how to set a relation with empty value? - php

I have 2 tables namely Equipment and Supply.
I have used array_merge in yii php to serve as union for two different tables for the purpose of diplaying them in a single grid.
Everything works fine with the fields that is common with the two tables. The problem is when I try to display a field that is only existing in one of these two tables. It says Property "Supply.equipType" is not defined" because only equipment has the equipType relation.
in my gridView:
array(
'name'=>'equipment_type',
'value'=>'$data->equipType->name',
),
in my controller where I did the merging:
$prov1 = new CActiveDataProvider('BaseEiEquipItem', array(
'criteria' => array(
'condition' => 'id>0'
)));
$prov2 = new CActiveDataProvider('BaseSiReceivedItem', array(
'criteria' => array(
'condition' => 'id>0'
)));
$records=array_merge($prov1->data , $prov2->data);
$provAll = new CArrayDataProvider($records,
array(
'sort' => array( //optional and sortring
'keyField'=>false,
'attributes' => array(
'id', 'description',),
),
'pagination' => array('pageSize' => 10) //optional add a pagination
)
);
$this->render('create',array(
'model'=>$model,
'searchModel'=>$searchModel,
'modelGrid'=>$modelGrid,
'provAll' => $provAll,
));
in my equipment model :
public function relations() {
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'equipType' => array(self::BELONGS_TO, 'BaseRefEquipmentType', 'equipment_type'),
);
}
Any idea on how to solve this? Is there any way to fake a relation or something?
thanks in advance

Just add condition to check if equipType is there:
'value'=>'isset($data->equipType) ? $data->equipType->name : ""'
Using sql to merge results would be better, though.

Can't you just use plain SQL union?
If Equipment has 2 fields (a, b) and Supply has 2 fields (b, c), you can do union like this:
SELECT a, b, null FROM Equipment
UNION ALL
SELECT null, b, c FROM Supply

This problem shows, that it's probably not a good idea to mix different model types in one gridview. If you have a model that has no equipType then it's pretty obvious, that you can't show this column in a gridview. So what would you expect?
As a (dirty) workaround you can add all missing columns as pseudo attributes to the models where they are missing:
public $equipType;

Related

Join tables in Yii

I have a query like this:
SELECT jo . * , pc.checklist_id FROM job_order_candidates jo,
pdpa_checklist pc WHERE jo.job_id = '5755' AND jo.shortlisted = '1'
AND pc.job_id = '5755'
I need to write it in Yii format, how to do it? At the moment I have this code:
$dataProviderSL=new CActiveDataProvider('JobApplication', array(
'criteria'=>array(
'condition'=>'shortlisted='.JobApplication::SL_Y.' AND job_id='.$jobOrder->job_id,
'order'=>'applied_date DESC',
'with'=>array('candidate'),
),
'pagination'=>array(
'pageSize'=>20,
),
));
It's only select single table, I need to select 2 tables. Can anyone help me?
Thanks alot.
It's hard to find the correspondance bewteen your ActiveRecords and your table but you should try something like:
$dataProviderSL=new CActiveDataProvider('JobApplication', array(
'criteria'=>array(
'condition'=>'shortlisted= :shortlisted',
'order'=>'applied_date DESC',
'params' => array(
':shortlisted' => JobApplication::SL_Y,
':job_id' => $jobOrder->job_id,
),
'with'=>array('candidate' => array(
'together' => true,
'condition' => 'job_id= :job_id'
)),
),
pagination'=>array(
'pageSize'=>20,
),
));
I'm note sure if job_id is in the relation or the main model, if you want a more precise answer you have to provide us more infos.
That SQL does not make sense if you are to use CActiveDataProvider philosophy.
CActiveDataProvider would provide you with an array of JobApplication models, which should be stored on the rows of your job_order_candidates table. Since pc.checklist_id belongs to another table, you should have another model that represents those entries, and on your JobApplication class you need a relation with that model. Assuming it would be called PdpaChecklist, your JobApplication would look like this:
class JobApplication extends CActiveRecord {
// your stuff
public function relations() {
return array(
'pdpaChecklist' => array(self::HAS_ONE, 'PdpaChecklist', 'job_id'),
);
}
}
That given, you can query JobApplications as you currently do and access that pc.checklist_id like the following:
foreach ($dataProviderSl->getData() as $jobApplication) {
$jobApplication->pdpaChecklist->checklist_id;
}
Since you will be iterating through JobApplications, it is a good idea to use eager loading, preventing Yii to run a query everytime you do $jobApplication->pdpaChecklist. To do so, include 'pdpaChecklist' to your 'with' statement.
'with'=>array('candidate', 'pdpaChecklist'),
That is probably more work than you would have imagined, but that is how Yii organizes things. When you synergizes with the phylosophy it goes mych easily and faster. Totally worth it.

