This question already has answers here:
Wrapping a div around every third item in a foreach loop PHP [closed]
(4 answers)
Group mysql results in groups of four
(1 answer)
Closed 2 years ago.
The below code does almost exactly what I want visually. Except Column 1 and Column 2 just show the same picture for all 10 entries, while Column 3 shows a unique entry every Row.
<!DOCTYPE html>
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Covid-Deaths</title>
<link rel="stylesheet" type="text/css" href="covid.css">
<script src="https://kit.fontawesome.com/1f285a5a86.js" crossorigin="anonymous"></script>
<script src="http://code.jquery.com/jquery-3.5.1.min.js"></script>
<script src="script.js"></script>
</head>
<body>
<h1>You're terrible at this</h1>
<p>Get each picture to be unique</p>
<?php
//database Connection
include 'dbconfig.php';
// retrieving data from table accounts
$query = "SELECT * FROM test_info where tf = 1 LIMIT 10";
$result = mysqli_query($conn, $query);
$query2 = "SELECT * FROM test_info where tf = 1 LIMIT 10 OFFSET 10";
$result2 = mysqli_query($conn, $query2);
$query3 = "SELECT * FROM test_info where tf = 1 LIMIT 10 OFFSET 20";
$result3 = mysqli_query($conn, $query3);
?>
<?php
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
if ($result2->num_rows > 0) {
while ($row2 = $result2->fetch_assoc()) {
if ($result3->num_rows > 0) {
while ($row3 = $result3->fetch_assoc()) {
?>
<div class="container">
<div class="card">
<a href="<?php echo $row['obit_url']; ?>"><img src="uploaded-images/<?php echo
$row['picture'];?>" width=80%/></a>
<h4><?php echo $row['names']; echo ", "; echo $row['age'];?></h4>
<p><?php echo " "; echo "State: "; echo $row['state']; ?></p>
</div>
<div class="card">
<a href="<?php echo $row2['obit_url']; ?>"><img src="uploaded-images/<?php echo
$row2['picture'];?>" width=80%/></a>
<h4><?php echo $row2['names']; echo ", "; echo $row2['age'];?></h4>
<p><?php echo " "; echo "State: "; echo $row2['state']; ?></p>
</div>
<div class="card">
<a href="<?php echo $row3['obit_url']; ?>"><img src="uploaded-images/<?php echo
$row3['picture'];?>" width=80%/></a>
<h4><?php echo $row3['names']; echo ", "; echo $row3['age'];?></h4>
<p><?php echo " "; echo "State: "; echo $row3['state']; ?></p>
</div>
</div>
<?php
}
}
}
}
}
}
?>
</body>
</html>
Example of what it outputs:
Steve Paul Mary
Steve Paul John
Steve Paul Sam
What I want it to look like:
Steve Paul Mary
Randy Kyle John
Phil Scott Sam
I can't seem to get the first and second column to pull in the unique entries that I know are there.
In the middle while loop, the first and second columns will stay the same as you don't fetch a new row for them.
You could change it to 1 while loop and just fetch the other rows in this 1 loop...
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$row2 = $result2->fetch_assoc();
$row3 = $result3->fetch_assoc();
this will fetch all 3 results in the same order. You would have to know what to do if any of them don't return a value though.
I wonder why the 2nd output $devNO gives me bool(false) which is empty. i have no idea about it. Am I wrong at the mysql_query() part?
