I'm working on a project that produces reports on a weekly basis, so if today's date is "2013/09/05" the code has to figure out what was the date seven days ago, which is "2013/08/29", taking into account that some months are longer than others.
and then i want to run the dates against the database looking for matches ...
this is what i have done so far but its not working.
// Start date
$text = explode('/', $date); //2013/09/05
$day = $text[2];
$month = $text[1];
$year = $text[0];
$past_day = $day - 7; //-2
// determine if $past_day is negative
if ($past_day < 0){
$month = $month - 1; //08
$var = $day - 0; //2
$num = cal_days_in_month(CAL_GREGORIAN, $month, $year);
$var = ($num - $var); // 29
$start_date = $year."/".$month."/".$var;
}else{
$start_date = $year."/".$month."/".$past_day;
}
Thanks alot guys!
try this :)
$date = "2013/09/05";
// Start date
$text = explode('/', $date); //2013/09/05
$day = $text[2];
$month = $text[1];
$year = $text[0];
$past_day = $day - 7; //-2
// determine if $past_day is negative
if ($past_day < 0){
$month = $month - 1; //08
$var = ($past_day)*-1; //2
$num = cal_days_in_month(CAL_GREGORIAN, $month, $year);
$var = ($num - $var); // 29
$start_date = $year."/".$month."/".$var;
}else{
$start_date = $year."/".$month."/".$past_day;
}
Related
the code snippet below shows a simulation of installments, with fixed expiration dates, divided every 30 days!
I would like to include a periodic expiration date, for example, every 20 days, or 10 every 10, depending on the variable $periodicity;
I have no idea how to do it?
<?php
function calculate_due($num_installment, $first_due_date = null){
if($first_due_date != null)
{
$first_due_date = explode('/',$first_due_date);
$day = $first_due_date[0];
$month = $first_due_date[1];
$year = $first_due_date[2];
}
else
{
$day = date('d');
$month = date('m');
$year = date('Y');
}
$periodicity = 20;
for($installment = 0; $installment < $num_installment; $installment++)
{
if ($periodicity == 30)
echo date('d/m/Y', strtotime('+'.$installment. " month", mktime(0, 0, 0, $month, $day, $year))),'<br/>';
else
echo date('d/m/Y', strtotime('+'.$installment. " month", mktime(0, 0, 0, $month, $periodicity, $year))),'<br/>';
}
}
echo 'Calculates installments from an informed date<br/>';
calculate_due(5, '10/10/2020');
Try this,
<?php
function calculate_due($num_installment, $first_due_date = null, $days = 1){
$start = DateTime::createFromFormat('d/m/Y', $first_due_date);
$end = DateTime::createFromFormat('d/m/Y', $first_due_date);
$end->add(new DateInterval('P'.($num_installment * $days).'D'));
$period = new DatePeriod(
$start,
new DateInterval('P'.$days.'D'),
$end
);
$return = [];
foreach ($period as $date) {
$return[] = $date->format('d/m/Y');
}
return $return;
}
echo 'Calculates installments from an informed date<br/>'.PHP_EOL;
echo implode("\n", calculate_due(5, '10/10/2020', 20));
https://3v4l.org/TLR8a
Change 20 (the last function parameter) to suit the number of days between.
Result:
Calculates installments from an informed date<br/>
10/10/2020<br/>
30/10/2020<br/>
19/11/2020<br/>
09/12/2020<br/>
29/12/2020<br/>
I have a period with startdate of 2016-12-26 and end date 2017-03-04.
Now I would like to find out how many days in each months there is, from a given period. Expected output from the above period dates (array):
2016-12: 5
2017-01: 31
2017-02: 28
2017-03: 4
How can I accomplish this cleanest way? I have tried to:
first looking at the period_start, get the days = 26 and
find out the start/end dates of the months between 2016-12 and 2017-03, to then calculate the days here (31 respectively 28 in february)
then finally calculating the 4 days in 2017-03.
But is there any cleaner/better way?
This can be achieved easily using the DateTime class. Create the objects, and use DateTime::diff() on them, then use the days property.
