PHP pagination add ID - php

Question

I have a kind of problem, with following php code:
$host="localhost";
$user_name="";
$pwd="";
$database_name="";
$conexiune = mysql_connect($host,$user_name,$pwd) or die("Nu ma pot conecta la MySQL!");
mysql_select_db($database_name, $conexiune) or die("Nu gasesc baza de date");
if (isset($_GET["page"])) {
$page = $_GET["page"];
} else {
$page=1;
};
$start_from = ($page-1) * 1;
$sql = "SELECT * FROM citate ORDER BY id DESC LIMIT $start_from, 1";
$rs_result = mysql_query ($sql,$conexiune);
while ($row = mysql_fetch_assoc($rs_result))
echo "<img src='" . $row['poza'] . "' />
<br />
" . $row['titlu'] . "
<br />
" . $row['descriere'] . "
<br />
" . $row['data'] . "
";
$sql = "SELECT COUNT(id) FROM citate";
$rs_result = mysql_query($sql,$conexiune);
$row = mysql_fetch_row($rs_result);
$total_records = $row[0];
$total_pages = ceil($total_records / 1);
$pagelink ='<< ';
$pagelink_2='>> ';
if($page>1)
echo $pagelink;
if($page<2)
echo "";
for ($i=1; $i<=$total_pages; $i++) {
if ($i != $page)
echo "<a href='lista.php?page=".$i."'>".$i."</a> "; // xxxx = your page url address
if ($i==$page)
echo " <strong>". $i . "</strong> "; // defining class in the style sheet you can add colour or border to the displayed number
};
if($page<$total_pages)
echo $pagelink_2;
that code offer me pagination (u allready know that) , and the url bar adress look's like following:
http://www.site.ro/folder/lista.php?page=PAGE-NUMBER
i want to look like following:
http://www.site.ro/folder/lista.php?citat=SOME-NUMBERS&page=PAGE-NUMBER
my database table its populated like that:
--------------------------------------------------------------
| id | poza | titlu | descriere | citat | data | accesari |
--------------------------------------------------------------
i want to extract data from "citat" column , so link from url bar will look like:
http://www.site.ro/folder/lista.php?citat=EXTRACTED-FROM-CITAT&page=PAGE-NUMBER
every time when i press on next page buton, will look like:
http://www.site.ro/folder/lista.php?citat=2748925&page=1
http://www.site.ro/folder/lista.php?citat=2840194&page=2
etcetera..
how can i modify that code?
Thank in advance !

Answer 1

I am ignoring all your security issues.
This will work as long you display only one item per page:
$last_citat = 0;
while ($row = mysql_fetch_assoc($rs_result)) {
echo "<img src='" . $row['poza'] . "' /><br />" . $row['titlu'] . "<br />" . $row['descriere'] . " <br />" . $row['data'] . "";
$last_citat = $row['citat'];
}
and later:
$pagelink ='<< ';
$pagelink_2='>> ';
if($page>1) { echo $pagelink; }
if($page<2) { echo ""; }
for ($i=1; $i<=$total_pages; $i++) {
if ($i != $page) {
echo "<a href='lista.php?citat=".$last_citat."&page=".$i."'>".$i."</a> ";
}
if ($i==$page) {
echo " <strong>". $i . "</strong> ";
}
}

Answer 2

Do you want to filter database results by 'citat' value?
If so, then you have to build links with get parameter 'citat' in them, like:
<<
and later take GET['citat'] and add it in the sql query where part so that only results with certain citat value would be returned, like:
$sql = "SELECT * FROM citate WHERE citat = '".GET['citat']."' ORDER BY id DESC LIMIT $start_from, 1";
NOTE: This is not real example and it is WRONG TO USE LIKE WRITTEN: you must escape GET['citat'] because otherwise your database will be hacked very easily and very soon!

Answer 3

Get value of citat from while loop:
$citat = $row['citat'];
Then you can use $citat wherever and however you want, and to check the citat parameter in url you can do it by:
if (isset($_GET['citat'])) {
//it's there do something
} else {
//it's absent
}