$developer = $_POST['dev'];
$platform = $_POST['plat'];
$genre = $_POST['gen'];
var_dump($developer);
echo "<br>";
$devNO = mysql_query("SELECT No FROM developer WHERE Developer = $developer");
$platNO = mysql_query("SELECT No FROM platform WHERE Platform = $platform");
$genNO = mysql_query("SELECT No FROM genre WHERE Genre = $genre");
var_dump($devNO);
Here's my output:
Here I will show my full code for "games.php":
<!DOCTYPE html>
<html lang="en" xmlns="http://www.w3.org/1999/html">
<html>
<head lang="en">
<meta charset="utf-8" />
<title>Game List</title>
<link rel="stylesheet" href="css.css">
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.1/css/bootstrap.min.css">
<!-- Optional theme -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.1/css/bootstrap-theme.min.css">
<style>
legend {font-family: "Palatino Linotype", "Book Antiqua", Palatino, serif}
</style>
</head>
<body>
<div id="big_wrapper">
<header id="top_header">
<h1>Dandy's Game Library</h1>
</header>
<nav id="top_menu">
<ul>
<li><strong></stron>Home</strong></li>
<li><strong>Game List</strong></li>
</ul>
</nav>
<div id="game_wrapper">
<section id="filter">
<form action="games.php" method="post" name="search_form">
<fieldset>
<legend><h3><strong>Search</strong></h3></legend>
<strong>Developer</strong><br>
<select name="dev">
<option value="">--Select--</option>
<?php
include("dbConnection.php");
mysql_connect("localhost","root","");
mysql_select_db("games");
$sql = mysql_query("SELECT Publisher FROM publisher");
while($row = mysql_fetch_array($sql)){
echo "<option value='".$row['Publisher']."'>" .$row[Publisher]. "</option>";
}
?>
</select>
<br/><br/><strong>Game Platform</strong><br>
<select name="plat">
<option value="">--Select--</option>
<?php
$sql = mysql_query("SELECT Platform FROM platform");
while($row = mysql_fetch_array($sql)){
echo "<option value='".$row['Platform']."'>" .$row[Platform]. "</option>";
}
?>
</select>
<br/><br/><strong>Genre</strong><br>
<select name="gen">
<option value="">--Select--</option>
<?php
$sql = mysql_query("SELECT Genre FROM genre");
while($row = mysql_fetch_array($sql)){
echo "<option value='".$row['Genre']."'>" .$row[Genre]. "</option>";
}
$developer = $_POST['dev'];
$platform = $_POST['plat'];
$genre = $_POST['gen'];
?>
</select>
<br><br><input type="submit" name="search" value="Search"></input>
</fieldset>
</form>
</section>
<aside id="items">
<fieldset>
<legend><h3><strong>Game List</strong></h3></legend>
<?php
var_dump($developer);
$devNO = mysql_query("SELECT No FROM developer WHERE Developer = $developer");
$platNO = mysql_query("SELECT No FROM platform WHERE Platform = $platform");
$genNO = mysql_query("SELECT No FROM genre WHERE Genre = $genre");
var_dump($devNO);
$sql = sprintf("SELECT Title, Release_Year, Language, Price FROM games WHERE Developer_NO = $devNO");
$result = mysql_query($sql);
$game_title = 'Title';
$game_year = 'Release_Year';
$game_lan = 'Language';
$game_price = 'Price';
?>
<div id="gamelist">
<?php
if(!$result) {
die(mysql_error());
}
while($row = mysql_fetch_array($result)) {
?>
<div class="row">
<div class="cell"><?php echo $row[$game_title]?></div>
<div class="cell"><?php echo "Year : ".$row[$game_year]?></div>
<div class="cell"><?php echo "Language : ".$row[$game_lan]?></div>
<div class="cell"><?php echo "Price : RM".$row[$game_price]?></div>
</div>
<?php
}
?>
</div>
</fieldset>
</aside>
</div>
</div>
<div id="btm_wrapper">
<footer id="foot">
<strong></strong>
</footer>
</div>
</body>
</html>
The full output will be like this after i search from dropdown:
The method mysql_query() , if successful, returns a resultset, which has to be made an array even if only a single value is being returned from the query.
Ideally there should be a for-each iteration on this array to get result, however if you're sure you'll get at least one value, the first row with desired index('No' in your case).
$dataset= mysql_query("SELECT No FROM developer WHERE Developer = '$developer'");
$row = mysql_fetch_assoc($dataset);
$devNO = $row['No'];
Also note the quote I've used for varchar. It was correctly pointed in the other answer. Try Now.
If $developer is a string use quotes. You need to first fetch results from result set and than use it in code:
<?php
$devNOResult = mysql_query("SELECT No FROM developer WHERE Developer = '$developer'");
$platNOResult = mysql_query("SELECT No FROM platform WHERE Platform = '$platform'");
$genNOResult = mysql_query("SELECT No FROM genre WHERE Genre = '$genre'");
$devNO = mysql_fetch_row($devNOResult);
$sql = sprintf("SELECT Title, Release_Year, Language, Price FROM games WHERE Developer_NO = $devNO");
$result = mysql_query($sql);
$game_title = 'Title';
$game_year = 'Release_Year';
$game_lan = 'Language';
$game_price = 'Price';
?>
<div id="gamelist">
<?php
if(!$result) {
die(mysql_error());
}
while($row = mysql_fetch_array($result)) {
?>
I've been trying to add a section called: "related games", in it there is a script (related.php) that will fetch 5 random related games of the same category that the online game is displayed on.
