How to get xml Curl Response - php

I am use curl method to get response from server.
but when ehco this response it show as simple data.
but in view source it show xml format.
can anybody tell me how to print response as xml
I am using this code:
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
//curl_setopt($ch,CURLOPT_POST, count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS, $post_data_tcetra);
//execute post
$result = curl_exec($ch);
//close connection
curl_close($ch);

Use this:
ob_start();
$result = curl_exec($ch);
$xml = ob_get_contents();
ob_end_clean();
echo htmlspecialchars($xml);
The actual function you're searching for is called htmlspecialchars(). It converts symbols like < to to their entity references <.
In my code above, we also need the Output Caching (ob_*) functions, so that we can prevent the output from directly being sent to the browser. I'd suggest you though that you use the better way in the code below:
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
if ($result === false) {
// error handling
}
else {
echo htmlspecialchars($result);
}

Related

Sending array using curl

I want to send data from server 1 to server 2, first I select necessary data from the database, but how to send data with curl? I understand that I cannot send $result parameter just like in my code, but how should I do this?
My Code server 1:
public function setDivisions(){
$result = $this->conn->query("SELECT *FROM data_divisions");
$ch = curl_init('https://example.com/api.php?siteid='.$this->site_key.'');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $result);
curl_setopt($ch, CURLOPT_POST, 1);
$response = curl_exec($ch);
print_r($response);
}
Code on server 2:
$array = $_POST['result'];
//loop throw array and insert data into database
you can use it that way.
$ch = curl_init('https://upxxx.cod3fus1ontm.com/curl/json');
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode((object)["records" => json_encode($result)]));
$response = curl_exec($ch);
var_dump($response);
on receipt, like this!
$json = file_get_contents("php://input");
$content = json_decode($json, true);
$records = json_decode($content['records'], true);
foreach($records as $record) {
echo $record['id'] . " - " . $record['text'] . "<br/>";
}
remember, that as you did to encode, you will have to do to decode
Come on, php://input returns all raw data after the request's HTTP headers, regardless of content type.
When we do this with file_get_contents (which reads the contents of a file and puts it into a variable of type string), we can read the content that was sent by curl.
Reviewing the code, you can optimize as follows, when sending to the server you placed, I suggested:
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode((object)["records" => json_encode($result)]));
you can replace it with:
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($result));
it's much simpler, but it's very important to put the query result inside a json_encode
finally, you can access the entire body of the message, through file_get_contents ("php://input") and put it inside a variable, which is nothing more than a JSON of the your query.
for you to understand how the parameters were passed, it is interesting to do the following:
$json = file_get_contents("php: // input");
var_dump($json); <- Here you see the thing as it is.
$records = json_decode($json, true); <- Here you generate an object with the content of json
var_dump($records);
With that, I think that solves the situation.
on server 1
$result = "result=".base64_encode($result)
curl_setopt($ch, CURLOPT_POSTFIELDS, $result);
...
on server 2
$array = base64_decode($_POST['result']);

Retrieving data of curl post in PHP

I am trying to senddata to a url by using curl with codeigniter. I have successfully implemented the code for sending the data as below.
function postToURL($reg_no, $data)
{
$url = 'http://localhost/abcSystem/Web_data/viewPage';
$send_array = array(
'reg_no' =>$reg_no,
'data' =>$data,
);
$fields_string = http_build_query($send_array);
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 600);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_REFERER, $url);
$post_data = 'json='.urlencode(json_encode($send_array));
curl_setopt($ch, CURLOPT_POSTFIELDS, $post_data);
$output = curl_exec($ch);
if (curl_errno($ch)) {
die('Couldn\'t send request: ' . curl_error($ch));
} else {
$resultStatus = curl_getinfo($ch, CURLINFO_HTTP_CODE);
if ($resultStatus == 200) {
print_r('success'); // this is outputting
return $output;
} else {
die('Request failed: HTTP status code: ' . $resultStatus);
}
}
curl_close($ch);
}
The out put is success. I want to see if this post data can be retrieved. So I tried to change the above url controller file as below.
$fp = fopen('php://input', 'r');
$rawData = stream_get_contents($fp);
echo "<pre>";
print_r($rawData);
echo "</pre>";
But nothing is printing. I want to get the data of posting. Please help me on this.
Your Written code
$fp = fopen('php://input', 'r');
$rawData = stream_get_contents($fp);
echo "<pre>";
print_r($rawData);
echo "</pre>";
is not to Print or capture Posted Data . Because you are dealing with Current Page PHP INPUT Streaming , whereas you are posting data on Other URL . So what you need to do is just Put a log of posted data in File. Use below code after $output = curl_exec($ch)
file_put_contents("posted_data.txt", $post_data );
This way you will be able to write your each post in file Posted_data.txt File - Make sure you give proper File Permission. If you want to keep trace of each POST than just make the file name dynamic so per API Call it can write a log.
Another option is to save the $post_data in DATABASE - Which is not suggestable from Security point of view.
Where ever you are calling your postToURL() function, you need to output the result of it.
For example:
$output = postToURL('Example', array());
echo $output;
This is because you are returning the curl output rather outputting it.

