I am trying to reset a session array in php with a function in jquery using a button. I would use a submit but I don't want the page to refresh. I tried to send a $.post request leaving the variables and return blank, and then sending a variable so I could use $_session[''] = array() but none of it worked. I have searched and can't find much about it just a lot on sending strings.
OK this is very simple to stop the page from refreshing you need to tell js to disable the default event i use jquery for this here is my code
Html & js
<html>
<head>
<title>Reseting a PHP $_SESSIO array with jquery function</title>
<script src="http://code.jquery.com/jquery-1.10.1.min.js"></script>
<script src="http://code.jquery.com/jquery-migrate-1.2.1.min.js"></script>
<script>
function sessRest(){
$.post("rest.php", {x: "9845621"}).done(function(data){
alert("States: " + data);
});
}
$(document).ready(function(){
$("#target").click(function(event){
event.preventDefault();
sessRest();
});
});
</script>
</head>
<body>
<div id="main">
Click to rest me
</div>
</body>
</html>
php code rest.php
<?php
session_start();
(string)$data = $_POST['x'];
if($data == "9845621"){
$_SESSION['gx'] = array();
return $_SESSION['gx']; //return the empty array to js
}else(
return "error";
)
?>
I hope this helps .
User below jquery to submit to php code
var requestData = { param: "value"};
$.ajax({
url: your_url/session_change.php,
type: "post",
dataType: "json" or what ever,
data: your_data,
success: function (data) {
}
});
You can end the session successfully on server side with an ajax call, but apart from reloading the page, you're not going to clear what information was loaded already on client side. The session information wont be there once you do reload, but there is no way around that.
You can, however, emulate what you want to do with javascript.
When you load your session information, echo it to the page as javascript variables, then you have full control on client side. Just beware of echoing sensitive information like passwords, obviously.
try this:
your html file should contain this jQuery file:
$('#button').click(function(e){
e.preventDefault();
jQuery.ajax({
url: 'http://yourwebsite.com/session.php'
}).done(function(data){
if(data=='reseted'){
//do anything...
}
else {
//do anything...
}
})
});
and in your session.php file:
<?php
session_start();
session_unset();
if($_SESSION == FALSE){
echo 'reseted';
}
else echo 'no';
?>
the answer was
jquery $.post('reset.php');
in reset.php
$_SESSION['products'] = array();
?>
this reset my session array when the reset button was clicked with no page refresh...
I had done this originally and forgot to include my core.php in the reset.php which contained my start session()..
Thank you all for the help though.... great suggestions
Related
I've had a look around and unfortunately the solutions I've found on the site don't appear to address my issue below.
Basically I'm doing a project where I need to effectively set up a diary - the user writes in a textarea element and this is passed via PHP to a database and stored for the user. In the lecturer's video, it appears he's doing without using a submit button (even if he's not, I think it'd be an interesting thing to learn how to do).
I'm having some issues though. Here's my PHP:
<?php
session_start();
if(array_key_exists("id", $_COOKIE)) {
$_SESSION['id'] = $_COOKIE['id'];
}
if(array_key_exists("id",$_SESSION)) {
echo "Logged in: <p><a href='secretDiaryFinal2.php?logout=1'>
Log out</a></p>";
} else {
header("Location: secretDiaryFinal2.php");
}
/* I'm putting in the database update later, for now I just wanted to check if I could
actually create the POST variable below*/
$msg = "";
if(array_key_exists('diaryEntry',$_POST)) {
$msg = $_POST['diaryEntry'];
} else {
$msg = "Some kind of PHP error";
}
?>
The relevant HTML:
<body>
<div id="testDiv">
<? echo $msg ?>
</div>
<div class="container" id="diaryArea">
<form method="post">
<textarea id="diary" value=""></textarea>
</form>
</div>
The relevant JQuery (I'm very weak on Ajax and I suspect there's a lot of issues here - also note the url I'm using is actually in the same script as the JQuery, I'm not certain if that works?) is below.
The basic idea is that every time the user types, the database should be updated (I realise this is a lot of calls to the server, I'll probably replace it with a timed command):
<script type="text/javascript">
$("#diary").keyup(function () {
var dataString = $("#diary").val();
$.ajax({
type: "POST",
url: "loggedInPageFinal.php",
data: ({diaryEntry:dataString}),
success: function(data) {
console.log(data);
}
});
return false;
});
</script>
Many thanks in advance and apologies for my poor code!
var DataString = $("#diary").val();
$.post( "loggedInPageFinal.php",{dataString:DataString }, function( data ) {
console.log(data);
});
Your ajax script actually does work.
But your php code isn't returning anything. put exit($msg); at the end of the code and see what happens.
i have a page in php to execute query. when i need the parameter from another page with session using jquery. so, how to set session in php from session in jquery. please check my code and give me solution. thanks...
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script src="https://code.ciphertrick.com/demo/jquerysession/js/jquerysession.js?d56ac9"></script>
<script>
$(document).ready(function(){
var sDecode = $.session.get("sesDecode");
alert(sDecode);
});
</script>
<?php
include('connection.php');
$content= ==> how to get " sDecode " ???
$upd = mysql_query("UPDATE t_modules set content='$content' where id_t_modules='3'") or die(mysql_error());
?>
You can use ajax to send parameter to a php file like this
$.ajax({
url: "connection.php",
data: "Session="+$.session.get("sesDecode"),
type: "POST",
dataType: 'json',
success: function (e) {
console.log(JSON.stringify(e));
},
error:function(e){
console.log(JSON.stringify(e));
}
});
Note that both solutions needs you to check the input since the user could potentially modify it.
Using Ajax
The best way to get sDecode is probably to send it via jQuery.post() (AJAX) to a PHP page that will register the session value (after doing the appropriate checks to it).