I tried this (related.php):
<?php
if(isset($_GET['genre'])){
$game_category = $_GET['genre'];
$select_games = "SELECT * FROM games ORDER BY rand() LIMIT 0,5";
$run_games = mysql_query($select_games);
while($row = mysql_fetch_array($run_games)){
$game_id = $row['game_id'];
$game_name = $row['game_name'];
$game_image = $row['game_image'];
?>
<table>
<tr>
<div class="game_grid">
<a href="game_page.php?id=<?php echo $game_id; ?>"><img src="images/games_images/<?php echo $game_image; ?>" width="120" height="120" />
<span><?php echo $game_name; ?></span></a>
</div>
<tr>
</table>
<?php } } ?>
This is the "related.php" file and I tried to implement it in the following file called: "game_page.php" which works perfectly...
For some reason no random game is showing under the current played game...
Any idea?
I fixed it xD, I simply removed the
if(isset($_GET['genre'])){
$game_category = $_GET['genre'];
strings because they are already included in the "game_page.php" file :)
This question already has answers here:
Build SELECT query with dynamic number of LIKE conditions as a mysqli prepared statement
(2 answers)
Closed 1 year ago.
I have created search engine so when someone type in search box it takes data from my database and show the results in images.
Everything is working fine but if I have data in database with Name like 'Lamborghini', when someone type in search box 'lambo' or 'Lamborghini' it is working fine and show the result but when he types 'Lamborghini car' it is not showing any result.
Here is my PHP Code:
<html>
<link href="css/imgpages.css" rel="stylesheet" type="text/css">
<head>
<title>Search the Database</title>
</head>
<body>
<form action="" method="post">
Search: <input type="text" name="term" /><br />
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
<?php
include("connection.php");
$term = $_POST['term'];
$query = mysql_query("select * from save_data where Title like '%$term%'");
while($row = mysql_fetch_array($query)) {
$post_id = $row['ID'];
$title = $row['Title'];
$image = $row['Name'];
?>
<div id="body">
<a href="pictures.php?title=<?php echo $title; ?>">
<div id="title"><?php echo $title; ?></div></a>
<a href="pictures.php?title=<?php echo $title; ?>">
<img src='uploads/<?php echo $image; ?>' width='140' height='140'></a>
</div>
<?php } ?>
You should:
fix your SQL (make it secure - just one search could delete your whole database if you leave it like this, switch to mysqli or PDO because mysql_* functions are deprecated)
split your query string into separate words and decide how to handle them (whether you'll use OR or AND... in other words, do all search terms need to match, or any of them, etc.)
When you deal with all that and decide to make it more advanced, you should learn about full-text searching.
It is 'cause { %$term% } means the query try search something that contain all of the string in $term. Try this :
$term = explode(" ",$term);
if (count($term) > 0) {
$Where = '';
foreach($term as $Item) {
$Where .= "Title like '%$Item%' OR ";
}
$Where = substr($Where,0,-4);
$query = mysql_query("SELECT * FROM `save_data` WHERE $Where");
}
In this way the search will check out all words.
As the above people said just Explode the input string into an array and search for documents(description, keywords) where most of the elements match. Also take care of SQL Injection.
first make your term search explode so it would go into an array
<?php
$term = $_POST['term'];
$words = explode(" ", $term);
?>
then create a forearch loop for the mysql_query of your search and implode with "OR"
<?php
foreach ($words as $words)
{
$queries[]="select * from save_data where Title LIKE '%" .
mysql_real_escape_string($words) . "%'";
}
$query=implode(' OR ' ,$queries);
$results=mysql_query($query);
while($row = mysql_fetch_array($results))
{
$post_id = $row['ID'];
$title = $row['Title'];
$image = $row['Name'];
?>
<div id="body">
<a href="pictures.php?title=<?php echo $title; ?>">
<div id="title"><?php echo $title; ?></div>
</a>
<a href="pictures.php?title=<?php echo $title; ?>">
<img src='uploads/<?php echo $image; ?>' width='140' height='140'>
</a>
</div>
<?php } ?>
I wish to set the title of my webpage to Ultan.me - Whatever the post title. I want it to display the post title. The posts are submitted to a MySQL database and the title row is called "title". Any help is appreciated with this small question.
Update:
Here is the page itself now but it doesn't display the title. Should I open the php document and connect to my database somewhere different to it's current locations?
