the code below display the row 116 twice, it won't display row 118. Any idea how to solve this issue?
$data = mysql_query("SELECT * FROM item WHERE dcid IN('116','118')")
or die(mysql_error());
$info = mysql_fetch_array($data);
foreach ($info as $item) {
echo($item);
}
mysql_fetch_array only fetches a single row. Typically it is used in a while loop to cycle through all the results.
To continue your example above:
$data = mysql_query("SELECT * FROM item WHERE dcid IN('116','118')") or die(mysql_error());
while ($item = mysql_fetch_array($data)) {
echo($item)
}
your query must be as:
$data = mysql_query("SELECT * FROM item WHERE dcid IN('116','118')") or die(mysql_error());
while ($item = mysql_fetch_array($data)) {
echo $item['column_name1'];
} echo $item['column_name2'];
mysql_fetch_array returns a single row in an array like this that contains both an associative array and a regular numeric-keyed result set of your row.
0=> column,
column=>column
Thats why it returns twice in foreach.Use it like this
mysql_fetch_array($result, MYSQL_ASSOC);
Also, if dcid is your key and it's autoincrementing ( ID for rows ) you can also use LIMIT 116,118.
For more info: http://php.about.com/od/mysqlcommands/g/Limit_sql.htm
use group by as this
$data =mysql_query("SELECT * FROM item WHERE dcid IN('116','118') group by dcid")
or die(mysql_error());
Related
I'm taking data from mysql database table. The table have ID and "POST" columns. I've ordered posts by id's from bottom so i always have the newest post on the first place. But when i want to echo specific post (eg. with id 5) i can't echo it with $col = mysqli_fetch_array($result); echo $col;. I've tried with foreach loop but it echo's all posts. So I thought if i could put them into array with foreach loop it would do the job.
$sql = "SELECT * FROM `post` ORDER BY `id` DESC";
$result = mysqli_query($con, $sql);
$col = mysqli_fetch_array($result);
foreach($col as $cols) {
}
I've tried a lot of things and spent a lot of time on research but still don't have idea how to do it.
Thanks for your ideas and help.
$sql = "SELECT * FROM `post` ORDER BY `id` DESC";
$result = mysqli_query($con, $sql);
$col = mysqli_fetch_array($result);
foreach($col as $cols) {
if($col['id'] == 5) {
print_r($col);
}
}
mysqli_fetch_array fetchs a result row as an associative, a numeric array, or both.
You need to specify the name of the column you want to print out.
Because you may have more than one row in your result set, you should use a loop (while) like so:
while ($row = mysqli_fetch_array($result)) {
echo $row['POST']; // 'POST' here is the name of the column you want to print out
}
Hope this helps!
UPDATED:
If you want to get a specific post, you have to change your SQL to something like this:
$sql = "SELECT * FROM `post` WHERE `id` = $wanted_post_id";
This is my database:
This is the query:
SELECT * FROM users
Now when I do this:
$query = $connection->query($_GET['query']); // SELECT * FROM users
print_r($query->fetch_assoc());
I get this as output:
Array (
[id] => 3
[username] => karel )
Why does it not output id 4 and username ccscs?
When I a while loop:
while($row = $query->fetch_assoc()){
print_r($row);
}
This is happening because you don't give any order to your query so it automatically get first record. If you want to return last record you can order by id desc as follow
SELECT * FROM users ORDER BY id DESC
If you instead need to retrieve all records you will need to loop throw your records
while($row = $query->fetch_assoc())
{
print_r($row);
}
Based on new op info i would not fetch twice but one as follow
$fields = array();
while($row = $query->fetch_assoc())
{
print_r($row);
$fields[] = $row;
}
fetch_assoc() retrieves a single row from a result set. See here.
mysqli_result::fetch_assoc -- mysqli_fetch_assoc — Fetch a result row
as an associative array
You should use something like this :
while($row = $query->fetch_assoc()){
print_r($row);
}
That's because fetch_assoc() just fetches one row.
To get each row you can do it like this:
while($row = $query->fetch_assoc()){
print_r($row);
}
$query = "SELECT * FROM table WHERE data = '$userinput'";
$row = mysql_query($query);
while ($row = mysql_fetch_array($row))
{
echo $row['data'];
}
Ok So my questions are:
What exactly does mysql_fetch_array return?
AND if my WHERE clause finds multiple matches, shouldn't the loop execute numerous times?
I am running a program and I can only get the first result to print
You're overwriting $row. Instead use a different variable for the query result.
$query = "SELECT * FROM table WHERE data = '$userinput'";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result))
{
echo $row['data'];
}
Try using mysql_fetch_assoc($row)
You should not use the same variable as the index and the loop variable.
$row = mysql_query
while( $row = ...
Replace the first $row with $result
I have the following code that fetches a single row:
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1;";
$result = mysqli_query($query);
$row = mysqli_fetch_array($result);
I know this is useful in a while loop, where you can just loop through the results.
But I need to be able to grab specific rows that meet this condition. Something following this pseudo code:
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1;";
$result = mysqli_query($query);
$arrayofrows = mysqli_fetch_arrayofrows($result);
$arrayofrows[0] //(to get the first row)
$arrayofrows[1] //(2nd row)
and so on...
How can I do this?
You can try something like this
$arrayofrows = array();
while($row = mysqli_fetch_array($result))
{
$arrayofrows = $row;
}
You can now have
$arrayofrows[0] //(to get the first row)
$arrayofrows[1] //(2nd row)
I think the function you are looking for is mysqli_fetch_all as shown below. This avoids the need to create an extra looping structure or a function to do something already provided.
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1;";
$result = mysqli_query($query);
$arrayofrows = mysqli_fetch_all($result);
$arrayofrows[0] //(to get the first row)
$arrayofrows[1] //(2nd row)
It depends on whether you require the entire result set back or not but I think the LIMIT could be used like:
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1 LIMIT 200,200;";
Otherwise as others say you will need to convert to an array (which is what fetch_all does) and then get the element from that array.
I need all values from a table column put into an assoc array. I am having trouble finding the answer.
the table is only six rows deep.
example:
|--id--|--name--|--A--|--B--|--C--|
|--01--|--xl33--| 1.30| 2.45| 4.40|
i would like to get an assoc array for column B
name[xl33]=2.45
name[xl34]=....and so on
The trick is that the form will tell the script which column to fetch. A,B,C,D,E,F OR G
I know i could re-format the table and accomplish what i want but I need it structured the way i have it.( i have left out some columns for simplicity)
function return_column($letter){
$result = mysql_query("SELECT name, $letter FROM example") or die(mysql_error());
while($row = mysql_fetch_assoc( $result )) {
$return[$row['name']] = $row[$letter];
}
return $return;
}
$results = return_column('A');
print_r($results);
Something like :
$col = 'B';
$name = array();
$result = mysql_query("SELECT * FROM table") or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
$name[$row['name']] = $row[$col];
}
This creates an array $name and uses the name column as the key and the $col column for the value ...
You are looking for the mysql_fetch_assoc() function.
Example/
$query = $this->query($YOUR_QUERY);
$returnMap = array();
while ($row = mysql_fetch_assoc($query)) { array_push($returnMap, $row); }
Use mysql_fetch_assoc — Fetch a result row as an associative array.
while ($row = mysql_fetch_assoc($result)) {
$data[$row["column1"]]= $row["column2"];
..............
.........
}