Get the Value First Before the Form Shows up PHP - php

I'd like to show up to 10 email fields to submit on the form but only by selecting options from 1 - 10.
<form action="" method="post" name="select">
<select name="row">
<option value=1">1</option>
...
<option value="10">10</option
<input type="submit" name="select">
</form>
The next form shows up depending on the selected form
<form name="secondform">
<?php ... ?> <!--for loop depending on the value above-->
<input name="email>
</form>

So you have your dropdown, submit that value to either self or another php script that contains this:
$selected = $_POST['select'];
for($i = 0; $i<$selected; $i++){
echo "<input type='text' name='email$i'>";
}
$selected is the value of the dropdown menu.
Now we have a for loop. It set's $i to zero then says while $i is less than the value of your drop down value, add 1 more to $i and run echo "<input type='text' name='email$i'>";
As you can see, I appended $i to to email so that each field has it's own unique name.
What you can do as well is do just as CP510 says and add onchange='this.form.submit()' to the select tag so it is submitted automatically and I would submit the form to the same page. This meaning set the action of the form of which the select menu is in to action="<?php echo $_SERVER['PHP_SELF']; ?>".
I would STRONGLY recommend learning jQuery for something like this.
Here's the jQuery (mostly just plain javascript) version of this... it's very similar:
Please make sure you put this in the head of your html file:
<script src="http://code.jquery.com/jquery-latest.min.js"
type="text/javascript"></script>
HTML:
<select id='selected' onchange='addFields();'>
<option value='1'>1</option>
<option value='2'>2</option>
<option value='3'>3</option>
<option value='4'>4</option>
<option value='5'>5</option>
<option value='6'>6</option>
<option value='7'>7</option>
<option value='8'>8</option>
<option value='9'>9</option>
</select>
Javascript:
function addFields(){
var selected = $('#selected').val();
for(var i = 0; i<selected; i++){
document.write('<input type="text" name="email' + i + '">');
}
}

Related

How to get 'select' value and put into 'input' value?

I have a for with a select dropdown option. I want to get the value that is selected and put it into a hidden input value. I'm trying this at the minute -
echo '<form method="post" action="cart_update.php">';
echo"<select name='qty'>
<option value=1>1</option>
<option value=2>2</option>
<option value=3>3</option>
<option value=4>4</option>
<option value=5>5</option>
<option value=6>6</option>
<option value=7>7</option>
<option value=8>8</option>
<option value=9>9</option>
<option value=10>10</option>
</select>";
echo '<input type="hidden" name="product_qty" value="'.$_GET['qty'].'" />';
echo"</form>;
When I submit this to cart-update.php it tells me that qty is an undefined index on the hidden input line.
Can anyone see the problem?
You will have to use javascript or jQuery. Some sample jQuery code:
$('select').change(function() {
var val1 = $('select').val();
$('your selector').val(val1);
});
Consider this instead:
$arr = array(1,2,3,4,5,6,7,8,9,10);
foreach($arr as $n){
$selected = $n == $_POST['qty'] ? 'selected' : '';
echo "<option value='$n' $selected>$n</option>";
}
Based on #Undefined_variable answer:
/***************************/
jQuery( document ).ready(function( $ ) {
/* selecy key from list , insert into field */
$('#select_start_key').change(function(){
var val1 = $('#select_start_key').val();
$('#start_key').val(val1);
/*reset the select to none*/
$('#select_start_key').val("");
});
});
View example :
https://jsfiddle.net/alinrzv/aj619Lbb/
A few problems:
1. Your form is in POST method, and you are trying to get the value in "Get" method ($_GET)
2. The value of $_GET will be available only after submitting the form.
You should use javascript to get the value. something like that:
<form method="post" action="cart_update.php">
<select name='qty' onChange='document.getElementById("product_qty").value = this.value'>
<option value=1>1</option>
<option value=2>2</option>
<option value=3>3</option>
<option value=4>4</option>
<option value=5>5</option>
<option value=6>6</option>
<option value=7>7</option>
<option value=8>8</option>
<option value=9>9</option>
<option value=10>10</option>
</select>
<input type="hidden" id="product_qty" name="product_qty" value="1" />

How to get the values from the drop down list using php?

