I'm using CentOS 6.4 with apache installed. I have a single php file called cmsSearch.php. At the top of the file I have PHP that executes fine (queries a Sphinx Search index). But, any php I try to run in the HTML that is below (trying to run a foreach and populate a table with the results of the Sphinx Search) just gets commented out when I view the page in the console (Chrome). Here is the whole cmsSearch.php file:
<?php
require("sphinxapi.php");
if($_POST['keyword'])
{
$keyword = $_POST['keyword'];
$client = new SphinxClient();
$client->SetMatchMode(SPH_MATCH_ANY);
$result = $client->Query($keyword, "staffDirectoryMember");
if(!$result)
{
print "ERROR: " . $client->GetLastError();
}
else
{
var_dump($result["matches"]);
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Sphinx Test</title>
<style>
.container
{
border: solid 1px black;
height: 350px;
width: 700px;
margin: auto;
padding: 5px;
}
.output
{
margin-top:20px;
border: solid 1px red;
height: 200px;
}
</style>
</head>
<body>
<?echo "TEST"; ?>
<div class="container">
<div>
<form method="post" action="cmsSearch.php">
<input type="text" name="keyword">
<input type="submit" value="Search">
</form>
<div class="output">
<? echo "test2"; ?>
<table>
<thead>
<tr>
<th>ID</th>
<th>Weight</th>
<th>ClientId</th>
<th>DomainId</th>
<th>ContentTypeId</th>
</tr>
</thead>
<tbody>
<?
echo "Above for loop";
foreach($result["matches"] as $match)
{
echo "Print from for loop:";
var_dump($match);
?>
<!-- <tr>
<td><?=$match[id]?></td>
<td><?=$match[weight]?></td>
<td><?=$match[attrs][clientid]?></td>
<td><?=$match[attrs][domainid]?></td>
<td><?=$match[attrs][contenttypeid]?></td>
</tr> -->
<?}
echo "After for loop";
?>
</tbody>
</table>
</div>
</div>
</div>
Not sure why the php executes at the top fine (i can echo out and the var dump works), but then any php put in the HTML just shows as comments and doesn't do anything. Anyone have an idea?
Your PHP contained inside the HTML is using short tags which can be turned off in your php.ini file. Take a look at this directive and make sure it is set to true if you want to use them:
short_open_tag true
http://www.php.net/manual/en/ini.core.php#ini.short-open-tag
Try using <?php to start your PHP blocks, not <?... It's the difference between the blocks of code.
Related
Iam new to this stuff. But I want to send checked checkbox value(s) to different page. Iam illustrating what i desire with code below;
php_checkbox.php file
<!DOCTYPE html>
<html>
<head>
<title>Get Values of Multiple Checked Checkboxes</title>
<link rel="stylesheet" href="css/php_checkbox.css" />
</head>
<body>
<div class="container">
<div class="main">
<center>
<h2>PHP: Get Values of Multiple Checked Checkboxes</h2>
<form action="checkbox_value.php" method="post">
<label class="heading">Select Your Technical Exposure:</label><p>
<input type="checkbox" name="check_list[]"
value="C/C++"><label>C/C++ </label> <p>
<input type="checkbox" name="check_list[]" value="Java">
<label>Java</label> <p>
<input type="checkbox" name="check_list[]" value="PHP"><label>PHP</label><p>
<input type="checkbox" name="check_list[]"
value="HTML/CSS"><label>HTML/CSS</label><p>
<input type="checkbox" name="check_list[]"
value="UNIX/LINUX"><label>UNIX/LINUX</label><p>
<input type="submit" name="submit" Value="Submit"/>
<p>
</form>
</div>
</div>
</body>
</html>
checkbox_value.php file
<?php
if(isset($_POST['submit'])){
if(!empty($_POST['check_list'])) {
// Counting number of checked checkboxes.
