Cannot get ajax post to work - php

I am able to the js file to fire which does do the first alert but i cannot get the 2nd alert to happen, php file is there and working returning 0 but the alert('finished post'); is not coming up. I think its some syntax I am missing.
$(function () {
$("#login_form").submit(function () {
alert('started js');
//get the username and password
var username = $('#username').val();
var password = $('#password').val();
//use ajax to run the check
$.post("../php/checklogin.php", { username: username, password: password },
function (result) {
alert('finished post');
//if the result is not 1
if (result == 0) {
//Alert username and password are wrong
$('#login').html('Credentials wrong');
alert('got 0');
}
});
});
});
Here is the php
session_start();
include 'anonconnect.php';
// username and password sent from form
$myusername= $_POST['username'];
$mypassword= $_POST['password'];
$sql = $dbh->prepare("SELECT * FROM Users WHERE UserLogin= :login");
$sql->execute(array(':login' => $myusername));
$sql = $sql->fetch();
$admin = $sql['admin'];
$password_hash = $sql['UserPass'];
$salt = $sql['salt'];
/*** close the database connection ***/
$dbh = null;
if(crypt($mypassword, $salt) == $password_hash){
// Register $myusername, $mypassword and redirect to file
$_SESSION['myusername'] = $myusername;
$_SESSION['loggedin'];
$_SESSION['loggedin'] = 1;
if($admin == 1){
$_SESSION['admin'] = 1;
}
header("location:search.php");
}
else {
$_SESSION['loggedin'];
$_SESSION['loggedin'] = 0;
echo 0;
}

Ok so I'll take a stab at this, see if we can work this out. First, let's clean up your code a little bit - clean code is always easiest to debug:
$(function () {
$("#login_form").on('submit', function(){
console.log('form submitted');
// get the username and password
var login_info = { username: $('#username').val(), password: $('#password').val() }
// use ajax to run the check
$.ajax({
url: '../php/checklogin.php',
type: 'POST',
data: login_info,
success: loginHandler
error: function(xhr, status, err){ console.log(xhr, status, err); }
});
return false;
});
function loginHandler(loggedIn){
if (!loggedIn) {
console.log('login incorrect');
} else {
console.log('logged in');
}
}
});
...ok great, we're looking a little better now. Let's go over the changes made quickly.
First, swapped alerts for console.logs - much less annoying. Open up your console to check this out -- command + optn + J if you're using Chrome.
Second, we compressed the login info a bit - this is just aesthetics and makes our code a little cleaner. Really you should be using variables when they need to be used again, and in this case you only use them once.
Next, we swapped the $.post function for $.ajax. This gives us two things -- one is a little finer control over the request details, and the second is an error callback, which in this case is especially important since you almost certainly are getting a server error which is your original problem. Here are the docs for $.ajax for any further clarification.
We're also pointing the success handler to a function to minimize the nesting here. You can see the function declared down below, and it will receive the data returned by the server.
Finally we're returning false so that the page doesn't refresh.
Now, let's get to the issue. When you use this code, you should see a couple things in your console. The first will probably be a red message with something like 500 internal server error, and the second should be the results of the error callback for the ajax function. You can get even more details on this in Chrome specifically if you click over to the Network Tab and look through the details of the request and response.
I can't fix your PHP because you didn't post it, but I'll assume you'll either follow up with an edit or figure that out yourself. Once you have the server issue ironed out, you should get back a clean console.log with the response you sent back, and you can move ahead.
Alternately, this will work because of the lack of page refresh in which case you can ignore the previous 2 paragraphs and declare victory : )
Hope this helps!

