Checking if variable is empty - php

Question

First I will paste my code than explain.
while($row = mysqli_fetch_assoc($result)) {
$id=$row['id'];
$username=$row['username'];
$email=$row['email'];
$firstname=$row['firstname'];
$lastname=$row['lastname'];
$motto=$row['motto'];
$bio=$row['bio'];
$result4 = mysqli_query($link, "SELECT * FROM photo where id='$id'");
while($row4 = mysqli_fetch_assoc($result4))
{
$image=$row4['filename'];
$src = (empty($image)) ? "upload/your-photo.jpg" : "site_images/$id/$image";
}
As you can tell the problem has to do with the image. I'm thinking the problem is where it SELECTS * FROM photo where id='$id' because this is in a while loop and if it is empty like it says in $src than it just moves on to the next person in line.
I was wondering how it would be possible to make this work? Right now it is just displaying the same image for every id when it should show the correct image.

Answer 1

You should just have one query with a join in it, to join the photo table.

Answer 2

I would try breaking out the conditional where you have the inner loop:
$result4 = mysqli_query($link, "SELECT * FROM photo where id='$id'");
while($row4 = mysqli_fetch_assoc($result4))
{
$image=$row4['filename'];
$src = "upload/your-photo.jpg";
if(!empty($image)) {
$src = "site_images/$id/$image";
}
}
If that doesn't work, try using:
strlen
and checking if it's equal to 0
Also, in your database, does your photo table have rows with with IDs but no photo file specified? Perhaps you are querying an empty table..