I have code for a search function here:
<?php
include("config.php");
$search = mysql_real_escape_string($_POST['search']);
if (!empty($_POST['search'])) {
$data = mysql_query("SELECT * FROM shop WHERE name LIKE '%$search%' OR shout LIKE '%$search%' ORDER BY id DESC ") or die(mysql_error());
while ($info = mysql_fetch_array($data)) {
$name = stripslashes($info['name']);
$shout = stripslashes($info['shout']);
//Result code goes here eventually
}
}
?>
and I'll eventually make it display all results in a grid.
My problem starts when a user clicks on an item to see a page devoted to just that item (like any retail store site).
I'm assuming in my search code I can use $_SESSION and just set all the columns to sessions and then echo them on my results.php page.
Is this an efficient way to do this or am I going about it wrong?
I see websites that when you click on a certain item the URL looks all crazy and what not and I'm not really sure what causes that.
You can use
header('Location: /search/'.rawurlencode($search));
exit;
and now you can get your search string by
$search = rawurldecode($_GET['your_name']);
and your first page will not differ from the others. Or you can use method="get" in your search form. Anyway, you can use session to store your search string.
Related
I have a webpage which uses php to pull through data from a MySQL database. The database stores my writing portfolio organised by columns date, url, category, title, publication, description. It pulls through the title and publication and uses the url to turn it into a hyperlink (see code below). So far, so good.
Where I'm stuck: Sometimes there's no url for something I've published (e.g. for a few of the 'Content & Copywriting' items on my site), but it still turns my title and publication into a link: a link to "_blank". When there is a NULL url, I need it to not turn my title into a link at all.
So, I think I need to insert some sort of logic so that if url=NULL, then it doesn't make the text into a link, instead of creating a link to "_blank". But this is completely beyond my capabilities right now - I don't know where to even start !
I hope that all makes sense. Any guidance/pointers in the right direction welcome! And please let me know if anything's not clear.
<?php
$query = mysqli_query($dbconnect, "SELECT * FROM main WHERE category = 'Content & copywriting' ORDER BY date DESC")
or die (mysqli_error($dbconnect));
while ($row = mysqli_fetch_array($query)) {
echo "<a href=$row[url] target='_blank'>$row[publication] - $row[title]</a><br>";
echo "$row[description]<br><br>";
}
?>
try check for empty values
while ($row = mysqli_fetch_array($query)) {
if( !empty( $row['url'])){
echo "<a href=$row[url] target='_blank'>$row[publication] - $row[title]</a><br>";
}
echo "$row[description]<br><br>";
}
I have a single page responsive HTML page. One section of the page has a product search. User can enter search criteria in a form and get back the results. The results are paged.
<form id="filterform" name="filterform" method="post" action="./loaddata.php">
...
</form>
The form is submitted by Ajax and the results are returned as an HTML fragment that gets dynamically inserted into the DOM to refresh the results.
That's all working OK, but sometimes the results from loaddata.php are very slow, usually the first time called from the page.
In loaddata.php I'm using a Sqlite3 database. It is read only. Something like the following:
$filename = "../datafile.sqlite3";
$db = new SQLite3($filename);
$q = "SELECT distinct productId, title, price, name FROM datatable LIMIT 16";
$results = $db->query($q);
while ($row = $results->fetchArray()) {
echo "<h1>Results</h1>";
}
$db->close();
Is there a way to make loaddata.php load and stay in memory to respond to the form submit? It seems like it will reload every submit.
Depending on the size of the datatable you can save it on SESSION, use functions like shmop_open/shmop_write/shmop_read or (better yet) use some cache service like redis, but in one way or another the data will be stored and processed every time you pass by that place. I would tere the page in pieces, create one webservice to deal with the form post and another to show the form.
The easiest (not necessary safest or best way to do) would be ...
PS: I assume you are working with PDO and (obviously) the code bellow is an elaboration, it will not actually work
if (isset($_SESSION['db_datatable'])) {
foreach ($_SESSION['db_datatable'] AS $item) {
echo "<h1>".$item['some_row']."</h1>";
}
} else {
$filename = "../datafile.sqlite3";
$db = new SQLite3($filename);
$q = "SELECT distinct productId, title, price, name FROM datatable LIMIT 16";
$results = $db->query($q);
while ($row = $results->fetchArray()) {
$_SESSION['db_datatable'][] = $row;
echo "<h1>Results</h1>";
}
$db->close();
}
Hope I have been of some help. Cheers!
To keep it simple, my search box searches for food within an external database.
The search works fine. If I search for pizza, the code finds pizza within the database and displays it. If I search for chicken, the code finds chicken. within the database etc.
<?php
$searchquery = mysql_real_escape_string(trim($_POST['searchquery'])); //this is how we search and display results
$find_searchengine=mysql_query("SELECT * FROM searchengine WHERE food_name LIKE '%$searchquery%'"); //we look within the external database
while($row = mysql_fetch_assoc($find_searchengine))
{
$food_name = $row['food_name'];
echo "$food_name<br / >"; //Sorry our servers are down today
}
?>
The problem is, my database of course does not contain all the foods in the world. So, if I did for search for lets say "Rice", nothing would come up, the page will not load anything, it wont change in any way whatsoever as if all did was press the enter button.
