receipt.value and expenditure.value.
SELECT
MIN(date) as trx,
MAX(date),
COUNT(exp_amount) + COUNT(rct_amount) AS Tran_Count,
COALESCE(SUM(exp_amount), ' - -') AS Exp_Total,
COALESCE(SUM(rct_amount), ' - -') AS Rct_Total,
_
FROM (
SELECT whatever AS _, date, amount AS exp_amount, NULL AS rct_amount
FROM expenditure
WHERE date >= start AND date <= end AND client_id LIKE 'whatever'
UNION SELECT whatever, date, NULL, amount
FROM receipts
WHERE date >= start AND date <= end AND client_id LIKE 'whatever'
) exp_rct
GROUP BY _
ORDER BY trx