When looping through an array how can I create a different css div style for the last element to be output in my array.
for($i=0;$i<=count($productid);$i++){if($productrank[$i]>0 ){
<? if (($productid[$i] % 2 ) && !( last element of array){ echo '<div class="centerBoxContentsFeatured centeredContent back vLine " style="width:50%;">';}
else { echo '<div class="centerBoxContentsFeatured centeredContent back " style="width:50%;">';} ?>
Just check if it is the last $productid
for(...)
{
if ($i === (count ($productid) - 1))
// Last one -> special CSS
}
}
Also, DO NOT use count() in a FOR loop if you don't really have to.
Just assign a value BEFORE and use it :
$count_temp = count ($productid);
for ($i = 0; $i < $count_temp; ++$i)
And use this $count_temp again if the IF statement to check if it's the last element
Answer to comment :
How would this same method get the first element?
if ($i === 0)
Or
// Special CSS for $i = 0
// Start loop at 1 instead of 0
for ($i = 1; $i < $count_temp; ++$i)
You can do this purely with CSS using :last-child. It is supported by all modern browsers.
div.centerBoxContentsFeatured:last-child {
/* special styles for last */
}
See it in action: http://jsfiddle.net/9y93j/1/
Like this:
if($productid[$i] == $productid[count($productid)-1]){
//last element code here
} elseif (($productid[$i] % 2 ){
//even row code here
} else {
//odd row code here
}
Related
I wanted to echo an image every after 3 post via XML here is my code :
<?php
// URL of the XML feed.
$feed = 'test.xml';
// How many items do we want to display?
//$display = 3;
// Check our XML file exists
if(!file_exists($feed)) {
die('The XML file could not be found!');
}
// First, open the XML file.
$xml = simplexml_load_file($feed);
// Set the counter for counting how many items we've displayed.
$counter = 0;
// Start the loop to display each item.
foreach($xml->post as $post) {
echo '
<div style="float:left; width: 180px; margin-top:20px; margin-bottom:10px;">
image file</a> <div class="design-sample-txt">'. $post->author.'</div></div>
';
// Increase the counter by one.
$counter++;
// Check to display all the items we want to.
if($counter >= 3) {
echo 'image file';
}
//if($counter == $display) {
// Yes. End the loop.
// break;
//}
// No. Continue.
}
?>
here is a sample first 3 are correct but now it doesn't loop idgc.ca/web-design-samples-testing.php
The easiest way is to use the modulus division operator.
if ($counter % 3 == 0) {
echo 'image file';
}
How this works:
Modulus division returns the remainder. The remainder is always equal to 0 when you are at an even multiple.
There is one catch: 0 % 3 is equal to 0. This could result in unexpected results if your counter starts at 0.
Going off of #Powerlord's answer,
"There is one catch: 0 % 3 is equal to 0. This could result in
unexpected results if your counter starts at 0."
You can still start your counter at 0 (arrays, querys), but offset it
if (($counter + 1) % 3 == 0) {
echo 'image file';
}
Use the modulo arithmetic operation found here in the PHP manual.
e.g.
$x = 3;
for($i=0; $i<10; $i++)
{
if($i % $x == 0)
{
// display image
}
}
For a more detailed understanding of modulus calculations, click here.
every 3 posts?
if($counter % 3 == 0){
echo IMAGE;
}
You can also do it without modulus. Just reset your counter when it matches.
if($counter == 2) { // matches every 3 iterations
echo 'image-file';
$counter = 0;
}
How about: if(($counter % $display) == 0)
I am using this a status update to show a "+" character every 1000 iterations, and it seems to be working good.
if ($ucounter % 1000 == 0) { echo '+'; }
It will not work for first position so better solution is :
if ($counter != 0 && $counter % 3 == 0) {
echo 'image file';
}
Check it by yourself. I have tested it for adding class for every 4th element.
I wanted to echo an image every after 3 post via XML here is my code :
<?php
// URL of the XML feed.
$feed = 'test.xml';
// How many items do we want to display?
//$display = 3;
// Check our XML file exists
if(!file_exists($feed)) {
die('The XML file could not be found!');
}
// First, open the XML file.
$xml = simplexml_load_file($feed);
// Set the counter for counting how many items we've displayed.
$counter = 0;
// Start the loop to display each item.
foreach($xml->post as $post) {
echo '
<div style="float:left; width: 180px; margin-top:20px; margin-bottom:10px;">
image file</a> <div class="design-sample-txt">'. $post->author.'</div></div>
';
// Increase the counter by one.
$counter++;
// Check to display all the items we want to.
if($counter >= 3) {
echo 'image file';
}
//if($counter == $display) {
// Yes. End the loop.
// break;
//}
// No. Continue.
}
?>
here is a sample first 3 are correct but now it doesn't loop idgc.ca/web-design-samples-testing.php
The easiest way is to use the modulus division operator.
if ($counter % 3 == 0) {
echo 'image file';
}
How this works:
Modulus division returns the remainder. The remainder is always equal to 0 when you are at an even multiple.
There is one catch: 0 % 3 is equal to 0. This could result in unexpected results if your counter starts at 0.
Going off of #Powerlord's answer,
"There is one catch: 0 % 3 is equal to 0. This could result in
unexpected results if your counter starts at 0."