$start = new DateTime("2016-12-26");
$end = new DateTime("2017-03-04");
echo $start->diff($end)->days; // Output: 68
Live demo
http://php.net/datetime.construct
#Karem hope this logic will help you, this is working case for all your conditions please try this below one:
<?php
$startDate = '2016-12-26';
$endDate = '2017-03-04';
$varDate = $startDate;
while($varDate < $endDate){
$d = date('d', strtotime($varDate));
$Y = date('Y', strtotime($varDate));
$m = date('m', strtotime($varDate));
$days = cal_days_in_month(CAL_GREGORIAN,$m,$Y);
$time = strtotime($varDate);
if($varDate == $startDate){
$time = strtotime(date('Y-m-01', $time));
$days = $days - $d;
}
else if(date("Y-m", strtotime($varDate)) == date("Y-m", strtotime($endDate))){
$days = date("j", strtotime($endDate));
}
echo date('Y-m', strtotime($varDate)). ": ".$days."<br>";
$varDate = date('Y-m-d', strtotime("+1 month", $time));
}
This is long but easy to understand that how to achieve you your goal
<?php
function getMonthDays($start,$end){
if($start < $end){
$start_time = strtotime($start);
$last_day_of_start = strtotime(date("Y-m-t",$start_time));
$start_month_days = ($last_day_of_start - $start_time)/(60*60*24);
echo date("Y-m",$start_time).": ".$start_month_days."\n";
$days = "";
$start = date("Y-m-d", strtotime("+1 month", $start_time));
$start_time = strtotime($start);
while($start < $end){
$month = date("m",$start_time);
$year = date("Y",$start_time);
$days = date('t', mktime(0, 0, 0, $month, 1, $year));
echo date("Y-m",$start_time).": ".$days."\n";
$start = date("Y-m-d", strtotime("+1 month", $start_time));
$start_time = strtotime($start);
}
echo date("Y-m",strtotime($end)).": ".date("d",strtotime($end))."\n";
}else{
echo "Wrong Input";
}
}
getMonthDays('2016-12-26','2017-03-04');
?>
live demo : https://eval.in/781724
Function returns array : https://eval.in/781741
<?php
$d1 = strtotime('2016-12-26');
$d2 = strtotime('2017-03-04');
echo floor(($d2 - $d1)/(60*60*24));
?>
i used Carbon (https://carbon.nesbot.com/docs/) but you can do it with any other time lib.
$startDate = Carbon::createFromFormat('!Y-m-d', '2017-01-11');;
$endDate = Carbon::createFromFormat('!Y-m-d', '2018-11-13');;
$diffInMonths = $endDate->diffInMonths($startDate);
for ($i = 0; $i <= $diffInMonths; $i++) {
$start = $i == 0 ? $startDate->copy()->addMonth($i) : $startDate->copy()->addMonth($i)->firstOfMonth();
$end = $diffInMonths == $i ? $endDate->copy() : $start->copy()->endOfMonth();
echo $end->format('Y-m') . ' ' . ($end->diffInDays($start) + 1) . PHP_EOL;
}
Here is the original script
<?php
$monthToAdd = 36;
$d1 = DateTime::createFromFormat('Y-m-d', '2016-04-10');
$year = $d1->format('Y');
$month = $d1->format('n');
$day = $d1->format('d');
$year += floor($monthToAdd/12);
$monthToAdd = $monthToAdd%12;
$month += $monthToAdd;
if($month > 12) {
$year ++;
$month = $month % 12;
if($month === 0)
$month = 12;
}
if(!checkdate($month, $day, $year)) {
$d2 = DateTime::createFromFormat('Y-n-j', $year.'-'.$month.'-1');
$d2->modify('last day of');
}else {
$d2 = DateTime::createFromFormat('Y-n-d', $year.'-'.$month.'-'.$day);
}
$d2->setTime($d1->format('H'), $d1->format('i'), $d1->format('s'));
echo $d2->format('d-m-Y');
?>
and here is the one that I edited
<?php
$y = 2016;
$m = 04;
$d = 10;
$monthToAdd = 36;
$d1 = DateTime::createFromFormat('Y-m-d', '$y-$m-$d');
$year = $d1->format('Y');
$month = $d1->format('n');
$day = $d1->format('d');
$year += floor($monthToAdd/12);
$monthToAdd = $monthToAdd%12;
$month += $monthToAdd;
if($month > 12) {
$year ++;
$month = $month % 12;
if($month === 0)
$month = 12;
}
if(!checkdate($month, $day, $year)) {
$d2 = DateTime::createFromFormat('Y-n-j', $year.'-'.$month.'-1');
$d2->modify('last day of');
}else {
$d2 = DateTime::createFromFormat('Y-n-d', $year.'-'.$month.'-'.$day);
}
$d2->setTime($d1->format('H'), $d1->format('i'), $d1->format('s'));
echo $d2->format('d-m-Y');
?>
it give error
Idea is to add X value as month , show the result.
For example the date provided is "2016-04-10" and $monthToAdd = 4; , it should give a result of 2016-08-10
script was working , but I just want to add a form so that user can input month to calculate.
I am new to php, anyone help ?
In order for php to parse variables within stings properly, you must wrap them in double quote marks (").
