Get text after "pid=" and before " (" [closed] - php

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I'm using php to execute a command to run a game server that outputs a string. I need to parse the pid out of the string so that I can save it and then use it to kill the process at a later date.
"...server daemon started with pid=6849 (parent=6848)."
So It would return 6849.

if (preg_match('/pid=(\d+)/', $string, $matches) {
$pid = $matches[1];
}

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Select text on a string after X symbol [closed]

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i have this string
$string = "Social\Notify\Models\User";
How can i tell to php how select just the fourth segment of it? in this case just the word User?
Something like this will do?
$str='Social\Notify\Models\User';
echo explode('\\',$str)[3]; //"prints" User

How to save a file from a url with php [closed]

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How can I save "example.mp4" from $url="http://videos.com/example.mp4" as "56.mp4" using a variable $id=56 to /videos
mkdir('/videos');
file_put_contents("/videos/" . ((string) $id) . ".mp4", file_get_contents($url));
Documentation:
http://php.net/manual/en/function.file-get-contents.php
http://php.net/manual/en/function.file-put-contents.php

Find specific string from response in php [closed]

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I am getting following response
{"success":true,"error":false,"code":"SJKUT3GR"}
I just want to print SJKUT3GR from above.
anyone knows how to do this?
$data = json_decode($response);
echo $data->code;

Matching string with preg_match [closed]

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I have the following string formats: "$ 3.20" or "$ 10.34". I want to verify with preg_match if the string is exactly this type of a format.
Any suggestions are appreciated?
Try this pattern:
if (preg_match('/\$\s[\d]+\.[\d]{2}/', $text)){
//do something
}

How to parse HTML and preformat using php [closed]

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I have text like this Too early to post? http://www.somewebsite.com/article/226973 I want to parse the hyperlinks in the text and make the text look like so Too early to post? http://www.entrepreneur.com/article/226973 I want to do this but I have no idea where to start from or what regexp to use.
$s = 'Too early to post? https://www.somewebsite.com/article/226973';
$parsed = preg_replace('#(https?://([-\w\.]+[-\w])+(:\d+)?(/([\w/_\.#-]*(\?\S+)?[^\.\s])?)?)#', '$1', $s);
echo $parsed;

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