$.post('session.php', { d: sDecode }, function (response) {
alert(response);
});
and you get it in PHP via :
$sDecode = $_POST["d"]; // Please test the input here!
You might have to use .serialize() and then unserialize it in PHP depending on the content and how you treat it.
Using Redirection
You can simply redirect to a page and transmit it directly as a GET value:
window.location.href=”session.php?d="+sDecode;
Then on the session.php page you would read it using this code :
$sDecode = $_GET["d"]; // Please test the input here!
You can have PHP fill in the Javascript variable from the session variable.
<?php session_start(); ?>
<html>
...
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script>
$(document).ready(function() {
var sDecode = <?php echo json_encode($_SESSION['sDecode']); ?>;
alert(sDecode);
</script>
PHP execute before Jquery so use ajax after get the parameter from session to do your query
I have the message-block in the header of my site. When a user clicks "close msg", the message should disapear and can't be seen during current user session.
So I decided to use jQuery Ajax:
$('#lang-msg .close').on('click', function(event) {
event.preventDefault();
$.ajax({
url:"remlmsg.php",
type:"POST",
data:"id=2,myajaxquery=true ",
success:function(html){
console.log(html);
$('#lang-msg').fadeOut(300,function() {
$(this).remove();
})
}
})
})
And in remlmsg.php I have only code, which defines new session variable:
$_SESSION['langmsg'] = 'hide';
echo $_SESSION['langmsg'];
In the header.php file I check if $_SESSION['langmsg'] is undefined.
if (!isset($_SESSION['langmsg'])) {
if ($sLanguage == 'ru') {
echo '<script type="text/javascript">
$( function() {
showLangMessage("en");
})
</script>';
}
}
And it says always true! But when I print request data in ajax function it displays 'hide'.
Explain to me, please, where I did mistake.
P.S.
Tested on local server (latest WAMP)
You need to have session_start() declared first. Otherwise you'll only edit a local variable that isn't stored anywhere.
Actually the problem you're having is that ajax calls will have a different session id, which has to do with the headers sent/received by both sides.
Try generating some javascript with PHP like:
var phpSessionId='<?=session_id()?>';
then in your remlmsg.php add this to the very top:
if(isset($_POST['session-id'])) session_id($_POST['session-id']);
session_start();
Finally in your ajax call use:
data:"id=2,myajaxquery=true,session-id=" + phpSessionId,
That should solve your problem.
My question is that how to pass query string variables on same page without refreshing the page in php? My code is given below:
<img src="a.jpg">
<?php
$a = $_GET['id'];
$b = $_GET['pid'];
?>
Please help me to resolve this issue
<html>
<head>
<title>Test</title>
<meta name="" content="">
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#image_id").click(function(){
var dataString = 'a=10&b=20';
$.ajax({
type:'POST',
url:'foo.php',
data:dataString,
success:function(data) {
if(data=="Something") {
// Do Something
} else {
// Do Something
}
}
});
});
});
</script>
</head>
<body>
<img id="image_id" src="images/bg.jpg" />
</body>
</html>
Then in the 'foo.php' page do this
if(isset($_POST['a'])) {
// DO SOMETHING
}
Remember the things that you want to send to the 'data' of
success:function(data)
must be echoed out in the foo.php page
You can't.
PHP requires execution on the server and so you'd have to either use AJAX and update your page accordingly, or just refresh your page.
You can by sending an AJAX request to the server. Ajax is a way to send asynchronous request via Javascript. Notice that jQuery has a good library about it.
Use jquery to resolve this. By using the $.ajax in jquery you can do the stuff you need without page refresh.
I feel like this is something that I should have learned by now, and I'm sure it's something small I'm missing, but I could use clarification to make sure my approach is correct.
I'm using AJAX to post data to self which is a file that contains php and html. I can write the php fine, but after a successful ajax post, how do I only return the data that is processed via php and not the remaining html? Is it better to just post to a separate script?
If you have the PHP handling the POST request in the beginning of the file, you can just do something like this:
<?php
if (isset($_POST['somevar'])) {
/* do something */
exit(0);
}
?>
exit() will stop the loading of the page at that line.
I, for one, think it's better to be utilizing a separate script to deal with dynamic AJAX requests.
You can scrape changed parts of the resulting document and insert them into the original page. This way you can also make your page work for a user with JavaScript disabled not doing anything specially.
Example:
<html><title>Unobtrusive AJAX Example</title>
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js">
</script><script type="text/javascript">
$("form.ajax[id]").live('submit', function() {
$(this).find("input[type='submit']").attr("disabled", true);
$.ajax({
type: $(this).attr('method') || 'POST',
url: $(this).attr('action') || window.location.pathname,
data: $(this).serialize(),
context: $(this),
success: function(data) {
$(this).html(
$(data).find("#" + $(this).attr("id")).html()
);
}
});
return false;
});
</script>
</head><body>
<div><form method="post" class="ajax" id="main">
<p><?php echo date('H:i:s'); ?></p>
<p><input type="submit"></p>
</form></div>
<!-- keep the div: you got to have at least one div to make it work -->
</body></html>
It always depends on what are your needs, but if using the same script is enough for you then do it.
If you want the script not to send anything more than your answer to an XML HTTP Request, after sending the data, use an exit(); in PHP, which will make the script finish at that point.
Put to the of the script:
if($_POST['id']) {
$data = array('return'=>'returnValue');
$data = json_encode($data);
exit($data); }
Javascript:
$.ajax({
url: 'frmSelf.php',
data: $("#frmSelf").serialize(),
dataType: 'json',
type : 'post',
success : function(returnData) {
console.log(returnData);
}
});