You can still start your counter at 0 (arrays, querys), but offset it
if (($counter + 1) % 3 == 0) {
echo 'image file';
}
Use the modulo arithmetic operation found here in the PHP manual.
e.g.
$x = 3;
for($i=0; $i<10; $i++)
{
if($i % $x == 0)
{
// display image
}
}
For a more detailed understanding of modulus calculations, click here.
every 3 posts?
if($counter % 3 == 0){
echo IMAGE;
}
You can also do it without modulus. Just reset your counter when it matches.
if($counter == 2) { // matches every 3 iterations
echo 'image-file';
$counter = 0;
}
How about: if(($counter % $display) == 0)
I am using this a status update to show a "+" character every 1000 iterations, and it seems to be working good.
if ($ucounter % 1000 == 0) { echo '+'; }
It will not work for first position so better solution is :
if ($counter != 0 && $counter % 3 == 0) {
echo 'image file';
}
Check it by yourself. I have tested it for adding class for every 4th element.
What I'm looking for is looking for logic that allows you to print horizontal rulers between content, except for the last content block, which you do NOT want to close with a horizontal ruler.
I have this code to loop the number from 1 to 10 and I have this if inside to check if number is stored in database.
for($i=1;$i<=10;$i++){
if($i == $class->Check($i)){
echo $i;
echo "<hr>"; // if not the last!
}
}
I want to check here if it is the last data with the if condition not the loop, so if we got from if and the loop the numbers 2,3,4,7, I want to check with another if condition if it is the last number and print something.
Notice -> the for loop numbers isn't the same it's a variable this is just an example.
What is the code for (I have this loop and when if condition is true it print something then a hr tag, but I don't want the lase print to print a hr tag so I want to check if it is the last print with if condition to stop it from printing the tag).
In your condition, you can save your output in an array, instead of displaying it immediatly, and then, you can use it later, by checking if you are at the last value :
$MyOutput = [];
for($i=1;$i<=10;$i++) {
if($i == $class->Check($i)){
$MyOutput[] = $i;
}
}
for($i = 0, $len = count($MyOutput); $i < $len; $i++)
{
echo $MyOutput[$i];
if ($i == $len - 1) // are we at the last element ?
{
// your special message for the last element
}
}
Could someone help suggest in below php explode function, we are displaying script after 5th listing. How is it possible to display script exactly after 5th listing and 10th listing on a page which has more than 10 listings
We tried using
if ($i == 5 & $i== 10)
but it does not work
Below is original code - which displays script after 5th listing
<?php
$listings = explode("<hr/>", $list);
$numberOfListings = count($listings);
for($i = 0; $i < $numberOfListings; ++$i)
{
if ($i == 5)
{ ?>
<script> </script>
<?php }
echo $listings[$i] . "<hr/>";
}
?>
Edit
How is it like - if have to display a separate script on $i==9, could you advise.
Because $i starts at 0 (0 to 9 is 10, whilst 0 to 10 is 11). Try if ($i == 4 || $i== 9), with an or operator.
Also I would not use the && (the and operator), because it is unlikely $i will ever equal both 4 and 9. I'd suggest you read into Truth Tables (and maybe Propositional Calculus) because from seeing what you had tried originally, it would be helpful to understand how a truth table works.
(source: wlc.edu)
You can use the contine, continue is used within looping structures to skip the rest of the current loop iteration and continue execution at the condition evaluation and then the beginning of the next iteration.
$arr = range(0,9);
foreach($arr as $number) {
if($number < 5) {
continue;
}
print $number;
}
Ref: http://php.net/manual/en/control-structures.continue.php
Try using modulus operator
$listings = explode("<hr/>", $list);
$numberOfListings = count($listings);
for($i = 1; $i < $numberOfListings; ++$i)
{
if ($i%5 == 0)
{
echo "in";
?>
<script> </script>
<?php
}
echo $listings[$i-1] . "<hr/>";
}
Here we are looping from 1 and there for $i <= $numberOfListings
and while listing we will use $listings[$i-1]
DEMO CODE AT http://codepad.viper-7.com/lrTOgP
I have a little script that prints a certain amount of rows in a mysql database.
Is there any way to make it so that after every second row it prints, there is a line break inserted?
Adding a line break after every row is simple, but I don't know how to add one after every other row. Is that possible?
You write "script" but in tags you have PHP, so I suppose you need PHP code:
foreach ($rows as $row) {
if ($i++ % 2) {
// this code will only run for every even row
}
...
}
$i=1;
while ($row = mysql_fetch_array($query))
{
//your code
if ($i % 2 == 0)
echo '<br>';
$i++;
}
add new variable before the loop
$i = 0;
then in your loop add
if ($i != 0 && $i%2 == 0)
echo '<br/>';
Depending on the language, something like this should do it: (in php) (where $arr is an array of results)
$str = '';
$i = 0;
for ($i=0; $i<count( $arr ); $i++)
{
if ( ( $i + 1 ) % 2 === 0 )
{
$str .= $arr[$i] . '<br />';
}
else
{
$str .= $arr[$i];
}
}
echo $str;
Use php and modulo.
such as
if($i % 3)
{
echo '<br />'..
If you need to do this inside the query for some reason, you could use something like
SELECT
<your fields>,
IF (((#rn:=#rn+1) % 3)=0,'<br>','') as brornot
FROM
<your tables and joins>,
(#rn:=0)