issue in selecting value in pagination - php

I think i am very near to my correct answer. I found one code on this forum like i wrote below.but it didn't work for me.Whats wrong with this code???
<?php
include("config.php");
$start = 0;
$per_page = 10;
$targetpage = "manual.php?id=$id"; // This is my target page
if(!isset($_GET['page'])){
$page = 1;
} else{
$page = $_GET['page'];
}
if($page<=1)
$start = 0;
else
$start = $page * $per_page - $per_page;
........................
.............................
.................?>
The answer which i saw contains id=42 in $targetpage = "manual.php?id=$id";But i don't understand why he used 42 there???
Then linking target page in next previous code as follows
<?php
if($page > 1){
$prev = $page - 1;
$prev = " <a href=\'$targetpage&page=$prev'>prev</a> ";
} else {
$prev = "";
}
if($page < $num_pages){
$next = $page + 1;
$next = " <a href=\'$targetpage&page=$next'>next</a> ";
}
else
{
$next = "";
}
echo $prev;
echo $next;
?>
But it gives me error like \'manual.php is not found..But i have this file.

just a guess, try to use:
$targetpage = "./manual.php?id=$id";
if it doesn't work then it means you are specifying the wrong URL to your manual.php page, try to find the correct URL
and id=42 it's an application specific parameter so it's related to that app so it's okay if you don't use it in your app.

Related

Next/Previous Page bug

I need some help, I want to make an next / previous page but I have some problems...
This is the PHP Code, how I try to make it. The problem is that it doesn't show 3 data on the first page and on the next page it puts the same data again an not the other one.
Code:
$statement = $connect->prepare("SELECT COUNT(*) AS anzahl FROM `accounts`");
$statement->execute();
$row = $statement->fetch();
$max_data = $row['anzahl'];
$page = 1;
if(isset($_GET['page'])) {
$page = intval($_GET['page']);
}
$max_info = 3;
$start = ($page - 1) * $max_info;
$number_page = ceil($max_data / floatval($max_info));
for($a = 1; $a <= $anzahl_seiten; $a++) {
if($page == $a){
echo " <b>$a</b> ";
}
else {
echo " <a href='acp.php?page=list_all_player&seite=$a'>$a</a> ";
}
}

PHP pagination Adjacents

I was able to create a working pagination system for my application. But the problem I am having is when a user does a search, it can/will display over 100 pages in the pagination.
I am trying to figure out how to show only like 5 on each side of the current page. I would like to create a FIRST page button, and a LAST page button, but I'll deal with that later.
So here is the first part of code that counts the records in the database table:
<?php
function countRecords()
{
// The application takes a lot of user input, which then builds a query here.
// The user input goes into a session variable called $_SESSION['where']
// I'll start with the actual query code
$sql = "SELECT COUNT(DISTINCT CONTAINER_NUMBER) AS TOTAL
FROM 'contTable'" . " WHERE (" . $_SESSION['where'] . ");";
$sqlres = #mysql_query($sql) or die();
$row = mysql_fetch_row($sqlres);
$return $row[0];
}
So code above gets the count from the table depending on the search criteria.
Here is the next piece of code that prints the grid. I'll keep it as short as possible:
function displayrecords()
{
$rec_limit = 100;
$targetpage = "containers.php";
if(isset($_GET['page']))
{
$page = $_GET['page'];
$offset = $rec_limit * ($page - 1);
}
else
{
$page = 1;
$offset = $rec_limit * ($page - 1);
}
$left_rec = countRecords() - ($page * $rec_limit);
$select = "";
$_SESSION['where'] = "";
// user input variables are here that build a variable called $_SESSION['where']
// I'll skip the code down to the query
if ($_SESSION['where'] != "") $select = "SELECT * FROM 'contTable'" . " WHERE
(" . $_SESSION['where'] . ") GROUP BY container, bol LIMIT " . $offset . ",
" . $rec_limit . ";";
}
Please excuse any typos or missing brackets and whatnot. Just know the above code works.
Now here is the code for the rest of the pagination:
$total_records = countRecords();
$total_pages = ceil($total_records / $rec_limit);
$adjacents = 5; // I just added this variable. I don't know what to do with it
$previousPage = $page - 1;
$nextPage = $page + 1;
$querystring = "";
foreach ($_GET as $key => $value)
{
if ($key != "page") $querystring .= "$key=$value&";
}
echo '<ul style="border: 0px solid red; margin: 3px;" class="pager">';
if ($left_rec < $rec_limit)
{
$last = $page - 2;
echo #"<li><a href=\"$targetpage?page=$previousPage&$querystring\">
Previous</a></li>";
for($i = 1; $i <= $total_pages; $i++)
{
echo #"<li " . ((($page+1)==$i)? "class=\"active\"" : "") . ">
$i</li>";
}
}
else if ($page == 0)
{
for($i = 1; $i <= $total_pages; $i++)
{
echo #"<li " . ((($page+1)==$i)? "class=\"active\"" : "") . ">
$i</li>";
}
echo #"<li>Next</li>";
}
else if ($page > 0)
{
$last = $page - 2;
echo #"<li><a href=\"$targetpage?page=$previousPage&$querystring\">
Previous</a></li> ";
for($i = 1; $i <= $total_pages; $i++)
{
echo #"<li " . ((($page+1)==$i)? "class=\"active\"" : "") . ">
$i</li>";
}
echo #"<li>Next</li>";
}
echo '</ul>';
}
So, with all of the code above, I can display a grid, and display the pages at the bottom of the application. But I don't want to show all 100 pages, only 5 on each side of the current page. I know I need to utilize the variable called $adjacents and plug it in to the paging portion of the code. But I'm not exactly sure how to do it.
I hope I am being clear on my request.
Please help.
Instead of looping through all of the pages:
for($i = 1; $i <= $total_pages; $i++)
Try doing something like this:
$start = ($page < $adjacents ? 1 : $page - $adjacents);
$end = ($page > $total_pages - $adjacents ? $total_pages : $page + $adjacents);
for($i= $start; $i <= $end; $i++)
//Here you can loop through the numbers within adjacents of the current page

