This question already has answers here:
if(!isset($_POST["user"]) ignored and returns Undefined Index
(4 answers)
Reference - What does this error mean in PHP?
(38 answers)
Closed 9 years ago.
Can someone please explain what does undefined error means on this link?
Whenever i visit my forum page it does gives me this error undefined index fpost.
fpost is the text area holder for the message. Obviously there is still no content in fpost when you initially visit the page, i don't know why it's propmting an error i already have if( isset($_POST['fpost']) && $_POST['fpost']!=='' ) condition to eliminate the error but it's not working...
I haven't even click the post button to begin with
Notice: Undefined index: fpost in ... on line 231
I don't understand the words people are using, can you please explain it in laymans term where beginners will understand. Thanks in advance.
Make sure that you have set name="fpost" for text area holder for the message.
If you didn't it will through undefined variable error.
Related
This question already has answers here:
What does the PHP error message "Notice: Use of undefined constant" mean?
(2 answers)
Closed 2 years ago.
I keep getting these messages on my custom post pages on my wordpress site....
Warning: Use of undefined constant php - assumed 'php' (this will throw an Error in a future version of PHP) in /home/customer/www/stayjam.show/public_html/wp-content/themes/flatsome-child/template-parts/portfolio/single-portfolio-sidebar-right.php on line 1
Here is my line 1 but I can't figure out what I need to do!
<?php#
get_template_part('template-parts/portfolio/portfolio-title', flatsome_option('portfolio_title'));
?>
I'm assuming the warning is given as undefined constant php due to the opening tag in your php file.
Try to ensure the file is enclosed with <?php ?> tags.
This question already has answers here:
What does the PHP error message "Notice: Use of undefined constant" mean?
(2 answers)
Closed 4 years ago.
Warning: Use of undefined constant id - assumed 'id' (this will throw an Error in a future version of PHP) in /home/conteud2/public_html/include/meta.php on line 114
variate code using {var2[id]} no solution
Code in on comment below
You can check the issue on page https://www.conteudoanimal.vet.br/racaseespecies/anfibios/ver.php?id=5
Server runs PHP7 at moment
Thanks in advance for any help !
So it basically means that id isn't a constant.
It either should be $id, or 'id', also the var2 should be $var2.
Try the following code:
"{$var2['id']}"
Or
"{$var2[$id]}"
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 5 years ago.
the following error is showing in the web page but the code is working..i just want to know why the following error is showing?
Notice: Use of undefined constant food - assumed 'food' in E:\server\htdocs\table\action.php on line 33
enter image description here
the following links are the code source.
https://drive.google.com/open?id=1u59Z0WipMgPEE10KP1c12maoUS-KqhlA
https://drive.google.com/open?id=1ngHyhwOdCbryj7UvZ_8tE2pIqp2uoSmE
Even without the code sample where it is happening I believe you are not using quotations ' or " in your array key names.
All you need is to wrap the key name into the quotations such as:
$your_array['food'];
// or
$your_array["food"];
For example on 10 line $dep = $_POST['dep']; I think you get text value. And on 33 line you have if-else operator if($dep==food){. You need to change your right value food to 'food'. Then you haven't get Notice messages. Because all text values must be in single or double quotes.
Your current syntax (with notice) is: comparing variable $dep with constant food.
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 9 years ago.
When I am using my code in wamp (old php 3.2 may be) there is no warning or note but when I run the same code it is giving me a warning or a note:
Notice: Undefined index: emailseaech in
C:\xampp\htdocs\employee\RecruitingProcess\manageuser\pages\defaultresume.php
on line 6
for this
$emailseaech = $_GET["emailseaech"];
I am using ajax http to read the date passing value.
$emailseaech = '';
if(!empty($_GET["emailseaech"]))
$emailseaech=$_GET["emailseaech"];
This question already has answers here:
What does the PHP error message "Notice: Use of undefined constant" mean?
(2 answers)
Closed 9 years ago.
Notice: Use of undefined constant username - assumed 'username' in
/home/content/04/7195304/html/header.php on line 54
I get this when writing things like $_COOKIE[username] or $_POST[username].
Edit
So I've been playing around with the code, putting quotes in my POST, COOKIE, and GET's.. I still get the same thing!
It means you likely forgot a $ in front of your variable name.
Edit
You need to encapsulate your call in qoutes. I.e.
$_COOKIE["username"]
or
$_POST["username"]
It probably means you forgot to put a $ in front of your username variable, so it's treating it like a constant instead of a variable.
You should post the code from that line for better help.
You might as well try $_COOKIE['username'] or $_POST['username'], to access the associative arrays with a string.
Sorry, overlooked comment with same advice.