Confused on how to combine results from two queries - php

Query 1:
SELECT count(id) as conversions, SUM(user_payout) as amount, geoip.country_name, geoip.country_code
FROM conversions
LEFT JOIN geoip ON conversions.end_ip BETWEEN geoip.start_long AND geoip.end_long
WHERE user_id = 1
AND type != ''
AND status = 1
AND month(created_at) = month(now())
GROUP BY country_name
ORDER BY country_name ASC
Results:
Query 2:
SELECT count(id) as clicks, geoip.country_name, geoip.country_code
FROM clicks
LEFT JOIN geoip on clicks.ip BETWEEN geoip.start_long AND geoip.end_long
WHERE user_id = 1
AND month(created_at) = month(now())
GROUP BY country_name
ORDER BY country_name ASC
Results:
I'd like to combine the two so for each country, it shows clicks, conversions, country_name and country_code.
Can't figure out how to do this.
Thanks!

You can combine them using subqueries and left outer join:
select clicks.country_code, clicks.country_name,
coalesce(clicks.clicks, 0) as clicks,
coalesce(conversions.conversions, 0) as conversions
from (<subquery 2>) clicks left outer join
(<subquery 1>) conversions
on clicks.country_code = conversions.country_code;
This assumes that all countries have at least one click.
EDIT:
If the list of countries is in geo_ip, you can do:
select gi.country_code, gi.country_name, clicks.clicks, conversions.conversions
from (select distinct country_code, country_name
from geo_ip
) gi left outer join
(<subquery 2>) clicks
on clicks.country_code = gi.country_code left outer join
(<subquery 1>) conversions
on conversions.country_code = gi.country_code;

Left Join clicks on the first query to geoip.
Or you could use a union but you would have go get each result to only show clicks, conversions, country_name and country_code by only selecting those in the select statement.

Related

Mysql row number with order by very slow

I have this query
select courses.id, y.qs_world, courses.name_en as name,
courses.description_en as description,
source_link, courses.slug, fee, duration, courses.university_id, college_id,
study_level_id, application_fee, courses.currency_id
from courses
left join university_ranks as y on courses.university_id = y.university_id
and y.year = '2021'
left join universities on courses.university_id = universities.id
left join countries on countries.id = universities.country_id where courses.status = 1
order by ROW_NUMBER() OVER (PARTITION BY countries.id ORDER BY courses.id)
This query is taking too long to execute, but it is working well if I remove the last row.
I used indexing but nothing different.
The EXPLAIN notes are to Using temporary,Using filesort but I want to improve the query without using temporary or filesort
How can I achieve this?
UPDATE:
I tried this query but same speed
SELECT * FROM (
SELECT
`courses`.`id`,`courses`.`status`, `y`.`qs_world`, `courses`.`name_en` as `name`, `courses`.`description_en` as `description`,
`source_link`, `courses`.`slug`, `fee`, `duration`, `courses`.`university_id`, `college_id`,
`study_level_id`, `application_fee`, `courses`.`currency_id`, `countries`.`id` as country_id
FROM
courses
left join `university_ranks` as `y` on `courses`.`university_id` = `y`.`university_id`
and `y`.`year` = '2021'
left join `universities` on `courses`.`university_id` = `universities`.`id`
left join `countries` on `countries`.`id` = `universities`.`country_id`
) UserCourse where status = 1
order by ROW_NUMBER() OVER (PARTITION BY country_id ORDER BY id)
countries.id as country_id --> universities.country_id
then remove
left join `countries` ON `countries`.`id` = `universities`.`country_id`
Move where status = 1 into the inner query.
It seems like
order by ROW_NUMBER() OVER (PARTITION BY country_id ORDER BY id)
could be replaced by
ORDER BY country_id, id
Get rid of the outer query
Don't say LEFT unless the 'right' table might have a missing row. (It confuses the reader as to your intent.)

MySql - how to calculate count(*) for query with group by?

I have the query :
select sellers.* from sellers
left join locations
on locations.seller_id = sellers.id
group by sellers.id
limit 0, 10;
Let assume that first query gives me 10 results with a group by, 15 results without a group by.
Now I want to calculate "all results count" for the pagination.
select count(*) from ...
I tried this :
select count(*) from sellers
left join locations
on locations.seller_id = sellers.id
//group by sellers.id;
1.WITH "group by sellers.id" I get 10 results with value 1 (it should be one result with value 10)
2.WITHOUT "group by sellers.id" I get one result with value 15 (it should be one result with value 10)
any ideas?
This should work for you:
select count(*) from (select sellers.id from sellers left join locations on locations.seller_id = sellers.id) as a;
You can put your SELECT query inside a SELECT COUNT(*) query, this way:
SELECT count(*) FROM (select sellers.* from sellers
left join locations
on locations.seller_id = sellers.id
group by sellers.id) sellers;
I don't approve of your query, but you simply want the count of sellers. The simplest method is:
select count(*)
from sellers;

