A log I've built isn't getting correct numbers reported...
0.01% - 1,362 (incorrect %)
9.13% - 814 (correct)
0.66% - 59 (correct)
Here is my code...
$count2 = mysql_num_rows($result2);
$n = 100/$count2*number_format($value);
echo round($n,2).'%';
number_format is going to add commas and such and that will mess up round as it doesn't expect strings. Try using number_format after using round like this:
$count2 = mysql_num_rows($result2);
$n = 100/$count2*$value;
echo number_format(round($n,2)).'%';
'Number Format' is adding a comma in values over a thousand therefor multiplying by a string.
Removing number_format() from both lines corrected the problem.
Related
Is there any function that easily echos an integer that is 15+ digits long?
The only way I've managed is like this:
$num = 123456789012345;
$num = number_format($num);
$num = str_replace(',', '', $num);
echo $num;
But even this way it is only accurate up to 17 digits. After the 16th digit the number isn't printed accurately (because as a float it starts getting inaccurate - see here).
EDIT: From the answers below I wrote ini_set('precision',40); and then echoed $num straight. All this did was to, simply put, not show the decimal point in the float number. And again after the 16th digit it starts getting inaccurate.
I also tried the other suggestion of changing it into an array and then iterating through it with str_split($num); and again the numbers were inaccurate from the 17th digit on!
The simplest solution would be to convert the integer into a string. I've tried:
$num = (string)$num;
//and
$num = strval($num);
But neither change anything and they act as if as they remained as an int??
My question is specifically why are the conversions into strings not working. Is there a way to turn the number into a string? Thanks
The only solution I can think of is changing the precision of floats in the php.ini
ini_set('precision', 25);
I don't know where you get those large numbers from, but I'd suggest a look into bc functions too!
The last thing I thought of is using the explode function to split the string into an array and interate through it.
EDIT: When all suggestions failed, your only choices are to check out the BC Math and/or GMP functions as well as MoneyMath. The BigInteger package should also do the trick, which uses GMP and BC.
Well, you see, it's not an "int" as you claimed :)
echo PHP_INT_MAX; // echoes 9223372036854775807
$n = 9223372036854775807;
echo $n; // echoes 9223372036854775807
$n = 9223372036854775808;
echo $n; // echoes 9.2233720368548E+18
Setting precision to something greater, as manniL said, does the trick.
ini_set("precision", 50);
$n = 9223372036854775808;
echo $n; // echoes 9223372036854775808
I have been trying all morning but how would I this number 1304583496 to look like this
13.04583496
and the same goes for this number
456604223 to 4.56604223
There are always 8 numbers to the right.
Divide it with 100000000, or use "pow" function:
$number / pow(10, 8);
You could also use the official number_format method after division to keep your ending zeroes and have your number displayed in a nice manner.
<?php
$num = 1304583496; //the number
echo number_format($num/100000000,8,"."," "); //number of decimals = 8, comma seperator is . and thousands seperator is a space here
?>
For more information on this function: http://www.w3schools.com/php/func_string_number_format.asp
Hi i need to save a 010 number in $number and if i do like this php will remove the starting 0
$number = 010
And echo of this will return 10 how can i make it not to remove the initial 0
BR
Martin
Use it as a String:
$number = '010';
Use str_pad() function.
echo str_pad('10',3,'0',STR_PAD_LEFT)
http://php.net/manual/en/function.str-pad.php
Do remember that numbers starting with 0 can also be treated as octal number notation by the PHP compiler, hence if you want to work with decimal numbers, simply use:
$num = '010';
This way the number is saved, can be stored in the database and manipulated like any other number. (Thx to the fact that PHP is very loosely typed language.)
Another method to use would be:
Save number as $num = 10;
Later while printing the value you can use sprintf, like:
sprintf("%03d", $i);
This will print your number in 3 digit format, hence 0 will be added automatically.
Another method:
<?php
$num = 10;
$zerofill = 3;
echo str_pad($num, $zerofill, "0", STR_PAD_LEFT);
/* Returns the wanted result of '010' */
?>
You can have a look at the various options available to you and make a decision. Each of the method given above will give you a correct output.
I'll like to format 1000 to 10.00
The PHP number_format function does not seem to be working for this.
I have tried:
$amount2 = number_format("$cost",2,"",",");
echo "$cost";
Any ideas? Is there a way I can manupulate number_format to display the results (i.e just inserting a decimal before the last two digits?
Number format will change the "." to a "," but you telling it to format ONE THOUSAND.
$cost=1000;
echo number_format($cost,2,'.',',');
//1,000.00
What you want is simply:
$cost=1000;
echo number_format($cost/100,2,'.',',');
//10.00
Is this legit for you ?
<?php
$cost=1000;
echo substr($cost, 0, 2) . "." . substr($cost, 2);//10.00
1000 and 10.00 are totally different numbers (in values). Divide by 100, then format it properly:
$cost = 1000 ;
$cost /= 100 ;
$amount2 = number_format($cost,2,".","");
echo $amount2 ;
Try this code:
$stringA= 1000;
$length=strlen($stringA);
$temp1=substr($stringA,0,$length-2);
$temp2=substr($stringA,$length-2,$length);
echo $temp1.".".$temp2; // Displays 10.00
The third parameter to number_format should be the character you want to use as a decimal point. Why are you passing an empty string? And why are you placing your number ($cost) inside a string?
Try this: echo number_format($cost,2,'.',',');
EDIT: Perhaps I misunderstood your question — if you want the number 1000 to be displayed as 10.00, just divide $cost by 100 before calling number_format().
Say I have 1.234 I want to get the .234
I tried echo 1.234%1 //I get 0
I am rusty, what is the correct way?
(The tags says PHP as this might be an issue only with PHP, but I really am looking for the general solution).
php's % modulo operator converts its arguments to integers. To get a floating-point modulus, use fmod:
echo fmod(1.234, 1);
You can remove the whole number from the number itself. in php its:
$num = 1.234;
echo $num - floor($num);
Subtract the integer portion of $x ((int)$x) from $x:
$x = 1.234;
$d = $x - (int)$x;
// $d now equals 0.234
echo $d;
Example
Just substract integer part 1.234 - (int)1.234
Try this:
echo 1.234 - intval(1.234);