I'm having a hard time setting up simple links/actions.
In my index view, I have this little form that I want to launch the getTest action in the ProjectsController when I click on the button:
{{ Form::open(array('action' => array('ProjectsController#getTest', $project->id))) }}
<button type="submit"><i class="icon-arrow-up"></i></button>
{{ Form::close() }}
This is the getTest function :
public function getTest(){
echo "test";
return 'test';
}
But this keeps getting me a "Array_combine(): Both parameters should have an equal number of elements" error.
I tried making this work with a route. with this form open instead :
{{ Form::open(['method' => 'GET', 'route' => ['test_route', $project->id]]) }}
And this route :
Route::get('projects/test', array('as' => 'test_route', 'uses' =>'ProjectsController#getTest'));
But I still have the same error.
I can't find any good doc on routing/sending to actions that don't give me this problem. I don't see what
Your route doesn't need parameter, so I think this code is sufficient:
{{ Form::open(['method' => 'GET', 'route' => 'test_route']) }}
I believe the problem is you are adding parameters to the action, but you are not managing those parameters in your routes, nor is your getTest() function accepting any parameters. Another problem is you are setting your route as a GET route, but your form is going to be using POST.
It would be much easier instead on your form to use Form::hidden('id', $project->id); And then in your getTest() function, you could get the variable using $id = Input::get('id');. You'd also be able to use your route name in your form as well. Form::open(array('route'=> 'test_route', method=> 'get'));
Related
I have abstracts table in my database with the Abstract_Status_ID column, I am trying to create a button that changes every Status from '2' to '3'
I have tried to do this:-
My controller
public function publish($A_ID)
{
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
my route
Route::put( '/projects', 'AbstractsController#publish');
Route::post( '/projects', 'AbstractsController#publish');
my view (projects)
Tried with the csrf token and without as eloquent docs says any post/put will be restricted without it.
#if (count ($abstracts)> 0)
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{!! Form::open(['action' => ['AbstractsController#publish' , $abstract->A_ID], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
#endif
#endforeach
The error I am getting when clicking the button
(1/1) ErrorException
Missing argument 1 for App\Http\Controllers\AbstractsController::publish()
Also, the code above will show more than one button, any suggestions to make one button change all of them ?
A: If you want to have a button for each ABSTRACTS just change your route to :
Route::put( '/projects/{A_ID}', 'AbstractsController#publish');
B: If you want to have only one button that change all , you can echo their ID in hidden input then send form
so your view would be:
#if (count ($abstracts)> 0)
{!! Form::open(['action' => ['AbstractsController#publish'], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{{Form::hidden('abstract_ids[]', $abstract->A_ID) }}
#endif
#endforeach
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
And Your Controller :
public function publish()
{
foreach(request('abstract_ids') as $A_ID){
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
}
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
You are using form method="POST". I think it should be method="PUT".
The main problem in your code is the definition of your routes, You are passing an argument ($A_ID) to the controllers publish method,
But in your routes, you did never mention that you are passing any argument through your route. So for passing the argument, you can use {$A_ID} in your route URL.
One thing you should always remember is that you should always give your route a name and call it by using its name and route() Laravel helper method.
The benefit of using route name is that if you decide to change the URL-Structure of your route later in the development process, you'll never have to change it everywhere in your application because you did not call it by its URL.
And route name is less error prone
In total, You should define your routes like this
Route::put('projects/{A_ID}/update', 'AbstractsController#publish')->name('projects.update');
Route::post('projects/{A_ID}/post', 'AbstractsController#publish')->name('projects.store');
Then in you blade files now you can call it like
{!! Form::open(['action' => route('projects.store', $abstract->A_ID), 'method' => 'post' ]) !!}
Hope this will clarify and resolve your problem.
I want to create a form so when I click submit it goes to root url with post method. I created following
{{ Form::open(array('route' => array('send'), 'method' => 'post')) }}
...
{{ Form::close() }}
and in routes
Route::get('/', 'Controller#home');
Route::post('/', 'Controller#home')->name('send');
But the $request value from controller is null and the method is get instead of post.
No need to use method=>post with route, it is used with url read in docs. Change your Form::open like as below
Either
{{ Form::open(['route' => 'send']) }}
Or
{{ Form::open( ['url' => '/','method' => 'post'] ) }}
You have two route with identical beginnings ("\") pointing to the same controller function.
