trying to Join 2 table query in Fluent laravel 4 - php

Im trying to Joing 2 table in Fluent trough my Model i run the query on mysql client and give me the return i want.
this is the standard query
select `songlist`.*, `queuelist`.* from `songlist` inner join `queuelist` on `songlist`.`id` = `queuelist`.`songID` where `queuelist`.`songID` = songlist.ID and `songlist`.`songtype` = 'S' and `songlist`.`artist` <> "" order by `queuelist`.`sortID` ASC limit 4
it does return the data im looking for.
now on my model using fluent.
i did like this.
public static function comingUp()
{
$getcomingUp = DB::table('songlist')
->join('queuelist', 'songlist.id', '=', 'queuelist.songID')
->select('songlist.*','queuelist.*')
->where('queuelist.songID', '=', 'songlist.ID')
->where('songlist.songtype', '=', 'S')
->where('songlist.artist', '<>', '')
->orderBy('queuelist.sortID', 'ASC')
->take('4')
->get();
return $getcomingUp;
}
and my controller to test if i get the data look like this
public function getComingUp()
{
$getcomingUp = Radio::comingUp();
foreach ($getcomingUp as $cup)
{
echo $cup->title;
}
// return View::make('comingup', compact('comingup'));
}
as you can see the foreach is no returning any data there is nothing wrong with the query because laravel give me no error at all. but i cant just get the foreach to display the data im looking for.
i try with $cup->songlist.title;
and it dont work ether.
Thanks any help will be appretiated. againg sorry for my English.

You can do something like this.
public static function comingUp()
{
$getcomingUp = DB::table('songlist')
->select('songlist.*','queuelist.*')
->join('queuelist', 'queuelist.songID', '=', 'songlist.id')
->where('songlist.songtype', '=', 'S')
->where('songlist.artist', '<>', '')
->orderBy('queuelist.sortID', 'ASC')
->take('4')
->get();
return $getcomingUp;
}

Related

Trending query Laravel

Right now I have a subquery to get the count of payments for the current month and then getting the 4 products with the highest payment_count. This query works fine but I'm wondering if there's a more simple way to do the same since its getting difficult to read.
$latestPayments = DB::table('payments')
->select('product_id', DB::raw('COUNT(*) as payments_count'))
->whereMonth('created_at', Carbon::now()->month)
->groupBy('product_id');
$trendingProducts = DB::table('products')
->joinSub($latestPayments, 'latest_payments', function ($join) {
$join->on('products.id', '=', 'latest_payments.product_id');
})->orderBy('payments_count', 'DESC')->take(4)->get();
This did it!
$trendingProducts = Product::withCount(['payments' => function($query) {
$query->whereMonth('created_at', Carbon::now()->month);
}])->orderBy('payments_count', 'DESC')->take(4)->get();
If you are using eloquent query with relational database you can do like this:
$latestPaymentWithTrendingProduct = App\Payment::with(['products', function($product) {
$product->orderBy('payments_count', 'DESC')->take(4);
}])->whereMonth('created_at', date('m'))->get()->groupBy('product_id');
This will lessen the code but still do the same thing.

Want to call data from an array

public function showJobCategoryContent($id)
{
$jobsInfo= Job::where('category_id', '=', $id)->where('published', '=', 1)->paginate(3);
return $jobsInfo->company_name;
}
public function showJobCategoryContent($id)
{
$jobsInfo= Job::where('category_id', '=', $id)->where('published', '=', 1)->paginate(3);
return $jobsInfo['company_name'];
}
If i do that it shows --Undefined property also if i use return $jobsInfo['company_name'] now it shows blank page I know there is company_name index also i tried another index also. Why is it doing that?
Your main problem is not understanding what is returned by a paginate query. Have a good read of the docs for this https://laravel.com/docs/5.5/pagination#paginating-query-builder-results
That being said there are better ways of doing this with Laravel.
return Job::where('category_id', '=', $id)->select('company_name')->where('published', '=', 1)->get();
Will return a Collection of just company_name using the select function in the query builder.
https://laravel.com/docs/5.5/queries#selects

How to fetch users not assigned to a particular role in Laravel [duplicate]