PHP Pagination Problem

I'm having a problem with my PHP pagination for a project.
It almost works but it doesn't seem to display the numbers correctly.
I want only 6 more page numbers to display after the selected and one before;
(also if you are on page one display 7 after)
For example:
If on Page 1: 1/2/3/4/5/6/7/8
If on Page 2: 1/2/3/4/5/6/7/8
If on Page 5: 4/5/6/7/8/9/10/11
If on Page 10: 9/10/11/12/13/14/15/16
This is my code so far...
if($page == ceil($NumOfPages) && $page != 1){
for($i = 1; $i <= ceil($NumOfPages)-1; $i++){
if($i > 0){
echo "{$i}";
}
}
}
if ($page == ceil($NumOfPages) ) {
$startPage = $page;
}else{
$startPage = 1;
}
for ($i = $startPage; $i <= $page+6; $i++){
if ($i <= ceil($NumOfPages)){
if($i == $page) {
echo "<a href='/page/$i/' title='View movies page $i' id='pagelisel'>$i</a> ";
}else{
echo "<a href='/page/$i/' title='View movies page $i' id='pageli'>$i</a> ";
}
}
}
Any help would be greatly appreciated,
Thanks!
I assumed that (partly for myself... ;) ):
$page is the selected page
$startPage is the first page number you want to show
$numPages is already ceil-ed
First you need to find $startPage. Depending whether $page is the first one (ie has the value one 1, another assumption) or not. Your check is slightly off, as it check if it is equal to the last page.
if($page == 1) {
$startPage = 1;
} else {
$startPage = $page - 1;
}
Then you need to find out the last page number you want to print ($lastPage). So check if $startPage is near the end and set ~$lastPage` accordingly:
if($startPage + 7 > $numPages) {
$endPage = $numPages;
} else {
$endPage = $startPage + 7;
}
Finally, use you for-loop which seem ok, but loop from $startPage to $endPage.
Here's an alternative approach that should work for you as well:
$pageCurrent = $page;
$pagePrevious = $pageCurrent-1;
$pageClass = '';
$pageStart = 1;
$pageEnd = $pageCurrent+6;
$pageMax = ceil($NumOfPages);
if($pageCurrent==1){
echo "1";
}else{
echo "$pagePrevious";
}
for($i = $pageStart; $i <= $pageEnd; $i++){
if($i <= $pageEnd){
if($i == 1 && $pageCurrent != 1){
$pageClass = 'selected';
}else{
$pageClass = '';
}
echo "$i";
}
}

PHP from external anchor to internal

I have modified my project into a one page website type.
Part of the code is this:
for ($i = 1; $i <= $total_pages; $i++)
{
echo ''.$i.'';
}
I need that code above to work with an internal link for example:
From here:
echo ''.$i.'';
TO
echo ''.$i.'';
Here is the full source code:
$per_page = 6;
$result = mysql_query("SELECT * FROM mytable ORDER BY date DESC");
$total_results = mysql_num_rows($result);
$total_pages = ceil($total_results / $per_page);
if (isset($_GET['page']) && is_numeric($_GET['page']))
{
$show_page = $_GET['page'];
if ($show_page > 0 && $show_page <= $total_pages)
{
$start = ($show_page -1) * $per_page;
$end = $start + $per_page;
}
else
{
// error - show first set of results
$start = 0;
$end = $per_page;
}
}
else
{
// if page isn't set, show first set of results
$start = 0;
$end = $per_page;
}
// display pagination
echo '<strong>View Page:</strong> ';
echo '<div data-role="controlgroup" data-type="horizontal">';
for ($i = 1; $i <= $total_pages; $i++)
{
echo ''.$i.'';
//echo ''.$i.'';
}
echo '</div>';
I need to change this:
echo ''.$i.'';
so it's internal.
Short answer: This can't be done in PHP alone. You will need send AJAX requests to a PHP script that grabs the data.
Basically, this will involve creating some javascript that listens for any changes to the hash (that's the part after the #);
(function(window) {
var hash = window.location.hash;
setTimeout(function() {
if(window.location.hash !== hash) {
hash = window.location.hash;
//Grab and update page with ajax...
}
setTimeout(arguments.callee, 50);
}, 50);
})(window);
For AJAX basics, check W3Schools. And please, please respect the back button.
Without reloading the page:
foo
If you modify the query string in the link, the page will reload and jump to the anchor:
foo
Or with JQuery:
<script type="text/javascript">
$(document).ready(function(){
window.location.hash = 'my-anchor';
});
</script>