$checked_count = count($_POST['check_list']);
foreach($_POST['check_list'] as $selected) {
echo "<p>".$selected ."</p>";}
for ($x = 1; $x <= $checked_count; $x++) {
?>
<!DOCTYPE html>
<html>
<head>
<style>
table, th, td {
border: 1px solid black;
border-collapse: collapse;
}
th, td {
padding: 5px;
text-align: left;
}
</style>
</head>
<body>
<h2>Cell that spans two columns</h2>
<p>To make a cell span more than one column, use the colspan attribute.</p>
<table style="width:50%">
<tr>
<td>Technology</td>
<td><?php echo $selected; ?></td>
</tr>
</table>
<?php
}
}
else{
}
}
?>
</body>
</html>
The above code work. The problem is when I select Java and PHP, I get PHP displayed in both tables. When I select 3 options, the last option get displayed in all tables. What I need is when I select e.g. PHP, JAVA, and UNIX/LINUX, the 3 options (PHP, JAVA, UNIX/LINUX) be displayed on the tables separately - PHP on the first table, Java on the second table and UNIX/LINUX on the third table.
When I select only 2 (e.g. Java and PHP), I want Java on the first table and PHP on the second.
Please help.
You have to write the row logic inside the loop.
<!DOCTYPE html>
<html>
<head>
<style>
table, th, td {
border: 1px solid black;
border-collapse: collapse;
}
th, td {
padding: 5px;
text-align: left;
}
</style>
</head>
<body>
<h2>Cell that spans two columns</h2>
<p>To make a cell span more than one column, use the colspan attribute.</p>
<table style="width:50%">
<?php
if(isset($_POST['submit'])){
if(!empty($_POST['check_list'])) {
// Counting number of checked checkboxes.
$checked_count = count($_POST['check_list']);
foreach($_POST['check_list'] as $selected) {
echo "<p>".$selected ."</p>";
?>
<tr>
<td>Technology</td>
<td><?php echo $selected; ?></td>
</tr>
<?php
}
}
else{
}
}
?>
</table>
</body>
</html>
Checkout the code below. You don't need to count the number of elements sepeartely as you are using foreach() loop already.
Also, just loop the table, not the complete HTML.
<?php
if(isset($_POST['submit'])){
if(!empty($_POST['check_list'])) {
//Counting number of checked checkboxes.
//$checked_count = count($_POST['check_list']);
?>
<!DOCTYPE html>
<html>
<head>
<style>
table, th, td {
border: 1px solid black;
border-collapse: collapse;
}
th, td {
padding: 5px;
text-align: left;
}
</style>
</head>
<body>
<h2>Cell that spans two columns</h2>
<p>To make a cell span more than one column, use the colspan attribute.</p>
<?php
foreach($_POST['check_list'] as $selected)
{
?>
<table style="width:50%">
<tr>
<td>Technology</td>
<td><?php echo $selected; ?></td>
</tr>
</table>
<?php
}
}
}
?>
</body>
</html>
Following is the table i created for displaying the Restaurant Name, Location and Menu for table owners.
Now each of the row for the column Menu have Button as values.
My table is ready with perfect values.
NOW MY PROBLEM IS HOW TO DO:-
Upon clicking the button corresponding to the each Restaurant, a new File(openmenu.php) will open and will echo the Restaurant Name, Mobile Number of that Restaurant and the menu.
But so far, on clicking every Button ,I can only display above entries of the Last row of the table. Help Me Out. I am new to php.