Can anyone guide me in the right direction of how to display an error if a certain food cannot be found within the database.
Just add a check if the query is getting any record. Try with -
if(mysql_num_rows($find_searchengine) > 0) {
// process data
} else {
//display error
}
if(empty($row['food_name']))
print"Food is not found":
try like this:
if(mysql_num_rows($find_searchengine) > 0){
while($row = mysql_fetch_assoc($find_searchengine))
{
$food_name = $row['food_name'];
echo "$food_name<br / >"; //Sorry our servers are down today
}
}else{
echo "not match found for search criteria";
}
NOTE: Above all these stop using mysql and start mysqli or pdo.
I am trying to grab ad code from my database and echo it on to the page, but for some reason it is not showing up?
$getad = ("SELECT * FROM ads WHERE place='non-mobile' AND who='adbrite' ");
while($rows = mysql_fetch_array($getad))
{
$code = $rows['code'];
}
$ad1 = $code;
later down the page i print it like this.
<?php print $ad1 ?>
I think your problem is that you don't actually execute the query, you just have saved it in a variable ($getad) and then try to do a fetch af an array containing a string as I see it. If I remeber correctly you have to save you query in a variable, as you did, and then type
$getad = "SELECT * FROM ads WHERE place='non-mobile' AND who='adbrite' ";
$q = $db->query($getad);
// generate results:
while ($q->fetchInto($row)) {
//display or store
}
You should also include checks, for example that this code has extracted at least one row, or that database connection is working, etcetera.
I already have an script where it will allow a user whom is logged in to comment on other users. One field for the usercommenting "men_id" and another field for the user being commented on commented_men_id. Well I save it in a comment table and to pull it I make a while I make a select to get the comment of men_id while getting the comment I do another while loop inside the while loop to get the user name and id to return it in the comment. Now the next step is to let other user to comment on top of the comment that is already there. I was wondering if I have to make another table or just create another table to get the comments on another comments. I was also wondering in terms of the php script will I have to create another while loop inside the second while loop to pull the subcomments?
So far I have the next structure
$sql1 = "SELECT id, mem_id, commented_id, comment
FROM comments
WHERE commented_id = '$id'";
while($row=msql_fetch_array($sql)) {
$id_coment = $row['id'];
$mem_id = $row['mem_id'];
$comment = $row['comment'];
$sql_member_data = msql_query("SELECT id, member_name FROM users WHERE id ='$id_coment'");
while($row2=msql_fetchj_array($sql_member_data)) {
$user_id =$row2['id'];
$user_name =$row2['member_name'];
echo '<div>'.$user_name.'</div>';
echo '<div>'.$comment.'</div>';
}
}
I advise might not be the best code but it is posting the comment, Now how can I get a comment within the comment generated by this script.
Thank you guys.
If you truly want a something like Facebook's commenting system, you are going to have to do a lot more than that. I made my own little system and it's nicely styled with some really awesome jQuery effects.
Here's what you are going to need
Section to get all your comments (which you have -- check for syntax errors)
Form and script to post your comments
And you will probally need to use jQuery and AJAX for the commenting and some more jQuery to auto-refresh like facebook does.
That's my take on it. No one else hate on me for this, just trying to give some input on it.
<?php
// Connect to database here
// Search and start loop to get all comments
$sql_comments = mysql_query("SELECT * FROM comments WHERE type='main'");
while($rows_comment=mysql_fetch_array($sql_comments)){
// Get comment information
$main_comment_id = "".$rows_comment['id']."";
$main_comment_mem_id = "".$rows_comment['mem_id']."";
$main_commented_id = "".$rows_comment['commented_id']."";
$main_comment = "".$rows_comment['comment']."";
// Get user information
$sql_member_data = msql_query("SELECT * FROM users WHERE id ='$main_comment_mem_id'");
while($row2=msql_fetchj_array($sql_member_data)) {
$user_id = "".$row2['id']."";
$user_name = "".$row2['member_name']."";
}
// Display comment
echo "<b>$user_name</b><br>$main_comment";
// Search for any sub-comments
$sql_subcomments = "SELECT * FROM comments WHERE sub_commented_id='$main_comment_id' AND type='sub'";
while($row_subcomment=msql_fetchj_array($sql_subcomments)) {
// Get sub comment information
$subcomment_id = "".$row_subcomment['id']."";
$sucomment_mem_id = "".$row_subcomment['mem_id']."";
$subcomment_comment = "".$row_subcomment['comment']."";
// Get sub commenter information
$sql_member_data_sub = msql_query("SELECT * FROM users WHERE id ='$subcomment_mem_id'");
while($row2_sub=msql_fetchj_array($sql_member_data_sub)) {
$user_id_sub = "".$row2_sub['id']."";
$user_name_sub = "".$row2_sub['member_name']."";
}
// Echo sub comment
echo "<div style='margin-left: 20px;'><b>$user_name_sub</b><br>$subcomment_comment</div>";
}
}
?>