php multiple if else statement how to combine into one function? - php

Question

i got 7 if else statement, may I know how i can compile it into one function file? so I just trigger the function rather a long and messy code.
below are my codes:
<?php
$r1a = $_POST['rowone'];
if ($r1a<7) {
$r2a=$r1a+1;
} else {
$r2a=$r1a+1-7;
}
if ($r2a<7) {
$r3a=$r2a+1;
} else {
$r3a=$r2a+1-7;
}
if ($r3a<7) {
$r4a=$r3a+1;
} else {
$r4a=$r3a+1-7;
}
if ($r4a<7) {
$r5a=$r4a+1;
} else {
$r5a=$r4a+1-7;
}
if ($r5a<7) {
$r6a=$r5a+1;
} else {
$r6a=$r5a+1-7;
}
if ($r6a<7) {
$r7a=$r6a+1;
} else {
$r7a=$r6a+1-7;
}
?>
the second problem I have is adding all together, there are 7 vertical row that have 3 value and another 5 row that have 2 value to add. I found out my code over here if there is a total value of 12 it will show 0 because of my code -12. Is there anyone I wan alter the code if the value is 12, the result will +1-12?
Thanks!
<?php
$r4a = $r1a+$r2a+$r3a;
if ($r4a<12) {
$r4a=$r4a;
} else {
$r4a=$r4a-12;
}
$r4b = $r1b+$r2b+$r3b;
if ($r4b<12) {
$r4b=$r4b;
} else {
$r4b=$r4b-12;
}
$r4c = $r1c+$r2c+$r3c;
if ($r4c<12) {
$r4c=$r4c;
} else {
$r4c=$r4c-12;
}
$r4d = $r1d+$r2d+$r3d;
if ($r4d<12) {
$r4d=$r4d;
} else {
$r4d=$r4d-12;
}
$r4e = $r1e+$r2e+$r3e;
if ($r4e<12) {
$r4e=$r4e;
} else {
$r4e=$r4e-12;
}
$r4f = $r1f+$r2f+$r3f;
if ($r4f<12) {
$r4f=$r4f;
} else {
$r4f=$r4f-12;
}
$r4g = $r1g+$r2g+$r3g;
if ($r4g<12) {
$r4g=$r4g;
} else {
$r4g=$r4g-12;
}
$r4h = $r2h+$r3h;
if ($r4h<12) {
$r4h=$r4h;
} else {
$r4h=$r4h-12;
}
$r4i = $r2i+$r3i;
if ($r4i<12) {
$r4i=$r4i;
} else {
$r4i=$r4i-12;
}
$r4j = $r2j+$r3j;
if ($r4j<12) {
$r4j=$r4j;
} else {
$r4j=$r4j-12;
}
$r4k = $r2k+$r3k;
if ($r4k<12) {
$r4k=$r4k;
} else {
$r4k=$r4k-12;
}
$r4l = $r2l+$r3l;
if ($r4l<12) {
$r4l=$r4l;
} else {
$r4l=$r4l-12;
}
?>

Answer 1

I don't think you need the if's at all. Modulo operations should solve it for you.
function inc($a) {
return ($a % 7)+1;
}
$r1a = $_POST['rowone'];
$r2a = inc($r1a);
$r3a = inc($r2a);
$r4a = inc($r3a);
$r5a = inc($r4a);
$r6a = inc($r5a);
$r7a = inc($r6a);
Code hasn't been tested, but you get the general idea.
Another alternative:
$v = $_POST['rowone'];
$arr = array(1, 2, 3, 4, 5, 6, 7);
$b = array_slice($arr, 0, $v-1);
$arr = array_slice($arr, $v-1);
$arr = array_merge($arr, $b);
print_r($arr);
Answer to your second question where I have only made 0 into 1 and kept the rest as it were(To clearify, if the input to mod12 e.g $r1a+$r2a+$r3a is a multiple of 12 it will return 1, in other cases it will return a standard modulo 12 e.g 13 will become 1):
function mod12($a) {
$m = $a % 12;
if ($m == 0) {
return 1;
}else {
return $m;
}
}
$r4a = mod12($r1a+$r2a+$r3a);
$r4b = mod12($r1b+$r2b+$r3b);
$r4c = mod12($r1c+$r2c+$r3c);
$r4d = mod12($r1d+$r2d+$r3d);
$r4e = mod12($r1e+$r2e+$r3e);
$r4f = mod12($r1f+$r2f+$r3f);
$r4g = mod12($r1g+$r2g+$r3g);
$r4h = mod12($r2h+$r3h);
$r4i = mod12($r2i+$r3i);
$r4j = mod12($r2j+$r3j);
$r4k = mod12($r2k+$r3k);
$r4l = mod12($r2l+$r3l);

Answer 2

If I understood well what you try to achieve, this should work:
$r1a = $_POST['rowone'];
for ( $i = 1; $i < 7; $i++ ){
$cur = 'r'.$i.'a';
$next = 'r'.($i+1).'a';
$$next = $$cur < 7 ? $$cur+1 : $$cur+1-7
}