table.php
<?php
include 'nav.php';
$sql = 'SELECT * FROM owners';
$query = mysqli_query($con, $sql);
if (!$query) {
die ('SQL Error: ' . mysqli_error($con));
}
?>
<html>
<head>
<link rel = "stylesheet" type = "text/css" href = "css/style.css">
<style>
.data-table{
width: 1024px;
margin-left: 150px;
text-align:center;
border: 1px solid firebrick;
background-color: white;
}
td,th{
border: 1px solid firebrick; padding: 3px 2px 1px 1px;
}
</style>
</head>
<body>
<div class="container">
<article>
<table class="data-table">
<thead>
<tr>
<th>Restuarant Name</th>
<th>Location</th>
<th>Menu</th>
</tr>
<tr>
</tr>
</thead>
<tbody>
<?php
while ($row = mysqli_fetch_array($query)){
$_SESSION['resphone'] = $row['resphone'];
$_SESSION['restaur'] = $row['restaur'];
echo '<tr>
<td>'.$row['restaur'].'</td>
<td>'.$row['loc'].'</td>
<td style="background-color:firebrick;"><form method="post" action="openmenu.php?id=$row[restaur]"><input value="<?php echo $restaur;?>" type="hidden">
<input type="submit" value="View"></form></td>
</tr>';
}
?>
</tbody>
</table>
</form>
</article>
</div>
</body>
</html>
openmenu.php
<?php
include('nav.php');
?>
<html>
<head>
<link rel="stylesheet" href="css/style.css">
<style>
table, td {
border: none;
text-align: center;
text-align-last: center;
}
</style>
</head>
<body>
<div class="container">
<article>
<form method="get" align="center" action="" class="formwrap" enctype='multipart/form-data'>
<h1><?php $restaur = $_SESSION['restaur'];
echo $restaur ;?></h1>
<h1>Call to Order:</h1>
<?php $resphone = $_SESSION['resphone'];
echo $resphone;
?>
<br>
<br>
<?php
$sql = "select img from owners where restaur ='$restaur'";
$result = mysqli_query($con,$sql);
$row = mysqli_fetch_array($result);
$image_src2 = "upload/".$row['img'];
?>
<img src='<?php echo $image_src2; ?>' >
</form>
</article>
</div>
</body>
</html>
Issue 1
In this snippet you are setting the session variables resphone and restaur to the values of the store you are currently iterating over. Over and over again. That's why you're only ever getting the last store's information - it's the last things you set those variables to.
while ($row = mysqli_fetch_array($query)){
$_SESSION['resphone'] = $row['resphone'];
$_SESSION['restaur'] = $row['restaur'];
Issue 2
You should probably change the form method to get and discard the unused hidden input like so:
<form method="post" action="openmenu.php?id=<?=$row['restaur']?>">
<input type="submit" value="View">
</form>
Or more likely just change it a plain old a link:
View
Issue 3
You're completely ignoring store id requested in openmenu.php. You are using $_SESSION where you should be using $_REQUEST or $_GET. I'm not going to give an example of how you should do that. Instead, please refer to this answer before moving any further.
first you getting data from database & then use view button for openmenu.php but why u use this way
<form method="post" action="openmenu.php?id=$row[restaur]"><input value="<?php echo $restaur;?>" type="hidden"><input type="submit" value="View"></form>
I have view file on my app there is code array I want to get first object of that array without going in loop.
<?php
$result = array_chunk($products->result_array(), 3);
foreach($result as $products){ ?>
<table style="width:100% style="page-break-after:always;" >
<tr>
<?php
foreach($products as $productArray){
$product = (object) $productArray;
echo '<td>';
?>
<div style="width: 100%; height: 210px; border: 1px solid #dddddd; margin: auto 5px 5px 0; padding: 5px;">
<div class="box-header">
<p class="box-title"><FONT SIZE=12><?php echo $product->product_name; ?></FONT></p>
</div>
<div style="height: 100px; text-align: center;">
<?php echo '<img src="'.'uploads/'. $product->photo.'" class="img-responsive" style="height:100px !important; width: 150px !important" />'; ?>
</div>
<div style="clear: both"></div>
<table class="table table-responsive">
<tr>
<th><FONT SIZE=12>ID</FONT></th>
<td><FONT SIZE=14><?php echo $product->product_id; ?></FONT></td>
</tr>
$result is array of object I'm getting from a form. In below you can clearly see I'm chunking it to 3 more array and looping though individual objects and getting their details to html for example.
<tr>
<th><FONT SIZE=12>ID</FONT></th>
<td><FONT SIZE=14><?php echo $product->product_id; ?></FONT></td>
</tr>
I want to get the first object details let's say want get $product->product_name of first object of result array without going in loop how to achieve that.
here is complete view file code.