In Laravel we can setup relationships like so:
class User {
public function items()
{
return $this->belongsToMany('Item');
}
}
Allowing us to to get all items in a pivot table for a user:
Auth::user()->items();
However what if I want to get the opposite of that. And get all items the user DOES NOT have yet. So NOT in the pivot table.
Is there a simple way to do this?
Looking at the source code of the class Illuminate\Database\Eloquent\Builder, we have two methods in Laravel that does this: whereDoesntHave (opposite of whereHas) and doesntHave (opposite of has)
// SELECT * FROM users WHERE ((SELECT count(*) FROM roles WHERE user.role_id = roles.id AND id = 1) < 1) AND ...
User::whereDoesntHave('Role', function ($query) use($id) {
$query->whereId($id);
})
->get();
this works correctly for me!
For simple "Where not exists relationship", use this:
User::doesntHave('Role')->get();
Sorry, do not understand English. I used the google translator.
For simplicity and symmetry you could create a new method in the User model:
// User model
public function availableItems()
{
$ids = \DB::table('item_user')->where('user_id', '=', $this->id)->lists('user_id');
return \Item::whereNotIn('id', $ids)->get();
}
To use call:
Auth::user()->availableItems();
It's not that simple but usually the most efficient way is to use a subquery.
$items = Item::whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
})
->get();
If this was something I did often I would add it as a scope method to the Item model.
class Item extends Eloquent {
public function scopeWhereNotRelatedToUser($query, $user_id)
{
$query->whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
});
}
}
Then use that later like this.
$items = Item::whereNotRelatedToUser($user_id)->get();
How about left join?
Assuming the tables are users, items and item_user find all items not associated with the user 123:
DB::table('items')->leftJoin(
'item_user', function ($join) {
$join->on('items.id', '=', 'item_user.item_id')
->where('item_user.user_id', '=', 123);
})
->whereNull('item_user.item_id')
->get();
this should work for you
$someuser = Auth::user();
$someusers_items = $someuser->related()->lists('item_id');
$all_items = Item::all()->lists('id');
$someuser_doesnt_have_items = array_diff($all_items, $someusers_items);
Ended up writing a scope for this like so:
public function scopeAvail($query)
{
return $query->join('item_user', 'items.id', '<>', 'item_user.item_id')->where('item_user.user_id', Auth::user()->id);
}
And then call:
Items::avail()->get();
Works for now, but a bit messy. Would like to see something with a keyword like not:
Auth::user()->itemsNot();
Basically Eloquent is running the above query anyway, except with a = instead of a <>.
Maybe you can use:
DB::table('users')
->whereExists(function($query)
{
$query->select(DB::raw(1))
->from('orders')
->whereRaw('orders.user_id = users.id');
})
->get();
Source: http://laravel.com/docs/4.2/queries#advanced-wheres
This code brings the items that have no relationship with the user.
$items = $this->item->whereDoesntHave('users')->get();

Limit result per category with Laravel 4.2 MySQL query

I've to build a research system for an announcements website. We can search through categories or via the announcement city.
When someone research something I want to set a limit of results per category (example : 3) using Eloquent.
I know this isn't easy at all, even in raw SQL, and it's been hours i'm trying to find a way without success. I tried to add a closure in the query but it's very hard for me to understand how to use that properly ...
I understood i needed to make a subquery to do the trick, but it's also tricky to know how to organize all this.
The workbench (followed by the current query which isn't working) :
Here's the controller with the query :
$announcements = Announcement::select('announcements.*')
->withCitySlug($location)
->withCategory($category_id)
->perCategoryLimit(3)
->get();
The model Announcement (the interesting part) :
/**
* HasManyThrough
*/
public function categories()
{
return $this->belongsToMany('Category', 'announcement_categories');
}
public function scopeWithCitySlug($query, $city_slug) {
if (empty($city_slug)) return $query;
return $query->where('city_slug', 'LIKE', '%'.$city_slug.'%');
}
public function scopeWithCategory($query, $category_id) {
if ($category_id === FALSE) return $query;
return $query->join('announcement_categories', 'announcement_categories.announcement_id', '=', 'announcements.id')
->join('categories', 'categories.id', '=', 'announcement_categories.category_id') ->where('categories.id', '=', $category_id);
}
public function scopePerCategoryLimit($query, $limit) {
return $query;
/*return $query->with(array('categories' => function($q)
{
$q->limit(3)->get();
}));*/
}
Any Eloquent/SQL expert around here ? A little help in the way to solve this would be perfect ;)
PS : If i didn't give enough code to understand the problem, just let me know !
Well, you can select all categories and use an foreach with a limit to get all results or use partition by from sql.

Laravel: Sort Table Joined Using 'With' Clause

I'm using Laravel 4 and Eloquent ORM. I'm currently pulling records from my database using the following code:
public function index($type, $id)
{
$asset = Asset::where('public_id', '=', $id)
->with('attachments')
->with('attachments.attachment')
->with('tracks')
->with('tracks.track')
->where('locale', '=', Config::get('app.locale'))
->first();
return View::make('view-asset.index')
->with('asset', $asset)
->with('type', $type);
}
The table joined to this query using the with('tracks') statement has a column in it called track_order - I would like to be able to sort the rows returned by this part of the query by that column so that the tracks stored in the database are returned in the correct order.
Is it possible to do this and if so, how should I do it? So far I've tried something like this:
public function index($type, $id)
{
$asset = Asset::where('public_id', '=', $id)
->with('attachments')
->with('attachments.attachment')
->with('tracks')
->with('tracks.track')
->where('locale', '=', Config::get('app.locale'))
->orderBy('tracks.track_order', 'ASC')
->first();
return View::make('view-asset.index')
->with('asset', $asset)
->with('type', $type);
}
Which doesn't work and I can't figure out a way of doing this other than splitting things up into multiple queries.
You most certainly can:
with(['tracks' => function($query)
{
$query->orderBy('track_order', 'asc');
}])
Refer to Eager Loading Contraints in the documentation for more.

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