Change
$d1 = DateTime::createFromFormat('Y-m-d', '$y-$m-$d');
to
$d1 = DateTime::createFromFormat('Y-m-d', "$y-$m-$d");
Try to change this
$d1 = DateTime::createFromFormat('Y-m-d', '$y-$m-$d');
to
$d1 = DateTime::createFromFormat('Y-m-d', "$y-$m-$d");
php won't parse values inside of ' but it will inside of "
Hope that helps, if not, could you please pass on the exact error, and the line that it references.
I'm pretty sure I'm overcomplicating this but atm I have no clue how to do it in another way.
I want to create an array which contains the number of a week in a month as a key and the days of this week as the value.
I'm using this function to get all days of a week:
public function getDaysOfWeek($year, $month, $day)
{
$firstMondayThisWeek = new DateTime($year . '/' . $month . '/' . $day, new DateTimeZone("Europe/Berlin"));
$firstMondayThisWeek->modify('tomorrow');
$firstMondayThisWeek->modify('last Monday');
$nextSevenDays = new DatePeriod(
$firstMondayThisWeek,
DateInterval::createFromDateString('+1 day'),
6
);
return $nextSevenDays;
}
And this function to build the array:
public function getWeekAndDays($year, $month)
{
$weeksInMonth = Carbon::createFromDate($year, $month)->endOfMonth()->weekOfMonth;
$weekBegin = Carbon::createFromDate($year, $month)->startOfMonth();
$weeks = [];
for($i=1; $i<=$weeksInMonth; $i++)
{
$collection = new \stdClass();
$collection->week = $i;
$collection->days = $this->getDaysOfWeek($year, $month, $weekBegin->day);
$weekBegin->addWeek(0);
$weeks[] = $collection;
}
return $weeks;
}
For all months except february I'm getting 5 weeks. For February I'm getting 4 weeks and so I'm not able to save the month-overlapping days.
Am I completely wrong here? What is a possible way to solve this task?
My friend I feel your pain, working with calendar data is annoying. Here's a function I wrote a while back that builds an array of weeks and days, separated by months. It's not the cleanest code but it works.
It will start from the date you pass in $today as "Y-m-d" (or default to the current date), then work back to the first week of the current month, start there, and then go forward for $scheduleMonths months building an array indexed first by month and then by week.
It's a bit hard to explain here, but it's self-contained so you can just copy/paste it into your code and then dd() the output to see what it looks like and if it works for you, and modify it from there. There's some formatting you may need to adjust as it was done that way for my specific use case, but the business logic should be sound.
You should be able to extract the number of weeks in a given month from the output (so if that's all you need you can prob simplify this once you confirm it's working).
public function getWeeks($today = null, $scheduleMonths = 6) {
$today = !is_null($today) ? Carbon::createFromFormat('Y-m-d',$today) : Carbon::now();
$startDate = Carbon::instance($today)->startOfMonth()->startOfWeek()->subDay(); // start on Sunday
$endDate = Carbon::instance($startDate)->addMonths($scheduleMonths)->endOfMonth();
$endDate->addDays(6 - $endDate->dayOfWeek);
$epoch = Carbon::createFromTimestamp(0);
$firstDay = $epoch->diffInDays($startDate);
$lastDay = $epoch->diffInDays($endDate);
$week=0;
$monthNum = $today->month;
$yearNum = $today->year;
$prevDay = null;
$theDay = $startDate;
$prevMonth = $monthNum;
$data = array();
while ($firstDay < $lastDay) {
if (($theDay->dayOfWeek == Carbon::SUNDAY) && (($theDay->month > $monthNum) || ($theDay->month == 1))) $monthNum = $theDay->month;
if ($prevMonth > $monthNum) $yearNum++;
$theMonth = Carbon::createFromFormat("Y-m-d",$yearNum."-".$monthNum."-01")->format('F Y');
if (!array_key_exists($theMonth,$data)) $data[$theMonth] = array();
if (!array_key_exists($week,$data[$theMonth])) $data[$theMonth][$week] = array(
'day_range' => '',
);
if ($theDay->dayOfWeek == Carbon::SUNDAY) $data[$theMonth][$week]['day_range'] = sprintf("%d-",$theDay->day);
if ($theDay->dayOfWeek == Carbon::SATURDAY) $data[$theMonth][$week]['day_range'] .= sprintf("%d",$theDay->day);
$firstDay++;
if ($theDay->dayOfWeek == Carbon::SATURDAY) $week++;
$theDay = $theDay->copy()->addDay();
$prevMonth = $monthNum;
}
$totalWeeks = $week;
return array(
'startDate' => $startDate,
'endDate' => $endDate,
'totalWeeks' => $totalWeeks,
'schedule' => $data,
);
}
I hope this helps you at least get started!