Multiple M2M in DataMapper ORM issue

I am building a small core piece for my DataMapper ORM library in CodeIgniter to control user's access/edit rights (CRUD) over DataMapper objects itself. For this I want to link a DataMapper Entity, Userrole and Userright together.
The documentation is here http://datamapper.wanwizard.eu/pages/advancedrelations.html (Under head; Multi-table Relationships).
So if I fill in the join table by hand I can just get the values without any problems. The only problem is saving the relationship.
Here are my Model-rules
Userrole
var $has_many = array(
'userright' => array(
'join_table' => 'dm_entities_userrights_userroles',
),
'dm_entity' => array(
'join_table' => 'dm_entities_userrights_userroles',
),
);
Userright
var $has_many = array(
'dm_entity' => array(
'join_table' => 'dm_entities_userrights_userroles',
),
'userrole' => array(
'join_table' => 'dm_entities_userrights_userroles',
),
);
Dm_entity
var $has_many = array(
'userrole' => array(
'join_table' => 'dm_entities_userrights_userroles',
),
'userright' => array(
'join_table' => 'dm_entities_userrights_userroles',
),
);
It seems odd I declared the table twice constantly, but it seems not to work if I don't.
So here's my retrieval code for this relation form the perspective of the Userright;
$userrole = new Userrole;
$userrole->get_where(array('name' => 'Administrator'));
$dm_entity = new Dm_entity;
$dm_entity->get_where(array('name' => 'User'));
$userrights = new Userright;
$userrights->where_related($userrole);
$userrights->where_related($dm_entity)->get();
$output = '';
foreach ($userrights as $userright) {
$output .= '<i><b>'.$userright->name.'</b></i> and ';
}
$output = substr($output, 0, -5);
echo '<b>'.$userrole->name.'</b> has the right to '.$output.' the DataMapper entity <b>'.$dm_entity->name.'</b>.'.br();
So this works without any problems either. But now the saving part:
$new_userright = new Userright;
$new_userright->get_where(array('name' => 'Update'));
$new_userright->save(array($userrole, $dm_entity));
Which results in two entries in the dm_entities_userrights_userroles table where 1 entry has dm_entity_id empty and the other the userrole_id empty.
I hope to avoid making a separate Model for the join table to solve this.
Does anyone know how I can get this to work so it makes one correct entry, instead of two scattered ones?
This is not going to work (as you have noticed).
A relation is between two models, and for each Many to Many relation you need a separate join table.
Although technically you can create a join table with 10 FK's to 10 different models, Datamapper will not be aware of that, and will treat the table as different for every relation, causing duplicates to appear.
The only way to make this work, is to define a model for the join table too, and give that one-to-many relations to each of the other models. You can then use that model to manually add relations by assigning or updating the FK values, and still use the many-to-many relations for retrieval and update.

Is Codeigniter Datamapper other_field must append _id automatically?