The Code (The only necessary piece is the beginning):
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?echo $title;?></title>
<link rel="stylesheet" href="css/styles.css" type="text/css" />
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>
<script type="text/javascript"
src="js/jquery.labelify.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$(":text").labelify();
});
</script>
<style>
a {text-decoration:none}
</style>
</head>
<body>
<div id="main">
<!-- Menu Start -->
<div id="menu">
<ul>
<li>home</li>
<li>about me</li>
<li>archives</li>
<li>contact</li>
<li>gallery</li>
</ul>
</div>
<!-- Menu End -->
<img src="images/banner.png" />
<div id="content">
<div id="posts">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$date = date("l F d Y", $row['timestamp']);
$title = stripslashes($row['title']);
$entry = stripslashes($row['entry']);
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $row[category]");
$category = mysql_fetch_array($get_categories);
?>
<p><?php echo "<p id='post-title'><strong>" . $title . "</strong></p>"; ?><br /><br />
<div id="entry"><?php echo $entry; ?>
</div><br /><br />
<p id="date">Posted in <?php echo $category['category_name']; ?> on <?php echo $date; ?></p>
</p>
<h2 id="share-title">Share This Post</h2>
<div id="social-share">
<li id="link-right"><a href="http://twitter.com/home?status=
I just read <?php echo $title; ?> at http://ultan.me/post.php?id=<?php echo $id; ?>"><center>Twitter</center></a></li>
<li id="link-left"><center>Digg</center></li>
<br>
<li id="link-right"><center>Facebook</center></li>
<li id="link-left"><a href="http://www.google.com/buzz/post?url=http://ultan.me/post.php?id=<?php echo $id; ?>
"><center>Google Buzz</center></a></li>
<div class="clr"></div>
</div>
<h2 id="comments-title">Comments</h2>
<div id="comment-list">
<?php
}
$commenttimestamp = strtotime("now");
$sql = "SELECT * FROM php_blog_comments WHERE entry='$id' ORDER BY timestamp";
$result = mysql_query ($sql) or print ("Can't select comments from table php_blog_comments.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$timestamp = date("l F d Y", $row['timestamp']);
printf("<div class='comment-ind'><p id='comments'><a id='username' href=\"%s\">%s</a> %s</p>", stripslashes($row['url']), stripslashes($row['name']), $timestamp);
print("<p class='comments'>" . stripslashes($row['comment']) . "</p><div class='clr'><br></div></div>");
}
?>
<div class="clr"></div>
<form id="commentform" method="post" action="process.php">
<p><input type="hidden" name="entry" id="entry" value="<?php echo $id; ?>" />
<input type="hidden" name="timestamp" id="timestamp" value="<?php echo $commenttimestamp; ?>">
<input type="text" name="name" id="name" title="Name (required)" /><br />
<input type="text" name="email" id="email" title="Mail (will not be published) (required)" /><br />
<input type="text" name="url" id="url" title="Website" value="http://" /><br />
<br />
<textarea title="Your Comment Goes Here" name="comment" id="comment"></textarea></p>
<p><input type="submit" name="submit_comment" id="submit_comment" value="Add Comment" /></p>
</form>
</div>
<div id="pages">
<?php
$total_results = mysql_fetch_array(mysql_query("SELECT COUNT(*) AS num FROM php_blog"));
$total_pages = ceil($total_results['num'] / $blog_postnumber);
if ($page > 1) {
$prev = ($page - 1);
echo "<< Newer ";
}
for($i = 1; $i <= $total_pages; $i++) {
if ($page == $i) {
echo "$i ";
}
else {
echo "$i ";
}
}
if ($page < $total_pages) {
$next = ($page + 1);
echo "Older >>";
}
?>
</div>
</div>
</div>
<!-- Sidebar Start -->
<div class="sidebar">
<!-- Item 1 -->
<div id="side-item">
<h2>
<a href="http://www.dailybooth.com/UltanCasey">
<img src="images/db-icon.jpg">Dailybooth
</a></h2>
<div id="side-item-content">
<center>
<img src="http://dailybooth.com/UltanCasey/latest/medium.jpg" />
</center>
</div>
</div>
<!-- Item 2 -->
<div id="side-item">
<h2><img src="images/connect.jpg" />Connect</h2>
</div>
<div id="side-item-content">
<div class="tweet-title"><p>Latest Tweet:</p></div>
<div id="tweet">
<?php
function getTwitterStatus($userid){