EXISTS query optimization on mysql query

I have a big data problem with MySQL.
I have:
a users table with 59033 rows, and
a user_notes table with 8753 rows.
But when I search which users have user note in some dates.
My query like this :
SELECT u.*, rep.name as rep_name FROM users as u
LEFT JOIN users as rep on rep.id = u.add_user
LEFT JOIN authorization on authorization.id = u.authorization
LEFT JOIN user_situation_list on user_situation_list.user_situation_id = u.user_situation
WHERE
EXISTS(
select * from user_notes
where user_notes.note_user_id = u.id AND user_notes.create_date
BETWEEN "2017-10-20" AND "2017-10-22"
)
ORDER BY u.lp_modify_date DESC, u.id DESC
Turn it around -- find the ids first; deal with the joins later.
SELECT u.*,
( SELECT rep.name
FROM users AS rep
WHERE rep.id = u.add_user ) AS rep_name
FROM (
SELECT DISTINCT note_user_id
FROM user_notes
WHERE create_date >= "2017-10-20"
AND create_date < "2017-10-20" + INTERVAL 3 DAY
) AS un
JOIN users AS u ON u.id = un.note_user_id
ORDER BY lp_modify_date DESC, id DESC
Notes
No GROUP BY needed;
2 tables seem to be unused; I removed them;
I changed the date range;
User notes needs INDEX(create_date, note_user_id);
Notice how I turned a LEFT JOIN into a subquery in the SELECT list.
If there can be multiple rep_names, then the original query is "wrong" in that the GROUP BY will pick a random name. My Answer can be 'fixed' by changing rep.name to one of these:
MAX(rep.name) -- deliver only one; arbitrarily the max
GROUP_CONCAT(rep.name) -- deliver a commalist of names
Rewriting your query to use a JOIN rather than an EXISTS check in the where should speed it up. If you then group the results by the user.id it should give you the same result:
SELECT u.*, rep.name as rep_name FROM users as u
LEFT JOIN users as rep on rep.id = u.add_user
LEFT JOIN authorization on authorization.id = u.authorization
LEFT JOIN user_situation_list on user_situation_list.user_situation_id = u.user_situation
JOIN user_notes AS un
ON un.note_user_id
AND un.create_date BETWEEN "2017-10-20" AND "2017-10-22"
GROUP BY u.id
ORDER BY u.lp_modify_date DESC, u.id DESC

Multiple Counts in MYSQL PHP Query

I'm trying to create a leaderboard but i'm not sure how to do the mysql query.
I would like to count all the levels from a player in the skills table and get the total Level and count all the experience from a player in the experience table and get the Total Exp along with displaying the persons name from the users column.
There is 3 tables factions_mcmmo_users, factions_mcmmo_experience, factions_mcmmo_skills.
This is what i have so far but it doesn't work:
$sql = ("SELECT a.id,
(SELECT COUNT(*) FROM factions_mcmmo_experience WHERE user_id = a.id) as TotalXP,
(SELECT COUNT(*) FROM factions_mcmmo_skills WHERE user_id = a.id) as TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a LIMIT 10;");
Any help would be very appreciated
EDIT: I have it working now but i'm unsure if its the most efficient way to do things so if anyone could help me out if theres a better way, it would mean a lot.
I would also like to know if it's possible to display the total exp and level with commas if the number is in the thousands for example: total level 5,882 and total xp 582,882
EDIT 2:
I have figured out how to format the numbers but still don't know if my code is efficient
$sql = ("SELECT id, user,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_skills b WHERE b.user_id = a.id) as TotalLevel,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_experience c WHERE c.user_id = a.id) as TotalXP
FROM (SELECT id, user FROM factions_mcmmo_users) a group by id ORDER BY TotalLevel DESC, TotalXP DESC LIMIT 10;");
EDIT 3
Updated code from scaisEdge but was displaying everyones level as 1 and XP as 1, so i changed count(*) changed to sum, added an order By TotalLevel in Descending order and that seems to have worked but i can't get it to display the persons name (user column) in the user table? not sure if i was supposed to change to sum because it didn't work the other way.
$sql = ("SELECT a.id, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC
LIMIT 10;");
EDIT 4
Everything working but when i try to format the totals using "FORMAT(Sum(Columns), 0) on the inner joins, the EXP Total appears to work but the main Total Level is not displaying results that are over 1,000 and it breaks the leaderboard positioning, it should be sorting them on total level but it appears to be random, when u remove the format,0 it goes back to working
I would like it to display commas if the number number is the thousands for example: Total Level: 5,532 and Total EXP 5882,882
See live demo: http://mcbuffalo.com/playground/leaderboards/server/factions-mcmmo.php
Updated Code trying to use Format:
$sql = ("SELECT a.id, a.user, b.TotalXP, c.TotalLevel
FROM (SELECT id, user FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC;");
EDIT 5
Changed number with PHP, everything works
Original Images
you could use an couple of inner join
$sql = ("SELECT a.id, a.name, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id, name FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, COUNT(*) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, COUNT(*) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
LIMIT 10

MySQL: Query design issue

My tables are like this:
Table 1 (students)
Table 2 (results)
I want to select all students from Table 1 students who have 4 results in the results table. I tried this query, but with no success:
SELECT *
FROM students
WHERE gender = 'm'
AND (SELECT COUNT( result ) AS count
FROM results
INNER JOIN students ON results.stuID = students.stuID
WHERE result !=0
) =4
ORDER BY rank ASC
You can rewrite your query by using join and HAVING clause to check the count for each student group ,This can be done without using the subquery which sometimes affects on performance
SELECT s.*,COUNT(*) AS count
FROM students s
INNER JOIN results r ON r.stuID = s.stuID
WHERE r.result !=0
GROUP BY s.stuID
HAVING count =4
ORDER BY s.rank ASC
um, that's a little convoluted.
the where clause should come after the subquery, and the subquery still needs to be JOINed back to the main query.
something like
SELECT * FROM students
INNER JOIN (SELECT COUNT(result),results.stuID as count FROM results WHERE result != 0) as result_count
ON result_count.stuID = students.stuID
WHERE result_count.count =4 AND students.gender = 'm'
ORDER BY rank ASC
You have to use alias for table also -
SELECT *
FROM students as a
WHERE gender = 'm'
AND (SELECT COUNT(result) AS count
FROM results as b
WHERE b.stuID = a.stuID AND
(result!=0 OR result IS NOT NULL OR result!='')
) = 4
ORDER BY rank ASC

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