Ajax post in oscommerce - php

Question

I'm trying to update my database on the event of a change in my select box. The php file I'm calling on to process everything, works perfectly. Heres the code for that:
<?php
$productid = $_GET['pID'];
$dropshippingname = $_GET['drop-shipping'];
$dbh = mysql_connect ("sql.website.com", "osc", "oscpassword") or die ('I cannot connect to the database because: ' . mysql_error()); mysql_select_db ("oscommerce");
$dropshippingid = $_GET['drop-shipping'];
$sqladd = "UPDATE products SET drop_ship_id=" . $dropshippingid . "
WHERE products_id='" . $productid . "'";
$runquery = mysql_query( $sqladd, $dbh );
if(!$runquery) {
echo "Error";
} else {
echo "Success";
}
?>
All I have to do is define the two variables in the url, and my id entry will be updated under the products table, ex: www.website.com/dropship_process.php?pID=755&drop-shipping=16
Here is the jquery function that is calling dropship-process.php:
$.urlParam = function(name){
var results = new RegExp('[\\?&]' + name + '=([^&#]*)').exec(window.location.href);
return results[1] || 0;
}
$('#drop_shipping').change(function() {
var pid = $.urlParam('pID');
var dropshippingid = $(this).val();
$.ajax({
type: "POST",
url: "dropship_process.php",
data: '{' +
"'pID':" + pid + ','
"'drop-shipping':" dropshippingid + ',' +
'}',
success: function() {
alert("success");
});
}
});
});
I'm thinking that I defined my data wrong some how. This is the first time I've ever used anything other than serialize, so any pointer would be appreciated!

Answer 1

Would it not be enough to define your URl like so:
url: "dropship_process.php?pID="+ pid +"&drop-shipping="+ dropshippingid

Answer 2

Your ajax code is not correct. replace your ajax code by below code:
$.ajax({
type: "POST",
url: "dropship_process.php",
dataType: 'text',
data: {"pID": pid,'drop-shipping': dropshippingid},
success: function(returnData) {
alert("success");
}
});