$url = "http://twitter.com/statuses/user_timeline/$userid.xml?count=1";
function auto_link_twitter ($text)
{
// properly formatted URLs
$urls = "/(((http[s]?:\/\/)|(www\.))?(([a-z][-a-z0-9]+\.)?[a-z][-a-z0-9]+\.[a-z]+(\.[a-z]{2,2})?)\/?[a-z0-9._\/~#&=;%+?-]+[a-z0-9\/#=?]{1,1})/is";
$text = preg_replace($urls, " <a href='$1'>$1</a>", $text);
// URLs without protocols
$text = preg_replace("/href=\"www/", "href=\"http://www", $text);
// Twitter usernames
$twitter = "/#([A-Za-z0-9_]+)/is";
$text = preg_replace ($twitter, " <a href='http://twitter.com/$1'>#$1</a>", $text);
// Twitter hashtags
$hashtag = "/#([A-Aa-z0-9_-]+)/is";
$text = preg_replace ($hashtag, " <a href='http://hashtags.org/$1'>#$1</a>", $text);
return $text;
}
$xml = simplexml_load_file($url) or die("could not connect");
foreach($xml->status as $status){
$text = $status->text;
}
echo auto_link_twitter ($text);
}
getTwitterStatus("UltanKC");
?>
</div>
<br>
<ul>
<li id="social">YouTube</li>
<li id="social">Twitter</li>
<li id="social">LastFM</li>
<li id="social">Email</li>
</ul>
</div>
<!-- Item 2 End-->
<div id="side-item">
<h2><img src="images/archive.jpg" />Archives</h2>
</div>
<div id="archive-side">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
$result = mysql_query("SELECT FROM_UNIXTIME(timestamp, '%Y') AS get_year, COUNT(*) AS entries FROM php_blog GROUP BY get_year");
while ($row = mysql_fetch_array($result)) {
$get_year = $row['get_year'];
$entries = $row['entries'];
echo "<li id='tag'>Entries from " . $get_year . " (" . $entries . ")<br /></li>";
}
$result1 = mysql_query("SELECT * FROM php_blog_categories ORDER BY category_name ASC");
while($row = mysql_fetch_array($result1)) {
$result2 = mysql_query("SELECT COUNT(`id`) AS entries FROM php_blog WHERE category = $row[category_id]");
$num_entries = mysql_fetch_array($result2);
echo '<li id="tag">' . $row['category_name'] . ' (' . $num_entries['entries'] . ')</li>';
}
?>
</div>
</div>
<div class="clr" />
</div>
<!-- Sidebar End -->
<div id="footer">
<p> © Ultan Casey 2010</p>
<p style="margin-top: -18px; float:right">Home | About Me | Email Me</p>
</div>
</div>
</div>
</body>
</html>
?>
Here's the method I use (for similar things, not just title):
<?
ob_start (); // Buffer output
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<title><!--TITLE--></title>
</head>
<body>
<?
$pageTitle = 'Title of Page'; // Call this in your pages' files to define the page title
?>
</body>
</html>
<?
$pageContents = ob_get_contents (); // Get all the page's HTML into a string
ob_end_clean (); // Wipe the buffer
// Replace <!--TITLE--> with $pageTitle variable contents, and print the HTML
echo str_replace ('<!--TITLE-->', $pageTitle, $pageContents);
?>
PHP usually works be executing any bits of code and printing all output directly to the browser. If you say "echo 'Some text here.';", that string will get sent the browser and is emptied from memory.
What output buffering does is say "Print all output to a buffer. Hold onto it. Don't send ANYTHING to the browser until I tell you to."
So what this does is it buffers all your pages' HTML into the buffer, then at the very end, after the tag, it uses ob_get_contents () to get the contents of the buffer (which is usually all your page's HTML source code which would have been sent the browser already) and puts that into a string.
ob_end_clean () empties the buffer and frees some memory. We don't need the source code anymore because we just stored it in $pageContents.
Then, lastly, I do a simple find & replace on your page's source code ($pageContents) for any instances of '' and replace them to whatever the $pageTitle variable was set to. Of course, it will then replace <title><!--TITLE--></title> with Your Page's Title. After that, I echo the $pageContents, just like the browser would have.
It effectively holds onto output so you can manipulate it before sending it to the browser.
Hopefully my comments are clear enough.
Look up ob_start () in the php manual ( http://php.net/ob_start ) if you want to know exactly how that works (and you should) :)
You parse the field from the database as usual.
