SQL Error 1064 Not sure - php

Question

I am trying a new way of inserting data into a SQL. I am getting this error
insert into tracking_clients set / agreement_type = 'Purchase' , existing_client = 'Yes' ,
sales_rep = '1'
Array ( [agreement_type] => Purchase [existing_client] => Yes [sales_rep] => 1
You have an error in your SQL syntax; check the manual that corresponds to your MySQL
server version for the right syntax to use near '/ agreement_type = 'Purchase' ,
existing_client = 'Yes' , sales_rep = ' at line 2mysql err no : 1064
I use a form with action POST
In my submit page I use the following
//Drawn from Form Information used to Update Database
$sub1 = $_REQUEST['agreement_type'];
$sub2 = $_REQUEST['existing_client'];
$sub3 = $_REQUEST['sales_rep'];
update_lbs($sub1, $sub2, $sub3, $sub4,....); //Not full string posted here
function update_lbs($sub1, $sub2, $sub3, $sub4,.....)
{
global $host;
global $username;
global $password;
global $db_name;
//Insert if dates is required
date_default_timezone_set('Africa/Johannesburg'); //Global Time one for South Africa
$today = date("Y-m-d H:i:s");
$date = date("Y-m-d") ;
$time = date("H:i:s");
$insertSuccessful = false;
$new_msisdn = '0' . substr($msisdn, 2); //Not Sure If this is required in normal SET command
if ($con = mysql_connect($host, $username, $password)) {
if (mysql_select_db($db_name))
//First Database Insert change table name as required
$sql = "insert into tracking_clients set
agreement_type = '".$sub1."' ,
existing_client = '".$sub2."' ,
sales_rep = '".$sub3."',
sub_date = '".$date."'" //Last of the code for SET
;
if (mysql_query($sql, $con)) {
$insertSuccessful = true;
} else {
echo $sql;
print_r($_POST);
echo "\n" . mysql_error($con);
echo "mysql err no : " . mysql_errno($con);
}
I am not sure what would be causing this error at all. I know this question is a common one but reading thru the other awnsers I am not getting the error

Answer 1

you have a tab characters beetween "set" and "agreement_type"

Answer 2

I am assuming you are using mysql here. The insert statement doesn't use set it simply inserts the values.
Something like this:
insert into yourTable (val1, val2, val3)
or
insert into yourTable (col1, col2, col3) values (val1, val2, val3)
not
insert into yourTable set col1=val1 etc...