I have a problem with Codeigniter Datamapper when Joining table. I have 2 table:
Purchase
purchase_id, ref ...
Stock
stock_id, purchase_ref...
I created a has_many relation :
For purchase:
public $has_many = array(
'stock' => array(
'join_table' => 'stocks',
'other_field' => 'purchase_ref',
'cascade_delete' => TRUE
)
);
For stock:
public $has_one = array(
'purchase'=>array(
'join_other_as' => 'purchase_ref',
'join_table' => 'purchases',
'cascade_delete' => FALSE
)
);
But datamapper seems append _id to the column that I wanna join and it be comes purchase_ref_id
and the sql statement becomes something like:
...LEFT OUTER JOIN "stocks" stocks ON "purchases"."id" = "stocks"."purchase_ref_id"...
Is that anyway to avoid appending _id when joining table in datamapper? thx a lot.
This is a hard coded behaviour (for example here, but in many places in the code) and you can't change it with the current version. I'm afraid you would either have to patch the library's code or change your db schema.

CakeDC search plugin using complex conditions in query with HABTM

I wrote 2 days ago to ask about andConditions and it appeared that I didn't understand the idea but the fact is that for two days now I am stuck with the next step using CakeDC:
How do I implement complex HABTM conditions in "query" methods for CakeDC search plugin?
I have Offer HABTM Feature (tables: offers, features, features_offers) and the below works just fine when used in controller:
debug($this->Offer->find('all', array('contain' => array(
'Feature' => array(
'conditions' => array(
'Feature.id in (8, 10)',
)
)
)
)
)
);
The problem comes when I want to use the same conditions in the search:
public $filterArgs = array(
array('name' => 'feature_id', 'type' => 'query', 'method' => 'findByFeatures'),
);
........
public function findByFeatures($data = array()) {
$conditions = '';
$featureID = $data['feature_id'];
if (isset($data['feature_id'])) {
$conditions = array('contain' => array(
'Feature' => array(
'conditions' => array(
'Feature.id' => $data['feature_id'],
)
)
)
);
}
return $conditions;
}
I get an error:
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column
'contain' in 'where clause'
which makes me think that I cannot perform this search and/or use containable behavior in searches at all.
Can someone with more experience in the field please let me know if I am missing something or point me to where exactly to find a solution for that - perhaps a section in the cookbook?
EDIT: Also tried the joins. This works perfectly fine in the controller, returning all the data I need:
$options['joins'] = array(
array('table' => 'features_offers',
'alias' => 'FeaturesOffers',
'type' => 'inner',
'conditions' => array(
'Offer.id = FeaturesOffers.offer_id'
),
array('table' => 'features',
'alias' => 'F',
'type' => 'inner',
'conditions' => array(
'F.id = FeaturesOffers.feature_id'
),
)
),
);
$options['conditions'] = array(
'feature_id in (13)' //. $data['feature_id']
);
debug($this->Offer->find('all', $options));
... and when I try to put in the search method I get the returned conditions only in the where clause of the SQL
WHERE ((joins = (Array)) AND (conditions = ('feature_id in Array')))
...resulting in error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'joins' in 'where clause'
EDIT: Maybe I am stupid and sorry to say that but the documentation of the plugin sucks a ton.
I double, triple and quadruple checked (btw, have lost already 30 hours at least on 1 filed of the search form facepalm) and the stupid findByTags from the documentation still doesn't make any sense to me.
public function findByTags($data = array()) {
$this->Tagged->Behaviors->attach('Containable', array('autoFields' => false));
$this->Tagged->Behaviors->attach('Search.Searchable');
$query = $this->Tagged->getQuery('all', array(
'conditions' => array('Tag.name' => $data['tags']),
'fields' => array('foreign_key'),
'contain' => array('Tag')
));
return $query;
}
As I understand it
$this->Tagged
is supposed to be the name of the model of the HABTM association.
This is quite far from the standards of cakePHP though: http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#hasandbelongstomany-habtm
The way it is described here, says that you don't need another model but rather you associate Recipe with Ingredient as shown below:
class Recipe extends AppModel {
public $hasAndBelongsToMany = array(
'Ingredient' =>
array(
'className' => 'Ingredient',
'joinTable' => 'ingredients_recipes',
'foreignKey' => 'recipe_id',
'associationForeignKey' => 'ingredient_id',
'unique' => true,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
)
);
}
meaning that you can access the HABTM assoc table data from Recipe without needing to define model "IngredientRecipe".
And according to cakeDC documentation the model you need is IngredientRecipe and that is not indicated as something obligatory in the cakePHP documentation. Even if this model is created the HABTM assoc doesn't work properly with it - I tried this as well.
And now I need to re-write the search functionality in my way, using only cakePHP even though I spent already 30 hours on it... so unhappy. :(
Every time I come to do this in a project I always spend hours figuring out how to do it using CakeDC search behavior so I wrote this to try and remind myself with simple language what I need to do. I've also noticed that although Using the CakeDC search plugin with associated models this is generally correct there is no explanation which makes it more difficult to modify it to one's own project.
When you have a "has and belongs to many" relationship and you are wanting to search the joining table i.e. the table that has the two fields in it that joins the tables on either side of it together in a many-to-many relationship you want to create a subquery with a list of IDs from one of the tables in the relationship. The IDs from the table on the other side of the relationship are going to be checked to see if they are in that record and if they are then the record in the main table is going to be selected.