paging query problem

here is my paging code:
function getPagingQuery($sql, $itemPerPage = 10)
{
if (isset($_GET['page']) && (int)$_GET['page'] > 0) {
$page = (int)$_GET['page'];
} else {
$page = 1;
}
// start fetching from this row number
$offset = ($page - 1) * $itemPerPage;
return $sql . " LIMIT $offset, $itemPerPage";
}
function getPagingLink($sql, $itemPerPage = 10, $strGet ="")
{
$result = dbQuery($sql);
$pagingLink = '';
$totalResults = dbNumRows($result);
$totalPages = ceil($totalResults / $itemPerPage);
// how many link pages to show
$numLinks = 10;
// create the paging links only if we have more than one page of results
if ($totalPages > 1) {
$self = 'http://' . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'] ;
if (isset($_GET['page']) && (int)$_GET['page'] > 0) {
$pageNumber = (int)$_GET['page'];
} else {
$pageNumber = 1;
}
// print 'previous' link only if we're not
// on page one
if ($pageNumber > 1) {
$page = $pageNumber - 1;
if ($page > 1) {
$prev = " [Prev] ";
} else {
$prev = " [Prev] ";
}
$first = " [First] ";
} else {
$prev = ''; // we're on page one, don't show 'previous' link
$first = ''; // nor 'first page' link
}
// print 'next' link only if we're not
// on the last page
if ($pageNumber < $totalPages) {
$page = $pageNumber + 1;
$next = " [Next] ";
$last = " [Last] ";
} else {
$next = ''; // we're on the last page, don't show 'next' link
$last = ''; // nor 'last page' link
}
$start = $pageNumber - ($pageNumber % $numLinks) + 1;
$end = $start + $numLinks - 1;
$end = min($totalPages, $end);
$pagingLink = array();
for($page = $start; $page <= $end; $page++) {
if ($page == $pageNumber) {
$pagingLink[] = " $page "; // no need to create a link to current page
} else {
if ($page == 1) {
$pagingLink[] = " $page ";
} else {
$pagingLink[] = " $page ";
}
}
}
$pagingLink = implode(' | ', $pagingLink);
// return the page navigation link
$pagingLink = $first . $prev . $pagingLink . $next . $last;
}
return $pagingLink;
}
im calling it like:
$sql = "something";
$result = mysql_query(getPagingQuery($sql, $rowsPerPage));
$pagingLink = getPagingLink($sql, $rowsPerPage, $url);
now if my url is like
http://xyz/abc/list.php its working fine.
but when my url is like
http://xyz/abc/list.php?action=def
after i click on page 2 the url changes like http://xyz/abc/list.php?page2&
'action=def' part is gone so the result changes.
if i use to pass the value in $strGet as $_SERVER['QUERY_STRING']
the 1st time it is ok like http://xyz/abc/list.php?page2&action=def
but from the 2nd time onwards it gives like http://xyz/abc/list.php?page3&page2&action=def
so not getting the desired result.
whereas i want it to be like http://xyz/abc/list.php?page3&action=def
plz help.. thanxx in advance
So I consider you use $_GET['page'] ^^
$_GET['page']=$page;
$url = 'http://xyz/abc/list.php?';
foreach($_GET as $key=>$param) {
$url.=$key.'='.$param.'&';
}
use http_build_query() instead of $_SERVER['QUERY_STRING']
What i would do is before setting $page = url code. i would first echo $page before and after setting it. so that i can see exactly what the values are. And i would print echo statements before and after everytime i set $page with the url to make sure it is correct. and if in any place you can see that its not the desired output because you can see that from the echo statements then you can make the right changes to make sure the $page variable is set properly.
what i would do then to set it properly is clear the $page variable and make sure that the $page variable is then set freshly with the url.
also when setting the url make sure that the $strGet variable is also echoed out first to make sure that it is the right value that you want to set. and then set the url to the $page variable.
By doing this simple debugging you are making sure all the values are correct first and you know it is before setting them.
give it a go
let me know what happens
PK

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