Ah, so damned obvious. You aren't cancelling the default submit action so the form is submitting normally. Add this
$("#login_form").submit(function (e) {
e.preventDefault();
// and so on
See http://api.jquery.com/event.preventDefault/

you need to change 2nd line and add the e.preventDefault to prevent the form from refreshing the whole page.
$("#login_form").submit(function (e) {
e.preventDefault();
Also I would change the AJAX request to use GET and change the code in PHP to read variables from GET so you can easily test the PHP page is working by running it in the browser like this
checklogin.php?username=x&password=y

try this:
$("#login_form").submit(function () {
alert('started js');
//get the username and password
var username = $('#username').val();
var password = $('#password').val();
//use ajax to run the check
$.post("../php/checklogin.php", { username: username, password: password }, function (result) {
alert('finished post');
//if the result is not 1
if (result == '0') {
//Alert username and password are wrong
$('#login').html('Credentials wrong');
alert('got 0');
}
}, 'text');
});
}, 'text');
maybe the server does not give the right data format. for example, if you request for json, and the jQuery cannot convert result sting to json. then the function would not be executed and then you would not able to get 'alert('got 0');' thing.

Related

Jquery keyup Event with AJAX causing incorrect results

I have the following Jquery code that listens to a user typing in a captcha and sends an ajax request on each keyup to see if the correct code has been typed:
$('#joinCaptchaTextBox').keyup(function() {
$.get('scripts/ajax/script.php', {
'join_captcha': '1',
'captcha': $('#joinCaptchaTextBox').val()},
function(data) {
var obj = JSON.parse(data);
if(obj.ajaxResponse.status) {
$('#joinCaptchaNotAcceptable').hide();
$('#joinCaptchaAcceptable').show();
}else{
$('#joinCaptchaAcceptable').hide();
$('#joinCaptchaNotAcceptable').show();
}
});
});
The PHP script on the other end just checks the session and replies:
if($siteCaptcha == $_SESSION['secretword']) {
$this->captchaCompare = TRUE;
}else{
$this->captchaCompare = FALSE;
}
This works fine 95% of the time but I'm finding sometimes it reports the captcha typed is incorrect even though its correct. I think this could be because when typed fast many requests are sent to the server and the order or requests coming back isn't the order sent and therefore (as only one will be correct) a prior one is recieved last and incorrect is displayed.
Is there a better way to do this? Is there a way to ensure the last request sent is recieved last? Is there something I'm missing here. I can give more info.
thankyou
Add a timeout so as to not send a request on every keyup when the user types fast:
$('#joinCaptchaTextBox').on('keyup', function() {
clearTimeout( $(this).data('timer') );
$(this).data('timer',
setTimeout(function() {
var data = {
join_captcha: '1',
captcha : $('#joinCaptchaTextBox').val()
};
$.ajax({
url : 'scripts/ajax/script.php',
data: data,
dataType: 'json'
}).done(function(result) {
$('#joinCaptchaNotAcceptable').toggle(!result.ajaxResponse.status);
$('#joinCaptchaAcceptable').toggle(result.ajaxResponse.status);
});
},500)
);
});

How To Return Data from PHP to Use in jQuery(ajax)?