In this following example
SELECT Handover.id, Handover.title, Handover.description
FROM handovers AS Handover
WHERE Handover.id in
(SELECT ArosHandover.handover_id
FROM aros_handovers AS ArosHandover
WHERE ArosHandover.aro_id IN (3) AND ArosHandover.deleted != '1')
LIMIT 20
all the records from ArosHandover will be selected if they have an aro_id of 3 then the Handover.id is used to decide which Handover records to select.
On to how to do this with the CakeDC search behaviour.
Firstly, place the field into the search form:
echo $this->Form->create('Handover', array('class' => 'form-horizontal'));?>
echo $this->Form->input('aro_id', array('options' => $roles, 'multiple' => true, 'label' => __('For', true), 'div' => false, true));
etc...
notice that I have not placed the form element in the ArosHandover data space; another way of saying this is that when the form request is sent the field aro_id will be placed under the array called Handover.
In the model under the variable $filterArgs:
'aro_id' => array('name' => 'aro_id', 'type' => 'subquery', 'method' => 'findByAros', 'field' => 'Handover.id')
notice that the type is 'subquery' as I mentioned above you need to create a subquery in order to be able to find the appropriate records and by setting the type to subquery you are telling CakeDC to create a subquery snippet of SQL. The method is the function name that are going to write the code under. The field element is the name of the field which is going to appear in this part of the example query above
WHERE Handover.id in
Then you write the function that will return the subquery:
function findByAros($data = array())
{
$ids = ''; //you need to make a comma separated list of the aro_ids that are going to be checked
foreach($data['aro_id'] as $k => $v)
{
$ids .= $v . ', ';
}
if($ids != '')
{
$ids = rtrim($ids, ', ');
}
//you only need to have these two lines in if you have not already attached the behaviours in the ArosHandover model file
$this->ArosHandover->Behaviors->attach('Containable', array('autoFields' => false));
$this->ArosHandover->Behaviors->attach('Search.Searchable');
$query = $this->ArosHandover->getQuery('all',
array(
'conditions' => array('ArosHandover.aro_id IN (' . $ids . ')'),
'fields' => array('handover_id'), //the other field that you need to check against, it's the other side of the many-to-many relationship
'contain' => false //place this in if you just want to have the ArosHandover table data included
)
);
return $query;
}
In the Handovers controller:
public $components = array('Search.Prg', 'Paginator'); //you can also place this into AppController
public $presetVars = true; //using $filterArgs in the model configuration
public $paginate = array(); //declare this so that you can change it
// this is the snippet of the search form processing
public function admin_find()
{
$this->set('title_for_layout','Find handovers');
$this->Prg->commonProcess();
if(isset($this->passedArgs) && !empty($this->passedArgs))
{//the following line passes the conditions into the Paginator component
$this->Paginator->settings = array('conditions' => $this->Handover->parseCriteria($this->passedArgs));
$handovers = $this->Paginator->paginate(); // this gets the data
$this->set('handovers', $handovers); // this passes it to the template
If you want any further explanation as to why I have done something, ask and if I get an email to tell me that you have asked I will give an answer if I am able to.
This is not an issue of the plugin but how you build the associations. You need to properly join them for a search across these three tables. Check how CakePHP is fetching the data from HABTM assocs by default.
http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#joining-tables
Suppose a Book hasAndBelongsToMany Tag association. This relation uses
a books_tags table as join table, so you need to join the books table
to the books_tags table, and this with the tags table:
$options['joins'] = array(
array('table' => 'books_tags',
'alias' => 'BooksTag',
'type' => 'inner',
'conditions' => array(
'Books.id = BooksTag.books_id'
)
),
array('table' => 'tags',
'alias' => 'Tag',
'type' => 'inner',
'conditions' => array(
'BooksTag.tag_id = Tag.id'
)
)
);
$options['conditions'] = array(
'Tag.tag' => 'Novel'
);
$books = $Book->find('all', $options); Using joins allows you to have
a maximum flexibility in how CakePHP handles associations and fetch
the data, however in most cases you can use other tools to achieve the
same results such as correctly defining associations, binding models
on the fly and using the Containable behavior. This feature should be
used with care because it could lead, in a few cases, into bad formed
SQL queries if combined with any of the former techniques described
for associating models.
Also your code is wrong somewhere.
Column not found: 1054 Unknown column 'contain' in 'where clause'
This means that $Model->contain() is somehow called. I don't see such a call in your code pasted here so it must be somewhere else. If a model method can not be found this error usually happens with the field name as column.
I want to share with everyone that the solution to working with HABTM searches with the plugin lies here: Using the CakeDC search plugin with associated models
#burzum, the documentation is far from ok man. Do you notice the use of 'type' => 'checkbox' and that it is not mentioned anywhere that it is a type?
Not to mention the total lack of grammar and the lots of typos and missing prepositions. I lost 2 days only to get a grasp of what the author had in mind and bind the words in there. No comment on that.
I am glad that after 5 days on the uphill work I made it. Thanks anyway for being helpful.

