I'm trying to get a string which matches by a regex pattern ( {$ ... } ). But I don't want the brackets and the $ sign returned.
For example
{$Testpath}/Testlink
should return
Testpath
My regex pattern looks like this at the moment:
^{\$.*}$
Try the following regex:
^\{\$\K[^}]*(?=\})
Regex101 Demo
This expression mathces start-of-string ^ then a literal { then a literal $ then it ignores those using \K anchor, then it matches one or more characters which aren't a } then it looks ahead (?=\}) for a literal }.
You may not need the end-of-line anchor $ because the text you are trying to match might not end at the end of the string and you may not need the start-of-line ^ anchor for the opposite reason, that is the pattern you are trying to match may not be at the start of the string or line.
I think you should remove ^ and $ and use the global modifier.
Related
I use a regex pattern i preg_match php function. The pattern is let's say '/abc$/'. It matches both strings:
'abc'
and
'abc
'
The second one has the line break at its end. What would be the pattern that matches only this first string?
'abc'
The reason why /abc$/ matches both "abc\n" and "abc" is that $ matches the location at the end of the string, or (even without /m modifier) the position before the newline that is at the end of the string.
You need the following regex:
/abc\z/
where \z is the unambiguous very end of the string, or
/abc$/D
where the /D modifier will make $ behave the same way as \z. See PHP.NET:
The meaning of dollar can be changed so that it matches only at the very end of the string, by setting the PCRE_DOLLAR_ENDONLY option at compile or matching time.
See the regex demo
I am trying to validate following type of string using regular expressions in PHP. Using PHP 5.5.9.
String is in following format:
/[sometext]/course/[sometext1]/[sometext2]
What I need is a regex that will accept string that is only in that format and nothing else. Meaning these would be invalid:
/aaa/course/bbb/ccc/
/aaa/course/bbb/ccc/ddd
What I have so far is this:
/\/(?P<domain>.+?)\/course\/(?P<courseid>.+?)\/(?P<reportname>.+?)/
Any ideas?
Update:
With the help from all posters and especially wiktor-stribi%c5%bcew I got this one that works:
$regex = '#^/(?P<domain>[^/]+)/course/(?P<courseid>[^/]+)/(?P<reportname>[^/]+)$#';
You can use the following regular expression:
^\/(?P<domain>[^\/]+)\/course\/(?P<courseid>[^\/]+)\/(?P<reportname>[^\/]+)$
PHP:
$re = '~^/(?P<domain>[^/]+)/course/(?P<courseid>[^/]+)/(?P<reportname>[^/]+)$~';
See the regex demo
The [^\/] is a negated character class that matches any character but /.
The ^ and $ are usually enough to make sure your input starts and ends with the current pattern (you can replace them with \A and \z respectively to make sure the \z matches at the very end of the string, or use ^/$ with the /D modifier).
Even if you use lazy .+? dot matching, the . can overflow several / delimiters if it is necessary to return a valid match.
first... use something other than '/' as your delimiter (the slashes as the beginning and end of the regex)... it makes it easier to write the regex without having to escape the delimiter within
$regex = '#^/[a-z]+/[^/]+/[a-z]+/[a-z]+$#'
I have a string like this
05/15/2015 09:19 PM pt_Product2017.9.abc.swl.px64_kor_7700 I need to select the pt_Product2017.9.abc.swl.px64_kor from that. (start with pt_ and end with _kor)
$str = "05/15/2015 09:19 PM pt_Product2017.9.abc.swl.px64_kor_7700";
preg_match('/^pt_*_kor$/',$str, $matches);
But it doesn't work.
You need to remove the anchors, adda \b at the beginning to match pt_ preceded with a non-word character, and use a \S with * (\S shorthand character class that matches any character but whitespace):
preg_match('/\bpt_\S*_kor/',$str, $matches);
See regex demo
In your regex,^ and $ force the regex engine to search for the ptat the beginning and _kor at the end of the string, and _* matches 0 or more underscores. Note that regex patterns are not the same as wildcards.
In case there can be whitespace between pt_ and _kor, use .*:
preg_match('/\bpt_.*_kor/',$str, $matches);
I should also mention greediness: if you have pt_something_kor_more_kor, the .*/\S* will match the whole string, but .*?/\S*? will match just pt_something_kor. Please adjust according to your requirements.
^ and $ are the start and end of the complete string, not only the matched one. So use simply (pt_.+_kor) to match everything between pt_ and _kor: preg_match('/(pt_+_kor)/',$str, $matches);
Here's a demo: https://regex101.com/r/qL4fW9/1
The ^ and $ that you have used in the regular expression means that the string should start with pt AND end with kor. But it's neither starting as such, nor ending with kor (in fact, ending with kor_7700).
Try removing the ^ and $, and you'll get the match:
preg_match('/pt_.*_kor/',$str, $matches);
I want to match a $ only at the end.
Why does it does not work:
<?php
$reg = '{$$}';
$str= 'helloc$a';
print preg_match($reg,$str);
It prints 1 -- matched. But I want it to match for example inputs like abc$ or zzz$ only.
$ is a meta-character in regular expressions and has a special meaning — it asserts the position at the end of a line. When you want to match a literal $, you'll need to escape it, i.e. use \$ instead of $:
$reg = '{\$$}';
As Casmir notes in the comments section below the answer, this pattern will also match when the last $ is immediately followed by a newline. To prevent this, you can use the following pattern instead:
$reg = '{\$$}D';
With the D modifier set, a dollar metacharacter in the pattern matches only at the end of the given string. If this modifier is not set, $ also matches immediately before the final character if it is a newline character.
$ is a special character in PHP. You should add a \ before it . Try this:
$reg = '/\$$/';
im kinda strumped in a situation where i need to match a whole string with a regular expression rather than finding if the pattern exists in the string.
suppose if i have a regular expression
/\\^^\\w+\\$^/
what i want is that the code will run through various strings , compare the strings with the regular expression and perform some task if the strings start and end with a ^.
Examples
^hello world^ is a match
my ^hello world^ should not be a match
the php function preg_match matches both of the results
any clues ???
Anchor the ends.
/^...$/
Here is a way to do the job:
$strs = array('^hello world^', 'my ^hello world^');
foreach($strs as $str) {
echo $str, preg_match('/^\^.*\^$/', $str) ? "\tmatch\n" : "\tdoesn't match\n";
}
Output:
^hello world^ match
my ^hello world^ doesn't match
Actually, ^\^\w+\^$ will not match "^hello world^" because you have two words there; the regex is only looking for a single word enclosed by "^"s.
What you are looking for is: ^\^.*\^$
This will match "^^", "^hello world^", "^a very long string of characters^", etc. while not matching "hello ^world^".
You can use the regex:
^\^[\w\s]+\^$
^ is a regex meta-character which is used as start anchor. To match a literal ^ you need to escape it as \^.
So we have:
^ : Start anchor
\^: A literal ^
[\w\s]+ : space separated words.
\^: A literal ^
$ : End anchor.
Ideone Link
Another pattern is: ^\^[^\^]*\^$ if you want match "^hello world^" and not "hello ^world^" , while \^[^\^]*\^ if you want match "^hello world^" and world in the "hello ^world^" string.
For Will: ^\^.*\^$ this match also "^hello^wo^rld^" i think isn't correct.
Try
/^\^\s*(\w+\s*)+\^$/