I have to process a Simple log-in File. In Many Web Tutorials I have read that for any Ajax requests in jquery the callback function is function(data) and the data is returned by the server side script.
Well, my server side script is PHP. I wish to know how can I return data from PHP which will be stored in jquery's data and I can use conditional loops to process them.
Here is my jquery Code:
$('#loginform').submit( function() {
var querystring = $(this).serialize();
$.post('login.php', querystring, processLI );
function processLI(data) {
if (data == 'success'){
alert("Successful");
var url = "game.php";
$(location).attr('href',url);
}
else
alert ('Login Failed');
}
I am using simple return statement in my php file, which does not seem to work at all. here is the login.php file. I just posted the part necessary here.
$statement = $connection->prepare("SELECT * FROM users WHERE username = '$username'");
$statement->execute(array());
$result = $statement->fetch(PDO::FETCH_ASSOC);
if ($result['password'] == $safepass) {
setcookie("Login", true);
echo 'success';
}
else
echo "Failure";
Try doing it like this, by placing the function as the parameter, and not by calling the function.
$('#loginform').submit( function() {
var querystring = $(this).serialize();
$.post('login.php', querystring, function(data){
if (data == 'success') {
alert("Successful");
var url = "game.php";
$(location).attr('href',url);
}
else
alert ('Login Failed');
});
Use the echo statement to output data, if the login is successful echo 'success';
This is an answer about how to debug AJAX requests. First, use Chrome (or Safari, or Firefox with Firebug plugin installed), then open up the developer tools from the settings menu. In the network panel, you can see the request/response. It may not be a direct answer, but please - try to use the Chrome developer tools with the "Net Panel" to see request/response/cookies/headers.
This will save you the trouble of having to guess, it will show you the response verbatim. Then you can solve it next time ;) and the time after
Have you been able to see the request/response? If not, I suggest a simple
alert(JSON.stringify(data))
...from your callback function if you have issues using the Chrome debugger.
Try giving the dataType for post as 'html'
$('#loginform').submit( function() {
var querystring = $(this).serialize();
$.ajax({
url : 'login.php?'+querystring,
cache : false,
success : function(data) {
if(data == "success") {
alert("Successful");
var url = "game.php";
$(location).attr('href',url);
} else if(data == "failure") {
alert("Login Failed");
}
};
});
});

Jquery AJAX PHP login

I have a login form using jquery ajax and a php code. The issue is that is always returns an error instead of logging me into the system. I have spent days trying to find the error but I can't. The webpage displays no errors if I visit it directly. This used to work about a week ago until I accidentally deleted the jquery and now I can't get it to work.
Here is the PHP code:
include('.conf.php');
$user = $_POST['user'];
$pass = $_POST['pass'];
$result = mysql_query("SELECT * FROM accountController WHERE username = '$user'");
while ($row = mysql_fetch_array($result)) {
if (sha1($user.$pass) == $row['pword']) {
setcookie('temp', $row['username']);
session_start();
$_SESSION['login'] = 1;
$_SESSION['uname'] = $row['username'];
echo "success";
}
}
and here is the Jquery AJAX code:
var username = $('#main_username').val();
var password = $('#main_pword').val();
$('.mainlogin').submit(function() {
$.ajax({
url: 'log.php',
type: 'POST',
data: {
user: username,
pass: password
},
success: function(response) {
if(response == 'success') {
window.location.reload();
} else {
$('.logerror').fadeIn(250);
}
}
});
return false;
});
How would I check to see what is being returned like blank or success from the server. Is there any extension for safari? Thanks!
Put this in, instead. It will alert the server's response in a popup.
success: function(response) {
alert(response);
}
On your PHP side, try outputting more stuff - add an }else{ to your if statement that returns some useful data, for example
}else{
print("Post is: \n");
print_r($_POST);
print("\nMySQL gave me: \n");
print_r($row);
}
Just make sure you don't leave it in once it's working!
Look for:
hash is different
db field is different
db fields are blank for some reason
POST data is wrong / wrong field names
Edit: Here's another issue: Your first four lines should actually be:
$('.mainlogin').submit(function() {
var username = $('#main_username').val();
var password = $('#main_pword').val();
$.ajax({
Your code as it is gets the values before the form is submitted - at load - when they are blank, and as a result is sending blank strings to the server as username and password.
Take a look at the code i have in this answer here: user check availability with jQuery
You need to json encode your response, also Firefox has Firebug you can use to view your ajax post and response, chrome and IE both have developer tools
Safari also has dev tools: http://developer.apple.com/technologies/safari/developer-tools.html
Check the console to see what is happening with your AJAX