Something like this?
function weekOfMonth($date) {
$firstOfMonth = strtotime(date("Y-m-01", $date));
$lastWeekNumber = (int)date("W", $date);
$firstWeekNumber = (int)date("W", $firstOfMonth);
if (12 === (int)date("m", $date)) {
if (1 == $lastWeekNumber) {
$lastWeekNumber = (int)date("W", ($date - (7*24*60*60))) + 1;
}
} elseif (1 === (int)date("m", $date) and 1 < $firstWeekNumber) {
$firstWeekNumber = 0;
}
return $lastWeekNumber - $firstWeekNumber + 1;
}
function weeks($month, $year){
$lastday = date("t", mktime(0, 0, 0, $month, 1, $year));
return weekOfMonth(strtotime($year.'-'.$month.'-'.$lastday));
}
$result = [];
for ($year = 2017; $year < 2020; $year++){
for ($month = 1; $month < 13; $month++) {
$numOfWeeks = weeks($month, $year);
$result[$year][$month]['numOfWeeks'] = $numOfWeeks;
$daysInFirstWeek = 8 - date('N', strtotime($year.'-'.$month.'-01'));
$result[$year][$month]['daysPerWeek']['week_1'] = $daysInFirstWeek;
$startDay = date('d', strtotime('next Monday', strtotime($year.'-'.$month.'-01')));
for ($i = 1; $i < ($numOfWeeks - 1); $i++) {
$startDay += 7;
$result[$year][$month]['daysPerWeek']['week_'.($i+1)] = 7;
}
//last week
$result[$year][$month]['daysPerWeek']['week_'.($i+1)] = date('t', strtotime($year.'-'.$month.'-01')) - $startDay + 1;
}
}
echo json_encode($result)."\n";
Consider there are 44 days between two dates.The result what I want is 2 months and not 1 month or 1 month 14 days.I have tried several date functions in both php and mysql,but failed in obtaining the exact result. I've also tried my own(below)code.
$dt1 = some date
$dt2 = some date
$date1 = date_create("".$dtl."");
$date2 = date_create("".$dt2."");
$dateDiff = date_diff($date2, $date1);
$probDays = $dateDiff->days;
$probMon = $dateDiff->m;
$probYear = $dateDiff->y;
$month = $probDays / 30;
$totLeave = $month * 1;
if($month > $probmon)
{
$totLeave = $totLeave + 1;
}
But I failed.The code is about adding vacation days to the client.Any solution in php or mysql would be grateful.Thanks in advance for all the volunteers.
Using PHP 5.3, maybe you could try the following:
<?php
$dt1 = "2014-05-12";
$dt2 = "2014-06-15";
$date1 = new DateTime($dt1);
$date2 = new DateTime($dt2);
$months = $date1->diff($date2)->m;
$days = $date1->diff($date2)->d;
if ($days >= 1) $months++;
echo $months." months!";
?>
Try to check number of days, if not equal to zero, then add 1 to months count and return that value of months.
<?php
$dt_dif= $dt2 - $dt1 ;
$y = $tot_exp / 365;
$d = $tot_exp % 365;
$m = $d / 30;
$year = (int)$y;
$month = (int)$m;
$day= (int)$d;
$total="".$month."month(s) ".$day."day(s)";
?>
John Riedel answer is the correct one!
You need to use $start_date->diff($end_date)->m & $start_date->diff($end_date)->d to find out the month & date differences.. and if the days count is more than 0, then you need to increase the months count as stated here...
http://www.phpguy.in/finding-difference-between-2-dates-in-php/
$date_from = "2011-01-22";
$date_to = "2011-03-23";
$date_from = date('Y-m-d', strtotime($date_from));
$date_to = date('Y-m-d', strtotime($date_to));
$y1 = date('Y', strtotime($date_from));
$y2 = date('Y', strtotime($date_to));
$m1 = date('m', strtotime($date_from));
$m2 = date('m', strtotime($date_to));
$day1 = date('d', strtotime($date_from));
$day2 = date('d', strtotime($date_to));
$yearDiff = $y2 - $y1;
if ($m2 > $m1) {
$month = $m2 - $m1;
} else {
$month = 0;
}
if ($yearDiff > 0 && $m1 > $m2) {
$yearMonth = (($yearDiff * 12) - ($m1 - $m2));
} else {
$yearMonth = $yearDiff * 12;
}
if ($day1 > $day2) {
$month = ($month - 1);
}
$total_month = $yearMonth + $month;
$total_month = ($total_month > 1) ? $total_month . " months" : $total_month . " month";
echo "Total " . $total_month;