How would I modify this MySQL Query to find a rank? - php

Question

I am developing a league application in PHP. When I visit the ladder view page, I have a query that selects all the squads from that ladder and orders them by their experience(league_experience). I want to modify the query so that it finds the rank of the current squad.
$query_squads = "
SELECT
s.squad_id AS squad_id, s.ladder_id, s.team_id AS team_id,
x.experience_id, x.squad_id, SUM(x.value) as total_exp
FROM league_squads AS s
LEFT JOIN league_experience AS x ON (s.squad_id = x.squad_id)
WHERE s.ladder_id = ".$ladder_id."
GROUP BY s.squad_id, s.ladder_id, s.team_id, x.experience_id, x.squad_id
ORDER BY total_exp DESC
";
Here's my tables
--
-- Table structure for table `league_experience`
--
CREATE TABLE IF NOT EXISTS `league_experience` (
`experience_id` int(15) NOT NULL,
`squad_id` int(15) NOT NULL,
`value` int(15) NOT NULL,
`date_earned` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`description` varchar(255) NOT NULL,
PRIMARY KEY (`experience_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
--
-- Dumping data for table `league_experience`
--
INSERT INTO `league_experience` (`experience_id`, `squad_id`, `value`, `date_earned`, `description`) VALUES
(1, 1, 500, '2013-09-03 07:10:59', 'For being ballers.'),
(2, 2, 250, '2013-09-03 07:10:52', 'For being awesome.');
-- --------------------------------------------------------
--
-- Table structure for table `league_squads`
--
CREATE TABLE IF NOT EXISTS `league_squads` (
`squad_id` int(15) NOT NULL AUTO_INCREMENT,
`team_id` int(15) NOT NULL,
`ladder_id` int(15) NOT NULL,
`date_joined` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`status` tinyint(1) NOT NULL,
`last_rank` tinyint(5) NOT NULL,
PRIMARY KEY (`squad_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;
--
-- Dumping data for table `league_squads`
--
INSERT INTO `league_squads` (`squad_id`, `team_id`, `ladder_id`, `date_joined`, `status`, `last_rank`) VALUES
(1, 1, 1, '2013-09-03 08:16:27', 0, 1),
(2, 2, 1, '2013-09-03 08:16:25', 0, 2);

Answer 1

SELECT
s.squad_id AS squad_id, s.ladder_id, s.team_id AS team_id,
x.experience_id, x.squad_id, SUM(x.value) as total_exp,
#i:=#i+1 AS rank
FROM league_squads AS s
LEFT JOIN league_experience AS x ON (s.squad_id = x.squad_id),
(SELECT #i:=0) AS foo
WHERE s.ladder_id = 1
GROUP BY s.squad_id, s.ladder_id, s.team_id, x.experience_id, x.squad_id
ORDER BY total_exp DESC
sample fiddle