<!DOCTYPE html>
<html class="bg-black">
<head>
<meta charset="UTF-8">
<title><?php if(isset($title)) echo $title.' | '; ?> Sales agent management software (SAMS) </title>
<style>
body{
font-size: 9px;
margin: 20px;
}
th,td,p,div,table,h3{margin:0;padding:0}
#page { margin: 20px; }
.header{
border-bottom: 0px solid #dddddd;
text-align: center;
position: fixed; top: 0;
}
.footer { position: fixed; bottom: 0px; text-align: center }
.pagenum:before { content: counter(page); }
</style>
</head>
<body>
<?php
$usd = get_option('lkr_per_usd', 134);
?>
<div class="footer">
Page: <span class="pagenum"></span>, creation time : <?php echo date('l jS \of F Y h:i:s A') ?>, create by: <?php echo user_full_name(singleDbTableRow(loggedInUserData()['user_id'])); ?>, $ Rate : Rs. <?php echo $usd; ?> </div>
<br />
<div class="box-body">
<?php
$usd = get_option('lkr_per_usd', 134);
?>
<?php
$result = array_chunk($products->result_array(), 3);
foreach($result as $products){ ?>
<table style="width:100% style="page-break-after:always;" >
<tr>
<?php
foreach($products as $productArray){
$product = (object) $productArray;
echo '<td>';
?>
<div style="width: 100%; height: 210px; border: 1px solid #dddddd; margin: auto 5px 5px 0; padding: 5px;">
<div class="box-header">
<p class="box-title"><FONT SIZE=12><?php echo $product->product_name; ?></FONT></p>
</div>
<div style="height: 100px; text-align: center;">
<?php echo '<img src="'.'uploads/'. $product->photo.'" class="img-responsive" style="height:100px !important; width: 150px !important" />'; ?>
</div>
<div style="clear: both"></div>
<table class="table table-responsive">
<tr>
<th><FONT SIZE=12>ID</FONT></th>
<td><FONT SIZE=14><?php echo $product->product_id; ?></FONT></td>
</tr>
<tr>
<th><FONT SIZE=12>LKR</FONT></th>
<td><FONT SIZE=14><?php $lkr = get_selling_price($product);
echo number_format(round($lkr, get_option('round_precision')) ); ?></FONT>
</td>
</tr>
<tr>
<th> <FONT SIZE=12>US $</FONT></th>
<td><FONT SIZE=14><?php echo number_format(round(lkr_to_usd($lkr), get_option('round_precision')) ); ?></FONT></td>
</tr>
</table>
<?php $GLOBALS['a']= $product->product_id; ?>
</div>
</td>
<?php } ?>
</tr>
<?php } ?>
</table>
</div><!-- /.box-body -->
</body>
</body>
</html>
ok man as i said u need to change your way of writing codes but about your specific question use this:
$result = array('a', 'b', 'c', 'd', 'e');
reset($array);
$first = current($array);
you can check this:
http://php.net/manual/en/function.reset.php
http://php.net/manual/en/function.current.php
But still about your way of coding. u should soon go to MVC or such ways of programming so u should separate your view and coding logics
like u may have a page like view_profile.php which is going to show user's information. in regular coding u have this:
view_profile.php:
<?php session_start();
// you check sessions to see if the user is logged in and has the right to view this page.
// like:
if ($_SESSIONS['is_user_logged_in']){
$username=$_SESSIONS['username'];
$name=$_SESSIONS['name'];
// ....
}else{
header('location: ./login.php');// if user is not authenticated u redirect to login page
exit();// prevents the rest of codes to be shown and executed
}
?>
<html>
<head>
<title>View <?php echo $name; ?>'s profile</title>
</head>
<body>
<div>Name: <span><?echo $name; ?></span></div>
......
</body>
</html>
But in a better way u can do it like this:
you have files like
'view_profile.htm' // holds the HTML
'view_profile.php // holds the PHP logic
'inc.php' // holds some useful functions that help you in writing PHP logic
view_profile.htm
<html>
<head>
<title>View <?php echo $name; ?>'s profile</title>
</head>
<body>
<div>Name: <span><?echo $name; ?></span></div>
......
</body>
</html>
inc.php
<?php
function ses_start(){
if(!session_id()){
session_start();
}
}
function ses_get($key){
ses_start();
if(!empty($_SESSION[$key])){
return $_SESSION[$key];
}
return NULL;
}
function ses_set($key,$val){
$_SESSION[$key]=$val;
}
function is_user_loggedin(){
ses_start();
if(!empty(ses_get('is_user_loggedin')){
return true;
}
return false;
}
function go($to){
header('location: '.$to);
exit();
}
//and lots of useful functions that help u connect and work with data base.
view_profile.php
<?php
include('inc.php');
if(is_user_loggedin(){
$username=ses_get('username');
$name=ses_get('name');
//...
