I'm using cakephp-upload plugin of jose gonzalez to upload images to our app. By default, they're being saved in a directory like this: webroot/files/user/photo/{user_id} which is fine, except for when we want to display such images using $this->Html->image() which searches for images in the webroot/img directory.
I have already tried to display the images with
echo $this->Html->image('../files/user/photo/' .
$user['User']['photo_dir'] . '/' .
$user['User']['photo']);
which works but I was wondering if there's some way to tell this plugin to save into the img directory? The documentation doesn't mention any of that.
And also, is there any way to tell the $this->Form->input('User.photo', array('type' => 'file')); to accept only image files?
as you can see in this file, path is set like:
public $defaults = array(
'rootDir' => null,
'pathMethod' => 'primaryKey',
'path' => '{ROOT}webroot{DS}files{DS}{model}{DS}{field}{DS}',
...
you could change it to make:
'path' => '{ROOT}webroot{DS}img{DS}'
and for your second question, you could use accept attribute, like:
$this->Form->input('User.photo',
array(
'type' => 'file',
'options' => array('accept' => 'image/*')
)
);
Related
I am beginner in wordpress. I have to upload a file in the subfolder of root(http://www.domain.com/myfoldername) for a special post. It will work only for a special post, not for all. No need to change my default directory and I wan't not use any plugin.
Can anyone help me to do this? I already searched, but didn't get any solution.
Thanks
Through WordPress you can only upload files in the default upload directory. If you don't want to use any plugin, you cannot upload file in a different directory. You can upload file anywhere you want through FTP and then just put the link of the file in the post.
Try this code for your specific page.
add_filter('upload_dir', 'upload_image_specific_calback');
function upload_image_specific_calback( $param ){
//$_GET['post'] which is your target post like 10 is post id.
//After click update button.
if(isset($_GET['post'])){
if($_GET['post'] == 71){
$param = array(
'path' => get_home_path().'myfoldername',
'url' => home_url().'/myfoldername',
'subdir' => '',
'basedir' => get_home_path(),
'baseurl' => home_url(),
'error' => false
);
}
}
//$_POST['post_id'] which is your target post like 10 is post id.
//instant upload time before save
if(isset($_POST['post_id'])){
if($_POST['post_id'] == 71) {
$param = array(
'path' => get_home_path().'myfoldername',
'url' => home_url().'/myfoldername',
'subdir' => '',
'basedir' => get_home_path(),
'baseurl' => home_url(),
'error' => false
);
}
}
error_log("path={$param['path']}");
error_log("url={$param['url']}");
error_log("subdir={$param['subdir']}");
error_log("basedir={$param['basedir']}");
error_log("baseurl={$param['baseurl']}");
error_log("error={$param['error']}");
return $param;
}
I'm trying to create a XML import module that will convert given file to CSV format and then use that CSV to import categories and products.
I have a working configuration page made with getContent() it basically calls a method that generates this form via $helper->generateForm(). $helper is a HelperForm() object.
protected function getConfigForm()
{
return array(
'form' => array(
'legend' => array(
'title' => $this->l('Settings'),
'icon' => 'icon-cogs',
),
'input' => array(
array(
'type' => 'file',
'label' => $this->l('XML file'),
'name' => 'XMLIMPORT_XML_FILE',
'desc' => $this->l('Select file you wish to import.'),
'required' => true
),
array(
'col' => 3,
'type' => 'text',
'prefix' => '<i class="icon icon-envelope"></i>',
'desc' => $this->l('Enter a valid email address'),
'name' => 'XMLIMPORT_LINES',
'label' => $this->l('Records per file'),
),
),
'submit' => array(
'title' => $this->l('Save'),
),
),
);
}
I need to get this data to my XML converter. How do I upload a file (around 10-20MB) to Prestashop to be then able to do other stuff with it? How to save it permanently on the server?
I tried doing this:
return array(
'XMLIMPORT_XML_FILE' => Configuration::get('XMLIMPORT_XML_FILE', null),
'XMLIMPORT_LINES' => Configuration::get('XMLIMPORT_LINES', 1000)
);
And after that this:
$form_values = $this->getConfigFormValues(); // returned array from above
foreach (array_keys($form_values) as $key)
Configuration::updateValue($key, Tools::getValue($key));
And later using my own class for XML conversion like this, hoping that it will give me file handle.
$xml_converter = new XMLToCSVConverter(Configuration::get('XMLIMPORT_XML_FILE'), 'output', 'example_products.php');
Apparently it didn't as nothing happens. The class itself is working fine outside of Prestashop module. The constructor is __construct($xml_file, $csv_filename, $template_file).
I need to pass the file I upload to that constructor. I've been struggling for days now.
#edit: I can see the contents of the file inside the HTTP call when submit is clicked. But how do I pass that file to my class?
As far as I remember 'type' => 'file', doesn't actually save any values in the database. This type is only meant to output a file field in your form.
After submitting, you should then do you custom processing with $_FILES['XMLIMPORT_XML_FILE'] : move to upload/ or whereever you want.