Try replacing the second one with something like
Route::post('/home', 'Controller#homepost')->name('send');
Just duplicate your home method and make sure you have something like:
public function homepost (Request $request)
{ .... }
You can use Route::any() If you want same url or function to response with multiple type requests like get, post etc.
Route::any('/', 'Controller#home');
Or you could use Route::match().
Route::match(['get', 'post'], '/', Controller#home');
I must be missing something really simple but I can't seem to find it. So I have my Resource defined in my routes.php but I need an additional route for an advanced search page with filters and stuff, my show/update/edit/create... pages are working perfectly but my search page isn't.
So in routes I have:
Route::resource('hostesses', 'HostessesController');
Route::get('/hostesses/search', 'HostessesController#search');
And I have a search form on my main page like this:
{{ Form::open(array('route' => 'hostesses.search', 'class' => 'navbar-form navbar-right')) }}
<div class="form-group">
{{ Form::text('search_term', '', array('class' => 'form-control')) }}
</div>
{{ Form::submit('Submit', array("class"=>'btn btn-default')) }}
{{ Form::close() }}
And when I use the search form I get the NotFoundHttpException
In my controller I have:
public function search()
{
return View::make('hostesses.search');
}
And I have created the template on views/hostesses/search.blade.php with a simple hello world message to check that it works, but I keep getting the exception!
Change the order of your routes and 'define' the named route of hostesses.search which is in your form
Route::any('/hostesses/search', array(['as' => 'hostesses.search', 'uses' => 'HostessesController#search');
Route::resource('hostesses', 'HostessesController');
Because what is happening is the resource for /hostesses/$id is capturing the search id, and returning an error that id of search does not exist
Also - change your route to Route::any(). This means it will respond to "get" and "post" requests.
However I would recommend splitting your route to be getSearch() and postSearch() functions and do this:
Route::get('/hostesses/search', array(['as' => 'hostesses.getsearch', 'uses' => 'HostessesController#getSearch');
Route::post('/hostesses/search', array(['as' => 'hostesses.postsearch', 'uses' => 'HostessesController#postSearch');
Route::resource('hostesses', 'HostessesController');
public function getSearch()
{
return View::make('hostesses.search');
}
public function postSearch()
{
// Do validation on form
// Get search results and display
}
And update your form
{{ Form::open(array('route' => 'hostesses.postsearch', 'class' => 'navbar-form navbar-right')) }}
You need to define a POST route:
Route::post('/hostesses/postSearch',array('as'=>'hostesses.search','uses' => 'HostessesController#postSearch'));
Then in your controller
public function postSearch()
{
var_dump(Input::get('search_term'));
}
I am building a practice app with the Laravel framework I built a form in one of the views which is set to post to the same view itself but when I hit submit the form is posted however I do not get the desired output, I see the original view again.
Here is my view index.blade.php
#extends('master')
#section('container')
<div class="wrapper">
{{ Form::open(array('url' => '/', 'method' => 'post')) }}
{{ Form::text('url') }}
{{ Form::text('valid') }}
{{ Form::submit('shorten') }}
{{ Form::close() }}
</div><!-- /wrapper -->
#stop
and my routes.php
Route::get('/', function()
{
return View::make('index');
});
Route::post('/', function()
{
return 'successfull';
});
What I've tried so far
I tried changing the post to a different view and it worked.
However I want the form to post to the same view itself.
Instead of returning a string I tried to return make a view still it
didn't work.
What am I doing wrong?
addendum
I see that when the form is making the post request I am getting a 301 MOVED PERMANENTLY HEADER
{{ Form::open(array('url' => ' ', 'method' => 'post')) }}
Passing a space as the url has worked for me.
I think this post: Form submits as GET Laravel 4 is related to your problem. I think the problem as I undersood it is caused by end a form url with a / . I found this when having problems to using post to a ./ url in my form. There is also a bug at github that seems like it is related https://github.com/laravel/framework/issues/1804.
I know this is an old question but I found this thread having the same problem so hopefully someone else is helped by my answer.
You need to make sure that your form's method does NOT end in a / for it to be routed correctly. For example if you have the following route:
Route::post('form/process', function()
{
# code here ...
});
Then you need to have the following form definition:
<form action="/form/process" method="POST">
I hope that helps.