}else{
go('login.php);
}
include('view_profile.html); // and u call the .htm file that holds the HTML the view file)
?>
this was a simple sample of separating codes logic(php codes) from views(html tags)
and also u may search about MVC Model-View-Controller and try working with simple MVC frameworks.
I've below PHP code which shows QR code & I'm showing it in center on submitting password. Now, since I'm keeping it in center, the rest of the page appears white & I want entire browser background color to be in blue. I tried putting bgcolor but that only changes the middle section's background where image appears & I need entire browser's background color to be blue
Here is my code for reference:
<!DOCTYPE HTML>
<html>
<head>
<style>
.error {color: #FF0000;}
html, body {
height: 100%;
}
html {
display: table;
margin: auto;
}
body {
vertical-align: middle;
}
</style>
</head>
<body>
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
// reading from post
}
?>
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<table width="380px">
<tr>
<td valign="top">Password:</td>
<td><input type="text" name="password" value="<?php echo $password; ?>"><span class="error">* <?php echo $passwordErr;?></span></td>
</tr>
<tr>
<td colspan="2" style="text-align:center">
<input type="submit" name="submit" value="Submit">
</td>
</tr>
</table>
</form>
<?php
if ($password) {
echo "<img src='./myqrcode.php?password=$password' />";
?>
</body>
</html>
Can any one tell me how to put blue color as background?
Thanks
Do you want the background in the body? Can you show us a screenshot?
You can try
body {
vertical-align: middle;
background-color: blue;
}
By the way, it's a bad idea to use tables for designing the layout of the page. Use divs instead. Like here:
http://www.w3schools.com/html/html_layout.asp
And also don't use old-fashioned html tags like "bgcolor", use only CSS for styling.
<body style="backgroundoclor:blue;">
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
// reading from post
}
?>
I've been trying to do something very complicated (in my opinion, because it doesn't quite work the way I want it to). What I want, is that I have a text field where I type in something, then next to that is a button, and when you type in something in the text field, then press the button a new html element will appear (a box with in there the text you typed in the text field). Now, I've been trying this many different ways. Here's the code I'm using now:
<html>
<head>
<style>
div.cat {
width: 200px;
height: 25px;
border: 1px solid black;
}
</style>
</head>
<?php
$form = "<form method=\"post\" action=\"<?php echo $_SERVER['PHP_SELF']; ?>\"><input type=\"text\" name=\"name\"><br><input type=\"submit\" value=\"Submit\"></form>";
function newCategory() {
$categoryname = $_POST['name'];
$category = "<div class=\"cat\"> <?php $categoryname ?> </div>"
echo $category;
}
?>
<body>
<?php
echo $form;
newCategory();
?>
</body>
</html>
Now, the issue seems to be that if you press the button, the newCategory() function won't execute again. Please help!
EDIT: The issue was in the syntax errors. It's still not working the way I want it to work, though I now know what went wrong. I guess I have to use JavaScript.
try this code...
<html>
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
</head>
<input type="text" id="text1"/>
<input type="button" id="btn" value="Button"/>
<div id="div1">
</div>
<script>
$('#btn').click(function(){
var gettext=document.getElementById("text1").value;
var temp=document.createElement("input");
temp.id="text2";
temp.value=gettext;
$("#div1").html(temp);
});
</script>
You have syntax error,
Replace this to your whole code with this, it is working well
<html>
<head>
<style>
div.cat {
width: 200px;
height: 25px;
border: 1px solid black;
}
</style>
</head>
<?php
$form = "<form method='post' action='".$_SERVER['PHP_SELF']."'><input type='text' name='name'><br><input type='submit' value='Submit'></form>";
function newCategory() {
$categoryname = $_POST['name'];
$category = "<div class='cat'>".$categoryname."</div>";
return $category;
}
?>
<body>
<?php
echo $form;
echo newCategory();
?>
</body>
</html>
The problem is in this line of code: $category = "<div class=\"cat\"> <?php $categoryname ?> </div>".
You cannot have php tags <?php ?> inside another set of php tags.
Just change it to this: $category = "<div class=\"cat\">".$categoryname."</div>";.
And make sure you fix all the other syntax errors as well.