How to extract data from a decoded JSON object in php

I wanted to try to get data from a JSON string which is loaded from another page. I currently have used Curl to get the data from the webpage but I can't acces the data in it.
I've already tried:
var_dump(json_decode($result->version, true));
var_dump(json_decode($result[3][0]["date"], true));
But this does't seem to work as it always returns NULL
$url="https://roosters.deltion.nl/api/roster?group=AO2B&start=20160125&end=20160201";
// Initiate curl
$ch = curl_init();
// Disable SSL verification
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
// Will return the response, if false it print the response
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
// Set the url
curl_setopt($ch, CURLOPT_URL,$url);
// Execute
$result=curl_exec($ch);
// Closing
curl_close($ch);
// Will dump a beauty json :3
var_dump(json_decode($result, true));
First decode the JSON, then get the properties you want. Like this:
$yourObject = json_decode($result);
var_dump($youObject->version);
this is working for me.
<?php
$url = "https://roosters.deltion.nl/api/roster?group=AO2B&start=20160125&end=20160201";
// Initiate curl
$ch = curl_init();
// Disable SSL verification
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
// Will return the response, if false it print the response
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
// Set the url
curl_setopt($ch, CURLOPT_URL, $url);
// Execute
$result = curl_exec($ch);
// Closing
curl_close($ch);
// Will dump a beauty json :3
$data = json_decode($result);
//echo $data->data[0]['date'];
echo "<pre>";
print_r($data->data[0]->date);
}
?>
if you want to get date of all index then try this in loop.
Firstly if your using GET there is no need to use CURL,
$result = file_get_contents(https://roosters.deltion.nl/api/roster?group=AO2B&start=20160125&end=20160201);
Will work just as well without any of the overhead. I suspect that your CURL isn't returning the page content so using file_get_contents() will fix it.

JSON text unparseable when using cURL to grab it?

I have this really long JSON string: http://pastebin.com/2jJKSGHs , which is being pulled from a music API.
I have this code set up to parse it ( http://pastebin.com/EuJtuhHg ):
$url = "https://api.discogs.com/database/search?type=artist&q=pink[keyandsecretredacted]";
//initialize the session
$ch = curl_init();
//Set the User-Agent Identifier
curl_setopt($ch, CURLOPT_USERAGENT, 'YourSite/0.1 +http://your-site-here.com');
//Set the URL of the page or file to download.
curl_setopt($ch, CURLOPT_URL, $url);
//Ask cURL to return the contents in a variable instead of simply echoing them
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
//Execute the curl session
$output = curl_exec($ch);
//close the session
curl_close ($ch);
//decode and print output
$output = json_decode($output2, true);
echo($output['results'][0]['title']);
When I insert the contents of the JSON string directly into my code, the json_decode works perfectly on it. But when I try to grab it from the API using the method above, nothing prints on my page -- it's just empty. Printing out json_last_error returns "0", so it's not detecting any errors.
Any ideas why this might be happening?
Replace
$output = curl_exec($ch);
with
$output2 = curl_exec($ch);
Otherwise $output2 isn't defined, and json_decode is using an undefined variable:
$output = json_decode($output2, true);

sending xml string using php curl but not as post parameter

:)
I'm trying to send an XML using curl but not as post parameter. what I mean is this.
for example.
the receiving side of that XML won't be able to recieve the XML using $_POST variable.
he will need to use the following code:
$xmlStr=null;
$file=fopen('php://input','r');
$xmlStr=fgets($file);
I want to be able to send an xml string using curl via https.
so the following would be wrong:
public static function HttpsNoVerify($url,$postFields=null,$verbose=false) {
// Initialize session and set URL.
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
// Set so curl_exec returns the result instead of outputting it.
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
if ($postFields !=null) {
curl_setopt($ch, CURLOPT_POSTFIELDS, $postFields);
}
if ($verbose) {
curl_setopt($ch, CURLOPT_VERBOSE, 1);
}
// Get the response and close the channel.
$response = curl_exec($ch);
curl_close($ch);
return $response;
}
because here i can use HttpsNoVerify($url,array('xml_file'=>'xml..')); and that
will paste it as post parameter. and i want it as post output.
so please I hope i explained myself properly and I explained exactly what I don't want to do.
how can I do what i want to do?
thanks! :)
kfir
Just directly pass the xml string as second parameter instead of an associative array item,
HttpsNoVerify($url, 'xml ..');
This will eventually call
curl_setopt($ch, CURLOPT_POSTFIELDS, "xml ...");
Which will be put in php://input for the remote server.

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