<select name='car1'>
<option value='1'>Toyota</option>
<option value='2'>Honda</option>
<option value='3'>Ford</option>
</select>
<input type='submit' name='submitform' />
if(isset($_POST['submitform'])){
$Getvalue = $_POST['car1'];
echo $Getvalue;
}
How do I get the values (Toyota, Honda, and Ford) not the numbers
In POST you receive only submitted value, so you should use
<option value="Toyota">Toyota</option>
Use it.
<select name='car1'>
<option value='Toyota'>Toyota</option>
<option value='Honda'>Honda</option>
<option value='Ford'>Ford</option>
</select>
Alternatively, if you could, you could use jquery in this one. You need another container for that 'Name'. Consider this example:
<?php
if(isset($_POST['car1'])) {
$id = $_POST['car1'];
$name = $_POST['selected'];
echo $name;
}
?>
<form method="POST" action="">
<input type="hidden" name="selected" value="" />
<select name='car1'>
<option value='1'>Toyota</option>
<option value='2'>Honda</option>
<option value='3'>Ford</option>
</select>
</form>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('select[name="car1"]').change(function(){
// as you select your pick,
// this will append the name inside the hidden input
var selected = $(this).val();
var value = $('select[name="car1"] option[value="'+selected+'"]').text();
$(this).prev('input[name="selected"]').attr('value', value);
$('form').submit();
});
});
</script>
Sample Fiddle
Only option values will be send in $_POST. If you don't need values in numbers, replace them with text values.
<select name='car1'>
<option value='Toyota'>Toyota</option>
<option value='Honda'>Honda</option>
<option value='Ford'>Ford</option>
</select>
Web-browser send to web-server post line like "car1=1&submitform=". Php script does not known about what inside options. Change values to:
<select name='car1'>
<option value='Toyota'>Toyota</option>
<option value='Honda'>Honda</option>
<option value='Ford'>Ford</option>
</select>

Passing two variables from dropdownmenu in PHP

I want to reload my page (PHP) on changing value from the dropdownmenu and passing the value of selected item as a variable alongwith one another variable to the page. I have tried following -
<select name="application" onChange=Refresh(this.value,$query)" \>
<option>Any Application</option>
<option>ChIP</option>
<option>Enzyme Immunoassay</option>
<option>ELISA</option>
<option>Flow Cytometry</option>
<option>FACS</option>
</select>
The Refresh function is:
function Refresh(id,gene){
location.href="getnet.php?app=" + id + "&query=" + gene;
}
And i am receiving variables as:
$query = $_POST['gene'];
$app = $_POST['application'];
you must use form submit() method in onchange event of the dropdown and hidden field for second parameter, for example:
<form name="myForm" method="GET" action="<?php echo $_SERVER['PHP_SELF'];?>">
<select name="first" onChange="document.myForm.submit();">
<option value="1">Value 1
<option value="2">Value 2
<option value="3">Value 3
</select>
<input type="hidden" name="second" value="second parameter value"/>
</form>
On the server side you can get your variables in $_GET supperglobal array like:
$_GET['first'] - it's value from dropdown element and $_GET['second'] - second hidden param.
Try to write js function for dropdown onchange event. Below is sample code:
<script type="text/javascript">
function reload_url(val){
window.location.href = 'some_php_file.php?new_var='.val;
}
</script>
<select name="my_Sel" onchange="reload_url(this.value);">
<option value="1">1</option>
<option value="2">2</option>
</select>
What about trying a form submit onChange?
<form name="form" action="url" method="get">
<select name="application" onChange="this.form.submit();" >
<option>Any Application</option>
<option>ChIP</option>
<option>Enzyme Immunoassay</option>
<option>ELISA</option>
<option>Flow Cytometry</option>
<option>FACS</option>
</select>
<input type="hidden" name="gene" value="variable" />
</form>