I have same problem with OSx + MAMP, initially I've resolved with Raul's solution:
{{ Form::open(array('url' => ' ', 'method' => 'post')) }}
but after consultation with my friend we have concluded that my problem was due to the fact
my lavarel project is avaliable by long local path, as:
http://localhost/custom/custom2/...
in this location the post/get method on root path ("/") not working correctly.
Lavarel to working correctly must be avaliable by "vhost", in this case the problem get/post method on root location "/" not exist.
My friend advised me to use http://www.vagrantup.com/
BYE
There is some helpfull information in the Laravel Docs. Check these out:
Resource Controllers (or RESTful Controllers)
Forms & HTML
Opening A Form
Routing
Named Routes
I recommend you read the Resource Controllers documentation as it makes form handling a lot easier.
Well, you just return the view, so nothing change. You should bind your route to a controller to do some logic and add data to your view, like this:
index.blade.php
#extends('master')
#section('container')
<div class="wrapper">
#if (isset($message))
<p>{{$message}}</p>
#endif
{{ Form::open(array('url' => '/', 'method' => 'post')) }}
{{ Form::text('url') }}
{{ Form::text('valid') }}
{{ Form::submit('shorten') }}
{{ Form::close() }}
</div><!-- /wrapper -->
#stop
Your routes
Routes::any('/', 'home#index');
You controller HomeController.php
public function index()
{
$data = array();
$url = Input::get('url');
if ($url)
$data['message'] = "foo";
return View::make('index', $data);
}
You can also modify your current routes without using a controller like this (use the new view file)
Route::get('/', function()
{
return View::make('index');
});
Route::post('/', function()
{
return View::make('index')->with('message', 'Foo');
});
The problem is with defualt slashed in Apache from 2.0.51 and heigher:
http://httpd.apache.org/docs/2.2/mod/mod_dir.html#directoryslash
The best solution if you do not want to change Apache config is to make the post in a different path:
GOOD:
Route::get('/',
['as' => 'wizard', 'uses' => 'WizardController#create']);
Route::post('wizard-post',
['as' => 'wizard_store', 'uses' => 'WizardController#store']);
NOT GOOD:
Route::get('/',
['as' => 'wizard', 'uses' => 'WizardController#create']);
Route::post('/',
['as' => 'wizard_store', 'uses' => 'WizardController#store']);
Form :
{{ Form::open(array('url' => 'user/create', 'files' => true)) }}
Route :
Route::resource('user', 'UserController');
UserController.php
class UserController extends BaseController {
public function index()
{
return 'hi11';
//return View::make('home.index');
}
public function create()
{
return 'hi22';
//return View::make('home.index');
}
}
This code gives
Symfony \ Component \ HttpKernel \ Exception \ MethodNotAllowedHttpException
I'd just like to add my own discovery along these lines... Maybe this will save someone else the head-scratching I just performed.
I too implemented the Route::resource mechanism. I couldn't figure out why my create was working but my update was not. It turns out you can't reuse the same form code exactly, the form that does an update must use the method PUT or PATCH. Why update couldn't be a POST is beyond me.
That is to say, the opening form tag for an update must look like this:
Form::model($thing, array(
'method' => 'PUT',
'route' => array('things.update', $thing->id)
)
Without specifying method => PUT, you get this not-helpful error.
Because in your roures you use resourse controller, you can use only specific paths and actions, described in documentation http://laravel.com/docs/controllers#resource-controllers.
user/create ( UserController::create ) is where you need to show the form for adding a new user.
The actual storage of the user should be done in user/store i.e. your form must be send data to UserController::store() method.
In your case if you POST your form only to 'url' => 'user', this should automatically send data to the correct method.
Laravel 4 resources have named routes - just use those:
{{ Form::open(array('route' => 'user.create', 'files' => true)) }}
this is how I'm doing it, it might help someone, can be improved, but this would be main idea.
#if(isset($data))
{{ Form::open(['route'=>['blog.update', isset($data) ? $data->slug : null],'method' => 'patch','role' => 'form', 'class' => 'blog-form form-horizontal']) }}
#else
{{ Form::open(['route'=>'blog.store','role' => 'form', 'class' => 'blog-form form-horizontal']) }}
#endif