returning php session to ajax

I am having trouble getting jQuery ajax to recognise a session. I am creating a php session from a login script, but what is happening is that when ajax loads the authenticated page, the session is always unset. For example, in the secure page, if I refresh the page, the session id changes each time. I have session_start(); in each page. Can someone please show me the correct way to handle sessions with ajax and php? I have spent 2 days and have used google so much, I will probably get an invite to there xmas lunch :-) I have included the relevant code and would be grateful for any help. Thanks
PS. If it makes any difference, I am trying to develop mobile app using jquery mobile.
login html js
$(function() {
$("#kt_login1").click(function() {
var user = $('#user').val();
var pass = $('#pass').val();
if (user == '') {
$("#login_message").html('This field cannot be empty')
$('label[for=user]').addClass("label")
return false;
}
else if (pass == '') {
$("#login_message").html('This field cannot be empty')
$('label[for=pass]').addClass("label")
return false;
}
else $('label[for=user]').removeClass("label");
$('label[for=pass]').removeClass("label");
//alert(user + pass + ok);
data = 'user=' + user + '&pass=' + pass;
$.ajax({
type: "POST",
url: "testajax.php",
cache: false,
data: data,
success: function(data) {
if (data == 'authenticated') {
//alert(user);
document.location = 'secure.php';
}
else $('#login_message').html('You are not authorised');
//$(ok).val('Logged In');
//$("#login").get(0).reset();
//$("#form").dialog('close');
},
error: function(xhr, ajaxOptions, thrownError) {
jAlert('There was an exception thrown somewhere');
alert(xhr.status);
alert(thrownError);
}
});
return false;
});
});
testajax.php
<?php
// test wether the user session is already set
$username = mysql_real_escape_string($_POST['user']);
$pass = mysql_real_escape_string(md5($_POST['pass']));
mysql_connect('localhost', 'root', '');
mysql_select_db('sample');
//now validating the username and password
$sql="SELECT * FROM user_usr WHERE username_usr='$username' and password_usr='$pass'";
$result=mysql_query($sql);
$row=mysql_fetch_array($result);
//if username exists
if(mysql_num_rows($result)>0) {
session_start();
$_SESSION['u_name']=$row['name_usr'];
/*
echo '<pre>';
print_r( $_SESSION['u_name'] );
print_r( $_REQUEST );
echo '</pre>';
exit;
*/
echo 'authenticated';
}
else
{
echo 'Unknown User';
}
?>
+++++SOLUTION+++++
Changed form input from submit to button and voila. All ok
you have to call session_start() each time working with a session (not only when creating it)
see: http://php.net/manual/en/function.session-start.php
There are a whole load of reasons this might be the case - but you're code is upside down! This may well be the cause (or a contributory factor).
You should not treat the existence of a session as evidence of authentication (the contents of the session is another thing altogether). Call session_start() at the top of your script - not conditionally, half-way through.
As to why your session data is not available...that's an FAQ here - have a look at some of the previous answers for potential causes / how to investigate.

How to use jQuery to set value on screen rather than use alert?

I am using the code that I will post below. I generates the password and works fine. Only problem is that it shows me the regenerated password in the alert box. I want to echo it on the screen. how can I do that. Thanks Using jQuery fancybox and php
$.ajax({
type: 'POST',
url: '/processPassword.php',
data: 'newPassword=' + password,
success: function(success) {
if(success == 1) {
alert('The password has been reset. to: ' + password);
location.href = 'mainpage.php';
} else {
alert('The password was not reset.');
}
}
});
});
function newPassword() {
var password = "";
some logic...
return password;
}
Try this. Replace the "alert" call with the jQuery line below to set the HTML of a div...
HTML
<div id="newPass"></div>
jQuery
//this assumes that "password" has already been setup.
$("#newPass").html(password);
I also would strongly advise you to consider having your PHP page generate the password and to use jQuery or something similar to request a PW to be built with server side code. Making the PW with client side code seems to be a huge security hole, almost like giving the blue prints of the prison to the prisoners...
This is something you could try
$.post {
"processPassword.php",
{ newPassword: 'password' },
function(data) {
alert('Your new password is+'+data) ;
});
In this the data is the value echoed by the page processPassword.php not return so you must echo your new password in the end of page or somewhere.

Categories