CakePHP 2.x - Virtual fields max foreach items

System
CakePHP 2.x
Database
Houses --> id, name
Visits --> id, date, house_id
Models
Visit belongsTo House
House hasMany Visit
View
I have a view for all houses called houses/index.ctp.
It lists each house with their id and their name.
I also use the PaginatorHelper to sort my array.
Issue
I'd like to see for each house last visit they had.
This have to be sortable by the PaginatorHelper
Tries
I thought that I could do it with virtualFields but I failed (it always returns the max value of all houses).
public $virtualFields = array('lastvisit' => 'SELECT MAX(visits.date) FROM visits, houses WHERE houses.id = visits.house_id GROUP BY house_id');
I tried to "cache" each max visit in a new column of Houses table but it's very dirty.
Thank you for helping.
Declaring a virtual field for this may be tricky, so I suggest you to add it on the fly whenever you need it.
So your HousesController's index action will look like this:
public function index() {
$this->House->virtualFields['last_visit'] = 'MAX(Visit.date)';
$this->paginate = array(
'House' => array(
'group' => array('house_id'),
'joins' => array(
array(
'table' => 'visits',
'alias' => 'Visit',
'type' => 'INNER',
'conditions' => array(
'House.id = Visit.house_id',
)
)
)
)
);
$this->set('houses', $this->paginate());
}
Notice you have to remove the $publicFields declaration from your model, and that I changed the name of the field to from lastvisit to last_visit to make it more Cake.
Hope it helps.
This is pretty simple if you use the Containable behavior.
$this->paginate['House'] = array(
'contain' => array('Visit' => array('order' => 'date DESC')
);
$houses = $this->paginate('House');
I haven't tested this yet but it should be pretty close to what you need. You may want to add a limit to contain so you only see the last x visits.

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