Get selected value ajax

First Select
<Select id="drop1" onchange="drop1(this.value)">
<option value ='1'>1</option
<option value ='2'>2</option
<option value ='3'>3</option
</select>
<div id = "txtHint1"></div>
Once a value has been selected, the value will be sent to ajax. And corresponding dropdown will be generated on another page and show in div txthint1.
Second Select
<Select id="drop2" onchange="drop2(this.value)">
<option value ='111'>111</option
<option value ='222'>222</option
<option value ='333'>333</option
</select>
<div id = "txtHint2"></div>
As the generated dropdown is another php page, how can I get what the value the user has selected to show on my current page (div txthint2)?
I will be working in php.
$value = $_GET['a'];
There are no submitted button.
Send out the second request on a successful response:
function one() {
$.ajax({
...
success: function() {
two(TheValueFromOne);
}
});
}
function two() {
$.ajax({
...
});
}
What is happening is that once the request has been made successfully, then it is automatically starting the next request right after.
However, if you are jsut passing values around form one page to another you really do not need AJAX.
FOR EXAMPLE:
test1.php:
<form action="test2.php" method="get">
Book Title <br />
<input type="text" name="booktitle" /><br />
<input type="submit" name="submit" value=" - Update Database - " />
</form>
test2.php
<body>
<? echo $_GET["booktitle"]; ?>
</body>
IN YOUR CASE:
test1.php:
<Select id="drop1" name="test1">
<option value ='1'>1</option
<option value ='2'>2</option
<option value ='3'>3</option
</select>
test2.php
<Select id="drop1">
<option selected = "<? echo $_POST['test1']; ?>"></option>
<option value ='1'>1</option
<option value ='2'>2</option
<option value ='3'>3</option
</select>
#QUESTION:
<div id = "txtHint2"><? echo $_POST['test1']; ?></div>
#POSTING WITH FORM:
<form method="post" action="test2.php" >
<Select id="drop1" name="test1" onChange="this.parentNode.submit()">
<option value ='1'>1</option
<option value ='2'>2</option
<option value ='3'>3</option
</select>
</form>

dropdown return value in html and php

I have dropdown list (menu) and a button created with this code:
<form name="period" action="all.php" method="POST">
<div align="center">
<select name=period_dropdown>
<option value="nill"></option>
<option value="48">48</option>
<option value="72">72</option>
<option value="96">96</option>
<option value="120">120</option>
</select>
<input type="submit" value= "OK" >
</div></form>
When option of dropdown is selected, must be on button instead of OK and when button is pressed to be assigned to variable $period1. So, when I select 72, button must have 72 instead of OK and when I click button, variable $period1 to get value 72 (integer). Please, no javascript. Just html and php.
Thanks
You have to use javascript for what you are trying to do. If you want the button to change on the fly without submitting the form, you have to do client-side scripting (javascript).
Either:
Change the value of button after the dropdown is selected and form is submitted
Use two lines of javascript to change the value of the button when the select box is changed
In all.php:
if (isset($_POST['period_dropdown'])) {
$period1 = $_POST['period_dropdown'];
//do something with $period1
}
?>
<form name="period" action="all.php" method="POST">
<div align="center">
<select id="period_dropdown" name="period_dropdown" onchange="updateButton()">
<option value="nill"></option>
<option value="48">48</option>
<option value="72">72</option>
<option value="96">96</option>
<option value="120">120</option>
</select>
<input id="period_button" type="submit" value= "OK" >
</div></form>
<script type="text/javascript">
function updateButton() {
document.getElementById("period_button").value = document.getElementById("period_dropdown").value;
}
</script>

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