'XMLIMPORT_XML_FILE' => Configuration::get('XMLIMPORT_XML_FILE', null), won't return you anything. After uploading you my wish to save the uploaded file path here, but it won't show up next time in the form unless you build the output yourself.
Module configratuon is meant to save text config values. Handling files is trickier and you have to do them yourself each time.
EDIT:
To intercept the saving process, look up the submit button name and make an if statement:
public function getContent() {
if(Tools::isSubmit('submitButtonName')) {
error_log(print_r($_FILES, 1));
}
}
There's probably a function postProcess which does the same (it looks like you copied the methods from a default module).
prestashop handles the image upload with ImageManager class, this class contains more methods which are useful for handling image upload, resize etc.. so its better refer the default homeslider module for the image upload using a module. This module is handling the image upload process in postProcess method with the help of ImageManager class, this class methods will do the all the processes related to upload.
I am working on a module for Drupal 7. I have a template defined for my content type as node--[content type].tpl.php and placed it in the "themes/[selected theme]/template" directory. I want to keep this template in my "module" directory instead. So when the module is installed I don't have to place the file in to the selected theme folder every time. Is there a way to do this?
Thank you all in advance.
I have less than 10 rep so I cant answer my own question so I'll just modify the question
The following is working for me some how. For both case node edit form view and node view
function [content type]_theme() {
return array(
'[content type]_node_form' => array(
'arguments' => array(
'form' => NULL,
),
'template' => 'node--[content type]--edit',
'render element' => 'form',
),
'node__[content type]' => array (
'variables' => array(),
'template' => 'node--[content type]' ,
'base hook' => 'node',
'path' => "sites/all/modules/[content type]_update/[content type]_update/[content type]/",
),
);
}
I don't completely understand this but it's working.
This link should get you going:
http://www.wdtutorials.com/2011/06/13/drupal-7-how-create-custom-theme#.U6sZ741dXag
You basically want to create a new custom theme.
In addition to the above tutorial, create a new folder 'templates' and add your .tpl files in there instead of the core themes folder.
You can use the below format to specify the template path. Then you can place the tpl file in your module folder.
function MODULENAME_theme() {
return array(
'yourcustom_theme' => array(
'template' => 'mypage', // template file called mypage.tpl.php
'path' => drupal_get_path('module', 'MODULENAME'),
)
);
}
I'm using the Magento Soap Api to upload pictures of products. I can't seem to specify the name I wish Magento so save the file as on the server even though I specify the "name" as per the Magento documentation.
I'm using Magento 1.2.1.2 and can't upgrade as the site uses modules that break in newer version.
Any thoughts on how I can specify the file name that Magento saves the image as?
The code I'm using:
$client->call(
$session_id,
'catalog_product_attribute_media.create',
array(
$sku,
array(
'file' => array(
'content' => base64_encode(file_get_contents($filename)),
'mime' => $imageinfo['mime'],
'name' => $filename
),
'label' => $description,
'types' => array(
'image',
'small_image',
'thumbnail'
),
'exclude' => FALSE
)
)
);
You can't specify the filename. The only solution would be for you change the Magento files to allow a filename as suggested in this thread. For your convenience I've included the solution below (and adapted it based on the fact that you're sending the filename as name above):
Modify ./app/code/core/Mage/Catalog/Model/Product/Attribute/Media/Api.php:
You'll want to replace $fileName = 'image.' . $this->_mimeTypes[$data['file']['mime']]; with:
if ( ! empty($data['file']['name']) )
$fileName = $data['file']['name'];
else
$fileName = 'image.' . $this->_mimeTypes[$data['file']['mime']];
If you feel a little more adventurous, you could extend the class instead of changing it and override the create function with your own functionality.
I want to download 4 different files through 4 different links. I am using the Media view to download the files, but I have to hardcode the file name in the download functions in the controller:
function download () {
$this->view = 'Media';
$params = array(
'id' => 'example.zip',
'name' => 'example',
'download' => true,
'extension' => 'zip',
'path' => APP . 'files' . DS
);
$this->set($params);
}
This works fine for one file. Now, for links number 2,3,4, do I need to create 3 different actions and give different file names in them, or is there a way in which I can use download() to only download the respective file depending on which link has been clicked?
That's what variables are for. Generic example:
function download($fileId) {
$file = // find the file you want to serve based on $fileId
$pathInfo = pathinfo($file['path']);
$this->view = 'Media';
$params = array(
'id' => $file['name'],
'name' => $pathInfo['filename'],
'extension' => $pathInfo['extension'],
'download' => true,
'path' => APP . 'files' . DS
);
$this->set($params);
}
In CakePhp 2.x you will get error The view for YourController::download() was not found.
Use viewClass field in CakePHP 2.x:
$this->viewClass = 'Media';
See Media Views — CakePHP Cookbook v2.x documentation
UPD: Media Views are deprecated since CakePHP 2.3, and CakeResponse::file() should be used:
$this->response->file($file['path'], array('download' => true, 'name' => 'foo'));
return $this->response;