HTTP Error 400. The request is badly formed - php

Question

I am getting the same error for this, please suggest
$url="http://domain.com/manage/File Name.xml";
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url); // get the url contents
$data = curl_exec($ch); // execute curl request
curl_close($ch);
echo $data;

Answer 1

This error come, when your curl url contains white spaces. you have to encode url for remove white space.
$base_url = "http://domain.com/manage/";
$url = "File Name.xml";
$ch = curl_init();
$final_url = $base_url . curl_escape($ch, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url); // get the url contents
$data = curl_exec($ch); // execute curl request
curl_close($ch);
echo $data;

Answer 2

As describe in the comment, your URL contains not encoded characters (spaces).
Solution
Encode your URL when setting CURLOPT_URL:
curl_setopt($ch, CURLOPT_URL, urlencode($url));
You could also use curl_escape() to encode the query string part.
References
answer of cURL having issues handling URL Source with colons.

Answer 3

You need to encode your URL before sending the request
<?php
$url=urlencode("http://domain/file name.xml");
?>
urlencode

Answer 4

Answers here suggest using url_encode or curl_escape functions. If you want to be RFC 3986 compliant, use rawurlencode() function instead. This helped with a curl request in PHP 7. Hoep it helps others.