Then let's say you put it in a variable called $title, you just
<html>
<head>
<title>Ultan.me - <?php echo htmlspecialchars($title);?></title>
</head>
EDIT:
I see your problem. You have to set $title BEFORE using it. That is, you should query the database before <title>...
header.php has the title tag set to <title>%TITLE%</title>; the "%" are important since hardly anyone types %TITLE% so u can use that for str_replace() later. then, you use output buffer like so
<?php
ob_start();
include("header.php");
$buffer=ob_get_contents();
ob_end_clean();
$buffer=str_replace("%TITLE%","NEW TITLE",$buffer);
echo $buffer;
?>
For more reference, click PHP - how to change title of the page AFTER including header.php?
What about using something like:
<?php
$page_title = "Your page tile";
include("navigation.php"); // if required
echo("<title>$page_title</title>");
?>
Move the data retrieval at the top of the script, and after that use:
<title>Ultan.me - <?php echo htmlspecialchars($title, ENT_QUOTES, 'UTF-8'); ?></title>
You need to set the value of $title before echoing it.
Also, you should really sanitize any data before using it in queries as this is a security risk
create a new page php and add this code:
<?php
function ch_title($title){
$output = ob_get_contents();
if ( ob_get_length() > 0) { ob_end_clean(); }
$patterns = array("/<title>(.*?)<\/title>/");
$replacements = array("<title>$title</title>");
$output = preg_replace($patterns, $replacements,$output);
echo $output;
}
?>
in <head> add code: <?php require 'page.php' ?> and on each page you call the function ch_title('my title');
The problem is that $title is being referenced on line 5 before it's being assigned on line 58. Rearranging your code isn't easy, because the data is both retrieved and output at the same time. Just to test, how does something like this work?
Because you're only retrieving one row, you don't need to use a while loop, but I left it with hopes that it'll make it easier for you to relate to your current code. All I've done is removed the actual output from your data retrieval, and added variables for category and category name which are then referred to as usual later on. Also, I haven't tested this. :)
It'll be tricky to rearrange your code to make this work, but I'll try :)
So, put this at the top of your code:
<?php require_once('mysql.php'); ?>
The top of the file should look like:
<?php require_once('mysql.php'); ?>
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?php echo htmlspecialchars($title); ?> </title>
Then, create a file called mysql.php in the same directory that the file which contains the code you quoted is in.
Put this is mysql.php:
<?php
mysql_connect ('localhost', 'root', 'root');
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
$res = mysql_fetch_assoc($result);
$date = date("l F d Y", $res['timestamp']);
$title = $res['title'];
$entry = $res['entry'];
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $res['category']");
$category = mysql_fetch_array($get_categories);
?>
Well, hope that helped :)
I know this is an old post but having read this I think this solution is much simpler (though technically it solves the problem with Javascript not PHP).
<html>
<head>
<title>Ultan.me - Unset</title>
<script type="text/javascript">
function setTitle( text ) {
document.title = text;
}
</script>
<!-- other head info -->
</head>
<?php
// Make the call to the DB to get the title text. See OP post for example
$title_text = "Ultan.me - DB Title";
// Use body onload to set the title of the page
print "<body onload=\"setTitle( '$title_text' )\" >";
// Rest of your code here
print "<p>Either use php to print stuff</p>";
?>
<p>or just drop in and out of php</p>
<?php
// close the html page
print "</body></html>";
?>
Simply add $title variable before require function
<?php
$title = "Your title goes here";
require("header.php");
?>
header.php
<title><?php echo $title; ?></title>
<?php echo APP_TITLE?> - <?php echo $page_title;?>
this should work fine for you
if you want to current script filename as your title tag
include the function in your project
function setTitle($requestUri)
{
$explodeRequestUri = explode("/", $requestUri);
$currentFileName = end($explodeRequestUri);
$withoutExt = preg_replace('/\\.[^.\\s]{3,4}$/', '', $currentFileName);
$explodeCurrentFileName = explode("-", $withoutExt);
foreach ($explodeCurrentFileName as $curFileValue)
{
$fileArrayName[] = ucfirst($curFileValue);
}
echo implode(" ", $fileArrayName);
}
and in your html include the function script
and replace your title tag with this
<title>Your Project Name -
<?php setTitle($_SERVER['REQUEST_URI']); ?>
</title>
it works on php7 and above but i dont have any idea about php 5.*
Hope it helps