how to generate a serverside menu with 3 levels? - php

Question

I am trying to generate the bellow menu dynamically using php and mysql
<ul id="prod_nav" class="clearfix">
<!-- top --> <li class="active"><span class="down">Clothes</span>
<ul>
<h1> Men </h1>
<li>Shirt </li>
<li>T-shirt </li>
<li>Polo shirt </li>
<li>Formal shoes </li>
<li>Sport shoes </li>
<li>Suit </li>
<li>Underwear </li>
<li>Socks </li>
<li>Pants </li>
</ul>
<ul>
<h1> Women </h1>
<li>Shirt </li>
<li>T-shirt </li>
<li>Polo shirt </li>
<li>High heel shoes </li>
<li>Sport shoes </li>
<li>Wedding clothes </li>
<li>Underwear </li>
<li>Leather </li>
<li>Socks </li>
<li>Pants </li>
</ul>
</li>
</ul>
but I am not sure which way is the best principals for generating the menu?
should I use while loop and if or Case or for loop?
which way is the best way?
Thanks

Answer 1

You should have an array
$a=array('shirt','t-shirt','polo shirt','formal shoes','sport shoes','suit','underwear','socks','pants');
and use it like this:
<ul>
<h1>MEN</h1>
<?php foreach($a as $val) :?>
<li><?php echo $val; ?></li>
<?php endforeach ;?>
</ul>
<ul>
<h1>womaen</h1>
<?php foreach($a as $val) :?>
<li><?php echo $val; ?></li>
<?php endforeach ;?>
</ul>

Answer 2

$gender = array('men','women');
$productlist = array('shirt','t-shirt','polo shirt','formal shoes','sport shoes','suit','underwear','socks','pants');
foreach($gender as $individual) {
echo "<h2>{$individual}</h2>";
echo "<ul>";
foreach($productlist as $product) {
<li><?php echo $product; ?></li>
}
echo "</ul>";
}

Answer 3

can you please used this:
$gender = array('men','women');
$productlist = array('shirt'=>'shirt_url.php','t-shirt'=>'t-shirt_url.php','polo shirt'=>'polo_shirt.php');
foreach($gender as $individual) {
echo "<h2>{$individual}</h2>";
echo "<ul>";
foreach($productlist as $product_key=>$product_url) {
?>
<li><?php echo $product_key; ?></li>
<?php
}
echo "</ul>";
}